Is there any way to take the difference between two datetime in sql server?
For example, my dates are
2010-01-22 15:29:55.090
2010-01-22 15:30:09.153
So, the result should be 14.063 seconds.
Just a caveat to add about DateDiff, it counts the number of times you pass the boundary you specify as your units, so is subject to problems if you are looking for a precise timespan.
e.g.
select datediff (m, '20100131', '20100201')
gives an answer of 1, because it crossed the boundary from January to February, so even though the span is 2 days, datediff would return a value of 1 - it crossed 1 date boundary.
select datediff(mi, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Gives a value of 1, again, it passed the minute boundary once, so even though it is approx 14 seconds, it would be returned as a single minute when using Minutes as the units.
SELECT DATEDIFF (MyUnits, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Substitute "MyUnits" based on DATEDIFF on MSDN
SELECT DATEDIFF(day, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
Replace day with other units you want to get the difference in, like second, minute etc.
I can mention four important functions of MS SQL Server that can be very useful:
1) The function DATEDIFF() is responsible to calculate differences between two dates, the result could be "year quarter month dayofyear day week hour minute second millisecond microsecond nanosecond", specified on the first parameter (datepart):
select datediff(day,'1997-10-07','2011-09-11')
2) You can use the function GETDATE() to get the actual time and calculate differences of some date and actual date:
select datediff(day,'1997-10-07', getdate() )
3) Another important function is DATEADD(), used to convert some value in datetime using the same datepart of the datediff, that you can add (with positive values) or substract (with negative values) to one base date:
select DATEADD(day, 45, getdate()) -- actual datetime adding 45 days
select DATEADD( s,-638, getdate()) -- actual datetime subtracting 10 minutes and 38 seconds
4) The function CONVERT() was made to format the date like you need, it is not parametric function, but you can use part of the result to format the result like you need:
select convert( char(8), getdate() , 8) -- part hh:mm:ss of actual datetime
select convert( varchar, getdate() , 112) -- yyyymmdd
select convert( char(10), getdate() , 20) -- yyyy-mm-dd limited by 10 characters
DATETIME cold be calculated in seconds and one interesting result mixing these four function is to show a formated difference um hours, minutes and seconds (hh:mm:ss) between two dates:
declare #date1 datetime, #date2 datetime
set #date1=DATEADD(s,-638,getdate())
set #date2=GETDATE()
select convert(char(8),dateadd(s,datediff(s,#date1,#date2),'1900-1-1'),8)
... the result is 00:10:38 (638s = 600s + 38s = 10 minutes and 38 seconds)
Another example:
select distinct convert(char(8),dateadd(s,datediff(s, CRDATE , GETDATE() ),'1900-1-1'),8) from sysobjects order by 1
I tried this way and it worked. I used SQL Server version 2016
SELECT DATEDIFF(MILLISECOND,'2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')/1000.00;
Different DATEDIFF Functions are:
SELECT DATEDIFF(year, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(quarter, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(month, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(dayofyear, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(day, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(week, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(hour, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(minute, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(second, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
SELECT DATEDIFF(millisecond, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');
Ref: https://learn.microsoft.com/en-us/sql/t-sql/functions/datediff-transact-sql?view=sql-server-2017
Ok we all know the answer involves DATEDIFF(). But that gives you only half the result you may be after. What if you want to get the results in human-readable format, in terms of Minutes and Seconds between two DATETIME values?
The CONVERT(), DATEADD() and of course DATEDIFF() functions are perfect for a more easily readable result that your clients can use, instead of a number.
i.e.
CONVERT(varchar(5), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
This will give you something like:
HH:MM
If you want more precision, just increase the VARCHAR().
CONVERT(varchar(12), DATEADD(minute, DATEDIFF(MINUTE, date1, date2), 0), 114)
HH:MM.SS.MS
There are a number of ways to look at a date difference, and more when comparing date/times. Here's what I use to get the difference between two dates formatted as "HH:MM:SS":
ElapsedTime AS
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
I used this for a calculated column, but you could trivially rewrite it as a UDF or query calculation. Note that this logic rounds down fractional seconds; 00:00.00 to 00:00.999 is considered zero seconds, and displayed as "00:00:00".
