I have an sqlite table with Date of Birth. I would like to execute a query to select those records where the age is more than 30.
I have tried the following but it doesn't work:
select * from mytable where dob > '1/Jan/1980'
select * from mytable where dob > '1980-01-01'
Some thing like this could be used:
select dateofbirth from customer Where DateofBirth BETWEEN date('1004-01-01') AND date('1980-12-31');
select dateofbirth from customer where date(dateofbirth)>date('1980-12-01');
select * from customer where date(dateofbirth) < date('now','-30 years');
If you are using Sqlite V3.7.12 or greater
Dont use date(dateofbirth) just use dateofbirth. So your query would look like this:
select * from customer where dateofbirth < date('now','-30 years');
Using the magic docs at the sqlite website:
select * from mytable where dob < date('now','-30 years');
Try writing using the date format 'YYYY-MM-DD'
select * from mytable where dob > '1980-01-01'
A more programic way would be something like this:
select * from mytable where datediff(dob, now()) > 30
You'll Need to find specific syntax for sqlite.
select * from mytable where date(dob) > date('1980-01-10')
QLite3 has some cool new date functions. Per the docs site you can use date(), time(), datetime(), julianday(), unixepoch(), or strftime() depending on how your column data is formatted.
If you use strftime(), like my suggestion below, then you have to make sure that your column data is formatted the same way as your strftime string.
You would probably want something like:
SELECT * FROM mytable WHERE dob < strftime("%m/%d/%Y", 'now', '-30 year');
Note that you might have to change the format string here to match your own.
And here's some code that I use personally to give you a better idea of how powerful it is. It lets me get all the orders from the previous 3 months, not including this month.
SELECT * FROM orders WHERE SHIPPEDDATE > strftime('%m/%d/%Y', 'now', 'start of month', '-3 month');
The modifiers are very powerful with sqlite. The first string inside strftime() is the format, the 2nd string is when you want the date to start. 'Start of month' puts the day to 1, and '-3 month' goes back 3 months. So if I ran that today (08/03/2022), the date it uses would be 05/01/2022.
Related
So, i´m trying to select rows between two dates.
In db, the dates also have time.
Therefor i need to use LIKE.
SQL
$query = "SELECT * FROM table WHERE date >= LIKE :selectedDateFrom AND <= LIKE :selectedDateTo";
$query_params = array(':selectedDateFrom' => $selectedDateFrom.="%", ':selectedDateTo' => $selectedDateTo.="%");
This one returns error!
How should it look like?
In db, the dates also have time.
Therefor i need to use LIKE.
No, you don't.
To select all date/times where the date component is between (from) and (to), inclusive, you can write it as
SELECT *
FROM table
WHERE date >= :selectedDateFrom
AND date < :selectedDateToPlusOne
(Note the < instead of <=, and set the second parameter to one day after the last day you want to include in your results.) This works even when the column includes times.
you can't use like with dates in SQL
SO use this:
$query = "SELECT * FROM table WHERE date >= :selectedDateFrom AND date <= :selectedDateTo";
You'd strip the time part from a datetime with DATE().
SELECT *
FROM mytable
WHERE date(mydate) >= :selectedDateFrom
AND date(mydate) <= :selectedDateTo;
Or with BETWEEN for better readability:
SELECT *
FROM mytable
WHERE date(mydate) BETWEEN :selectedDateFrom AND :selectedDateTo;
My table myTab has the column startDate, which has the datatype "DATE". The data in this column are stored like dd.mm.yyyy.
Now I'm trying to get data with this query:
SELECT * FROM myTab WHERE startDate like '%01.2015"
Somehow it doesn't work and I don't know why.
Hope someone can help.
To make a text search on the date you would have to convert the date to text.
It's more efficient if you calculate the first and last date for what you want to find and get everything between them. That way it's done as numeric comparisons instead of a text pattern match, and it can make use of an index if there is one:
SELECT * FROM myTab WHERE startDate >= DATE '2015-01-01' AND startDate < DATE '2015-02-01'
SELECT * FROM myTab WHERE TO_CHAR(startDate,'dd.mm.yyyy') LIKE '%01.2015'
If the field type is "DATE" then the value isn't stored as a string, it's a number managed by Oracle, so you have to convert it to a string:
SELECT * FROM myTab WHERE to_char(startDate, 'MM.YYYY') = '01.2015';
You can also use date ranges in SQL queries:
SELECT * FROM myTab
WHERE startDate
BETWEEN to_date('01.01.2015', 'DD.MM.YYYY')
AND to_date('31.01.2015', 'DD.MM.YYYY');
Regarding you actual question "Somehow it doesn't work and I don't know why."
