I have two tables
Table A:
ID
1
2
3
4
Table B:
ID
1
2
3
I have two requests:
I want to select all rows in table A that table B doesn't have, which in this case is row 4.
I want to delete all rows that table B doesn't have.
I am using SQL Server 2000.
You could use NOT IN:
SELECT A.* FROM A WHERE ID NOT IN(SELECT ID FROM B)
However, meanwhile i prefer NOT EXISTS:
SELECT A.* FROM A WHERE NOT EXISTS(SELECT 1 FROM B WHERE B.ID=A.ID)
There are other options as well, this article explains all advantages and disadvantages very well:
Should I use NOT IN, OUTER APPLY, LEFT OUTER JOIN, EXCEPT, or NOT EXISTS?
For your first question there are at least three common methods to choose from:
NOT EXISTS
NOT IN
LEFT JOIN
The SQL looks like this:
SELECT * FROM TableA WHERE NOT EXISTS (
SELECT NULL
FROM TableB
WHERE TableB.ID = TableA.ID
)
SELECT * FROM TableA WHERE ID NOT IN (
SELECT ID FROM TableB
)
SELECT TableA.* FROM TableA
LEFT JOIN TableB
ON TableA.ID = TableB.ID
WHERE TableB.ID IS NULL
Depending on which database you are using, the performance of each can vary. For SQL Server (not nullable columns):
NOT EXISTS and NOT IN predicates are the best way to search for missing values, as long as both columns in question are NOT NULL.
select ID from A where ID not in (select ID from B);
or
select ID from A except select ID from B;
Your second question:
delete from A where ID not in (select ID from B);
SELECT ID
FROM A
WHERE NOT EXISTS( SELECT 1
FROM B
WHERE B.ID = A.ID
)
This would select 4 in your case
SELECT ID FROM TableA WHERE ID NOT IN (SELECT ID FROM TableB)
This would delete them
DELETE FROM TableA WHERE ID NOT IN (SELECT ID FROM TableB)
SELECT ID
FROM A
WHERE ID NOT IN (
SELECT ID
FROM B);
SELECT ID
FROM A a
WHERE NOT EXISTS (
SELECT 1
FROM B b
WHERE b.ID = a.ID)
SELECT a.ID
FROM A a
LEFT OUTER JOIN B b
ON a.ID = b.ID
WHERE b.ID IS NULL
DELETE
FROM A
WHERE ID NOT IN (
SELECT ID
FROM B)
Related
I have two tables in my database. From the Table B i collect some data. I include by using JOIN the data from Table A. In this table there is a column user_id. The user id in table B is the the id from Table A. No i want to get all data from table A but without showing data if the table A id is in the table B column user_id available. I think the trick is the correct usage of JOIN but i need to check the whole column and not just one line.
SQL Query (which is probably not working)
SELECT * FROM tableB
JOIN tableA
ON tableB.user_id = tableA.id
WHERE tableB.user_id != tableA.id
Please see my example i have prepared in Excel:
To select all the data from tableA where id is not available in tableB you don't need join rather you can use not exists or not in.
