Business World 1256987 monthly 10 2009-10-28
Business World 1256987 monthly 10 2009-09-23
Business World 1256987 monthly 10 2009-08-18
Linux 4 U 456734 monthly 25 2009-12-24
Linux 4 U 456734 monthly 25 2009-11-11
Linux 4 U 456734 monthly 25 2009-10-28
I get this result with the query:
SELECT DISTINCT ljm.journelname,ljm. subscription_id,
ljm.frequency,ljm.publisher, ljm.price, ljd.receipt_date
FROM lib_journals_master ljm,
lib_subscriptionhistory
lsh,lib_journal_details ljd
WHERE ljd.journal_id=ljm.id
ORDER BY ljm.publisher
What I need is the latest date in each journal?
I tried this query:
SELECT DISTINCT ljm.journelname, ljm.subscription_id,
ljm.frequency, ljm.publisher, ljm.price,ljd.receipt_date
FROM lib_journals_master ljm,
lib_subscriptionhistory lsh,
lib_journal_details ljd
WHERE ljd.journal_id=ljm.id
AND ljd.receipt_date = (
SELECT max(ljd.receipt_date)
from lib_journal_details ljd)
But it gives me the maximum from the entire column. My needed result will have two dates (maximum of each magazine), but this query gives me only one?
You could change the WHERE statement to look up the last date for each journal:
AND ljd.receipt_date = (
SELECT max(subljd.receipt_date)
from lib_journal_details subljd
where subljd.journelname = ljd.journelname)
Make sure to give the table in the subquery a different alias from the table in the main query.
You should use Group By if you need the Max from date.
Should look something like this:
SELECT
ljm.journelname
, ljm.subscription_id
, ljm.frequency
, ljm.publisher
, ljm.price
, **MAX(ljd.receipt_date)**
FROM
lib_journals_master ljm
, lib_subscriptionhistory lsh
, lib_journal_details ljd
WHERE
ljd.journal_id=ljm.id
GROUP BY
ljm.journelname
, ljm.subscription_id
, ljm.frequency
, ljm.publisher
, ljm.price
Something like this should work for you.
SELECT ljm.journelname
, ljm.subscription_id
, ljm.frequency
, ljm.publisher
, ljm.price
,md.max_receipt_date
FROM lib_journals_master ljm
, ( SELECT journal_id
, max(receipt_date) as max_receipt_date
FROM lib_journal_details
GROUP BY journal_id) md
WHERE ljm.id = md.journal_id
/
Note that I have removed the tables from the FROM clause which don't contribute anything to the query. You may need to replace them if yopu simplified your scenario for our benefit.
Separate this into two queries one will get journal name and latest date
declare table #table (journalName as varchar,saleDate as datetime)
insert into #table
select journalName,max(saleDate) from JournalTable group by journalName
select all fields you need from your table and join #table with them. join on journalName.
Sounds like top of group. You can use a CTE in SQL Server:
;WITH journeldata AS
(
SELECT
ljm.journelname
,ljm.subscription_id
,ljm.frequency
,ljm.publisher
,ljm.price
,ljd.receipt_date
,ROW_NUMBER() OVER (PARTITION BY ljm.journelname ORDER BY ljd.receipt_date DESC) AS RowNumber
FROM
lib_journals_master ljm
,lib_subscriptionhistory lsh
,lib_journal_details ljd
WHERE
ljd.journal_id=ljm.id
AND ljm.subscription_id = ljm.subscription_id
)
SELECT
journelname
,subscription_id
,frequency
,publisher
,price
,receipt_date
FROM journeldata
WHERE RowNumber = 1
Related
I have this table
SELECT PolicyID, ItemID, Period, Inventory1, Inventory2
FROM tblInventory
I want to convert this table into this:
The period will be converted as Column such as Inventory1 -1 and Inventory2 -1 until 4th period, per period there are two columns included: inventory1 and inventory2.
I would like to ask help on how to code this in SQL. Thank you!
To use PIVOT with your example you want to UNPIVOT the data first.
