I need to get the last day of the month given as a date in SQL. If I have the first day of the month, I can do something like this:
DATEADD(DAY, DATEADD(MONTH,'2009-05-01',1), -1)
But does anyone know how to generalize it so I can find the last day of the month for any given date?
From SQL Server 2012 you can use the EOMONTH function.
Returns the last day of the month that contains the specified date,
with an optional offset.
Syntax
EOMONTH ( start_date [, month_to_add ] )
How ... I can find the last day of the month for any given date?
SELECT EOMONTH(#SomeGivenDate)
Here's my version. No string manipulation or casting required, just one call each to the DATEADD, YEAR and MONTH functions:
DECLARE #test DATETIME
SET #test = GETDATE() -- or any other date
SELECT DATEADD(month, ((YEAR(#test) - 1900) * 12) + MONTH(#test), -1)
You could get the days in the date by using the DAY() function:
dateadd(day, -1, dateadd(month, 1, dateadd(day, 1 - day(date), date)))
Works in SQL server
Declare #GivenDate datetime
SET #GivenDate = GETDATE()
Select DATEADD(MM,DATEDIFF(MM, 0, #GivenDate),0) --First day of the month
Select DATEADD(MM,DATEDIFF(MM, -1, #GivenDate),-1) --Last day of the month
I know this is a old question but here is another solution that works for me
SET #dtDate = "your date"
DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,#dtDate)+1,0))
And if some one is looking for different examples here is a link http://blog.sqlauthority.com/2007/08/18/sql-server-find-last-day-of-any-month-current-previous-next/
I hope this helps some one else.
stackoverflow Rocks!!!!
For SQL server 2012 or above use EOMONTH to get the last date of month
SQL query to display end date of current month
DECLARE #currentDate DATE = GETDATE()
SELECT EOMONTH (#currentDate) AS CurrentMonthED
SQL query to display end date of Next month
DECLARE #currentDate DATE = GETDATE()
SELECT EOMONTH (#currentDate, 1 ) AS NextMonthED
Based on the statements:
SELECT DATEADD(MONTH, 1, #x) -- Add a month to the supplied date #x
and
SELECT DATEADD(DAY, 0 - DAY(#x), #x) -- Get last day of month previous to the supplied date #x
how about adding a month to date #x and then retrieving the last day of the month previous to that (i.e. The last day of the month of the supplied date)
DECLARE #x DATE = '20-Feb-2012'
SELECT DAY(DATEADD(DAY, 0 - DAY(DATEADD(MONTH, 1, #x)), DATEADD(MONTH, 1, #x)))
Note: This was test using SQL Server 2008 R2
Just extend your formula out a little bit:
dateadd(day, -1,
dateadd(month, 1,
cast(month('5/15/2009') as varchar(2)) +
'/1/' +
cast(year('5/15/2009') as varchar(4)))
This works for me, using Microsoft SQL Server 2005:
DATEADD(d,-1,DATEADD(mm, DATEDIFF(m,0,'2009-05-01')+1,0))
WinSQL to get last day of last month (i.e today is 2017-02-09, returns 2017-01-31:
Select dateadd(day,-day(today()),today())
Try to run the following query, it will give you everything you want :)
Declare #a date =dateadd(mm, Datediff(mm,0,getdate()),0)
Print('First day of Current Month:')
Print(#a)
Print('')
set #a = dateadd(mm, Datediff(mm,0,getdate())+1,-1)
Print('Last day of Current Month:')
Print(#a)
Print('')
Print('First day of Last Month:')
set #a = dateadd(mm, Datediff(mm,0,getdate())-1,0)
Print(#a)
Print('')
Print('Last day of Last Month:')
set #a = dateadd(mm, Datediff(mm,0,getdate()),-1)
Print(#a)
Print('')
Print('First day of Current Week:')
set #a = dateadd(ww, Datediff(ww,0,getdate()),0)
Print(#a)
Print('')
Print('Last day of Current Week:')
set #a = dateadd(ww, Datediff(ww,0,getdate())+1,-1)
Print(#a)
Print('')
Print('First day of Last Week:')
set #a = dateadd(ww, Datediff(ww,0,getdate())-1,0)
Print(#a)
Print('')
Print('Last day of Last Week:')
set #a = dateadd(ww, Datediff(ww,0,getdate()),-1)
Print(#a)
WinSQL: I wanted to return all records for last month:
where DATE01 between dateadd(month,-1,dateadd(day,1,dateadd(day,-day(today()),today()))) and dateadd(day,-day(today()),today())
This does the same thing:
where month(DATE01) = month(dateadd(month,-1,today())) and year(DATE01) = year(dateadd(month,-1,today()))
This query can also be used.
