I am going through an issue to setup a file upload validator on callback.
I want to achieve this:
I have a form, where user choose the type of the file they are uploading and upload the file.
So I want to set the validator to handle images in case they chose "img" as type, and pdf if they chose "pdf".
Moreover I want to specify the mime type and path and validatedFileClass according to the type.
I tried this.. but i can't get it to work
$this->validatorSchema->setPostValidator(
new sfValidatorCallback(array('callback' => array($this, 'validateUploadedFiles')))
);
the function:
public function validateUploadedFiles($form_validator, $values){
$this_year = date("Y");
$this_month = date("m");
$basic_validator = array(
'required' => true,
'path' => sfConfig::get('sf_upload_dir').'restaurant/media/'.$this_year.'/'.$this_month.'/'
);
$doc_validator = $video_validator = $img_validator = $pdf_validator = $basic_validator;
$pdf_validator['mime_types'] = array ('application/pdf');
$doc_validator['mime_types'] = array ('application/msword', 'application/vnd.openxmlformats');
$img_validator['mime_types'] = 'web_images';
//$img_validator['validated_file_class'] = 'imgHandling';
$video_validator['mime_types'] = array('video/mpeg', 'video/3gpp', 'video/mp4', 'video/quicktime');
switch( $values['type'] ):
case 'pdf' : $validator = $pdf_validator; break;
case 'img' : $validator = $img_validator; break;
case 'word' : $validator = $doc_validator; break;
case 'video' : $validator = $video_validator; break;
endswitch;
//$form->getValidatorSchema()->offsetUnset('url') ;
//print_r($validator_fields);
$validator = new sfValidatorFile( $validator );
$validator_schema = new sfValidatorSchema();
$validator_schema->offsetSet('url', $validator);
//$validator_fields = $form->getValidatorSchema()->getFields();
$schema = parent::getValidatorSchema();
$schema->offsetUnset('url') ;
$schema->offsetSet('url', $validator);
// $path = sfConfig::get('sf_upload_dir').'restaurant/media/'.$this_year.'/'.$this_month.'/';
// $values['url'] = new sfValidatedFile( $values['url']['name'], $values['url']['type'], $values['url']['tmp_name'], $values['url']['size'] , $path);
//TODO get this url value run through the new added validator
//$values['url'] = $validator_schema->clean(array( 'url' => $values['url'] ));
return $values;
}
the problem i am facing is that , this function receives the url value as array, and even if I update the validators schema, it's not validating the url and keeps on sending it as array to the object saving method.
So how to make something like
url.validateFile() from inside this function
Not sure about the best solution, but I'd prefer to split validation process into 2 parts:
Validate mime type
If mime is ok, then validate URL
Or vise versa, your choice.
The glue would be sfValidatorAnd.
Did I understand you right?
Related
Hello guys How to get the original client name of an image in the collection?
I have this new code to upload more than three images
public function store(){
$action = '';
$data = $this->validate([
'album_title' => 'required',
'photos.*' => 'image|max:2000', // 2MB Max
]);
//New Code with collections
$filenames = collect($this->photos)->map->store('photos');
if($this->galleryId){
Gallery::find($this->galleryId)->update($data);
$action = 'edit';
}else{
// Gallery::create($data);
Gallery::create([
'album_title' => $this->album_title,
'photos' => $filenames->implode(','),
]);
$action = 'store';
}
$this->emit('showEmitedFlashMessage', $action);
$this->resetInputFields();
$this->emit('refreshParent');
$this->emit('closeGalleryModal');
}
but it save something like this
photos/xTNV0cQ7YzpyUsJ6OdrpQirwfCPdzDtKJAKoWUFm.jpg,photos/32PkRR9bFhM7BqAy9OWG05m5fe53PUXtidEMhlnn.jpg,photos/Dyps8wCsga0zdALGsKEOS9jcYSNshnixw4UWzhEL.jpg
What I want is to save the original name of the images.
What I usually do is set the file name to a uuid for storage in the system, but retain the original filename in the database so that you can rename it for downloads if you want. To get the original file name, you need to look at the post data for that.
like so:
$this->active_document->original_filename = $this->uploaded_file->getClientOriginalName();
More info here in the docs: https://laravel.com/docs/8.x/filesystem#file-uploads
In my admin module's controller's listMappingsAction action, I want to show a Vue.JS template, passing two variables that need to call $this->module->getPathUri() to be assigned a value:
<?php
namespace XYZ\Controller;
use PrestaShopBundle\Controller\Admin\FrameworkBundleAdminController;
use PrestaShopBundle\Security\Annotation\AdminSecurity;
class AutomatizedMappingController extends FrameworkBundleAdminController
{
/**
* #AdminSecurity("is_granted('read', request.get('_legacy_controller'))", message="Access denied.")