SELECT
*
FROM
(
SELECT
UP.PolicyId
, UP.ItemId
, CONCAT(UP.Inventories, '-', UP.Period) AS Inventories
, UP.Inventory
FROM
tblInventory AS TI
UNPIVOT
(
Inventory FOR Inventories IN (Inventory1, Inventory2)
) AS UP
) AS UNP
PIVOT
(
MAX(Inventory)
FOR Inventories IN
(
[Inventory1-1], [Inventory1-2], [Inventory1-3], [Inventory1-4]
, [Inventory2-1], [Inventory2-2], [Inventory2-3], [Inventory2-4]
)
) AS PVT
I need to create one master table to present in reporting services, but i have an issue on how to combine the data.
To be more specific, i have one table named "Reservaciones" which store information from residences that have been reserved in certain dates.
Now for example, I´m grouping the information by this fields:
R.ClaTrab AS WorkerId
R.ClaUbicacion AS UbicationID
R.ClaEstancia AS ResidenceID
R.FechaIni AS InitialDay
R.FechaFin AS LastDay
And the result is First result**
As you see in the picture we have two rows duplicated, the number four and number five to be exact.
So far this is my code
SELECT
R.ClaTrab AS WorkerId,
MAX(E.NomEstancia) AS ResidenceName,
R.ClaUbicacion AS UbicationID,
R.ClaEstancia AS ResidenceID,
DATEDIFF(DAY, R.FechaIni, R.FechaFin) AS NumberDays,
R.FechaIni AS InitialDay,
R.FechaFin AS LastDay
FROM Reservaciones AS R
INNER JOIN Estancias AS E ON E.ClaEstancia = R.ClaEstancia
WHERE E.ClaUbicacionEst = 3
GROUP BY R.ClaTrab,R.ClaUbicacion, R.ClaEstancia, R.FechaIni, R.FechaFin
ORDER BY R.FechaIni
I Want the result to be like this desire result, but i dont know how to do it, i have tried PIVOT but i cant get the result i want it.
If u need more information please, ask me.
thank you very much.
SOLUTION:
What i did is use the ROW NUMBER() and OVER PARTITION BY to create a group of workers in the same residence, then PIVOT the result in new columns.
SNIPPET
SELECT * FROM(
SELECT
MAX(E.NomEstancia) AS ResidenceName,
R.FechaIni AS InitialDay,
R.FechaFin AS LastDay,
DATEDIFF(DAY, R.FechaIni, R.FechaFin) AS NumberDays,
T.NomTrab AS Worker,
R.ClaUbicacion AS UbicationID,
R.ClaEstancia AS ResidenceID,
ROW_NUMBER() OVER(PARTITION BY FechaIni,FechaFin, R.ClaUbicacion, R.ClaEstancia ORDER BY T.NomTrab) AS GUEST
FROM Reservaciones AS R
INNER JOIN Estancias AS E ON E.ClaEstancia = R.ClaEstancia
INNER JOIN Trabajadores AS T ON T.ClaTrab = R.ClaTrab
WHERE E.ClaUbicacionEst = 3
GROUP BY T.NomTrab, R.ClaUbicacion, R.ClaEstancia, R.FechaIni,R.FechaFin) AS ONE
PIVOT( MAX(Worker) FOR GUEST IN ([1],[2],[3])) AS pvt
In the new query I added a new join to obtain the name of the workers
Since there can only be 2 workers, you can use Min and Max.
with cte as(
SELECT
R.ClaTrab AS WorkerId,
MAX(E.NomEstancia) AS ResidenceName,
R.ClaUbicacion AS UbicationID,
R.ClaEstancia AS ResidenceID,
DATEDIFF(DAY, R.FechaIni, R.FechaFin) AS NumberDays,
R.FechaIni AS InitialDay,
R.FechaFin AS LastDay
FROM
Reservaciones AS R
INNER JOIN
Estancias AS E
ON E.ClaEstancia = R.ClaEstancia
WHERE
E.ClaUbicacionEst = 3
GROUP BY
R.ClaTrab,
R.ClaUbicacion,
R.ClaEstancia,
R.FechaIni,
R.FechaFin),
cte2 as(
select
ResidenceName
,UbicationID
,ResidenceID
,NumberDays
,InitalDay
,LastDay
,Worker1 = max(WorkerId)
,Worker2 = min(WorkerId)
from
cte
group by
ResidenceName
,UbicationID
,ResidenceID
,NumberDays
,InitalDay
,LastDay)
select
ResidenceName
,UbicationID
,ResidenceID
,NumberDays
,InitalDay
,LastDay
,Worker1
,Worker2 = case when Worker1 = Worker2 then NULL else Worker2 end
from
cte2
ONLINE DEMO WITH PARTIAL TEST DATA
I have a table in SQL server 2008 with data.
