I am trying to convert from an int to a string but I am having trouble. I followed the execution through the debugger and the string 'myT' gets the value of 'sum' but the 'if' statement does not work correctly if the 'sum' is 10,11,12. Should I not be using a primitive int type to store the number? Also, both methods I tried (see commented-out code) fail to follow the true path of the 'if' statement. Thanks!
int x = [my1 intValue];
int y = [my2 intValue];
int sum = x+y;
//myT = [NSString stringWithFormat:#"%d", sum];
myT = [[NSNumber numberWithInt:sum] stringValue];
if(myT==#"10" || myT==#"11" || myT==#"12")
action = #"numGreaterThanNine";
If you just need an int to a string as you suggest, I've found the easiest way is to do as below:
[NSString stringWithFormat:#"%d",numberYouAreTryingToConvert]
You can use literals, it's more compact.
NSString* myString = [#(17) stringValue];
(Boxes as a NSNumber and uses its stringValue method)
The commented out version is the more correct way to do this.
If you use the == operator on strings, you're comparing the strings' addresses (where they're allocated in memory) rather than the values of the strings. This is very occasional useful (it indicates you have the exact same string object), but 99% of the time you want to compare the values, which you do like so:
if([myT isEqualToString:#"10"] || [myT isEqualToString:#"11"] || [myT isEqualToString:#"12"])
== shouldn't be used to compare objects in your if. For NSString use isEqualToString: to compare them.
int val1 = [textBox1.text integerValue];
int val2 = [textBox2.text integerValue];
int resultValue = val1 * val2;
textBox3.text = [NSString stringWithFormat: #"%d", resultValue];
Simply convert int to NSString
use :
int x=10;
NSString *strX=[NSString stringWithFormat:#"%d",x];
Dot grammar maybe more swift!
#(intValueDemo).stringValue
for example
int intValueDemo = 1;
//or
NSInteger intValueDemo = 1;
//So you can use dot grammar
NSLog(#"%#",#(intValueDemo).stringValue);
Related
That may sound odd.
I got an NSString value NSString * numb = [self.dataDict valueForKey:#"id"]; and i know, that is it some kind of integer (for example, i need that integer to comparison - if val less or equal then something). I need to know what integer is it.
What i've tried:
NSNumber *numba = [self.dataDict valueForKey:#"id"];
NSLog output - numba is 2038735264
And actually that was 428.
is there any way to achieve the point? Thanks!
That is piece of responseObject:
(
{
id = 3;
dog = "\U041a\U0430\U043a\U043e\U0439-\U0442\U043e \U043c\U0443\U0434\U0430\U043a \U043d\U0430\U043a\U0440\U0443\U0442\U0438\U043b";
image = "cute_dog/116.jpg";
score = 586;
},
{
id = 115;
dog = "\U0422\U0430\U043d\U044f \U041a\U043b\U044e\U043a\U0432\U0438\U043d\U0430";
image = "cute_dog/115.jpg";
score = 481;
},
There are a number of methods you can use to convert an NSString to a number. What numeric type would you like?
NSString *string = self.dataDict[#"id"];
int intValue = string.intValue;
NSInteger integerValue = string.integerValue;
long long longLongValue = string.longLongValue;
Trying something like this.
NSNumber *numba = [NSNumber numberWithInt[self.dataDict valueForKey:#"id"]];
//For string
NSString *stringValue = [numba stringValue];
//For integer
NSInteger integer = [numba integerValue];
Hi I have made an IOS app that converts binary, hexadecimal and decimal values. It all works fine except for my decimal to binary conversion. Here is what I have. It returns 0s and 1s but far too many. Can anyone tell me why this is or help me with a better method?
NSString *newDec = [display text]; //takes user input from display
NSString *string = #"";
NSUInteger x = newDec;
int i = 0;
while (x > 0) {
string = [[NSString stringWithFormat:#"%u", x&1] stringByAppendingString:string];
x = x>> 1;
++i;
}
display.text = string; //Displays result in ios text box
Try this:
NSUInteger x = [newDec integerValue];
And next time don't ignore the Compiler's "Incompatible pointer to Integer conversion" hint...
Explanation: Afaik, assigning an object to an int, actually assigns the address of the object to that integer, not the content of the string (which is what you want).