DECLARE #SelectedDate DATE = GETDATE()
SELECT DATEADD(DAY, - DAY(#SelectedDate), DATEADD(MONTH, 1 , #SelectedDate)) EndOfMonth
--## Useful Date Functions
SELECT
GETDATE() AS [DateTime],
CAST(GETDATE() AS DATE) AS [Date],
DAY(GETDATE()) AS [Day of Month],
FORMAT(GETDATE(),'MMMM') AS [Month Name],
FORMAT(GETDATE(),'MMM') AS [Month Short Name],
FORMAT(GETDATE(),'MM') AS [Month No],
YEAR(GETDATE()) AS [Year],
CAST(DATEADD(DD,-(DAY(GETDATE())-1),GETDATE()) AS DATE) AS [Month Start Date],
EOMONTH(GETDATE()) AS [Month End Date],
CAST(DATEADD(M,-1,DATEADD(MM, DATEDIFF(M,0,GETDATE()),0)) AS DATE) AS [Previous Month Start Date],
CAST(DATEADD(S,-1,DATEADD(MM, DATEDIFF(M,0,GETDATE()),0)) AS DATE) AS [Previous Month End Date],
CAST(DATEADD(M,+1,DATEADD(MM, DATEDIFF(M,0,GETDATE()),0)) AS DATE) AS [Next Month Start Date],
CAST(DATEADD(D,-1,DATEADD(MM, DATEDIFF(M,0,GETDATE())+2,0)) AS DATE) AS [Next Month End Date],
CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE()),0) AS DATE) AS [First Day of Current Week],
CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE())+1,-1) AS DATE) AS [Last Day of Current Week],
CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE())-1,0) AS DATE) AS [First Day of Last Week],
CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE()),-1) AS DATE) AS [Last Day of Last Week],
CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE())+1,0) AS DATE) AS [First Day of Next Week],
CAST(DATEADD(WW, DATEDIFF(WW,0,GETDATE())+2,-1) AS DATE) AS [Last Day of Next Week]
My 2 cents:
select DATEADD(DAY,-1,DATEADD(MONTH,1,DATEADD(day,(0-(DATEPART(dd,'2008-02-12')-1)),'2008-02-12')))
Raj
using sql server 2005, this works for me:
select dateadd(dd,-1,dateadd(mm,datediff(mm,0,YOUR_DATE)+1,0))
Basically, you get the number of months from the beginning of (SQL Server) time for YOUR_DATE. Then add one to it to get the sequence number of the next month. Then you add this number of months to 0 to get a date that is the first day of the next month. From this you then subtract a day to get to the last day of YOUR_DATE.
Take some base date which is the 31st of some month e.g. '20011231'. Then use the
following procedure (I have given 3 identical examples below, only the #dt value differs).
declare #dt datetime;
set #dt = '20140312'
SELECT DATEADD(month, DATEDIFF(month, '20011231', #dt), '20011231');
set #dt = '20140208'
SELECT DATEADD(month, DATEDIFF(month, '20011231', #dt), '20011231');
set #dt = '20140405'
SELECT DATEADD(month, DATEDIFF(month, '20011231', #dt), '20011231');
Using SQL Server, here is another way to find last day of month :
SELECT DATEADD(MONTH,1,GETDATE())- day(DATEADD(MONTH,1,GETDATE()))
I wrote following function, it works.
It returns datetime data type. Zero hour, minute, second, miliseconds.
CREATE Function [dbo].[fn_GetLastDate]
(
#date datetime
)
returns datetime
as
begin
declare #result datetime
select #result = CHOOSE(month(#date),
DATEADD(DAY, 31 -day(#date), #date),
IIF(YEAR(#date) % 4 = 0, DATEADD(DAY, 29 -day(#date), #date), DATEADD(DAY, 28 -day(#date), #date)),
DATEADD(DAY, 31 -day(#date), #date) ,
DATEADD(DAY, 30 -day(#date), #date),
DATEADD(DAY, 31 -day(#date), #date),
DATEADD(DAY, 30 -day(#date), #date),
DATEADD(DAY, 31 -day(#date), #date),
DATEADD(DAY, 31 -day(#date), #date),
DATEADD(DAY, 30 -day(#date), #date),
DATEADD(DAY, 31 -day(#date), #date),
DATEADD(DAY, 30 -day(#date), #date),
DATEADD(DAY, 31 -day(#date), #date))
return convert(date, #result)
end
It's very easy to use.
