Pointer to "value struct x" - c++-cli

How do I dynamically allocate a value struct and get a pointer to it?
If I have:
value struct x
{
String ^myString;
};
I can do this:
x vsInstance;
x *pvs = &vsInstance; // "Unmanaged pointer" to managed object
And I can do this:
x ^vsInstance = gcnew x;
But I can't do this:
x *pvs = new vsInstance
I need a * pointer rather than a ^ because I am trying to hold this value struct inside an unmanaged class, and I need to dynamically allocate this object every time a class is created.

I found that what I was trying to do was unnecessary, I used gcroot which solved my design problem. However, I found that I can get a native pointer from pin_ptr but that it would not work in this circumstance

Related

Kotlin Native Initialize Array of Struct

In Kotlin/Native, what is the correct way to create and initialize an array of a structure? My code interfaces with a C library that defines the relevant structures as:
typedef struct VkDeviceQueueCreateInfo {
...
} VkDeviceQueueCreateInfo;
typedef struct VkDeviceCreateInfo {
...
uint32_t queueCreateInfoCount;
const VkDeviceQueueCreateInfo* pQueueCreateInfos;
...
} VkDeviceCreateInfo;
I've created wrapper classes DeviceQueueCreateInfo and DeviceCreateInfo. The Kotlin bindings are generated as classes inheriting from CStructVar and used like this:
class DeviceQueueCreateInfo(...) {
// Allocates in `scope` and fills a `VkDeviceQueueCreateInfo`
fun toRaw(scope: MemScope): VkDeviceQueueCreateInfo = ...
}
class DeviceCreateInfo(val queueCreateInfos: List<DeviceQueueCreateInfo>) {
// Allocates in `scope` and fills a `VkDeviceCreateInfo`
fun toRaw(scope: MemScope) = with(scope) {
alloc<VkDeviceCreateInfo>().also {
it.queueCreateInfoCount = queueCreateInfos.size.toUInt()
it.pQueueCreateInfos = ??? // Allocate array of struct in `scope`
}
}
}
I've added a ??? to the code to show where I'm having trouble. Kotlin NativePlacement has allocArray<T>(length: Int), so that was obviously my first stop:
it.pQueueCreateInfos = allocArray(queueCreateInfos.size)
And then to initialize them I tried:
it.pQueueCreateInfos = allocArray<VkDeviceQueueCreateInfo>(queueCreateInfos.size)
.also { arr ->
queueCreateInfos.forEachIndexed { index, x -> arr[index] = x.toRaw(scope) }
}
However, this fails to compile with error No set method providing array access at arr[index] = x. I wrote the following code which compiles and runs as expected:
val floats = listOf(1f, 2f, 3f)
allocArray<FloatVar>(floats.size).also { arr ->
floats.forEachIndexed { index, x -> arr[index] = x }
}
The code is identical apart from the type used, leading me to believe that I was perhaps trying to assign to an rvalue. I went looking for VkDeviceQueueCreateInfoVar only to find this:
Also, any C type has the Kotlin type representing the lvalue of this type, i.e., the value located in memory rather than a simple immutable self-contained value. Think C++ references, as a similar concept. For structs (and typedefs to structs) this representation is the main one and has the same name as the struct itself, for Kotlin enums it is named ${type}Var, for CPointer it is CPointerVar, and for most other types it is ${type}Var.
This states that for structs, the lvalue representation has the same name as the struct (no Var suffix)... so VkDeviceQueueCreateInfo should represent an assignable lvalue, and I'm confused as to why I am unable to assign values to my array. It occurs to me that Kotlin's assignment does something very different to a C assignment, but I had assumed there would be an idiomatic way to perform a structure assignment.
I've looked through the other overloads and methods in NativePlacement to find one that allows me to initialize the values in the newly created array, and I found allocArray<T>(length: Long, initializer: T.(index: Long)->Unit), but this seems to suffer from the same problem.
How do I allocate and initialize an array of structures through cinterop?

What does variable-initialization line do in VB.Net?

Can someone please tell what the following line of VB.Net is initializing:
Dim x As SomeType() = New SomeType(0) {}
What holds x variable? Is it an array? How can it be translated to C# for example?
I guess SomeType is probably an anonymous type, but still have no clue...
The line:
Dim x As SomeType() = New SomeType(0) {}
declares an array of SomeType objects, which can hold one instance of SomeType.
When declaring an array of objects the value that is passed into the constructor is the max index of the array. So this declaration is basically declaring an array with a length of 1. The {} portion of the line is where you could define the values that should be stored in the array. If you were to change SomeType to integer you could instantiate and fill your array like:
Dim intArray as Integer() = New Integer(0) {7}
and that would give the first instance stored in the intArray variable a value of 7.
SomeType is not an anonymous type. SomeType would be a class that would have to be defined somewhere in your app.
In C# I think the sytax would look like:
SomeType[] x = new SomeType[0];
I'm not exactly sure how you would accomplish the {} portion of the VB.NET line in C#.
It's simply declaring and initializing an array of a given type. In C# I think it would be, quite similarly:
SomeType[] x = new SomeType[0] { };
Is it an array?
Yes. VB uses () for arrays instead of C#'s [].
I guess SomeType is probably an anonymous type
No, it's a defined static type like any other.