I would prefer not exists
Using not exists:
SELECT * from tableA a
WHERE NOT EXISTS (
SELECT 1
FROM tableB b
WHERE b.user_id = a.id
);
using not in:
SELECT * from tableA a
WHERE id not in (SELECT user_id FROM tableB );
DB-Fiddle:
create table TableA (id int, name varchar(50), lastname varchar(50));
insert into TableA values(1,'john','smith');
insert into TableA values(2,'Paul','smith');
create table TableB (id int, user_id int, something varchar(50));
insert into TableB values(1,2,'bla');
insert into TableB values(2,3,'bla');
Query: (using not exists)
SELECT * from tableA a
WHERE NOT EXISTS (
SELECT 1
FROM tableB b
WHERE b.user_id = a.id
);
Output:
id
name
lastname
1
john
smith
Query: (using not in)
SELECT * from tableA
WHERE id not in (SELECT user_id FROM tableB );
Output:
id
name
lastname
1
john
smith
db<fiddle here
I think I get what you want. You want not exists:
SELECT *
FROM tableB b JOIN
tableA a
ON b.user_id = a.id
WHERE NOT EXISTS (SELECT 1
FROM tableA a2
WHERE b.user_id = a2.id
);
EDIT:
I wrote the above, but I didn't fully follow the JOIN conditions. You either seem to want to join on id:
SELECT *
FROM tableB b JOIN
tableA a
ON b.id = a.id
WHERE NOT EXISTS (SELECT 1
FROM tableA a2
WHERE b.user_id = a2.id
);
Or no JOIN at all:
SELECT *
FROM tableB b
WHERE NOT EXISTS (SELECT 1
FROM tableA a2
WHERE b.user_id = a2.id
);
Table A:
id Name
1 a
2 b
3 c
4 d
5 e
Table B:
id Name
3 c
4 d
5 e
Here, id is the primary key connected to Table B.
I need output like this:-
id
1
2
That means, which ids in Table A are not present in Table B
Use EXCEPT operator:
select id from tableA
except
select id from tableB
You can use a left join, which will preserve all records on the left side and associate them with null if no matching record is available on the right side.
This way you can then filter on the right side columns to be null to get the desired outcome
select t1.id
from tableA t1
left join
tableB t2
on t1.id = t2.id
where t2.id is null
Use NOT EXISTS in WHERE clause
SELECT id FROM TableA A
WHERE NOT EXISTS(SELECT 1 FROM TableB B WHERE A.id = B.Id )
Using Not in statement.
Try this:-
Select id from TableA
where id not in (Select id from TableB);
You can use minus:
select * from tableA
minus
select * from tableB
I have 3 tables. All of them have a column - id. I want to find if there is any value that is common across the tables. Assuming that the tables are named a.b and c, if id value 3 is present is a and b, there is a problem. The query can/should exit at the first such occurrence. There is no need to probe further. What I have now is something like
( select id from a intersect select id from b )
union
( select id from b intersect select id from c )
union
( select id from a intersect select id from c )
Obviously, this is not very efficient. Database is PostgreSQL, version 9.0
id is not unique in the individual tables. It is OK to have duplicates in the same table. But if a value is present in just 2 of the 3 tables, that also needs to be flagged and there is no need to check for existence in he third table, or check if there are more such values. One value, present in more than one table, and I can stop.
Although id is not unique within any given table, it should be unique across the tables; a union of distinct id should be unique, so:
select id from (
select distinct id from a
union all
select distinct id from b
union all
select distinct id from c) x
group by id
having count(*) > 1
Note the use of union all, which preserves duplicates (plain union removes duplicates).
I would suggest a simple join:
select a.id
from a join
b
on a.id = b.id join
c
on a.id = c.id
limit 1;
If you have a query that uses union or group by (or order by, but that is not relevant here), then you need to process all the data before returning a single row. A join can start returning rows as soon as the first values are found.
An alternative, but similar method is:
select a.id
from a
where exists (select 1 from b where a.id = b.id) and
exists (select 1 from c where a.id = c.id);
If a is the smallest table and id is indexes in b and c, then this could be quite fast.
Try this
select id from
(
select distinct id, 1 as t from a
union all
select distinct id, 2 as t from b
union all
select distinct id, 3 as t from c
) as t
group by id having count(t)=3
It is OK to have duplicates in the same table.
The query can/should exit at the first such occurrence.
SELECT 'OMG!' AS danger_bill_robinson
WHERE EXISTS (SELECT 1
FROM a,b,c -- maybe there is a place for old-style joins ...