Table contains data with amount of time organization has worked on request
CREATE TABLE support
( ID varchar(50),
IN_ORGANIZATION varchar(MAX),
FROM_ORGANIZATION varchar(MAX),
TIMEDIF datetime );
INSERT INTO support
(ID, IN_ORGANIZATION,FROM_ORGANIZATION,TIMEDIF )
VALUES
('22907','ORGANIZATION_NAME_1','RODLAY LLP','2017-04-15 14:58:00.000'),
('22907','MARY LOAN','ORGANIZATION_NAME_1','2017-04-15 15:00:00.000'),
('23289','VENIXTON Ltd','ORGANIZATION_NAME_1','2017-04-21 11:00:00.000'),
('23289','ORGANIZATION_NAME_1','Ocean Loan','2017-04-21 12:00:00.000'),
('23289','Ocean Loan','ORGANIZATION_NAME_1','2017-04-21 13:00:00.000')
;
I want to find time work organizations with the request: ORGANIZATION_NAME_1.
Help me write CURSOR to calculate the time.
Result:
ID, TIMEDIF(minutes)
22907, 2
23289, 120
Datediff function will do the trick
select id,datediff(minute,min(timedif),max(timedif) ) AS time from support
where in_organization = 'ORGANIZATION_NAME_1' or from_organization = 'ORGANIZATION_NAME_1'
group by id ;
My Output:
|id |time
1 |22907 |2
2 |23289 |120
Let tme know in case of any queries.
Maybe this query will help you:
select
id,
DATEDIFF(m,MIN(TIMEDIF),MAX(TIMEDIF)) as [TIMEDIF(minutes)]
from support
where IN_ORGANIZATION ='ORGANIZATION_NAME_1'
or FROM_ORGANIZATION ='ORGANIZATION_NAME_1'
group by id
If you are just arbitrarily trying to get the TimeDifferences between rows you could try something like this:
; WITH x AS
(
SELECT *, ROW_NUMBER() OVER(ORDER BY id) AS rwn
From dbo.support
)
SELECT
x.ID
, y.ID AS NextID
, x.IN_ORGANIZATION
, y.IN_ORGANIZATION NextInOrg
, x.FROM_ORGANIZATION
, y.FROM_ORGANIZATION NextFromOrg
, x.TIMEDIF
, y.TIMEDIF AS NextTimeDiff
, x.rwn
, DATEDIFF(MINUTE, x.TIMEDIF, y.TIMEDIF) AS DifferenceFromOneToTheNext
FROM x
INNER JOIN x y ON x.rwn = y.rwn - 1
If you put in an identity that self seeds you can already get a pointer for reference. This is really arbitrary though.
I have a table deposit which have column Refund_amt ,Deposit_amt having different Rows with same GR_no . here my question is ,I want to subtract deposit_amt column from Refund_amt
I tried various alternative in query but didn't succeed
My query :
SELECT d.Gr_no
, d.Rec_No
, d.Deposite_Amt
, d.penalty_Amt
, d.Refund_Amt - Refund
, s.Name
, s.cur_std
, cur_div
From
( select d.Refund_Amt refund
from deposite d
, std_gr s
where d.Gr_no = s.Gr_no )
Result would look like this in final total column :
Thank you
You are looking for an aggregation per std_gr: the sum of the deposites minus the sum of the refunds. One way is to do this aggregation in a subquery and join this subquery to your table.