*/
function listMappingsAction() {
return $this->render('#Modules/XYZ/views/templates/admin/app.html.twig', [
'XYZ' => [
'pathApp' => $this->module->getPathUri() . 'views/js/app.js',
'chunkVendor' => $this->module->getPathUri() . 'views/js/chunk-vendors.js',
]
]);
}
}
The use of $this->module->getPathUri() results in this error being displayed:
Attempted to call an undefined method named "getPathUri" of class "XYZ\Controller\AutomatizedMappingController". [Symfony\Component\Debug\Exception\UndefinedMethodException 0]
What could I call to make it work? The docs don't mention this use case... https://devdocs.prestashop.com/1.7/modules/concepts/templating/vuejs/faq/#how-to-send-data-from-symfony-controller-to-vuejs
First of all you need to know there is a difference between a module and a admin-controller. You cannot call $this->module->getPathUri() because your not using a extends ModuleAdminController, extends ModuleFrontController, extends Module ...
So you can only call $this->module if your actually using files inside a module.
Since i don't know which path you are trying to go to ill pass you a few variables which you might be able to use.
$this->module->name = crezzurmodulename
$this->module->getLocalPath() = C:\yourstore/modules/crezzurmodulename/
$this->module->getPathUri() = /yourstore/modules/crezzurmodulename/
_MODULE_DIR_ = /yourstore/modules/
_PS_MODULE_DIR_ = C:\yourstore/modules/
__DIR__ = C:\yourstore\modules\crezzurmodulename\controllers\front
_PS_CAT_IMG_DIR_ = C:\yourstore/img/c/
_PS_PROD_IMG_DIR_ = C:\yourstore/img/p/
_PS_TMP_IMG_DIR_ = C:\yourstore/img/tmp/
_PS_ROOT_DIR_ = C:\yourstore
_PS_CACHE_DIR_ = C:\yourstore/var/cache/dev\
_PS_BASE_URL_ = http://127.0.0.1
__PS_BASE_URI__ = /yourstore/
_PS_TRANSLATIONS_DIR_ = C:\yourstore/translations/
_PS_BASE_URL_SSL_ = http://127.0.0.1 or https://127.0.0.1
_PS_DOWNLOAD_DIR_ = C:\yourstore/download/
_PS_COL_IMG_DIR_ = C:\yourstore/img/co/
_PS_SHIP_IMG_DIR_ = C:\yourstore/img/s/
_PS_UPLOAD_DIR_ = C:\yourstore/upload/
I am using yii mail swiftmailer extension to send mail .when am using this mail extension along with ccaptcha validation in the same form the mail is not sending.when it has be used alone without captcha validation it is sending email.i need to send email using this extension along with the ccaptcha validation in yii.
for email:
$subjek="verifymail";
$from="sender#gmail.com";
$getEmail="to#gmail.com";
$message= new YiiMailMessage;
$message->subject=$subjek;
$message->from=$from;
$message->setBody($activationlink, 'text/html');
$message->addTo($getEmail);
Yii::app()->mail->send($message);
I think you are missing port and host information in your code,unless you didnt show your whole code,see example here
public function actionViewTest() {
// Render view and get content
// Notice the last argument being `true` on render()
$content = $this->render('viewTest', array(
'Test' => 'TestText 123',
), true);
// Plain text content
$plainTextContent = "This is my Plain Text Content for those with cheap emailclients ;-)\nThis is my second row of text";
// Get mailer
$SM = Yii::app()->swiftMailer;
// Get config
$mailHost = 'mail.example.com';
$mailPort = 25; // Optional
// New transport
$Transport = $SM->smtpTransport($mailHost, $mailPort);
// Mailer
$Mailer = $SM->mailer($Transport);
// New message
$Message = $SM
->newMessage('My subject')
->setFrom(array('from#example.com' => 'Example Name'))
->setTo(array('recipient#example.com' => 'Recipient Name'))
->addPart($content, 'text/html')
->setBody($plainTextContent);
// Send mail
$result = $Mailer->send($Message);
}
If your host is gmail,put the port to 587 or 465
$mail->Port = 587; or $mail->Port = 465;
here is a question almost similar to your question
I have the hypothetical Zoo extension in which I've Animal model with photo field and FrontEnd (FE) plugin with typical CRUD actions. photo field is typical FAL's FileReference and it works perfectly in backend (BE) with common TCA IRRE config.