If you anticipate that periods may be more than a few days long, this code switches to D:HH:MM:SS format when needed:
ElapsedTime AS
CASE WHEN DATEDIFF(S, StartDate, EndDate) >= 359999
THEN
CAST(DATEDIFF(S, StartDate, EndDate) / 86400 AS VARCHAR(7)) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 86400 / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
ELSE
RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) / 3600 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 3600 / 60 AS VARCHAR(2)), 2) + ':'
+ RIGHT('0' + CAST(DATEDIFF(S, StartDate, EndDate) % 60 AS VARCHAR(2)), 2)
END
The following query should give the exact stuff you are looking out for.
select datediff(second, '2010-01-22 15:29:55.090' , '2010-01-22 15:30:09.153')
Here is the link from MSDN for what all you can do with datediff function .
https://msdn.microsoft.com/en-us/library/ms189794.aspx
Internally in SQL Server dates are stored as 2 integers. The first integer is the number of days before or after the base date (1900/01/01). The second integer stores the number of clock ticks after midnight, each tick is 1/300 of a second.
More info here
Because of this, I often find the simplest way to compare dates is to simply substract them. This handles 90% of my use cases. E.g.,
select date1, date2, date2 - date1 as DifferenceInDays
from MyTable
...
When I need an answer in units other than days, I will use DateDiff.
SELECT DATEDIFF(yyyy, '2011/08/25', '2017/08/25') AS DateDiff
It's gives you difference between two dates in Year
Here (2017-2011)=6 as a result
Syntax:
DATEDIFF(interval, date1, date2)
Use This for DD:MM:SS:
SELECT CONVERT(VARCHAR(max), Datediff(dd, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'))
+ ':'
+ CONVERT(CHAR(8), Dateadd(s, Datediff(s, '2019-08-14 03:16:51.360',
'2019-08-15 05:45:37.610'), '1900-1-1'), 8)
So this isn't my answer but I just found this while searching around online for a question like this as well. This guy set up a procedure to calculate hours, minutes and seconds. The link and the code:
--Creating Function
If OBJECT_ID('UFN_HourMinuteSecond') Is Not Null
Drop Function dbo.UFN_HourMinuteSecond
Go
Exec(
'Create Function dbo.UFN_HourMinuteSecond
(
#StartDateTime DateTime,
#EndDateTime DateTime
) Returns Varchar(10)
As
Begin
Declare #Seconds Int,
#Minute Int,
#Hour Int,
#Elapsed Varchar(10)
Select #Seconds = ABS(DateDiff(SECOND ,#StartDateTime,#EndDateTime))
If #Seconds >= 60
Begin
select #Minute = #Seconds/60
select #Seconds = #Seconds%60
If #Minute >= 60
begin
select #hour = #Minute/60
select #Minute = #Minute%60
end
Else
Goto Final
End
Final:
Select #Hour = Isnull(#Hour,0), #Minute = IsNull(#Minute,0), #Seconds = IsNull(#Seconds,0)
select #Elapsed = Cast(#Hour as Varchar) + '':'' + Cast(#Minute as Varchar) + '':'' + Cast(#Seconds as Varchar)
Return (#Elapsed)
End'
)
declare #dt1 datetime='2012/06/13 08:11:12', #dt2 datetime='2012/06/12 02:11:12'
select CAST((#dt2-#dt1) as time(0))
PRINT DATEDIFF(second,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153')
select
datediff(millisecond,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153') / 1000.0 as Secs
result:
Secs
14.063
Just thought I'd mention it.