2 example:
select [dbo].[fn_GetLastDate]('2016-02-03 12:34:12')
select [dbo].[fn_GetLastDate](GETDATE())
Based on the most voted answer at below link I came up with the following solution:
declare #mydate date= '2020-11-09';
SELECT DATEADD(month, DATEDIFF(month, 0, #mydate)+1, -1) AS lastOfMonth
link: How can I select the first day of a month in SQL?
I couldn't find an answer that worked in regular SQL, so I brute forced an answer:
SELECT *
FROM orders o
WHERE (MONTH(o.OrderDate) IN ('01','03','05','07','08','10','12') AND DAY(o.OrderDate) = '31')
OR (MONTH(o.OrderDate) IN ('04','06','09','11') AND DAY(o.OrderDate) = '30')
OR (MONTH(o.OrderDate) IN ('02') AND DAY(o.OrderDate) = '28')
---Start/End of previous Month
Declare #StartDate datetime, #EndDate datetime
set #StartDate = DATEADD(month, DATEDIFF(month, 0, GETDATE())-1,0)
set #EndDate = EOMONTH (DATEADD(month, DATEDIFF(month, 0, GETDATE())-1,0))
SELECT #StartDate,#EndDate
Related
Number of days left in a given month
How do I find the number of days left in the current month?
Example if current month is November and todays date is 16/11/2016
The Numbers of days in month – Elapse days = ? I want to do it dynamically
In my example 30 – 16 = 14
declare #date date
set #date='16 Nov 2016'
select datediff(day, #date, dateadd(month, 1, #date)) - 16 AS DaysLeft
Since this is sql server 2008 you can't use EOMonth (that was introduced in 2012 version).
You have to do some date adds and date diffs:
SELECT DATEDIFF(DAY,
GETDATE(),
DATEADD(MONTH,
1,
DATEADD(DAY, 1 - DAY(GETDATE()), GETDATE())
)
) - 1
explanations:
DATEADD(DAY, 1 - DAY(GETDATE()), GETDATE()) gets the first day of the current month, the wrapping DATEADD adds one month, and the wrapping DATEDIFF returns the number of days between the current date and the first date of the next month. This is why you need to subtruct 1 to get the correct number of days.
--For SQL 2012 And Above Version Use Below Query to Get Count Of Days Left In A Month
DECLARE #date DATE
SET #date=GETDATE()
SELECT DATEDIFF(DAY, #date,EOMONTH(#date))
-- And for Sql Server 2008 Use Below Query to Get Count of Days Left for the Month
DECLARE #date Date
SET #date=GETDATE()
SELECT DATEDIFF(DAY, #date, DATEADD(MONTH, 1, #date)) - DATENAME(DAY,GETDATE())
AS DaysLeft
Simply use the Datepart function:
declare #date date
set #date='16 Nov 2016'
select datediff(day, #date, dateadd(month, 1, #date)) - Datepart(DAY,#date)
Change your date to getdate()
declare #date date
set #date=GETDATE()
select datediff(day, #date, dateadd(month, 1, #date)) - DATENAME(DAY,GETDATE())
AS DaysLeft
DECLARE #date DATE SET #date='16 Nov 2016' SELECT DATEDIFF(DAY, #date,EOMONTH(#date))
Use EOMONTH and DATEDIFF functions
declare #date date
set #date='16 Nov 2016'
select datediff(day,#date,eomonth(#date)) as days_left
Use below solution For Below versions of sql server 2012
DECLARE #DATE DATE
SET #DATE='16 NOV 2016'
SELECT DATEDIFF(DAY,#DATE,DATEADD( MM,DATEDIFF(MM,0,#DATE)+1,0))-1 AS DAYS_LEFT
FUNCTION example
CREATE Or ALTER FUNCTION ReturnDaysLeftInMonth(#Date Date)
RETURNS Int
AS
BEGIN
RETURN DATEDIFF(DAY, #Date, EOMONTH(#Date)) + 1
END
Or use
Declare #Date Date
Set #Date=GETDATE()
DATEDIFF(DAY, #Date, EOMONTH(#Date)) + 1
How do I get yesterdays date and if the current date is Monday I would need Sunday, Saturday and Friday. This is already asked here for ms access. I now need this for SQL server. How would I go about this?
Will create an inline view that will return the previous date in SQL It will return between 1 and 3 rows depending on the current date.
If current date is Monday Return:
Sundays date
Saturdays date
Fridays date
If current date is Tuesday then Return: Mondays date
If current date is Wednesday then Return: Tuesdays date
If current date is Thursday then Return: Wednesdays date
If current date is Friday then Return: Thursdays date
If current date is Saturday then Return: Fridays date
If current date is Sunday then Return: Saturdays date
I hope this helps explain what I am trying to do more clearly.
sample select query
--get previous date
select * from [Purchase Orders] where MyDate in (previous date(s))
Not entirely clear about the question though. But you can do something on the similar lines.
