Ranking before grouping problem in SQL Server 2005 - sql

Question

HI,
This should be easy but I don't understand enough about how grouping works.
Basically I have 2 tables "Categories" and "Items"
Categories
ID
CategoryName
Items
ID
CategoryID
ItemName
Photo
Score
All I want to do is get 1 row for each category which contains the Category ID, the Category Name and the photo that belongs to the highest scoring item.
So I have tried joining the categories to the items and grouping by the CategoryID. Trouble is that I want to order the items so that the highest scoring items are at the top before it does the groupings to make sure that the photo is from the current highest scoring item in that category. If I select MAX(I.score) I can get the highest score but I'm not sure how to get accompanying photo as MAX(photo) will obviously give me the photo with the highest file name alphabetically.
I hope I've explained that well.

Answer 1

You could try something like (Full example)
DECLARE #Categories TABLE(
ID INT,
CategoryName VARCHAR(50)
)
DECLARE #Items TABLE(
ID INT,
CategoryID INT,
ItemName VARCHAR(50),
Photo VARCHAR(50),
Score FLOAT
)
INSERT INTO #Categories (ID,CategoryName) SELECT 1, 'Cat1'
INSERT INTO #Categories (ID,CategoryName) SELECT 2, 'Cat2'
INSERT INTO #Items (ID,CategoryID,ItemName,Photo,Score) SELECT 1, 1, 'Item1', 'PItem1', 1
INSERT INTO #Items (ID,CategoryID,ItemName,Photo,Score) SELECT 2, 1, 'Item2', 'PItem2', 2
INSERT INTO #Items (ID,CategoryID,ItemName,Photo,Score) SELECT 3, 1, 'Item3', 'PItem3', 3
INSERT INTO #Items (ID,CategoryID,ItemName,Photo,Score) SELECT 4, 2, 'Item4', 'PItem4', 5
INSERT INTO #Items (ID,CategoryID,ItemName,Photo,Score) SELECT 5, 2, 'Item5', 'PItem5', 2
SELECT *
FROM (
SELECT c.ID,
c.CategoryName,
i.Photo,
i.Score,
ROW_NUMBER() OVER(PARTITION BY i.CategoryID ORDER BY i.Score DESC) RowID
FROM #Categories c INNER JOIN
#Items i ON c.ID = i.CategoryID
) CatItems
WHERE RowID = 1
Using the ROW_NUMBER you can selet the items you require.

Answer 2

You need to aggregate first and join back like this.
(If you change grouping, you need to change JOIN)
SELECT
...
FROM
(
select
max(Score) AS MaxScore,
CategoryID
FROM
Items
GROUP BY
CategoryID
) M
JOIN
Items I ON M.CategoryID = I.CategoryID AND M.MaxScore = I.Score
JOIN
Categories C ON I.CategoryID = C.CategoryID

Answer 3

This is a pretty common problem, and one that SQL Server doesn't solve particularly well. Something like this should do the trick, though:
select
c.ID,
c.CategoryName,
item.*
from Categories c
join (
select
ID,
CategoryID,
ItemName,
Photo,
Score,
(row_number() over order by CategoryID, Score desc) -
(rank() over order by CategoryID) as rownum
from Items) item on item.CategoryID = c.CategoryID and item.rownum = 0
While there is no explicit group by clause, this (for practical purposes) groups the Categories records and gives you a joined statement that allows you to view any property of the highest scoring item.

Answer 4

You can use row numbers to rank items per category:
select *
from (
select
row_number() over (partition by c.id order by i.score desc) rn
, *
from Categories c
join Items i on c.ID = i.CategoryID
) sub
where rn = 1
In SQL 2005, you can't reference a row_number() directly in a where, so it's wrapped in a subquery.

Answer 5

Exactly as you worded it:
"the Category ID, the Category Name and the photo that belongs to the highest scoring item." -- Now here I surmise you really meant "...highest scoring item in that category", no?)
Select CategoryID, c.Categoryname, Photo
From items i Join Categoiries c
On c.ID = i.CategoryId
Where Score = (Select Max(Score) From Items
Where CategoryID = i.CategoryId)
If you really meant the highest scoring item on the whole items table, then just omit the predicate in the subquery
Select CategoryID, c.Categoryname, Photo
From items i Join Categoiries c
On c.ID = i.CategoryId
Where Score = (Select Max(Score) From Items)
Both these queries will return multiple rows per group if there are more than one item in the defined group which tie for highest score..