I'm able to successful upload the file to the storage, it's visible in the Filelist module, and I can use it in BE during my Animal editing, anyway I can't create FileReference within my FE plugin.
My current approach looks like this:
/**
* #param \Zoo\Zoo\Domain\Model\Animal $animal
*/
public function updateAction(\Zoo\Zoo\Domain\Model\Animal $animal) {
// It reads proper uploaded `photo` from form's $_FILES
$file = $this->getFromFILES('tx_zoo_animal', 'photo');
if ($file && is_array($file) && $file['error'] == 0) {
/** #type $storageRepository \TYPO3\CMS\Core\Resource\StorageRepository */
$storageRepository = GeneralUtility::makeInstance('\TYPO3\CMS\Core\Resource\StorageRepository');
$storage = $storageRepository->findByUid(5); // TODO: make target storage configurable
// This adds uploaded file to the storage perfectly
$fileObject = $storage->addFile($file['tmp_name'], $storage->getRootLevelFolder(), $file['name']);
// Here I stuck... below line doesn't work (throws Exception no. 1 :/)
// It's 'cause $fileObject is type of FileInterface and FileReference is required
$animal->addPhoto($fileObject);
}
$this->animalRepository->update($animal);
$this->redirect('list');
}
anyway attempt to create reference by this line throws exception:
$animal->addPhoto($fileObject);
How can I resolve this?
Checked: DataHandler approach (link) won't work also, as it's unavailable for FE users.
TL;DR
How to add FileReference to Animal model from existing (just created) FAL record?
You need to do several things. This issue on forge is where I got the info, and some stuff is taken out of Helmut Hummels frontend upload example (and the accompanying blogpost) which #derhansen already commented.
I'm not entirely sure if this is everything you need, so feel free to add things. This does not use a TypeConverter, which you should probably do. That would open further possibilities, for example it would be easily possible to implement deletion and replacement of file references.
You need to:
Create a FAL file reference object from the File object. This can be done using FALs resource factory.
Wrap it in a \TYPO3\CMS\Extbase\Domain\Model\FileReference (method ->setOriginalResource)
EDIT: This step is unnecessary as of TYPO3 6.2.11 and 7.2, you can directly use the class \TYPO3\CMS\Extbase\Domain\Model\FileReference.
But, because the extbase model misses a field ($uidLocal) in 6.2.10rc1, that won't work. You need to inherit from the extbase model, add that field, and fill it. Don't forget to add a mapping in TypoScript to map your own model to sys_file_reference.
config.tx_extbase.persistence.classes.Zoo\Zoo\Domain\Model\FileReference.mapping.tableName = sys_file_reference
The class would look like this (taken from the forge issue):
class FileReference extends \TYPO3\CMS\Extbase\Domain\Model\FileReference {
/**
* We need this property so that the Extbase persistence can properly persist the object
*
* #var integer
*/
protected $uidLocal;
/**
* #param \TYPO3\CMS\Core\Resource\ResourceInterface $originalResource
*/
public function setOriginalResource(\TYPO3\CMS\Core\Resource\ResourceInterface $originalResource) {
$this->originalResource = $originalResource;
$this->uidLocal = (int)$originalResource->getUid();
}
}
Add this to the TCA of the image field, in the config-section (adapt to your table and field names of course):
'foreign_match_fields' => array(
'fieldname' => 'photo',
'tablenames' => 'tx_zoo_domain_model_animal',
'table_local' => 'sys_file',
),
EDIT: Use \TYPO3\CMS\Extbase\Domain\Model\FileReference in this step if on TYPO3 6.2.11 or 7.2 or above.
So at the end add the created $fileRef instead of $fileObject
$fileRef = GeneralUtility::makeInstance('\Zoo\Zoo\Domain\Model\FileReference');
$fileRef->setOriginalResource($fileObject);
$animal->addPhoto($fileRef);
Don't tell anyone what you have done.