Using DATEPART and DATEADD
DECLARE #TodaysDate DATETIME
SET #TodaysDate = '2013-04-10'
SELECT CASE
WHEN DATEPART (DW, DATEADD (DD, -1, #TodaysDate )) IN (1, 6, 7)
THEN 'WeekEnd' ELSE 'WeekDay'
END D
Using the query you linked to, you can try the code below:
SELECT *
FROM [Purchase Order]
WHERE MyDate >= CASE
WHEN DATENAME(dw, CONVERT(CHAR(8), GETDATE() , 112)) LIKE 'Monday' THEN CONVERT(CHAR(8), DATEADD(dd, -3, GETDATE()), 112)
ELSE CONVERT(CHAR(8), DATEADD(dd, -1, GETDATE()), 112)
END
AND MyDate < CONVERT(CHAR(8),GETDATE(),112)
You can use the following table function:
CREATE FUNCTION dbo.ufnPreviousDay (#suppliedDate DATE)
RETURNS #PreviousDates TABLE (PreviousDate DATE)
AS
BEGIN
INSERT INTO #PreviousDates (
PreviousDate)
SELECT
PreviousDate = DATEADD(DAY, -1, #suppliedDate)
IF DATEPART(WEEKDAY, DATEADD(DAY, ##DATEFIRST - 1, #suppliedDate)) = 1 -- If Monday
BEGIN
INSERT INTO #PreviousDates (
PreviousDate)
SELECT
PreviousDate = DATEADD(DAY, -2, #suppliedDate)
UNION ALL
SELECT
PreviousDate = DATEADD(DAY, -3, #suppliedDate)
END
RETURN
END
You can use it like this:
SELECT
T.*
FROM
dbo.ufnPreviousDay('2018-03-19') AS T
/*
Result:
2018-03-18
2018-03-17
2018-03-16
*/
If you want today's previous dates:
SELECT
T.*
FROM
YourTable AS T
INNER JOIN dbo.ufnPreviousDay(GETDATE()) AS M ON T.MyDate = M.PreviousDate
Is there is a way to group dates by week of month in SQL Server?
For example
Week 2: 05/07/2012 - 05/13/2012
Week 3: 05/14/2012 - 05/20/2012
but with Sql server statement
I tried
SELECT SOMETHING,
datediff(wk, convert(varchar(6), getdate(), 112) + '01', getdate()) + 1 AS TIME_
FROM STATISTICS_
GROUP BY something, TIME_
ORDER BY TIME_
but it returns the week number of month. (means 3)
How to get the pair of days for current week ?
For example, now we are in third (3rd) week and I want to show 05/14/2012 - 05/20/2012
I solved somehow:
SELECT DATEADD(ww, DATEDIFF(ww,0,<my_column_name>), 0)
select DATEADD(ww, DATEDIFF(ww,0,<my_column_name>), 0)+6
Then I will get two days and I will concatenate them later.
All right, bear with me here. We're going to build a temporary calendar table that represents this month, including the days from before and after the month that fall into your definition of a week (Monday - Sunday). I do this in a lot of steps to try to make the process clear, but I probably haven't excelled at that in this case.
We can then generate the ranges for the different weeks, and you can join against your other tables using that.
SET DATEFIRST 7;
SET NOCOUNT ON;
DECLARE #today SMALLDATETIME, #fd SMALLDATETIME, #rc INT;
SELECT #today = DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()), 0), -- today
#fd = DATEADD(DAY, 1-DAY(#today), #today), -- first day of this month
#rc = DATEPART(DAY, DATEADD(DAY, -1, DATEADD(MONTH, 1, #fd)));-- days in month
DECLARE #thismonth TABLE (
[date] SMALLDATETIME,
[weekday] TINYINT,
[weeknumber] TINYINT
);
;WITH n(d) AS (
SELECT TOP (#rc+12) DATEADD(DAY, ROW_NUMBER() OVER
(ORDER BY [object_id]) - 7, #fd) FROM sys.all_objects
)
INSERT #thismonth([date], [weekday]) SELECT d, DATEPART(WEEKDAY, d) FROM n;
DELETE #thismonth WHERE [date] < (SELECT MIN([date]) FROM #thismonth WHERE [weekday] = 2)
OR [date] > (SELECT MAX([date]) FROM #thismonth WHERE [weekday] = 1);
;WITH x AS ( SELECT [date], weeknumber, rn = ((ROW_NUMBER() OVER
(ORDER BY [date])-1) / 7) + 1 FROM #thismonth ) UPDATE x SET weeknumber = rn;
-- now, the final query given all that (I've only broken this up to get rid of the vertical scrollbars):
;WITH ranges(w,s,e) AS (
SELECT weeknumber, MIN([date]), MAX([date]) FROM #thismonth GROUP BY weeknumber
)
SELECT [week] = CONVERT(CHAR(10), r.s, 120) + ' - ' + CONVERT(CHAR(10), r.e, 120)
--, SOMETHING , other columns from STATISTICS_?