Oracle make an implicit conversion from DATE to VARHCAR2, however it uses the default NLS_DATE_FORMAT which is probably different to what you use in your query.
The data in this column are stored like dd.mm.yyyy.
Oracle does not store date in the format you see. It stores it internally in proprietary format in 7 bytes with each byte storing different components of the datetime value.
WHERE startDate like '%01.2015"
You are comparing a DATE with a STRING, which is pointless.
From performance point of view, you should use a date range condition so that if there is any regular INDEX on the date column, it would be used.
SELECT * FROM table_name WHERE date_column BETWEEN DATE '2015-01-01' AND DATE '2015-02-01'
To understand why a Date range condition is better in terms of performance, have a look at my answer here.
I solved my problem that way. Thank you for suggestions for improvements. Example in C#.
string dd, mm, aa, trc, data;
dd = nData.Text.Substring(0, 2);
mm = nData.Text.Substring(3, 2);
aa = nData.Text.Substring(6, 4);
trc = "-";
data = aa + trc + mm + trc + dd;
"Select * From bdPedidos Where Data Like '%" + data + "%'";
To provide a more detailed answer and address this https://stackoverflow.com/a/42429550/1267661 answer's issue.
In Oracle a column of type "date" is not a number nor a string, it's a "datetime" value with year, month, day, hour, minute and seconds.
The default time is always midnight "00:00:00"
The query:
Select * From bdPedidos Where Data Like '%" + data + "%'"
won't work in all circumstances because a date column is not a string, using "like" forces Oracle to do a conversion from date value to string value.
The string value may be year-month-day-time or month-day-year-time or day-month-year-time, that all depends how a particular Oracle instance has set the parameter NLS_DATE_FORMAT to show dates as strings.
The right way to cover all the possible times in a day is:
Select *
From bdPedidos
Where Data between to_date('" + data + " 00:00:00','yyyy-mm-dd hh24:mi:ss')
and to_date('" + data + " 23:59:59','yyyy-mm-dd hh24:mi:ss')
SELECT * FROM myTab WHERE startDate like '%-%-2015';
This will search for all dates in 2015. If this doesn't work, try:
SELECT * FROM myTab WHERE startDate like '%-%-15';
I am looking for a way to select a whole days worth of data from a where statement. Timestamp is in unix time such as (1406045122). I want to select the today's date of unix time range and find all the food that has been added in today. Thank in advance. This is the code I wrote. I'm not sure what I should put in the ( ????? ) part. I know it has to do with 60*60*24=86400 secs per day but I'm not too sure how I can implement this.
Select timestamp,food from table1 where timestamp = ( ????? );
Select timestamp,food
FROM table1
WHERE timestamp > :ts
AND timestamp <= (:ts + 86400);
replace :ts with the starting timstamp and you'll filter a whole day's worth of data
edit
This select query would give you the current timestamp (there may be more efficient ones, i don't work with sqlite often)
select strftime("%s", current_timestamp);
You can find more info about them here: http://www.tutorialspoint.com/sqlite/sqlite_date_time.htm
Using the strftime() function, combined with the date() function we can write this following query which will not need any manual editing. It will return the records filtered on timestamp > start of today & timestamp <= end of today.
Select timestamp,food
FROM table1
WHERE timestamp > strftime("%s", date(current_timestamp))
AND timestamp <= (strftime("%s", date(current_timestamp)) + 86400);
Your mileage will likely depend on your version of SQL but for example on MySQL you can specify a search as being BETWEEN two dates, which is taken conventionally to mean midnight on each. So
SELECT * FROM FOO WHERE T BETWEEN '2014-07-01' AND '2014-07-02';
selects anything with a timestamp anywhere on 1st July 2014. If you want to make it readable you could even use the ADDDATE function. So you could do something like
SET #mydate = DATE(T);
SELECT * FROM FOO WHERE T BETWEEN #mydate AND ADDDATE(#mydate, 1);
The first line should truncate your timestamp to be 00:00:00. The second line should SELECT only records from that date.