select
d.*, sums.final_total
from deposite d
join
(
select std_gr, nz(sum(deposite_amt),0) - nz(sum(refund_amt),0) as final_total
from deposite
group by std_gr
) as sums on sums.std_gr = d.std_gr
order by d.rec_no;
I have those two tables
1-Add to queue table
TransID , ADD date
10 , 10/10/2012
11 , 14/10/2012
11 , 18/11/2012
11 , 25/12/2012
12 , 1/1/2013
2-Removed from queue table
TransID , Removed Date
10 , 15/1/2013
11 , 12/12/2012
11 , 13/1/2013
11 , 20/1/2013
The TansID is the key between the two tables , and I can't modify those tables, what I want is to query the amount of time each transaction spent in the queue
It's easy when there is one item in each table , but when the item get queued more than once how do I calculate that?
Assuming the order TransIDs are entered into the Add table is the same order they are removed, you can use the following:
WITH OrderedAdds AS
( SELECT TransID,
AddDate,
[RowNumber] = ROW_NUMBER() OVER(PARTITION BY TransID ORDER BY AddDate)
FROM AddTable
), OrderedRemoves AS
( SELECT TransID,
RemovedDate,
[RowNumber] = ROW_NUMBER() OVER(PARTITION BY TransID ORDER BY RemovedDate)
FROM RemoveTable
)
SELECT OrderedAdds.TransID,
OrderedAdds.AddDate,
OrderedRemoves.RemovedDate,
[DaysInQueue] = DATEDIFF(DAY, OrderedAdds.AddDate, ISNULL(OrderedRemoves.RemovedDate, CURRENT_TIMESTAMP))
FROM OrderedAdds
LEFT JOIN OrderedRemoves
ON OrderedAdds.TransID = OrderedRemoves.TransID
AND OrderedAdds.RowNumber = OrderedRemoves.RowNumber;
The key part is that each record gets a rownumber based on the transaction id and the date it was entered, you can then join on both rownumber and transID to stop any cross joining.
Example on SQL Fiddle
DISCLAIMER: There is probably problem with this, but i hope to send you in one possible direction. Make sure to expect problems.
You can try in the following direction (which might work in some way depending on your system, version, etc) :
SELECT transId, (sum(add_date_sum) - sum(remove_date_sum)) / (1000*60*60*24)
FROM
(
SELECT transId, (SUM(UNIX_TIMESTAMP(add_date)) as add_date_sum, 0 as remove_date_sum
FROM add_to_queue
GROUP BY transId
UNION ALL
SELECT transId, 0 as add_date_sum, (SUM(UNIX_TIMESTAMP(remove_date)) as remove_date_sum
FROM remove_from_queue
GROUP BY transId
)
GROUP BY transId;
A bit of explanation: as far as I know, you cannot sum dates, but you can convert them to some sort of timestamps. Check if UNIX_TIMESTAMPS works for you, or figure out something else. Then you can sum in each table, create union by conveniently leaving the other one as zeto and then subtracting the union query.
As for that devision in the end of first SELECT, UNIT_TIMESTAMP throws out miliseconds, you devide to get days - or whatever it is that you want.
This all said - I would probably solve this using a stored procedure or some client script. SQL is not a weapon for every battle. Making two separate queries can be much simpler.
Answer 2: after your comments. (As a side note, some of your dates 15/1/2013,13/1/2013 do not represent proper date formats )
select transId, sum(numberOfDays) totalQueueTime
from (
select a.transId,
datediff(day,a.addDate,isnull(r.removeDate,a.addDate)) numberOfDays
from AddTable a left join RemoveTable r on a.transId = r.transId
order by a.transId, a.addDate, r.removeDate
) X
group by transId
Answer 1: before your comments
Assuming that there won't be a new record added unless it is being removed. Also note following query will bring numberOfDays as zero for unremoved records;
select a.transId, a.addDate, r.removeDate,
datediff(day,a.addDate,isnull(r.removeDate,a.addDate)) numberOfDays
from AddTable a left join RemoveTable r on a.transId = r.transId
order by a.transId, a.addDate, r.removeDate