FROM ranges AS r
-- LEFT OUTER JOIN dbo.STATISTICS_ AS s
-- ON s.TIME_ >= r.s AND s.TIME_ < DATEADD(DAY, 1, r.e)
-- comment this out if you want all the weeks from this month:
WHERE w = (SELECT weeknumber FROM #thismonth WHERE [date] = #today)
GROUP BY r.s, r.e --, SOMETHING
ORDER BY [week];
Results with WHERE clause:
week
-----------------------
2012-05-14 - 2012-05-20
Results without WHERE clause:
week
-----------------------
2012-04-30 - 2012-05-06
2012-05-07 - 2012-05-13
2012-05-14 - 2012-05-20
2012-05-21 - 2012-05-27
2012-05-28 - 2012-06-03
Note that I chose YYYY-MM-DD on purpose. You should avoid regional formatting like M/D/Y especially for input but also for display. No matter how targeted you think your audience is, you're always going to have someone who thinks 05/07/2012 is July 5th, not May 7th. With YYYY-MM-DD there is no ambiguity whatsoever.
Create a calendar table, then you can query week numbers, first/last days of specific weeks and months etc. You can also join on it queries to get a date range etc.
How about a case statement?
case when datepart(day, mydatetime) between 1 and 7 then 1
when datepart(day, mydatetime) between 8 and 14 then 2
...
You'll also have to include the year & month unless you want all the week 1s in the same group.
It's not clear of you want to "group dates by week of month", or alternately "select data from a given week"
If you mean "group" this little snippet should get you 'week of month':
SELECT <stuff>
FROM CP_STATISTICS
WHERE Month(<YOUR DATE COL>) = 5 --april
GROUP BY Year(<YOUR DATE COL>),
Month(<YOUR DATE COL>),
DATEDIFF(week, DATEADD(MONTH, DATEDIFF(MONTH, 0, <YOUR DATE COL>), 0)
, <YOUR DATE COL>) +1
Alternately, if you want "sales for week 1 of April, ordered by date" You could do something like..
DECLARE #targetDate datetime2 = '5/3/2012'
DECLARE #targetWeek int = DATEDIFF(week, DATEADD(MONTH,
DATEDIFF(MONTH, 0, #targetDate), 0), #targetDate) +1
SELECT <stuff>
FROM CP_STATISTICS
WHERE MONTH(#targetDate) = Month(myDateCol) AND
YEAR(#targetDate) = Year (myDateCol) AND
#targetWeek = DATEDIFF(week, DATEADD(MONTH,
DATEDIFF(MONTH, 0, myDateCol), 0), myDateCol) +1
ORDER BY myDateCol
Note, things would get more complicated if you use non-standard weeks, or want to reach a few days into an earlier month for weeks that straddle a month boundary.
EDIT 2
From looking at your 'solved now' section. I think your question is "how do I get data out of a table for a given week?"
Your solution appears to be:
DECLARE #targetDate datetime2 = '5/1/2012'
DECLARE #startDate datetime2 = DATEADD(ww, DATEDIFF(ww,0,targetDate), 0)
DECLARE #endDate datetime2 = DATEADD(ww, DATEDIFF(ww,0,#now), 0)+6
SELECT <stuff>
FROM STATISTICS_
WHERE dateStamp >= #startDate AND dateStamp <= #endDate
Notice how if the date is 5/1 this solution results in a start date of '4/30/2012'. I point this out because your solution crosses month boundaries. This may or may not be desirable.
I may be using the wrong term (hence why I can't find it on google).
"Are there any functions or common code for Accounting Months Deliminations?"
For Example, this month started on a friday but on most accounting journals the weeks are measured by the first monday of the month so instead of having the 1st of July it would be the 4th of July. Same thing with the month end (29th instead of the 31st)
Again, I'm sure someone has created this 'wheel' before, and I can't seem to find it for the life of me.
The following query assumes a table, SalesTable, has a field called Amount (the value you want to sum) and a field called SaleDate (the date on which the sale occured.) It also assumes that accounting months begin the first Monday of the month and end on the Sunday prior to the beginning of the next accounting month.