Please forgive the simplicity of the question. I'm completely new to Objective C.
I'd like to know how to concatenate integer and string values and print them to the console.
This is what I'd like for my output:
10 + 20 = 30
In Java I'd write this code to produce the needed results:
System.Out.Println(intVarWith10 + " + " + intVarWith20 + " = " + result);
Objective-C is quite different. How can we concatenate the 3 integers along with the strings in between?
You can use following code
int iFirst,iSecond;
iFirst=10;
iSecond=20;
NSLog(#"%#",[NSString stringWithFormat:#"%d + %d =%d",iFirst,iSecond,(iFirst+iSecond)]);
Take a look at NSString - it has a method stringWithFormat that does what you require. For example:
NSString* yString = [NSString stringWithFormat:#"%d + %d = %d",
intVarWith10, intVarWith20 , result];
You can use C style syntax, with NSLog (If you just need to print)
NSLog(#"%d+%d=%d",intvarWith10,intvarWith20,result);
If you want a string variable holding the value
NSString *str = [NSString stringWithFormat:#"%d+%d=%d",intvarWith10,intvarWith20,result];
You have to create an NSString with format and specify the data type.
Something like this :
NSInteger firstOperand=10;
NSInteger secondOperand=20;
NSInteger result=firstOperand+secondOperand;
NSString *operationString=[NSString stringWithFormat:#"%d + %d = %d",firstOperand,secondOperand,result];
NSLog(#"%#",operationString);
NSString with format follows the C printf syntax
Check below code :
int i = 8;
NSString * tempStr = [NSString stringWithFormat#"Hello %d",i];
NSLog(#"%#",tempStr);
I strongly recommend you this link Objective-C Reference.
The Objective-C int data type can store a positive or negative whole number. The actual size or range of integer that can be handled by the int data type is machine and compiler implementation dependent.
So you can store like this.
int a,b;
a= 10;
b= 10;
then performing operation you need to first understand NSString.
C style character strings are composed of single byte characters and therefore limited in the range of characters that can be stored.
int C = a + b;
NSString *strAnswer = [NSString stringWithFormat:#"Answer %d + %d = %d", a , b, c];
NSLog(#"%#",strAnswer)
Hope this will help you.
I have a NSString(e.g. 'P1')
I have to add 1 in this NSString to get 'P2'.
How will i do this??
Thanks for any help.
You can convert your NSString to an NSInteger like so:
NSInteger myInteger = [[myString substringWithRange:NSMakeRange(1, 1)] integerValue];
In your case if myString was your string P1, myInteger would be 1. So you could then do:
myInteger = myInteger + 1;
Which would then make myInteger 2. To then put that number back after P do:
myString = [NSString stringWithFormat:#"P%i", myInteger];
Now myString is P2.
Split it in to a prefix containing the P and a suffix containing the number. How you do this depends on the possible format of your string.
Then send intValue to the string.
Increment the number
Put it all back together with -stringWithFormat:
Is there a general purpose function in Objective-C that I can plug into my project to simplify concatenating NSStrings and ints?
[NSString stringWithFormat:#"THIS IS A STRING WITH AN INT: %d", myInt];
That's typically how I do it.
Both answers are correct. If you want to concatenate multiple strings and integers use NSMutableString's appendFormat.
NSMutableString* aString = [NSMutableString stringWithFormat:#"String with one int %d", myInt]; // does not need to be released. Needs to be retained if you need to keep use it after the current function.
[aString appendFormat:#"... now has another int: %d", myInt];
NSString *s =
[
[NSString alloc]
initWithFormat:#"Concatenate an int %d with a string %#",
12, #"My Concatenated String"
];
I know you're probably looking for a shorter answer, but this is what I would use.
string1,x , these are declared as a string object and integer variable respectively. and if you want to combine both the values and to append int values to a string object and to assign the result to a new string then do as follows.
NSString *string1=#"Hello";
int x=10;
NSString *string2=[string1 stringByAppendingFormat:#"%d ",x];
NSLog(#"string2 is %#",string2);
//NSLog(#"string2 is %#",string2); is used to check the string2 value at console ;
It seems the real answer is no - there is no easy and short way to concatenate NSStrings with Objective C - nothing similar to using the '+' operator in C# and Java.