Sol-1:
select
StartTime
, EndTime
, CONVERT(NVARCHAR,(EndTime-StartTime), 108) as TimeDiff
from
[YourTable]
Sol-2:
select
StartTime
, EndTime
, DATEDIFF(hh, StartTime, EndTime)
, DATEDIFF(mi, StartTime, EndTime) % 60
from
[YourTable]
Sol-3:
select
DATEPART(hour,[EndTime]-[StartTime])
, DATEPART(minute,[EndTime]-[StartTime])
from
[YourTable]
Datepart works the best
Please check below trick to find the date difference between two dates
DATEDIFF(DAY,ordr.DocDate,RDR1.U_ProgDate) datedifff
where you can change according your requirement as you want difference of days or month or year or time.
CREATE FUNCTION getDateDiffHours(#fdate AS datetime,#tdate as datetime)
RETURNS varchar (50)
AS
BEGIN
DECLARE #cnt int
DECLARE #cntDate datetime
DECLARE #dayDiff int
DECLARE #dayDiffWk int
DECLARE #hrsDiff decimal(18)
DECLARE #markerFDate datetime
DECLARE #markerTDate datetime
DECLARE #fTime int
DECLARE #tTime int
DECLARE #nfTime varchar(8)
DECLARE #ntTime varchar(8)
DECLARE #nfdate datetime
DECLARE #ntdate datetime
-------------------------------------
--DECLARE #fdate datetime
--DECLARE #tdate datetime
--SET #fdate = '2005-04-18 00:00:00.000'
--SET #tdate = '2005-08-26 15:06:07.030'
-------------------------------------
DECLARE #tempdate datetime
--setting weekends
SET #fdate = dbo.getVDate(#fdate)
SET #tdate = dbo.getVDate(#tdate)
--RETURN #fdate
SET #fTime = datepart(hh,#fdate)
SET #tTime = datepart(hh,#tdate)
--RETURN #fTime
if datediff(hour,#fdate, #tdate) <= 9
RETURN(convert(varchar(50),0) + ' Days ' + convert(varchar(50),datediff(hour,#fdate, #tdate))) + ' Hours'
else
--setting working hours
SET #nfTime = dbo.getV00(convert(varchar(2),datepart(hh,#fdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,#fdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,#fdate)))
SET #ntTime = dbo.getV00(convert(varchar(2),datepart(hh,#tdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,#tdate))) + ':'+ dbo.getV00(convert(varchar(2),datepart(ss,#tdate)))
IF #fTime > 17
begin
set #nfTime = '17:00:00'
end
else
begin
IF #fTime < 8
set #nfTime = '08:00:00'
end
IF #tTime > 17
begin
set #ntTime = '17:00:00'
end
else
begin
IF #tTime < 8
set #ntTime = '08:00:00'
end
-- used for working out whole days
SET #nfdate = dateadd(day,1,#fdate)
SET #ntdate = #tdate
SET #nfdate = convert(varchar,datepart(yyyy,#nfdate)) + '-' + convert(varchar,datepart(mm,#nfdate)) + '-' + convert(varchar,datepart(dd,#nfdate))
SET #ntdate = convert(varchar,datepart(yyyy,#ntdate)) + '-' + convert(varchar,datepart(mm,#ntdate)) + '-' + convert(varchar,datepart(dd,#ntdate))
SET #cnt = 0
SET #dayDiff = 0
SET #cntDate = #nfdate
SET #dayDiffWk = convert(decimal(18,2),#ntdate-#nfdate)
--select #nfdate,#ntdate
WHILE #cnt < #dayDiffWk
BEGIN
IF (NOT DATENAME(dw, #cntDate) = 'Saturday') AND (NOT DATENAME(dw, #cntDate) = 'Sunday')
BEGIN
SET #dayDiff = #dayDiff + 1
END
SET #cntDate = dateadd(day,1,#cntDate)
SET #cnt = #cnt + 1
END
--SET #dayDiff = convert(decimal(18,2),#ntdate-#nfdate) --datediff(day,#nfdate,#ntdate)
--SELECT #dayDiff
set #fdate = convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) + ' ' + #nfTime
set #tdate = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate)) + ' ' + #ntTime