Again, I highly recommend a table-based approach to this, but if you can't modify the schema, this should do the trick in T-SQL:
SELECT
CASE WHEN s.SaleDate < DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
THEN DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, DATEADD(day,-7,s.SaleDate) ),DATEADD(day,-7,s.SaleDate) )), 0)
ELSE DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
END AccountingMonth,
SUM(s.Amount) TotalSales
FROM SalesTable s
GROUP BY
CASE WHEN s.SaleDate < DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
THEN DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, DATEADD(day,-7,s.SaleDate) ),DATEADD(day,-7,s.SaleDate) )), 0)
ELSE DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
END
Note that the AccountingMonth return field actually contains the date of the first Monday of the month. In actual practice, you probably want to wrap this entire query in another query that reformats AccountingMonth to whatever you like... "2011-07", "2011-08", etc.
Here's how it works: This bit of code is the important part:
DATEADD(WEEK, DATEDIFF(WEEK, 0, DATEADD(DAY, 6 - DATEPART(DAY, s.SaleDate ),s.SaleDate )), 0)
It takes any date and returns the first Monday of the month in which that date occurred. In your case, however, you have to do a little more work because a sale might have occurred in the window between the first of the month and the first Monday of the month. The CASE statement detects that scenario and, if it's true, subtracts a week off of the date before calculating the first Monday.
Good luck!
-Michael
I have some code that takes in a year and month and returns the fiscal start and end dates. Perhaps this will give you something to go by:
DECLARE #yr int;
DECLARE #mo int;
SELECT #yr = 2011
SELECT #mo = 7
DECLARE #FiscalMonthStartDate datetime
DECLARE #FiscalMonthEndDate datetime
DECLARE #startOfMonth datetime
DECLARE #startOfNextMonth datetime
select #startOfMonth = CAST((CAST(#yr AS VARCHAR(4)) + '-' + CAST(#mo AS VARCHAR(2)) + '-' + '01') as DATE)
select #startOfNextMonth = CAST((CAST(#yr AS VARCHAR(4)) + '-' + CAST((#mo + 1) AS VARCHAR(2)) + '-' + '01') as DATE)
SELECT #FiscalMonthStartDate =
CASE
WHEN DATEPART(DW,#startOfMonth) = 0
THEN DATEADD(DD, 1, #startOfMonth)
ELSE
DATEADD(DD, 8 - DATEPART(DW,#startOfMonth), #startOfMonth)
END
SELECT #FiscalMonthEndDate =
CASE
WHEN DATEPART(DW,#startOfNextMonth) = 0
THEN DATEADD(DD, 1, #startOfNextMonth)
ELSE
DATEADD(DD, 8 - DATEPART(DW,#startOfNextMonth), #startOfNextMonth)
END
-- subtract one day to get end of fiscal month (not start of next fiscal month)
SELECT #FiscalMonthEndDate = DATEADD(DD, -1, #FiscalMonthEndDate)
SELECT #FiscalMonthStartDate, #FiscalMonthEndDate
I want to get the records of last month based on my db table [member] field "date_created".
What's the sql to do this?
For clarification,
last month - 1/8/2009 to 31/8/2009
If today is 3/1/2010, I'll need to get the records of 1/12/2009 to 31/12/2009.
All the existing (working) answers have one of two problems:
They will ignore indices on the column being searched
The will (potentially) select data that is not intended, silently corrupting your results.
1. Ignored Indices:
For the most part, when a column being searched has a function called on it (including implicitly, like for CAST), the optimizer must ignore indices on the column and search through every record. Here's a quick example:
We're dealing with timestamps, and most RDBMSs tend to store this information as an increasing value of some sort, usually a long or BIGINTEGER count of milli-/nanoseconds. The current time thus looks/is stored like this:
1402401635000000 -- 2014-06-10 12:00:35.000000 GMT
You don't see the 'Year' value ('2014') in there, do you? In fact, there's a fair bit of complicated math to translate back and forth. So if you call any of the extraction/date part functions on the searched column, the server has to perform all that math just to figure out if you can include it in the results. On small tables this isn't an issue, but as the percentage of rows selected decreases this becomes a larger and larger drain. Then in this case, you're doing it a second time for asking about MONTH... well, you get the picture.
2. Unintended data:
Depending on the particular version of SQL Server, and column datatypes, using BETWEEN (or similar inclusive upper-bound ranges: <=) can result in the wrong data being selected. Essentially, you potentially end up including data from midnight of the "next" day, or excluding some portion of the "current" day's records.
