How do you rename a S3 key in a bucket with boto?
You can't rename files in Amazon S3. You can copy them with a new name, then delete the original, but there's no proper rename function.
Here is an example of a Python function that will copy an S3 object using Boto 2:
import boto
def copy_object(src_bucket_name,
src_key_name,
dst_bucket_name,
dst_key_name,
metadata=None,
preserve_acl=True):
"""
Copy an existing object to another location.
src_bucket_name Bucket containing the existing object.
src_key_name Name of the existing object.
dst_bucket_name Bucket to which the object is being copied.
dst_key_name The name of the new object.
metadata A dict containing new metadata that you want
to associate with this object. If this is None
the metadata of the original object will be
copied to the new object.
preserve_acl If True, the ACL from the original object
will be copied to the new object. If False
the new object will have the default ACL.
"""
s3 = boto.connect_s3()
bucket = s3.lookup(src_bucket_name)
# Lookup the existing object in S3
key = bucket.lookup(src_key_name)
# Copy the key back on to itself, with new metadata
return key.copy(dst_bucket_name, dst_key_name,
metadata=metadata, preserve_acl=preserve_acl)
There is no direct method to rename the file in s3. what do you have to do is copy the existing file with new name (Just set the target key) and delete the old one. Thank you
//Copy the object
AmazonS3Client s3 = new AmazonS3Client("AWSAccesKey", "AWSSecretKey");
CopyObjectRequest copyRequest = new CopyObjectRequest()
.WithSourceBucket("SourceBucket")
.WithSourceKey("SourceKey")
.WithDestinationBucket("DestinationBucket")
.WithDestinationKey("DestinationKey")
.WithCannedACL(S3CannedACL.PublicRead);
s3.CopyObject(copyRequest);
//Delete the original
DeleteObjectRequest deleteRequest = new DeleteObjectRequest()
.WithBucketName("SourceBucket")
.WithKey("SourceKey");
s3.DeleteObject(deleteRequest);
Related
I am building a Python Lambda in AWS and wanted to add an S3 trigger to it. Following these instructions I saw how to get the bucket and key on which I got the trigger using:
def func(event):
bucket = event['Records'][0]['s3']['bucket']['name']
key = urllib.parse.unquote_plus(event['Records'][0]['s3']['object']['key'], encoding='utf-8')
There is an example of such an object in the link, but I wasn't able, however, to find a description of the entire event object anywhere in AWS' documentation.
Is there a documentation for this object's structure? Where might I find it?
You can find documentation about the whole object in the S3 documentation:
https://docs.aws.amazon.com/AmazonS3/latest/userguide/notification-content-structure.html
I would also advise to iterate the records, because there could be multiple at once:
for record in event['Records']:
bucket = record['s3']['bucket']['name']
key = record['s3']['object']['key']
[...]
I am trying to update the existing metadata of my S3 object but in spite of updating it is creating the new one. As per the documentation, it is showing the same way but don't know why it is not able to update it.
k = s3.head_object(Bucket='test-bucket', Key='test.json')
s3.copy_object(Bucket='test-bucket', Key='test.json', CopySource='test-bucket' + '/' + 'test.json', Metadata={'Content-Type': 'text/plain'}, MetadataDirective='REPLACE')
I was able to update using the copy_from method
s3 = boto3.resource('s3')
object = s3.Object(bucketName, uploadedKey)
object.copy_from(
CopySource={'Bucket': bucketName,'Key': uploadedKey},
MetadataDirective="REPLACE",
ContentType=value
)
S3 metadata is read-only, so updating only metadata of an S3 object is not possible. The only way to update the metadata is to recreate/copy the object. Check the 1st paragraph of the official docs
You can set object metadata at the time you upload it. After you upload the object, you cannot modify object metadata. The only way to modify object metadata is to make a copy of the object and set the metadata.
I have about 1000 objects in S3 which named after
abcyearmonthday1
abcyearmonthday2
abcyearmonthday3
...
want to rename them to
abc/year/month/day/1
abc/year/month/day/2
abc/year/month/day/3
how could I do it through boto3. Is there easier way of doing this ?
As explained in Boto3/S3: Renaming an object using copy_object
you can not rename an object in S3 you have to copy object with a new name and then delete the Old object
s3 = boto3.resource('s3')
s3.Object('my_bucket','my_file_new').copy_from(CopySource='my_bucket/my_file_old')
s3.Object('my_bucket','my_file_old').delete()
There is not direct way to rename S3 object.
Below two steps need to perform :
Copy the S3 object at same location with new name.
Then delete the older object.
I had the same problem (in my case I wanted to rename files generated in S3 using the Redshift UNLOAD command). I solved creating a boto3 session and then copy-deleting file by file.