set #markerFDate = convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) + ' ' + '17:00:00'
set #markerTDate = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate)) + ' ' + '08:00:00'
--select #fdate,#tdate
--select #markerFDate,#markerTDate
set #hrsDiff = convert(decimal(18,2),datediff(hh,#fdate,#markerFDate))
--select #hrsDiff
set #hrsDiff = #hrsDiff + convert(int,datediff(hh,#markerTDate,#tdate))
--select #fdate,#tdate
IF convert(varchar,datepart(yyyy,#fdate)) + '-' + convert(varchar,datepart(mm,#fdate)) + '-' + convert(varchar,datepart(dd,#fdate)) = convert(varchar,datepart(yyyy,#tdate)) + '-' + convert(varchar,datepart(mm,#tdate)) + '-' + convert(varchar,datepart(dd,#tdate))
BEGIN
--SET #hrsDiff = #hrsDiff - 9
Set #hrsdiff = datediff(hour,#fdate,#tdate)
END
--select FLOOR((#hrsDiff / 9))
IF (#hrsDiff / 9) > 0
BEGIN
SET #dayDiff = #dayDiff + FLOOR(#hrsDiff / 9)
SET #hrsDiff = #hrsDiff - FLOOR(#hrsDiff / 9)*9
END
--select convert(varchar(50),#dayDiff) + ' Days ' + convert(varchar(50),#hrsDiff) + ' Hours'
RETURN(convert(varchar(50),#dayDiff) + ' Days ' + convert(varchar(50),#hrsDiff)) + ' Hours'
END
For Me This worked Perfectly
Convert(varchar(8),DATEADD(SECOND,DATEDIFF(SECOND,LogInTime,LogOutTime),0),114)
and the Output is
HH:MM:SS which is shown accurately in my case.
Please try
DECLARE #articleDT DATETIME;
DECLARE #nowDate DATETIME;
-- Time of the ARTICLE created
SET #articleDT = '2012-04-01 08:10:16';
-- Simulation of NOW datetime
-- (in real world you would probably use GETDATE())
SET #nowDate = '2012-04-10 11:35:36';
-- Created 9 days ago.
SELECT 'Created ' + CAST(DATEDIFF(day, #articleDT, #nowDate) AS NVARCHAR(50)) + ' days ago.';
-- Created 1 weeks, 2 days, 3 hours, 25 minutes and 20 seconds ago.
SELECT 'Created '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 / 24 / 7 AS NVARCHAR(50)) + ' weeks, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 / 24 % 7 AS NVARCHAR(50)) + ' days, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 / 60 % 24 AS NVARCHAR(50)) + ' hours, '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) / 60 % 60 AS NVARCHAR(50)) + ' minutes and '
+ CAST(DATEDIFF(second, #articleDT, #nowDate) % 60 AS NVARCHAR(50)) + ' seconds ago.';
For MS SQL, you can convert the datetime value to a double value.
The integer part contains the number of days since 1900-01-01, the fractional part contains the time in hours.
So you can calculate date difference as:
cast(date1-date2 as FLOAT)
Related
My start and finish columns are in the format Yyyy-mm-dd HH:mm:ss.ms I want the difference between the two in HH:mm:ss.ms format. How do I go about this?
My query looks like this:
select *, convert(time,
Dateadd(s,
Datediff(s, A.Finish, A.Start),
Cast('1900-01-01 00:00:00.000000' as datetime2)
)
) as dif
from (
select *,
dateadd(s,convert(int,left(start,10)),'1970-01-01') as Start,
dateadd(s,convert(int,left(finish,10)),'1970-01-01') as Finish,
from tableB
) A
order by dif asc
I've converted unix time stamps to standard format in inner query. When I run this the start date and start time appear as '2019-12-11 15:45:20.000' and '2019-12-12 15:45:17.000' but my dif appears as '00:00:03',which is wrong.
