I have a table that has a column for dateofbirth varchar(10). All the data inside is stored like this '02/01/1990'.
I need to convert it to datetime. I've tried
CAST(DateofBirth AS DATEITME) AS BirthDate
But I keep getting this error when I try importing:
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value"
I need it like this:
1990-02-01 00:00:00:000
SELECT CONVERT(Datetime, '2011-09-28 18:01:00', 120) -- to convert it to Datetime SELECT CONVERT( VARCHAR(30), #date ,105) -- italian format [28-09-2011 18:01:00] + ' ' + SELECT CONVERT( VARCHAR(30), #date ,108 ) -- full date [with time/minutes/sec]
You need to convert a Varchar in format MM/DD/YYYY to a Datetime.
Sql server recognizes a set of predefined date formats that it is able to automatically parse. See this cheat list.
Your input format corresponds to sql server date format 101, hence you can do :
SELECT CONVERT(Datetime, '02/01/1990', 101)
If you try to do it in sql query there is syntax to do it .
Here a link ..
SQL Server Convert Varchar to Datetime
Your cast statement works for me:
Declare #dateofbirth varchar(10) = '02/01/1990'
select cast(#dateofbirth as datetime)AS BirthDate
Result:
BirthDate
1990-02-01 00:00:00.000
I have below sample data:
03202012 as date but the column datatype is Varchar.
I want to convert it to 2012-03-20 00:00:00.000 as Datetime.
I tried using
CAST(CONVERT(CHAR(10), Column, 101) AS DATETIME)
But I get an error:
The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.
Complete code snippet to test:
DECLARE #Column VARCHAR(MAX) = '03202012'
SELECT CAST(CONVERT(CHAR(10), #Column, 101) AS DATETIME)
Use yyyyMMdd format, that always works:
DECLARE #myDateString varchar(10) = '03202012';
SELECT cast( substring(#myDateString, 5, 4)+
substring(#myDateString, 1, 2)+
substring(#myDateString, 3, 2) AS datetime);
I found below script help me solved my concern.
SELECT convert(datetime, STUFF(STUFF('31012016',3,0,'-'),6,0,'-'), 105)
Result: 2016-01-31 00:00:00.000
Thanks all for the effort. :D
In MySQL, you can use the STR_TO_DATE function to convert a string to a date. For your example, it would look like this
STR_TO_DATE("03-02-2012", "%m-%d-%Y");
Note that the format part of the string must match the format part of the date.
Edit: Just found out this is for SQL Server, but I assume this will work there as well.
I want to convert a datetime to a specific format. The conversion should result in a variable of type datetime and not char or varchar. How do I do this in SQL server 2000, 2005 and 2008 ?
select CONVERT(varchar(30),getdate(),120)
I tried this, but it gives me a string. I want a datetime without the milli-seconds. SS 2012 has an option for this, but not previous versions.
http://blog.sqlauthority.com/2012/11/21/sql-server-display-datetime-in-specific-format-sql-in-sixty-seconds-033-video/
You can't have it both ways ... a variable of type "datetime" is defined as:
Defines a date that is combined with a time of day
with fractional seconds that is based on a 24-hour clock
You can CONVERT and DISPLAY in whatever format you choose, but the datetime data type will always have the milliseconds, even if you set them to zero.
You can remove the milliseconds from the datetime like this:
DATEADD(ms, -DATEPART(ms, date), date) > '2013-11-18 03:21:52'
Also check SQL Server Date Formats
or may be try like this to remove the millisecond part:-
declare #str datetime
set #str = '2013-11-18 17:24:05.784'
select convert(datetime, convert(char(19), #str, 126))
In my table I have myDate column of type nvarchar(50).
The result I need is to select this date/time: 07/11/2013 11:22:07
And I need to get 07/11/2013 11:22:07 am from it (add am/pm to the original date&time).
I tried everything but get only the original data without am/pm.
This is an example from my query :
select convert(dateTime,myDate,100) as Date from Info
or
select convert(dateTime,myDate,0) as Date from Info
What am I missing ?
try this !!
declare #date datetime
set #date='07/11/2013 11:22:07'
SELECT cast(convert(varchar(20),substring(convert(nvarchar(20),#date, 9), 0, 21)
+ ' ' + substring(convert(nvarchar(30), #date, 9), 25, 2),105) as datetime)
Your field is a NVARCHAR field so just return it without any conversion. In your query you convert string representation into the DATETIME type and returns it. Your browser software which shows query results convert DateTime value into string representation to show it to you and conversion format depends on this software usually you can change it changing Windows Regional Settings.
You can get AM/PM data using following query
declare #date datetime
select #date= CAST('07/11/2013 11:22:07' AS datetime)
select RIGHT ( CONVERT(VARCHAR,#date,9),2)
How do I convert a string of format mmddyyyy into datetime in SQL Server 2008?
My target column is in DateTime
I have tried with Convert and most of the Date style values however I get an error message:
'The conversion of a varchar data type to a datetime data type resulted in an out-of-range value.'