Like
import boto3
session = boto3.session.Session(aws_access_key_id=my_access_key_id,aws_secret_access_key=my_secret_access_key).resource('s3')
# Save in a list the tuples of filenames (with prefix): [(old_s3_file_path, new_s3_file_path), ..., ()] e.g. of tuple ('prefix/old_filename.csv000', 'prefix/new_filename.csv')
s3_files_to_rename = []
s3_files_to_rename.append((old_file, new_file))
for pair in s3_files_to_rename:
old_file = pair[0]
new_file = pair[1]
s3_session.Object(s3_bucket_name, new_file).copy_from(CopySource=s3_bucket_name+'/'+old_file)
s3_session.Object(s3_bucket_name, old_file).delete()
I want to add Folder in my amazon s3 bucket using coding.
Can you please suggest me how to achieve this?
There are no folders in Amazon S3. It just that most of the S3 browser tools available show part of the key name separated by slash as a folder.
If you really need that you can create an empty object with the slash at the end. e.g. "folder/" It will looks like a folder if you open it with a GUI tool and AWS Console.
As everyone has told you, in AWS S3 there aren't any "folders", you're thinking of them incorrectly. AWS S3 has "objects", these objects can look like folders but they aren't really folders in the fullest sense of the word. If you look for creating folders on the Amazon AWS S3 you won't find a lot of good results.
There is a way to create "folders" in the sense that you can create a simulated folder structure on the S3, but again, wrap your head around the fact that you are creating objects in S3, not folders. Going along with that, you will need the command "put-object" to create this simulated folder structure. Now, in order to use this command, you need the AWS CLI tools installed, go here AWS CLI Installation for instructions to get them installed.
The command is this:
aws s3api put-object --bucket your-bucket-name --key path/to/file/yourfile.txt --body yourfile.txt
Now, the fun part about this command is, you do not need to have all of the "folders" (objects) created before you run this command. What this means is you can have a "folder" (object) to contain things, but then you can use this command to create the simulated folder structure within that "folder" (object) as I discussed earlier. For example, I have a "folder" (object) named "importer" within my S3 bucket, lets say I want to insert sample.txt within a "folder" (object) structure of the year, month, and then a sample "folder" (object) within all of that.
If I only have the "importer" object within my bucket, I do not need to go in beforehand to create the year, month, and sample objects ("folders") before running this command. I can run this command like so:
aws s3api put-object --bucket my-bucket-here --key importer/2016/01/sample/sample.txt --body sample.txt
The put-object command will then go in and create the path that I have specified in the --key flag. Here's a bit of a jewel: even if you don't have a file to upload to the S3, you can still create objects ("folders") within the S3 bucket, for example, I created a shell script to "create folders" within the bucket, by leaving off the --body flag, and not specifying a file name, and leaving a slash at the end of the path provided in the --key flag, the system creates the desired simulated folder structure within the S3 bucket without inserting a file in the process.
Hopefully this helps you understand the system a little better.
Note: once you have a "folder" structure created, you can use the S3's "sync" command to syncronize the descendant "folder" with a folder on your local machine, or even with another S3 bucket.
Java with AWS SDK:
There are no folders in s3, only key/value pairs. The key can contain slashes (/) and that will make it appear as a folder in management console, but programmatically it's not a folder it is a String value.
If you are trying to structure your s3 bucket, then your naming conventions (the keys you give your files) can simply follow normal directory patterns, i.e. folder/subfolder/file.txt.
When searching (depending on language you are using), you can search via prefix with a delimiter. In Java, it would be a listObjects(String storageBucket, String prefix, String delimiter) method call.
The storageBucket is the name of your bucket, the prefix is the key you want to search, and the delimiter is used to filter your search based off the prefix.
The AWS:S3 rails gem does this by itself:
AWS::S3::S3Object.store("teaser/images/troll.png", file, AWS_BUCKET)
Will automatically create the teaser and images "folders" if they don't already exist.
With AWS SDK .Net works perfectly, just add "/" at the end of the name folder:
var folderKey = folderName + "/"; //end the folder name with "/"
AmazonS3 client = Amazon.AWSClientFactory.CreateAmazonS3Client(AWSAccessKey, AWSSecretKey);
var request = new PutObjectRequest();
request.WithBucketName(AWSBucket);
request.WithKey(folderKey);
request.WithContentBody(string.Empty);
S3Response response = client.PutObject(request);
Then refresh your AWS console, and you will see the folder
With aws cli, it is possible to copy an entire folder to a bucket.
aws s3 cp /path/to/folder s3://bucket/path/to/folder --recursive
There is also the option to sync a folder using aws s3 sync
This is a divisive topic, so here is a screenshot in 2019 of the AWS S3 console for adding folders and the note:
When you create a folder, S3 console creates an object with the above
name appended by suffix "/" and that object is displayed as a folder
in the S3 console.