Here is the complete function to upload file in TYPO3 using FAL and create filereference
/**
* Function to upload file and create file reference
*
* #var array $fileData
* #var mixed $obj foreing model object
*
* #return void
*/
private function uploadAndCreateFileReference($fileData, $obj) {
$storageUid = 2;
$resourceFactory = \TYPO3\CMS\Core\Resource\ResourceFactory::getInstance();
//Adding file to storage
$storage = $resourceFactory->getStorageObject($storageUid);
if (!is_object($storage)) {
$storage = $resourceFactory->getDefaultStorage();
}
$file = $storage->addFile(
$fileData['tmp_name'],
$storage->getRootLevelFolder(),
$fileData['name']
);
//Creating file reference
$newId = uniqid('NEW_');
$data = [];
$data['sys_file_reference'][$newId] = [
'table_local' => 'sys_file',
'uid_local' => $file->getUid(),
'tablenames' => 'tx_imageupload_domain_model_upload', //foreign table name
'uid_foreign' => $obj->getUid(),
'fieldname' => 'image', //field name of foreign table
'pid' => $obj->getPid(),
];
$data['tx_imageupload_domain_model_upload'][$obj->getUid()] = [
'image' => $newId,
];
$dataHandler = \TYPO3\CMS\Core\Utility\GeneralUtility::makeInstance(
'TYPO3\CMS\Core\DataHandling\DataHandler'
);
$dataHandler->start($data, []);
}
where $filedata =
$this->request->getArgument('file_input_field_name');
And
$obj = //Object of your model for which you are creating file
reference
This example does not deserve a beauty prize but it might help you. It works in 7.6.x
private function uploadLogo(){
$file['name'] = $_FILES['logo']['name'];
$file['type'] = $_FILES['logo']['type'];
$file['tmp_name'] = $_FILES['logo']['tmp_name'];
$file['size'] = $_FILES['logo']['size'];
// Store the image
$resourceFactory = \TYPO3\CMS\Core\Resource\ResourceFactory::getInstance();
$storage = $resourceFactory->getDefaultStorage();
$saveFolder = $storage->getFolder('logo-companies/');
$newFile = $storage->addFile(
$file['tmp_name'],
$saveFolder,
$file['name']
);
// remove earlier refereces
$GLOBALS['TYPO3_DB']->exec_DELETEquery('sys_file_reference', 'uid_foreign = '. $this->getCurrentUserCompanyID());
$addressRecord = $this->getUserCompanyAddressRecord();
// Create new reference
$data = array(
'table_local' => 'sys_file',
'uid_local' => $newFile->getUid(),
'tablenames' => 'tt_address',
'uid_foreign' => $addressRecord['uid'],
'fieldname' => 'image',
'pid' => $addressRecord['pid']
);
$GLOBALS['TYPO3_DB']->exec_INSERTquery('sys_file_reference', $data);
$newId = $GLOBALS['TYPO3_DB']->sql_insert_id();
$where = "tt_address.uid = ".$addressRecord['uid'];
$GLOBALS['TYPO3_DB']->exec_UPDATEquery('tt_address', $where, array('image' => $newId ));
}
For Actionscript 2.0
Let's say this page
www.example.com/mypage
returns some html that I want to parse in Actionscript.
How do i call this page from Actionscript while getting back the response in a string variable?
use LoadVars():
var lv = new LoadVars();
//if you want to pass some variables, then:
lv.var1 = "BUTTON";
lv.var2 = "1";
lv.sendAndLoad("http://www.example.com/mypage.html", lv, "POST");
lv.onLoad = loadedDotNetVars;
function loadedDotNetVars(success)
{
if(success)
{
// operation was a success
trace(lv.varnameGotFromPage)
}
else
{
// operation failed
}
}
//if you dont want to send data, just get from it, then use just lv.Load(...) instead of sendAndLoad(...)
I understand. Use this code then:
docXML = new XML(msg);
XMLDrop = docXML.childNodes;
XMLSubDrop = XMLDrop[0].childNodes;
_root.rem_x = (parseInt(XMLSubDrop[0].firstChild));
_root.rem_y = (parseInt(XMLSubDrop[1].firstChild));
_root.rem_name = (XMLSubDrop[2].firstChild);
var htmlFetcher:LoadVars = new LoadVars();
htmlFetcher.onData = function(thedata) {
trace(thedata); //thedata is the html code
};
Use:
htmlFetcher.load("http://www.example.com/mypage");
to call.
I suppose you could use:
page = getURL("www.example.com/mypage.html");
And it would load the page contents on the page variable.