JavaFX: File upload to REST service / servlet fails because of missing boundary - file-upload

Question

I'm trying to upload a file using JavaFX using the HttpRequest. For this purpose I have written the following function.
function uploadFile(inputFile : File) : Void {
// check file
if (inputFile == null or not(inputFile.exists()) or inputFile.isDirectory()) {
return;
}
def httpRequest : HttpRequest = HttpRequest {
location: urlConverter.encodeURL("{serverUrl}");
source: new FileInputStream(inputFile)
method: HttpRequest.POST
headers: [
HttpHeader {
name: HttpHeader.CONTENT_TYPE
value: "multipart/form-data"
}
]
}
httpRequest.start();
}
On the server side, I am trying to handle the incoming data using the Apache Commons FileUpload API using a Jersey REST service. The code used to do this is a simple copy of the FileUpload tutorial on the Apache homepage.
#Path("Upload")
public class UploadService {
public static final String RC_OK = "OK";
public static final String RC_ERROR = "ERROR";
#POST
#Produces("text/plain")
public String handleFileUpload(#Context HttpServletRequest request) {
if (!ServletFileUpload.isMultipartContent(request)) {
return RC_ERROR;
}
FileItemFactory factory = new DiskFileItemFactory();
ServletFileUpload upload = new ServletFileUpload(factory);
List<FileItem> items = null;
try {
items = upload.parseRequest(request);
}
catch (FileUploadException e) {
e.printStackTrace();
return RC_ERROR;
}
...
}
}
However, I get a exception at items = upload.parseRequest(request);:
org.apache.commons.fileupload.FileUploadException: the request was rejected because no multipart boundary was found
I guess I have to add a manual boundary info to the InputStream. Is there any easy solution to do this? Or are there even other solutions?

Answer 1

Have you tried just using the InputStream from HttpServletRequest like so
InputStream is = httpRequest.getInputStream();
BufferedInputStream in = new BufferedInputStream(is);
//Write out bytes
out.close();
is.close();