Any help would be appreciated
I have used two sources to try to help you:
https://www.rodolforodarte.com/2011/05/using-datediff-to-display-hhmmss/
AND
Show datediff as seconds, milliseconds
Here is my result code:
DECLARE #START_DATE DATETIME
DECLARE #END_DATE DATETIME
SET #START_DATE = '2011-01-01 16:00:22.000'
SET #END_DATE = '2011-01-01 22:47:21.022'
SELECT CONVERT(varchar(6), DATEDIFF(MILLISECOND, #START_DATE, #END_DATE)/3600000)
+ ':'
+ RIGHT('0' + CONVERT(varchar(2), (DATEDIFF(MILLISECOND, #START_DATE, #END_DATE) % 3600000) / 60000), 2)
+ ':'
+ RIGHT('0' + CONVERT(varchar(2), ((DATEDIFF(MILLISECOND, #START_DATE, #END_DATE) % 3600000) % 60000) / 1000), 2)
+ ':'
+ RIGHT('000' + CONVERT(varchar(2), (((DATEDIFF(MILLISECOND, #START_DATE, #END_DATE) % 3600000) % 60000) % 1000)), 3) AS 'HH:MM:SS:MS'
And here is a small demo
I'm trying to calculate the difference between two datetime values.
I tried datediff(s, begin,end) and datediff(ms, begin,end) however I want the difference to be returned as seconds,milliseconds like the following:
4,14
63,54
SELECT
DATEDIFF(MILLISECOND, begin, end) / 1000,
DATEDIFF(MILLISECOND, begin, end) % 1000
FROM ...;
If you absolutely must form it as a string in your SQL query (can't your presentation tier do that?), then:
SELECT
CONVERT(VARCHAR(12), DATEDIFF(MILLISECOND, begin, end) / 1000)
+ ','
+ RIGHT('000' + CONVERT(VARCHAR(4), DATEDIFF(MILLISECOND, begin, end) % 1000), 3)
FROM ...;
Also I really hope you have better column names than begin and end.
Actually, the marked answer originally produced wrong results for milliseconds 1 - 99:
Example 1 second, 27 milliseconds:
DATEDIFF % 1000 will return 27
CONVERT will convert to '27'
String concatenation will build '1' + ',' + '27'
Result: '1.27' which means 270ms rather than 27ms
Don't forget to pad the milliseconds to three zeros:
DECLARE #start datetime2(7) = '2015-07-03 09:24:33.000'
DECLARE #end datetime2(7) = '2015-07-03 09:24:34.027'
SELECT
CAST (DATEDIFF(SECOND, #start, #end) AS nvarchar(3)) + N'.' +
RIGHT('000' + CAST((DATEDIFF(MILLISECOND, #start, #end) % 1000) AS nvarchar(3)), 3)
DATEDIFF takes only two arguments in MySQL. This works for me:
TIMESTAMPDIFF(SECOND, NOW(), '2019-09-09 18:52:00')
I am currently working an SQL script to calculate the difference between two dates which would give me the result in DD:HH:MI:SEC format.
Example:
Date 1: 7/30/12 4:00 PM
Date 2: 5/4/12 10:31 AM
And the result should be 87:05:29:00
Can you kindly help with the script for this?