WHERE a.id = b.id
OR a.id = c.id
OR c.id = b.id
);
Update: it appears the optimiser does not like carthesian joins with 3 OR conditions. The below query is a bit faster:
SELECT 'WTF!' AS danger_bill_robinson
WHERE exists (select 1 from a JOIN b USING (id))
OR exists (select 1 from a JOIN c USING (id))
OR exists (select 1 from c JOIN b USING (id))
;
I have a Scenario where i am required to search unique id in Mutiple tables and assign a level based on where it exist.
Table Hierarchy
TableA
TableB
TableC
Table B holds primary key of table A and Table C holds the Primary of TableB
I need to have a function that takes Id as parameter and Searches that Id in this Table Hierarchy and Return Level i-e If it exist in TableA Level should be One. If it exists in TableB Level should be 2 and if it's in TableC then level should be 3
Here's one way:
SELECT CASE WHEN EXISTS(SELECT 1 FROM TableC WHERE id = #id) THEN '3'
WHEN EXISTS(SELECT 1 FROM TableB WHERE id = #id) THEN '2'
WHEN EXISTS(SELECT 1 FROM TableA WHERE id = #id) THEN 'One'
END AS "Level"
Assuming you want to return the highest level, 3 being the highest for TableC, then something like this should work using the CASE statement:
SELECT
CASE
WHEN C.Id IS NOT NULL THEN 3
WHEN B.Id IS NOT NULL THEN 2
WHEN A.Id IS NOT NULL THEN 1
END as Level
FROM (SELECT #Id as Id) H
LEFT JOIN TableA A ON H.Id = A.Id
LEFT JOIN TableB B ON H.Id = B.Id
LEFT JOIN TableC C ON H.Id = C.Id
Where #Id is the Id of the value you are searching for, for example SELECT 1 as Id.
Good luck.
You need a query that looks like this:
SELECT 1 FROM TableA WHERE id = {0}
UNION ALL
SELECT 2 FROM TableB WHERE id = {0}
UNION ALL
SELECT 3 FROM TableC WHERE id = {0}
The advantage to this over "WHEN" statements is that a) I don't like WHEN statements, and b) if a key exists in multiple tables, this returns a record for each, giving you the opportunity to build program logic around handling that case.
I have table A
Id | Name | Department
-----------------------------
0 | Alice | 1
0 | Alice | 2
1 | Bob | 1
and table B
Id | Name
-------------
0 | Alice
I want to select all unique Ids in table A which do not exist in table B. how can I do this?
select distinct id
from TableA a
where not exists (
select id
from TableB
where id = a.id
)
Just to provide a different solution than NOT IN :
SELECT DISTINCT A.Id
FROM A
LEFT OUTER JOIN B
ON A.Id = B.Id
WHERE B.Id IS NULL
The "good" solution is usually MINUS or EXCEPT, but MySQL doesn't support it.
This question was asked a few time ago and someone posted an article comparing NOT IN, NOT EXISTS and LEFT OUTER JOIN ... IS NULL. It would be interesting if someone could find it again!
The most efficient answer is to use a left join, as using "NOT IN" can sometimes prevent a query from using an index, if present.
The answer in this case would be something like
SELECT DISTINCT
*
FROM
TableA a
LEFT JOIN
TableB b
ON
a.Id = b.Id
WHERE
b.Id IS NULL
Alternatively, this is more readable than a left join, and more efficient than the NOT IN solutions
SELECT * FROM TableA a where NOT EXISTS (SELECT * FROM TableB where Id = a.Id)
I'd use a NOT EXISTS Like this:
SELECT A.Id
FROM TableA A
WHERE NOT EXISTS (SELECT B.Id FROM TableB B WHERE A.Id = B.Id)
GROUP BY A.Id
SELECT DISTINCT Id FROM A WHERE Id NOT IN (SELECT ID FROM B);
SELECT DISTINCT Id FROM A WHERE Id NOT IN(SELECT DISTINCT Id FROM B);
The subquery will get all the IDs in B. The group by...having will get all the unique IDs in A that are also not in B.
select *
from A
where id not in
(
select distinct id
from B
)
group by ID
having count(*) > 1;