Is there a function or a workaround in SQL Server 2005 that is equivalent to the new_time() function in oracle?
No, there is not equivalent functionality to Oracle's NEW_TIME() function in SQL Server 2005. It was added to SQL Server 2008 - DATETIMEOFFSET.
CLR UDF would be the most likely alternative.
Related
For Example:
Here, Is this function EncryptByPassPharase() support in sql server 2000? If Not Then is there any function like that in sql server 2000? How Can I do same thing in sql server 2000?
INSERT INTO login_details(username,password) VALUES('smith2',EncryptByPassPhrase('12','XXX'))
No, the function EncryptByPassPharase() is not support for SQL Server < 2008. On microsoft doc has been detail about it. You can se more detail here ENCRYPTBYPASSPHRASE
How can I transfer a SQL Server Compact database to SQL Server 2008 by using
a SQL Server 2008 procedure?
Yes, you can create a SQLCLR procedure using the SQL Server Compact OLEDB provider. I have some sample code here: http://erikej.blogspot.dk/2008/10/accessing-sql-compact-from-sql-server.html
If you want to do a one off transfer from SQL Server Compact to SQL Server 2008, you can use my ExportSqlCe command line to in combination with sqlcmd to transfer the entire database
I am new to Hibernate and I need help/answers for few doubts.
1) I am using Oracle 10g dialect and If I use Session.CreateSqlQuery("Oracle syntax SQL Query");
My Question: If I change my dialect to SQL Server 2008. will the query which I have created by using CreateSqlQuery() changes/run's on SQL server 2008.?
or Do i need to change the Query once again.
Thanks & Regards,
Anand.
You need to specify the dialect of SQL server 2008.
It is database dependent.You cannot use same dialect for both databases
Do you know any function implementation I could use for decrypting data encrypted by AES/Rijndael in SQL Server 2000?
xp_crypt might do it
Without the CLR and other whizzy stuff in SQL Server 2005+ it will be difficult in the raw SQL available in SQL Server 2000.
I am creating partition function and schemes.
In SQL Server 2008, it only defines range partitioning and not list partitions.
Dont we have list partitioning in SQL Server?
I am using SQL Server 2008 Enterprise edition.
There is no List Partitioning in SQL Server 2008. But you can fake it into creating one using the LEFT clause.
Read up here:
http://www.sqlservercentral.com/articles/partition/64740/