Regards,
Arjun
If you are using sql-server then you can do this:
declare #x int,
#dt1 smalldatetime = '1996-03-25 03:24:16',
#dt2 smalldatetime = getdate()
set #x = datediff (s, #dt1, #dt2)
SELECT convert(varchar, #x / (60 * 60 * 24)) + ':'
+ convert(varchar, dateadd(s, #x, convert(datetime2, '0001-01-01')), 108)
Reference here
Well, you if want to perform some calculation, you could do this as well:
DECLARE #SecsInADay INT = 60 * 60 * 24
DECLARE #DATE1 DATETIME = CONVERT(DATETIME,'30/07/2012 16:00:00')
DECLARE #DATE2 DATETIME = CONVERT(DATETIME,'04/05/2012 10:31:00')
DECLARE #Days INT = DATEDIFF(DAY, #DATE2, #DATE1)
DECLARE #DiffInSeconds INT = DATEDIFF(SECOND, #DATE2, #DATE1)
DECLARE #TotalDaysInSeconds INT = #Days * #SecsInADay
DECLARE #RemainingHours INT = #DiffInSeconds - #TotalDaysInSeconds
DECLARE #Hours INT = #RemainingHours / 3600
DECLARE #Seconds INT = #RemainingHours % 3600
DECLARE #Minutes INT = #Seconds / 60
DECLARE #RemainingSeconds INT = #Seconds % 60
SELECT
CASE WHEN #Days < 10 THEN '0' + CAST(#Days AS VARCHAR) ELSE CAST(#Days AS VARCHAR) END + ':' +
CASE WHEN #Hours < 10 THEN '0' + CAST(#Hours AS VARCHAR) ELSE CAST(#Hours AS VARCHAR) END + ':' +
CASE WHEN #Minutes < 10 THEN '0' + CAST(#Minutes AS VARCHAR) ELSE CAST(#Minutes AS VARCHAR) END + ':' +
CASE WHEN #RemainingSeconds < 10 THEN '0' + CAST(#RemainingSeconds AS VARCHAR) ELSE CAST(#RemainingSeconds AS VARCHAR) END
Hi i had a similar problem, took some time to think and here's my solution, I've had the Table with user subscriptions, there sad starting time and closing time, my problem was a bit more complex bit basically it came down to this:
SELECT subscription_id, time_open, time_closed, TIMESTAMPDIFF(DAY,time_open,time_closed) AS Day,
HOUR(sec_to_time(TIMESTAMPDIFF(SECOND,ADDDATE(`time_open`, INTERVAL TIMESTAMPDIFF(DAY,time_open,time_closed) DAY),`time_closed`))) AS Hour,
MINUTE(sec_to_time(TIMESTAMPDIFF(SECOND,ADDDATE(`time_open`, INTERVAL TIMESTAMPDIFF(DAY,time_open,time_closed) DAY),`time_closed`))) AS Minute,
SECOND(sec_to_time(TIMESTAMPDIFF(SECOND,ADDDATE(`time_open`, INTERVAL TIMESTAMPDIFF(DAY,time_open,time_closed) DAY),`time_closed`))) AS Second
FROM `user_subscription`
So basically what this query does is that it calculates days by deducing dates in the first line. Then it adds the number of the full days to the starting time and reduces the closing time my the sum, so what remains is the time in the current day. After that you just select Hours, minutes, and seconds from that. If you want it all together you can concatenate the strings but this way you can use it further, unlike the strings.
I have been tasked with writting a report from MS Dynamic CRM. The report contains appointment and account information. I am using Visual Studio 2005 and SQL 2005.
The problem I have found is that if an appointment has a scheduled start date that falls after Britsh Summer Time but has a creation date before (BST) then the ScheduledStart field of the dbo.Appointment DB udates with the offset time + or - on hour. This means when I look for an appointment using reporting services and key in the time the appointment is due to start it returns no results because in the DB the time is either one hour earlier or later. I can manually amend the time for my search but this then returns the incorrect time on the report.
This will of course ony happen twice a year as appointments are only arranged a couple of weeks in advance but it is still a pain!
Is there a way using Transact SQL (or any method availbale to SSRS) I can allow for daylight saving times so even though the DB shows a Sceduled Start (dbo.Appointment.ScheduledStart) of say 11:00:00 the appointment is actually due to start at 10:00:00?
Alternately this case statement will work inside your existing query.