Then 'using coding' you can simply adjust the object name by prepending a valid folder name string and a forward slash.
For Swift I created a method where you pass in a String for the folder name.
Swift 3:
import AWSS3
func createFolderWith(Name: String!) {
let folderRequest: AWSS3PutObjectRequest = AWSS3PutObjectRequest()
folderRequest.key = Name + "/"
folderRequest.bucket = bucket
AWSS3.default().putObject(folderRequest).continue({ (task) -> Any? in
if task.error != nil {
assertionFailure("* * * error: \(task.error?.localizedDescription)")
} else {
print("created \(Name) folder")
}
return nil
})
}
Then just call
createFolderWith(Name:"newFolder")
In iOS (Objective-C), I did following way
You can add below code to create a folder inside amazon s3 bucket programmatically. This is working code snippet. Any suggestion Welcome.
-(void)createFolder{
AWSS3PutObjectRequest *awsS3PutObjectRequest = [AWSS3PutObjectRequest new];
awsS3PutObjectRequest.key = [NSString stringWithFormat:#"%#/", #"FolderName"];
awsS3PutObjectRequest.bucket = #"Bucket_Name";
AWSS3 *awsS3 = [AWSS3 defaultS3];
[awsS3 putObject:awsS3PutObjectRequest completionHandler:^(AWSS3PutObjectOutput * _Nullable response, NSError * _Nullable error) {
if (error) {
NSLog(#"error Creating folder");
}else{
NSLog(#"Folder Creating Sucessful");
}
}];
}
Here's how you can achieve what you're looking for (from code/cli):
--create/select the file (locally) which you want to move to the folder:
~/Desktop> touch file_to_move
--move the file to s3 folder by executing:
~/Desktop> aws s3 cp file_to_move s3://<path_to_your_bucket>/<new_folder_name>/
A new folder will be created on your s3 bucket and you'll now be able to execute cp, mv, rm ... statements i.e. manage the folder as usual.
If this new file created above is not required, simply delete it. You now have an s3 bucket created.
You can select language of your choice from available AWS SDK
Alternatively you can try minio client libraries available in Python, Go, .Net, Java, Javascript for your application development environment, it has example directory with all basic operations listed.
Disclaimer: I work for Minio
In swift 2.2 you can create folder using
func createFolderWith(Name: String!) {
let folderRequest: AWSS3PutObjectRequest = AWSS3PutObjectRequest()
folderRequest.key = Name + "/"
folderRequest.bucket = "Your Bucket Name"
AWSS3.defaultS3().putObject(folderRequest).continueWithBlock({ (task) -> AnyObject? in
if task.error != nil {
assertionFailure("* * * error: \(task.error?.localizedDescription)")
} else {
print("created \(Name) folder")
}
return nil
})
}
Below creates a empty directory called "mydir1".
Below is nodejs code, it should be similar for other languages.
The trick is to have slash (/) at the end of the name of object, as in "mydir1/", otherwise a file with name "mydir1" will be created.
let AWS = require('aws-sdk');
AWS.config.loadFromPath(__dirname + '\\my-aws-config.json');
let s3 = new AWS.S3();
var params = {
Bucket: "mybucket1",
Key: "mydir1/",
ServerSideEncryption: "AES256" };
s3.putObject(params, function (err, data) {
if (err) {
console.log(err, err.stack); // an error occurred
return;
} else {
console.log(data); // successful response
return;
/*
data = {
ETag: "\"6805f2cfc46c0f04559748bb039d69ae\"",
ServerSideEncryption: "AES256",
VersionId: "Ri.vC6qVlA4dEnjgRV4ZHsHoFIjqEMNt"
}
*/
} });
Source: http://docs.aws.amazon.com/AWSJavaScriptSDK/latest/AWS/S3.html#putObject-property
in-order to create a directory inside s3 bucket and copy contents inside that is pretty simple.
S3 command can be used:
aws s3 cp abc/def.txt s3://mybucket/abc/
Note: / is must that makes the directory, otherwise it will become a file in s3.
I guess your query is just simply creating a folder inside folder(subfolder).
so while coping any directory data inside a bucket sub folder use command like this.
aws s3 cp mudit s3://mudit-bucket/Projects-folder/mudit-subfolder --recursive
It will create a subfolder and put ur directory contents in it. Also once your subfolder data gets empty. Your Subfolder will automatically gets deleted.
You can use copy command to create a folder while copy a file.
aws s3 cp test.xml s3://mybucket/myfolder/test.xml
How can I create a folder under a bucket using boto library for Amazon s3?