Suppose I have a date 2010-07-29. Now I would like to check the result of one day ahead. how to do that
For example,
SELECT *
from table
where date = date("2010-07-29")
How to do one day before without changing the string "2010-07-29"?
I searched and get some suggestion from web and I tried
SELECT *
from table
where date = (date("2010-07-29") - 1 Day)
but failed.
MySQL
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATE_SUB('2010-07-29', INTERVAL 1 DAY)
AND '2010-07-29'
Change DATE_SUB to DATE_ADD if you want to add a day (and reverse the BETWEEN parameters).
SQL Server
SELECT *
FROM TABLE t
WHERE t.date BETWEEN DATEADD(dd, -1, '2010-07-29')
AND '2010-07-29'
Oracle
SELECT *
FROM TABLE t
WHERE t.date BETWEEN TO_DATE('2010-07-29', 'YYYY-MM-DD') - 1
AND TO_DATE('2010-07-29', 'YYYY-MM-DD')
I used BETWEEN because the date column is likely DATETIME (on MySQL & SQL Server, vs DATE on Oracle), which includes the time portion so equals means the value has to equal exactly. These queries give you the span of a day.
If you're using Oracle, you can use the + and - operators to add a number of days to a date.
http://psoug.org/reference/date_func.html
Example:
SELECT SYSDATE + 1 FROM dual;
Will yield tomorrow's date.
If you're not using Oracle, please tell use what you ARE using so we can give better answers. This sort of thing depends on the database you are using. It will NOT be the same across different databases.
Depends of the DateTime Functions available on the RDBMS
For Mysql you can try:
mysql> SELECT DATE_ADD('1997-12-31',
-> INTERVAL 1 DAY);
mysql> SELECT DATE_SUB('1998-01-02', INTERVAL 31 DAY);
-> '1997-12-02'
If youre using MSSQL, you're looking for DateAdd() I'm a little fuzzy on the syntax, but its something like:
Select * //not really, call out your columns
From [table]
Where date = DateAdd(dd, -1, "2010-07-29",)
Edit: This syntax should be correct: it has been updated in response to a comment.
I may have the specific parameters in the wrong order, but that should get you there.
In PL SQL : select sysdate+1 from dual;
I need some help figuring out and SQL Statement.
I know what I want I just cant express it.
Im using php, so it doesnt need to be exclusivly SQL, its to act as a filter.
Pseudo code
$query="SELECT * FROM MyTable WHERE 'TIS' is not older than 2 days or empty = ''$ORDER"; }
TIS in the name of the column in my table were I store dates in this format 03-12-09 (d,m,y).
The $ORDER is for ordering the values based on values from other fields not dates.
Im looking at
SELECT *
FROM orders
WHERE day_of_order >
(SELECT DATEADD(day,-30, (SELECT MAX(day_of_order) FROM orders)) AS "-30 Days");
But i dont quite think im on the rigth track with this.
Thanks
Try the following:
SELECT *
FROM MyTable
WHERE COALESCE(TIS, SYSDATE) > SYSDATE - INTERVAL '2' DAY
$ORDER
I don't know what database you're using - the above uses Oracle's method of dealing with time intervals. If you're using SQL Server the following should be close:
SELECT *
FROM MyTable
WHERE COALESCE(TIS, GETDATE()) > DATEADD(Day, -2, GETDATE())
$ORDER
In MySQL try this:
SELECT *
FROM MyTable
WHERE COALESCE(TIS, NOW()) > DATE_SUB(NOW(), INTERVAL 2 DAYS)
$ORDER
I hope this helps.
So, I was pretty lost in all this.
How did it got solved:
First I understood that the Statement I was using was not supported by MySql thanks to eligthment from Bob Jarvis.
_ Second In a comment by vincebowdren wich "strongly" adviced me to change the data type on that field to Date wich indeed I had not, it was a string.
It was pretty Dumb for me to try using SQL operations for Dates on a field that had String values.
So I just RTFM: http://dev.mysql.com/doc/refman/5.1/en/date-and-time-functions.html
and:
mysql> SELECT something FROM tbl_name
-> WHERE DATE_SUB(CURDATE(),INTERVAL 30 DAY) <= date_col;
Then proceeded to change the field value to date.
and this is my perfectly working query:
$query="SELECT * FROM MyTable WHERE DATE_SUB(CURDATE(),INTERVAL 2 DAY) <= TIS OR TIS = 0000-00-00 $ORDER "; }
I would like to thank the posters for their aid.