SELECT CASE
WHEN ([Created_Date] BETWEEN
Dateadd(yy, Datediff(yy, 0, [Scheduled_Date]), 0)
AND
Convert(DATETIME, Convert(VARCHAR(4), Year([Created_Date])) + '-03-' + Convert(VARCHAR(2), (31 - (5 * Year([Created_Date])/4 + 4) % 7)) + ' 01:00:00', 20))
AND
([ScheduledDate] BETWEEN
Convert(DATETIME, Convert(VARCHAR(4), Year([Created_Date])) + '-03-' + Convert(VARCHAR(2), (31 - (5 * Year([Created_Date])/4 + 4) % 7)) + ' 01:00:00', 20)
AND
Convert(DATETIME, Convert(VARCHAR(4), Year([Created_Date])) + '-10-' + Convert(VARCHAR(2), (31 - (5 * Year([Created_Date])/4 + 1) % 7)) + ' 00:00:00', 20))
THEN Dateadd(hh, 1, [Scheduled_Date])
ELSE [Scheduled_Date]
END AS [Scheduled_Date]
CREATE FUNCTION OffsetBST (#CreatedDateTime DATETIME,
#ScheduledDateTime DATETIME)
RETURNS DATETIME
AS
BEGIN
DECLARE #InDateYear VARCHAR(4)
DECLARE #StartDay VARCHAR(2)
DECLARE #EndDay VARCHAR(2)
DECLARE #BSTStart DATETIME
DECLARE #BSTEnd DATETIME
DECLARE #OffsetDateTime DATETIME
SET #StartDay = Convert(VARCHAR(2), (31 - (5 * Year(#CreatedDateTime)/4 + 4) % 7))
SET #EndDay = Convert(VARCHAR(2), (31 - (5 * Year(#CreatedDateTime)/4 + 1) % 7))
SET #InDateYear = Convert(VARCHAR(4), Year(#CreatedDateTime))
SET #BSTStart = Convert(DATETIME, #InDateYear + '-03-' + #StartDay + ' 01:00:00', 20)
SET #BSTEnd = Convert(DATETIME, #InDateYear + '-10-' + #EndDay + ' 00:00:00', 20)
IF (#CreatedDateTime BETWEEN DATEADD(yy, DATEDIFF(yy,0,#ScheduledDateTime), 0) AND #BSTStart)
AND (#ScheduledDateTime BETWEEN #BSTStart AND #BSTEnd)
SET #OffsetDateTime = Dateadd(hh, 1, #ScheduledDateTime)
ELSE
SET #OffsetDateTime = Dateadd(hh, 0, #ScheduledDateTime)
RETURN #OffsetDateTime
END
You can use this in your data source select statement. You will provide it with the created date and scheduled date and it will determine if the scheduled date requires a BST offset.
Like so:
SELECT A.Appointment_ID, A.Appointment_Name, dbo.OffsetBST(A.Created_Date,
A.Scheduled_Date) as Scheduled_Date
FROM AppointmentsTable as A
Given two date/times:
#start_date = '2009-04-15 10:24:00.000'
#end_date = '2009-04-16 19:43:01.000'
Is it possible to calculate the time elapsed between the two dates in the following format
1d 9h 19m
You can get the difference between the two dates to whatever resolution you want (in your example, minutes):
DATEDIFF(minute, #start_date, #end_date)
From there it's a simple matter of dividing minutes into hours and hours into days and modding the remainder.
I know this thread is older and the original participants are likely no longer watching, but I stumbled upon it, and had already written some code fairly recently to do something very close to what jdiaz is requesting. The result is rendered as a string in D:H:M:S format.