What kind of pointer returned if I use "&" to get address of a value type in C++\CLI?

Suppose I write the following code:
public ref class Data
{
public:
Data()
{
}
Int32 Age;
Int32 year;
};
public void Test()
{
int age = 30;
Int32 year = 2010;
int* pAge = &age;
int* pYear = &year;
Data^ data = gcnew Data();
int* pDataYear = &data->Year; // pData is interior pointer and the compiler will throw error
}
If you compile the program, the compiler will throw error:
error C2440: 'initializing' : cannot convert from 'cli::interior_ptr' to 'int *'
So I learned the "&data->Year" is a type of interior pointer.
UPDATES: I tried to use "&(data->Year)", same error.
But how about pAge and pYear?
Are they native pointers, interior pointers or pinned pointers??
If I want to use them in the following native function:
void ChangeNumber(int* pNum);
Will it be safe to pass either pAge or pYear?
They (pAge and pYear) are native pointers, and passing them to a native function is safe. Stack variables (locals with automatic storage lifetime) are not subject to being rearranged by the garbage collector, so pinning is not necessary.
Copying managed data to the stack, then passing it to native functions, solves the gc-moving-managed-data-around problem in many cases (of course, don't use it in conjunction with callbacks that expect the original variable to be updated before your wrapper has a chance to copy the value back).
To get a native pointer to managed data, you have to use a pinning pointer. This can be slower than the method of copying the value to the stack, so use it for large values or when you really need the function to operate directly on the same variable (e.g. the variable is used in callbacks or multi-threading).
Something like:
pin_ptr<int> p = &mgd_obj.field;
See also the MSDN documentation

Tracking reference in C++/CLI

Can someone please explain me the following code snippet?
value struct ValueStruct {
int x;
};
void SetValueOne(ValueStruct% ref) {
ref.x = 1;
}
void SetValueTwo(ValueStruct ref) {
ref.x = 2;
}
void SetValueThree(ValueStruct^ ref) {
ref->x = 3;
}
ValueStruct^ first = gcnew ValueStruct;
first->x = 0;
SetValueOne(*first);
ValueStruct second;
second.x = 0;
SetValueTwo(second); // am I creating a copy or what? is this copy Disposable even though value types don't have destructors?
ValueStruct^ third = gcnew ValueStruct;
third->x = 0;
SetValueThree(third); // same as the first ?
And my second question is: is there any reason to have something like that?:
ref struct RefStruct {
int x;
};
RefStruct% ref = *gcnew RefStruct;
// rather than:
// RefStruct^ ref = gcnew RefStruct;
// can I retrieve my handle from ref?
// RefStruct^ myref = ???
What is more: I see no difference between value type and ref type, since both can be pointed by handler ;(
Remember that the primary use of C++/CLI is for developing class libraries for consumption by GUIs / web services built in other .NET languages. So C++/CLI has to support both reference and value types because other .NET languages do.
Furthermore, C# can have ref parameters that are value typed as well, this isn't unique to C++/CLI and it doesn't in any way make value types equivalent to reference types.
To answer the questions in your code comments:
am I creating a copy or what?
Yes, SetValueTwo takes its parameter by value, so a copy is made.
is this copy Disposable even though value types don't have destructors?
Incorrect. Value types can have destructors. Value types cannot have finalizers. Since this particular value type has a trivial destructor, the C++/CLI compiler will not cause it to implement IDisposable. In any case, if a parameter is an IDisposable value type, the C++/CLI compiler will ensure that Dispose is called when the variable goes out of scope, just like stack semantics for local variables. This includes abnormal termination (thrown exception), and allows managed types to be used with RAII.
Both
ValueStruct% ref = *gcnew ValueStruct;
and
ValueStruct^ ref = gcnew ValueStruct;
are allowed, and put a boxed value type instance on the managed heap (which isn't a heap at all, but a FIFO queue, however Microsoft chooses to call it a heap like the native memory area for dynamic allocation).
Unlike C#, C++/CLI can keep typed handles to boxed objects.
If a tracking reference is to a value type instance on the stack or embedded in another object, then the value type content has to be boxed in the process of formed the reference.
Tracking references can also be used with reference types, and the syntax to obtain a handle is the same:
RefClass^ newinst = gcnew RefClass();
RefClass% reftoinst = *newinst;
RefClass^% reftohandle = newinst;
RefClass stacksem;
RefClass^ ssh = %stacksem;
One thing that I can never seem to remember completely is that the syntax isn't 100% consistent compared to native C++.
Declare a reference:
int& ri = i; // native
DateTime% dtr = dt; // managed tracking reference
Declare a pointer:
int* pi; // native
Stream^ sh; // tracking handle
Form a pointer:
int* pi = &ri; // address-of native object
DateTime^ dth = %dtr; // address-of managed object
Note that the unary address-of operator is the same as the reference notation in both standard C++ and C++/CLI. This seems to contradict a tracking reference cannot be used as a unary take-address operator (MSDN) which I'll get back to in a second.
First though, the inconsistency:
Form a reference from a pointer:
int& iref = *pi;
DateTime% dtref = *dth;
Note that the unary dereference operator is always *. It is the same as the pointer notation only in the native world, which is completely opposite of address-of which, as mentioned above, are always the same symbol as the reference notation.
Compilable example:
DateTime^ dth = gcnew DateTime();
DateTime% dtr = *dth;
DateTime dt = DateTime::Now;
DateTime^ dtbox = %dt;
FileInfo fi("temp.txt");
// FileInfo^ fih = &fi; causes error C3072
FileInfo^ fih = %fi;
Now, about unary address-of:
First, the MSDN article is wrong when it says:
The following sample shows that a tracking reference cannot be used as a unary take-address operator.
The correct statement is:
% is the address-of operator for creation of a tracking handle. However its use is limited as follows:
A tracking handle must point to an object on the managed heap. Reference types always exist on the managed heap so there is no problem. However, value types and native types may be on the stack (for local variables) or embedded within another object (member variables of value type). Attempts to form a tracking handle will form a handle to a boxed copy of the variable: the handle is not linked to the original variable. As a consequence of the boxing process, which requires metadata which does not exist for native types, it is never possible to have a tracking handle to an instance of a native type.
Example code:
int i = 5;
// int^ ih = %i; causes error C3071
System::Int32 si = 5;
// System::Int32^ sih = %si; causes error C3071
// error C3071: operator '%' can only be applied to an instance
// of a ref class or a value-type
If System::Int32 isn't a value type then I don't know what is. Let's try System::DateTime which is a non-primitive value type:
DateTime dt = DateTime::Now;
DateTime^ dtbox = %dt;
This works!
As a further unfortunate restriction, primitive types which have dual identity (e.g. native int and managed value type System::Int32) are not handled correctly, the % (form tracking reference) operator cannot perform boxing even when the .NET name for the type is given.