OP wants mmddyy and a plain convert will not work for that:
select convert(datetime,'12312009')
Msg 242, Level 16, State 3, Line 1
The conversion of a char data type to a datetime data type resulted in
an out-of-range datetime value
so try this:
DECLARE #Date char(8)
set #Date='12312009'
SELECT CONVERT(datetime,RIGHT(#Date,4)+LEFT(#Date,2)+SUBSTRING(#Date,3,2))
OUTPUT:
-----------------------
2009-12-31 00:00:00.000
(1 row(s) affected)
SQL Server can implicitly cast strings in the form of 'YYYYMMDD' to a datetime - all other strings must be explicitly cast. here are two quick code blocks which will do the conversion from the form you are talking about:
version 1 uses unit variables:
BEGIN
DECLARE #input VARCHAR(8), #mon CHAR(2),
#day char(2), #year char(4), #output DATETIME
SET #input = '10022009' --today's date
SELECT #mon = LEFT(#input, 2), #day = SUBSTRING(#input, 3,2), #year = RIGHT(#input,4)
SELECT #output = #year+#mon+#day
SELECT #output
END
version 2 does not use unit variables:
BEGIN
DECLARE #input CHAR(8), #output DATETIME
SET #input = '10022009' --today's date
SELECT #output = RIGHT(#input,4) + SUBSTRING(#input, 3,2) + LEFT(#input, 2)
SELECT #output
END
Both cases rely on sql server's ability to do that implicit conversion.
Likely you have bad data that cannot convert. Dates should never be stored in varchar becasue it will allow dates such as ASAP or 02/30/2009. Use the isdate() function on your data to find the records which can't convert.
OK I tested with known good data and still got the message. You need to convert to a different format becasue it does not know if 12302009 is mmddyyyy or ddmmyyyy. The format of yyyymmdd is not ambiguous and SQL Server will convert it correctly
I got this to work:
cast( right(#date,4) + left(#date,4) as datetime)
You will still get an error message though if you have any that are in a non-standard format like '112009' or some text value or a true out of range date.
I found this helpful for my conversion, without string manipulation. https://learn.microsoft.com/en-us/sql/t-sql/functions/cast-and-convert-transact-sql
CONVERT(VARCHAR(23), #lastUploadEndDate, 121)
yyyy-mm-dd hh:mi:ss.mmm(24h) was the format I needed.
Convert would be the normal answer, but the format is not a recognised format for the converter, mm/dd/yyyy could be converted using convert(datetime,yourdatestring,101) but you do not have that format so it fails.
The problem is the format being non-standard, you will have to manipulate it to a standard the convert can understand from those available.
Hacked together, if you can guarentee the format
declare #date char(8)
set #date = '12312009'
select convert(datetime, substring(#date,5,4) + substring(#date,1,2) + substring(#date,3,2),112)
Look at CAST / CONVERT in BOL that should be a start.
If your target column is datetime you don't need to convert it, SQL will do it for you.
Otherwise
CONVERT(datetime, '20090101')
Should do it.
This is a link that should help as well:
I'd use STUFF to insert dividing chars and then use CONVERT with the appropriate style. Something like this:
DECLARE #dt VARCHAR(100)='111290';
SELECT CONVERT(DATETIME,STUFF(STUFF(#dt,3,0,'/'),6,0,'/'),3)
First you use two times STUFF to get 11/12/90 instead of 111290, than you use the 3 to convert this to datetime (or any other fitting format: use . for german, - for british...) More details on CAST and CONVERT
Best was, to store date and time values properly.
This should be either "universal unseparated format" yyyyMMdd
or (especially within XML) it should be ISO8601: yyyy-MM-dd or yyyy-MM-ddThh:mm:ss More details on ISO8601
Any culture specific format will lead into troubles sooner or later...
use Try_Convert:Returns a value cast to the specified data type if the cast succeeds; otherwise, returns null.
DECLARE #DateString VARCHAR(10) ='20160805'
SELECT TRY_CONVERT(DATETIME,#DateString)
SET #DateString ='Invalid Date'
SELECT TRY_CONVERT(DATETIME,#DateString)
Link:MSDN TRY_CONVERT (Transact-SQL)
I had luck with something similar:
Convert(DATETIME, CONVERT(VARCHAR(2), #Month) + '/' + CONVERT(VARCHAR(2), #Day)
+ '/' + CONVERT(VARCHAR(4), #Year))
The root cause of this issue can be in the regional settings - DB waiting for YYYY-MM-DD while an app sents, for example, DD-MM-YYYY (Russian locale format) as it was in my case. All I did - change locale format from Russian to English (United States) and voilà.
This seems the easiest way..
SELECT REPLACE(CONVERT(CHAR(10), GETDATE(), 110),'-','')
SQL standard dates while inserting or updating Must be between 1/1/1753 12:00:00 AM and 12/31/9999 11:59:59 PM.
So if you are inserting/Updating below 1/1/1753 you will get this error.
DECLARE #d char(8)
SET #d = '06082020' /* MMDDYYYY means June 8. 2020 */
SELECT CAST(FORMAT (CAST (#d AS INT), '##/##/####') as DATETIME)
Result returned is the original date string in #d as a DateTime.