What you should be doing:
So we need a way that's safe for our data, and will use indices (if viable). The correct way is then of the form:
WHERE date_created >= #startOfPreviousMonth AND date_created < #startOfCurrentMonth
Given that there's only one month, #startOfPreviousMonth can be easily substituted for/derived by:
DATEADD(month, -1, #startOfCurrentMonth)
If you need to derive the start-of-current-month in the server, you can do it via the following:
DATEADD(month, DATEDIFF(month, 0, CURRENT_TIMESTAMP), 0)
A quick word of explanation here. The initial DATEDIFF(...) will get the difference between the start of the current era (0001-01-01 - AD, CE, whatever), essentially returning a large integer. This is the count of months to the start of the current month. We then add this number to the start of the era, which is at the start of the given month.
So your full script could/should look similar to the following:
DECLARE #startOfCurrentMonth DATETIME
SET #startOfCurrentMonth = DATEADD(month, DATEDIFF(month, 0, CURRENT_TIMESTAMP), 0)
SELECT *
FROM Member
WHERE date_created >= DATEADD(month, -1, #startOfCurrentMonth)
AND date_created < #startOfCurrentMonth
All date operations are thus only performed once, on one value; the optimizer is free to use indices, and no incorrect data will be included.
SELECT *
FROM Member
WHERE DATEPART(m, date_created) = DATEPART(m, DATEADD(m, -1, getdate()))
AND DATEPART(yyyy, date_created) = DATEPART(yyyy, DATEADD(m, -1, getdate()))
You need to check the month and year.
Add the options which have been provided so far won't use your indexes at all.
Something like this will do the trick, and make use of an index on the table (if one exists).
DECLARE #StartDate DATETIME, #EndDate DATETIME
SET #StartDate = dateadd(mm, -1, getdate())
SET #StartDate = dateadd(dd, datepart(dd, getdate())*-1, #StartDate)
SET #EndDate = dateadd(mm, 1, #StartDate)
SELECT *
FROM Member
WHERE date_created BETWEEN #StartDate AND #EndDate
DECLARE #StartDate DATETIME, #EndDate DATETIME
SET #StartDate = DATEADD(mm, DATEDIFF(mm,0,getdate())-1, 0)
SET #EndDate = DATEADD(mm, 1, #StartDate)
SELECT *
FROM Member
WHERE date_created BETWEEN #StartDate AND #EndDate
An upgrade to mrdenny's solution, this way you get exactly last month from YYYY-MM-01
Last month consider as till last day of the month.
31/01/2016 here last day of the month would be 31 Jan. which is not similar to last 30 days.
SELECT CONVERT(DATE, DATEADD(DAY,-DAY(GETDATE()),GETDATE()))
One way to do it is using the DATEPART function:
select field1, field2, fieldN from TABLE where DATEPART(month, date_created) = 4
and DATEPART(year, date_created) = 2009
will return all dates in april. For last month (ie, previous to current month) you can use GETDATE and DATEADD as well:
select field1, field2, fieldN from TABLE where DATEPART(month, date_created)
= (DATEPART(month, GETDATE()) - 1) and
DATEPART(year, date_created) = DATEPART(year, DATEADD(m, -1, GETDATE()))
declare #PrevMonth as nvarchar(256)
SELECT #PrevMonth = DateName( month,DATEADD(mm, DATEDIFF(mm, 0, getdate()) - 1, 0)) +
'-' + substring(DateName( Year, getDate() ) ,3,4)
SQL query to get record of the present month only
SELECT * FROM CUSTOMER
WHERE MONTH(DATE) = MONTH(CURRENT_TIMESTAMP) AND YEAR(DATE) = YEAR(CURRENT_TIMESTAMP);
SELECT * FROM Member WHERE month(date_created) = month(NOW() - INTERVAL 1 MONTH);
select * from [member] where DatePart("m", date_created) = DatePart("m", DateAdd("m", -1, getdate())) AND DatePart("yyyy", date_created) = DatePart("yyyy", DateAdd("m", -1, getdate()))
DECLARE #StartDate DATETIME, #EndDate DATETIME
SET #StartDate = DATEADD(mm, DATEDIFF(mm, 0, getdate()) - 1, 0)
SET #EndDate = dateadd(dd, -1, DATEADD(mm, 1, #StartDate))
SELECT * FROM Member WHERE date_created BETWEEN #StartDate AND #EndDate
and another upgrade to mrdenny's solution.
It gives the exact last day of the previous month as well.
WHERE
date_created >= DATEADD(MONTH, DATEDIFF(MONTH, 31, CURRENT_TIMESTAMP), 0)
AND date_created < DATEADD(MONTH, DATEDIFF(MONTH, 0, CURRENT_TIMESTAMP), 0)
I'm from Oracle env and I would do it like this in Oracle:
select * from table
where trunc(somedatefield, 'MONTH') =
trunc(sysdate -INTERVAL '0-1' YEAR TO MONTH, 'MONTH')
Idea: I'm running a scheduled report of previous month (from day 1 to the last day of the month, not windowed). This could be index unfriendly, but Oracle has fast date handling anyways.