I followed the manual, and created the keys with permission, metadata etc, but no where in the boto's documentation it describes how to create folders under a bucket, or create a folder under folders in bucket.
There is no concept of folders or directories in S3. You can create file names like "abc/xys/uvw/123.jpg", which many S3 access tools like S3Fox show like a directory structure, but it's actually just a single file in a bucket.
Assume you wanna create folder abc/123/ in your bucket, it's a piece of cake with Boto
k = bucket.new_key('abc/123/')
k.set_contents_from_string('')
Or use the console
Use this:
import boto3
s3 = boto3.client('s3')
bucket_name = "YOUR-BUCKET-NAME"
directory_name = "DIRECTORY/THAT/YOU/WANT/TO/CREATE" #it's name of your folders
s3.put_object(Bucket=bucket_name, Key=(directory_name+'/'))
With AWS SDK .Net works perfectly, just add "/" at the end of the folder name string:
var folderKey = folderName + "/"; //end the folder name with "/"
AmazonS3 client = Amazon.AWSClientFactory.CreateAmazonS3Client(AWSAccessKey, AWSSecretKey);
var request = new PutObjectRequest();
request.WithBucketName(AWSBucket);
request.WithKey(folderKey);
request.WithContentBody(string.Empty);
S3Response response = client.PutObject(request);
Then refresh your AWS console, and you will see the folder
Tried many method above and adding forward slash / to the end of key name, to create directory didn't work for me:
client.put_object(Bucket="foo-bucket", Key="test-folder/")
You have to supply Body parameter in order to create directory:
client.put_object(Bucket='foo-bucket',Body='', Key='test-folder/')
Source: ryantuck in boto3 issue
Append "_$folder$" to your folder name and call put.
String extension = "_$folder$";
s3.putObject("MyBucket", "MyFolder"+ extension, new ByteArrayInputStream(new byte[0]), null);
see:
http://www.snowgiraffe.com/tech/147/creating-folders-programmatically-with-amazon-s3s-api-putting-babies-in-buckets/
Update for 2019, if you want to create a folder with path bucket_name/folder1/folder2 you can use this code:
from boto3 import client, resource
class S3Helper:
def __init__(self):
self.client = client("s3")
self.s3 = resource('s3')
def create_folder(self, path):
path_arr = path.rstrip("/").split("/")
if len(path_arr) == 1:
return self.client.create_bucket(Bucket=path_arr[0])
parent = path_arr[0]
bucket = self.s3.Bucket(parent)
status = bucket.put_object(Key="/".join(path_arr[1:]) + "/")
return status
s3 = S3Helper()
s3.create_folder("bucket_name/folder1/folder2)
It's really easy to create folders. Actually it's just creating keys.
You can see my below code i was creating a folder with utc_time as name.
Do remember ends the key with '/' like below, this indicates it's a key:
Key='folder1/' + utc_time + '/'
client = boto3.client('s3')
utc_timestamp = time.time()
def lambda_handler(event, context):
UTC_FORMAT = '%Y%m%d'
utc_time = datetime.datetime.utcfromtimestamp(utc_timestamp)
utc_time = utc_time.strftime(UTC_FORMAT)
print 'start to create folder for => ' + utc_time
putResponse = client.put_object(Bucket='mybucketName',
Key='folder1/' + utc_time + '/')
print putResponse
Although you can create a folder by appending "/" to your folder_name. Under the hood, S3 maintains flat structure unlike your regular NFS.
var params = {
Bucket : bucketName,
Key : folderName + "/"
};
s3.putObject(params, function (err, data) {});
S3 doesn't have a folder structure, But there is something called as keys.
We can create /2013/11/xyz.xls and will be shown as folder's in the console. But the storage part of S3 will take that as the file name.
Even when retrieving we observe that we can see files in particular folder (or keys) by using the ListObjects method and using the Prefix parameter.
Apparently you can now create folders in S3. I'm not sure since when, but I have a bucket in "Standard" zone and can choose Create Folder from Action dropdown.
This question is more relevant to the future, so adding this update.
I am using the upload_file method as shown below.
fold ='/my/system/filePath/tabmcq/Tables/auto/18.tsv'
s3_client.upload_file(
Filename = full/file/path/filename.extension,
Bucket = "tab-mcq-de",
Key = f"{fold.split('/')[-3]}/{fold.split('/')[-2]}/{fold.split('/')[-1]}"
)
Ideas is the "Filename" parameter requires the absolute file path of your system.
The "Key" parameter requires the relative file path from the source directory where your files are located
In case of this example, Key parameter has to contain "Tables/auto/18.tsv" value, for client to create the folders.
Hope this helps.
The following works using Python boto3
s3 = boto3.client("s3")
s3.put_object(Bucket="dest_bucket", Key='folder_name/')