Step one would be to get the time span in seconds:
DECLARE #ElapsedS INT
SET #ElapsedS = DATEDIFF(second, #start_date, #end_date)
Now create the following scalar function:
CREATE FUNCTION [dbo].[udfTimeSpanFromSeconds]
(
#Seconds int
)
RETURNS varchar(15)
AS
BEGIN
DECLARE
--Variable to hold our result
#DHMS varchar(15)
--Integers for doing the math
, #Days int --Integer days
, #Hours int --Integer hours
, #Minutes int --Integer minutes
--Strings for providing the display
, #sDays varchar(5) --String days
, #sHours varchar(2) --String hours
, #sMinutes varchar(2) --String minutes
, #sSeconds varchar(2) --String seconds
--Get the values using modulos where appropriate
SET #Hours = #Seconds/3600
SET #Minutes = (#Seconds % 3600) /60
SET #Seconds = (#Seconds % 3600) % 60
--If we have 24 or more hours, split the #Hours value into days and hours
IF #Hours > 23
BEGIN
SET #Days = #Hours/24
SET #Hours = (#Hours % 24)
END
ELSE
BEGIN
SET #Days = 0
END
--Now render the whole thing as string values for display
SET #sDays = convert(varchar, #Days)
SET #sHours = RIGHT('0' + convert(varchar, #Hours), 2)
SET #sMinutes = RIGHT('0' + convert(varchar, #Minutes), 2)
SET #sSeconds = RIGHT('0' + convert(varchar, #Seconds), 2)
--Concatenate, concatenate, concatenate
SET #DHMS = #sDays + ':' + #sHours + ':' + #sMinutes + ':' + #sSeconds
RETURN #DHMS
END
Now feed your timespan into the newly created function:
SELECT TimeSpan = dbo.udfTimeSpanFromSeconds(#ElapsedS)
Should produce '1:09:19:01'
CONVERT(
varchar(8),
(
CAST(#end_date AS DATETIME)
-
CAST(#start_date AS DATETIME)
)
,108
)
This'll give it to you as HH:MM:SS
Cheers
DATEDIFF can return unintuitive values. For example, the two dates below differ by one second yet DATEDIFF with the parameters below and interpreted as others have interpreted it above returns 1 year:
SELECT DATEDIFF(year, '2005-12-31 23:59:59', '2006-01-01 00:00:00')
Look at the MSDN documentation for DATEDIFF to understand how it works.
datediff(datepart, date1, date2);
Rex's answer is more complete.
Here's how you format the datediff (50d 8h 35m) in a query:
Declare #Date1 as Datetime, #Date2 as Datetime
Set #Date1 = '2005-01-01 08:00:00'
Set #Date2 = '2005-02-20 16:35:30'
Select
CAST(DATEDIFF(Minute,#Date1, #Date2)/60/24 as Varchar(50)) ++ 'd ' ++
CAST((DATEDIFF(Minute,#Date1, #Date2)/60)-((DATEDIFF(Minute,#Date1, #Date2)/60/24)*24) as Varchar(50)) ++ 'h ' ++
CAST((DATEDIFF(Minute,#Date1, #Date2)) - (DATEDIFF(HOUR,#Date1, #Date2)*60) as Varchar(50)) ++ 'm' as FormattedDateDiff
DECLARE #FirstDate DATETIME, #SecondDate DATETIME, #result VARCHAR(MAX)
SELECT #FirstDate = '2017-03-01 09:54:00.637', #SecondDate = GETDATE()
DECLARE #Day INT,#Month INT,#Hour INT, #Minute INT,#TotalSeconds INT,#Year INT
SELECT #TotalSeconds = ABS(DATEDIFF(SECOND,#FirstDate,#SecondDate))
-- Standard values in seconds
DECLARE #YearSeconds INT, #MonthSeconds INT, #DaySeconds INT, #HourSeconds INT, #MinuteSeconds INT
SELECT #MinuteSeconds = 60
SELECT #HourSeconds = 60 * #MinuteSeconds
SELECT #DaySeconds = 24 * #HourSeconds
SELECT #MonthSeconds = 30 * #DaySeconds
SELECT #YearSeconds = 12 * #MonthSeconds
--SELECT #MinuteSeconds AS [Minutes], #HourSeconds AS [Hours], #DaySeconds AS [Day],#MonthSeconds AS [Month],#YearSeconds AS [Year]
IF #TotalSeconds < #MinuteSeconds
BEGIN
SELECT #result = CAST(#TotalSeconds AS NVARCHAR(20)) + ' seconds ago'
END
ELSE IF #TotalSeconds < #HourSeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(MINUTE,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' minutes ago'
END
ELSE IF #TotalSeconds < #DaySeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(HOUR,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' hours ago'
END
ELSE IF #TotalSeconds < #MonthSeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(DAY,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' days ago'
END
ELSE IF #TotalSeconds < #YearSeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(MONTH,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' months ago'
END
ELSE IF #TotalSeconds > #YearSeconds
BEGIN
SELECT #result = CAST(ABS(DATEDIFF(YEAR,#FirstDate,#SecondDate)) AS NVARCHAR(20)) + ' year ago'
END
SELECT #result