Is there a similar simple and short way in MS SQL? The answer comparing year and month separately seems silly to Oracle folks.
You can get the last month records with this query
SELECT * FROM dbo.member d
WHERE CONVERT(DATE, date_created,101)>=CONVERT(DATE,DATEADD(m, datediff(m, 0, current_timestamp)-1, 0))
and CONVERT(DATE, date_created,101) < CONVERT(DATE, DATEADD(m, datediff(m, 0, current_timestamp)-1, 0),101)
I don't think the accepted solution is very index friendly
I use the following lines instead
select * from dbtable where the_date >= convert(varchar(10),DATEADD(m, -1, dateadd(d, - datepart(dd, GETDATE())+1, GETDATE())),120) and the_date <= dateadd(ms, -3, convert(varchar(10),DATEADD(m, 0, dateadd(d, - datepart(dd, GETDATE())+1, GETDATE())),120));
Or simply (this is the best).
select * from dbtable where the_date >= convert(varchar(10),DATEADD(m, -1, dateadd(d, - datepart(dd, GETDATE())+1, GETDATE())),120) and the_date < SELECT convert(varchar(10),DATEADD(m, -1, dateadd(d, - datepart(dd, GETDATE())+1, GETDATE())),120);
Some help
-- Get the first of last month
SELECT convert(varchar(10),DATEADD(m, -1, dateadd(d, - datepart(dd, GETDATE())+1, GETDATE())),120);
-- Get the first of current month
SELECT convert(varchar(10),DATEADD(m, -1, dateadd(d, - datepart(dd, GETDATE())+1, GETDATE())),120);
--Get the last of last month except the last 3milli seconds. (3miliseconds being used as SQL express otherwise round it up to the full second (SERIUSLY MS)
SELECT dateadd(ms, -3, convert(varchar(10),DATEADD(m, 0, dateadd(d, - datepart(dd, GETDATE())+1, GETDATE())),120));
Here is what I did so I could put it in a view:
ALTER view [dbo].[MyView] as
with justdate as (
select getdate() as rightnow
)
, inputs as (
select dateadd(day, 1, EOMONTH(jd.rightnow, -2)) as FirstOfLastMonth
,dateadd(day, 1, EOMONTH(jd.rightnow, -1)) as FirstOfThisMonth
from justdate jd
)
SELECT TOP 10000
[SomeColumn]
,[CreatedTime]
from inputs i
join [dbo].[SomeTable]
on createdtime >= i.FirstOfLastMonth
and createdtime < i.FirstOfThisMonth
order by createdtime
;
Note that I intentionally ran getdate() once.
In Sql server for last one month:
select * from tablename
where order_date > DateAdd(WEEK, -1, GETDATE()+1) and order_date<=GETDATE()
DECLARE #curDate INT = datepart( Month,GETDATE())
IF (#curDate = 1)
BEGIN
select * from Featured_Deal
where datepart( Month,Created_Date)=12 AND datepart(Year,Created_Date) = (datepart(Year,GETDATE())-1)
END
ELSE
BEGIN
select * from Featured_Deal
where datepart( Month,Created_Date)=(datepart( Month,GETDATE())-1) AND datepart(Year,Created_Date) = datepart(Year,GETDATE())
END
DECLARE #StartDate DATETIME, #EndDate DATETIME
SET #StartDate = dateadd(mm, -1, getdate())
SET #StartDate = dateadd(dd, datepart(dd, getdate())*-1, #StartDate)
SET #EndDate = dateadd(mm, 1, #StartDate)
set #StartDate = DATEADD(dd, 1 , #StartDate)
The way I fixed similar issue was by adding Month to my SELECT portion
Month DATEADD(day,Created_Date,'1971/12/31') As Month
and than I added WHERE statement
Month DATEADD(day,Created_Date,'1971/12/31') = month(getdate())-1
If you are looking for last month so try this,
SELECT
FROM #emp
WHERE DATEDIFF(MONTH,CREATEDDATE,GETDATE()) = 1
If you are looking for last month so try this,
SELECT
FROM #emp
WHERE DATEDIFF(day,CREATEDDATE,GETDATE()) between 1 and 30
A simple query which works for me is:
select * from table where DATEADD(month, 1,DATEFIELD) >= getdate()
If you are looking for previous month data:
date(date_created)>=date_sub(date_format(curdate(),"%Y-%m-01"),interval 1 month) and
date(date_created)<=date_sub(date_format(curdate(),'%Y-%m-01'),interval 1 day)
This will also work when the year changes. It will also work on MySQL.