Difference between value parameter and reference parameter?

Difference between value parameter and reference parameter ? This question is asked sometime by interviewers during my interviews. Can someone tell me the exact difference that is easy to explain with example? And is reference parameter and pointer parameter are same thing ?
Thanks
Changes to a value parameter are not visible to the caller (also called "pass by value").
Changes to a reference parameter are visible to the caller ("pass by reference").
C++ example:
void by_value(int n) { n = 42; }
void by_ref(int& n) { n = 42; }
void also_value(int const& n); // Even though a reference is used, this is
// semantically a value parameter---though there are implementation
// artifacts, like not being able to write "n = 42" (it's const) and object
// identity (&n here has different ramifications than for by_value above).
One use of pointers is to implement "reference" parameters without using a special reference concept, which some languages, such as C, don't have. (Of course you can also treat pointers as values themselves.)
The main difference is whether the object passed is copied. If it's a value parameter the compiler must generate such code that altering the function parameter inside the function has no effect on the original object passsed, so it will usually copy the object. In case of reference parameters the compiler must generate such code taht all operations are done on the original object being passed.
A pointer is a low-level way of representing a reference, so passing a pointer (by value) is how languages like C typically achieve pass by reference semantics.
The difference is pretty simple: direct parameters are passed by value, and the receiver receives a copy of what is passed; meaning that if the parameter is modified by the receiver, these changes will not be reflected back to the caller. (This is often called, appropriately enough, pass by value, or by copy.
There are basically three kinds of parameters; pointer, reference and direct.
The difference is pretty simple: direct parameters are passed by value, and the receiver receives a copy of what is passed; meaning that if the parameter is modified by the receiver, these changes will not be reflected back to the caller. (This is often called, appropriately enough, pass by value, or bycopy.
Pointers are also passed by value, but rather than sending the actual value, the caller sends the address of the value. This means that by following this pointer, the receiver can modify the argument. Note that changes made to the actual pointer still aren't reflected back to the caller.
The final form, call-by-reference, is sort of a middle ground between these two approaches. Essentially it can be thought of as a pointer that looks like a value.
It is worth mentioning that at the core of it all, parameters are always passed by value, but different languages have different ways of implementing reference semantics (see Kylotans answer).
// Example using C
// bycopy
int multiply(int x, int y) {
return x * y;
}
void multiply_p(int *x, int y) {
*x *= y;
}
int main () {
int i, j, k;
i = 20;
j = 10;
k = multiply(i,j); // k is now 200
multiply_p(&i, k); // i is now 4000 (200 * 20)
return 0;
}
Pseudocode:
Pass by Value:
void setTo4(value) { // value is passed by value
value = 4;
}
int x = 1;
setTo4(x);
// x is still 1
Pass by Reference:
void setTo4(value) { // value is passed by reference
value = 4;
}
int x = 1;
setTo4(x);
// x is 4