I frequently come across this problem. I have a file:
something
something2
something3
which I want output as:
"something","something2","something3"
any quick tool for this, preferably online?
If its just a one off thing, it'd be pretty easy to just do it with a search & replace in any advanced-ish text editor...
For example in notepad++:
Do a Replace (CTRL+H)
Set "Search Mode" to "Extended"
Find: \r\n
Replace with: ","
(of course you'll need an extra quote at the very start & very end of the file).
If you need to do it more than once, writing a small script/program that did a regular expression replace over the file would be fairly straight forward too.
Edit: If you really wanted to do it online, you could use an online regular expression tester (in this case you want to use \n as the regex and "," as your replace pattern, leaving the other settings alone).
A quick Python hack?
lines = open('input.txt').xreadlines()
txt = ','.join(['"%s"' % x for x in lines])
open('output.txt', 'w').write(txt)
Related
In vue, is there a way to have a value span multiple lines in an .env file. Ex:
Instead of:
someValue=[{"someValue":"Here is a really really long piece which should be split into multiple lines"}]
I want to do something like:
someValue=`[{"someValue":"Here is a really
really long piece which
should be split into multiple lines"}]`
Doing the latter gives me a JSON parsing error if I try to do JSON.parse(someValue) in my code
I don't know if this will work, but I can't format a comment appropriately enough to get the point across so see if this will work:
someValue=[{"someValue":"Here is a really\
really long piece which\
should be split into multiple lines"}]
Where "\" should escape the newline similar to how you can write long bash commands while escaping the newline. I'm not certain the .env interpreter will support it though.
EDIT
Looks like this won't work. This syntax was actually proposed, but I don't think it was incorporated. See motdotla/dotenv#333 (which is what Vue uses to parse .env).
Like #zero298 said, this isn't possible. Likely you could delimit the entry with a character that wouldn't show up normally in the text (^ is a good candidate), then parse it within the application using string.replace('^', '\n');
All.
I am used to programming VBA in Excel, but am new to the structures in Word.
I am working through a library of text files to update them. Many of them are either OCR documents, or were manually entered.
Each has a recurring pattern, the most common of which is unnecessary carriage returns.
For example, I am looking at several text files where there is a double return after each line. A search and replace of all double carriage returns removes all paragraph distinctions.
However, each line is approximately 30 characters long, and if I manually perform the following logic, it gives me a functional document.
If there is a double carriage return after 30+ characters, I replace them with a space.
If there were less than 30 characters prior to the double return, I replace them with a single return.
Can anyone help me with some rudimentary code that would help me get started on that? I could then modify it for each "pattern" of text documents I have.
e.g.
In this case, there are more than
thirty characters per line. And I
will keep going to illustrate this
example.
This would be a new paragraph, and
would be separated by another of
the single returns.
I want code that would return:
In this case, there are more than thirty character returns. And I will keep going to illustrate this example.
This would be a new paragraph, and would be separated by another of the single returns.
Let me know if anyone can throw something out that I can play with!
You can do this without code (which RegEx requires), simply using Word's own wildcard Find/Replace tools, where:
Find = ([!^13]{30,})[^13]{1,}
Replace = \1^32
and, to clean up the residual multi-paragraph breaks:
Find = [^13]{2,}
Replace = ^p
You could, of course, record the above as a macro...
Here is a RegEx that might work for you:
(\n\n)(?<!\.(\n\n))
The substitution is just a plain space, you can try it out (and modify / tweak it) here: https://regex101.com/r/zG9GPw/4
This 'pattern' tells the RegEx engine to look for the newline character \n which occurs x2 like this \n\n (worth noting this is from your question and might be different in your files, e.g. could be \r\n) and it assumes that a valid line break will be proceeded by a full stop: \..
In RegEx the full stop symbol is a single character wild card so it needs to be escaped with the '\' (n and r are normal characters, escaping them tells the RegEx engine they represent newline and return characters).
So... the expression is looking for a group of x2 newline characters but then uses a negative look-behind to exclude any matches where the previous character was a full stop.
Anyway, it's all explained on the site:
Here is how you could do a RegEx find and replace using NotePad++ (I'm not sure if it comes with RegEx or if a plugin is needed, either way it is easy). But you can set a location, filters (to target specific file types), and other options (such as search in sub-directories).
Other than that, as #MacroPod pointed out you could also do this with MS Word, document by document, not using any code :)
I'm trying to write a simple multi-line Alias that says several predefined strings of characters in mIRC. The problem is that the strings can contain:
{
}
|
which are all used in the scripting language to group sections of code/commands. So I was wondering if there was an escape character I could use.
In lack of that, is there a method, or alternative way to be able to "say" multiple lines of these strings, so that this:
alias test1 {
/msg #　samplestring}contains_chars|
/msg # _that|break_continuity}{
}
Outputs this on typing /test1 on a channel:
<MyName> samplestring}contains_chars|
<MyName> _that|break_continuity}{
It doesn't have to use the /msg command specifically, either, as long as the output is the same.
So basically:
Is there an escape character of sorts I can use to differentiate code from a string in mIRC scripting?
Is there a way to tell a script to evaluate all characters in a string as a literal? Think " " quotes in languages like Java.
Is the above even possible using only mIRC scripting?
"In lack of that, is there a method, or alternative way to be able to "say" multiple lines of these strings, so that this:..."
I think you have to have to use msg # every time when you want to message a channel. Alterativelty you can use the /say command to message the active window.
Regarding the other 3 questions:
Yes, for example you can use $chr(123) instead of a {, $chr(125) instead of a } and $chr(124) instead of a | (pipe). For a full list of numbers you can go to http://www.atwebresults.com/ascii-codes.php?type=2. The code for a dot is 46 so $chr(46) will represent a dot.
I don't think there is any 'simple' way to do this. To print identifiers as plain text you have to add a ! after the $. For example '$!time' will return the plain text '$time' as $time will return the actual value of $time.
Yes.
I have a big string, precisely - an XSLT code - that I would like to hardcode in my VB.net program. I tried with putting " before every quotation mark, but it still didn't work out, and it's pretty mocking to place it 100 times. Using Chr(34) is also not the best solution.
Is there some way, like to put # (or another character) before the string itself that will define and work for all the characters in the string that need to be escaped ?
If it is a large string. Why not save it to file and then read the file into memory before you want to use it. That way you don't have to do any escaping and it will be easy to modify if you decide to change it.
I've made some good progress with my first attempt at a program, but have hit another road block. I'm taking standard output (as a string) froma console CMD window (results of dsquery piped to dsget) and have found small rectangles in the output. I tried using Regex to clean the little bastards but it seems they are related to the _ (underscore), which I need to keep (to return 2000/NT logins). Odd thing is - when I copy the caharcter and paste it into VS2K10 Express it acts like a carrige return??
Any ideas on finding out what these little SOB's are -- and how to remove them?
Going to try using /U or /A CMD switch next..
The square is often just used whenever a character is not displayable. The character could very well be a CR. You can use a Regular Expression to just get normal characters or remove the CR LF characters using string.replace.
You mentioned that you are using the string.replace function, and I am wondering if you are replacing the wrong character or something like that. If all your trying to do is remove a carriage return I would skip the regular expressions and stick with the string.replace.
Something like this should work...
strInputString = strInputString.replace(chr(13), "")
If not could you post a line or two of code.
On a side note, this might give some other examples....
Character replacement in strings in VB.NET