MSBuild doesn't respect PublishUrl property for my ClickOnce app - msbuild

I'm trying to make a batch file to publish the few ClickOnce application we have in one click. I'm using msbuild for that, and as an example the below command line shows how I'm doing it:
msbuild
MyApp.sln
/t:Publish
/p:Configuration=Release
/p:PublishUrl="C:\Apps\"
/v:normal > Log.txt
(wrapped for easier reading)
when I run the above command it builds and publish the application in the release directory, i.e. bin\release! Any idea why msbuild doesn't respect PublishUrl property in my example above?
PS: I tried also different combinations including remove 'Configuration', use 'Rebuild' and 'PublishOnly' as targets, and remove the the quotation marks but without any success.

You are setting the wrong property. Try PublishDir instead.
You can pass it into MSBuild as you are or you can set it in the project file (or maybe the sln file too, not sure I always use the project file.) like this
<PropertyGroup>
<PublishDir>C:\Dev\Release\$(BuildEnvironment)\</PublishDir>
</PropertyGroup>
I've just done a few blog posts on MsBuild and ClickOnce stuff, check it out you 'should' find them useful...

Some features are done by Visual-Studio and not by the MSBuild-script. So the click-once-deployment behaves differently when it's executed from the command-line.
The ApplicationRevision isn't increased with every build. This works only when is exectued from Visual Studio
In in somecases, the PublishUrl isn't used. Quote from MSDN:
For example, you could set the PublishURL to an FTP path and set the InstallURL to a Web URL. In this case, the PublishURL is only used in the IDE to transfer the files, but not used in the command-line builds. Finally, you can use UpdateUrl if you want to publish a ClickOnce application that updates itself from a separate location from which it is installed.
I've created a special MSBuild-file which does this things. It runs the publish-target and copies then the files to the right location.
An example of the build-file, as requested by alhambraeidos. It basically runs the regular VisualStudio-build and then copies the click-once data to the real release folder. Note that removed some project-specific stuff, so it's maybe broken. Furthermore it doesn't increase the build-number. Thats done by our Continues-Build-Server:
<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="4.0" DefaultTargets="Publish" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<!-- the folder of the project to build -->
<ProjLocation>..\YourProjectFolder</ProjLocation>
<ProjLocationReleaseDir>$(ProjLocation)\bin\Release</ProjLocationReleaseDir>
<ProjPublishLocation>$(ProjLocationReleaseDir)\app.publish</ProjPublishLocation>
<!-- This is the web-folder, which provides the artefacts for click-once. After this
build the project is actually deployed on the server -->
<DeploymentFolder>D:\server\releases\</DeploymentFolder>
</PropertyGroup>
<Target Name="Publish" DependsOnTargets="Clean">
<Message Text="Publish-Build started for build no $(ApplicationRevision)" />
<MSBuild Projects="$(ProjLocation)/YourProject.csproj" Properties="Configuration=Release" Targets="Publish"/>
<ItemGroup>
<SchoolPlannerSetupFiles Include="$(ProjPublishLocation)\*.*"/>
<SchoolPlannerUpdateFiles Include="$(ProjPublishLocation)\Application Files\**\*.*"/>
</ItemGroup>
<Copy
SourceFiles="#(SchoolPlannerSetupFiles)"
DestinationFolder="$(DeploymentFolder)\"
/>
<Copy
SourceFiles="#(SchoolPlannerUpdateFiles)"
DestinationFolder="$(DeploymentFolder)\Application Files\%(RecursiveDir)"
/>
<CallTarget Targets="RestoreLog"/>
</Target>
<Target Name="Clean">
<Message Text="Clean project:" />
<MSBuild Projects="$(ProjLocation)/YourProject.csproj" Properties="Configuration=Release" Targets="Clean"/>
</Target>
</Project>

I'll put in my 2 cents, this syntax seems to work (right or wrong):
/p:publishUrl="C:\\_\\Projects\\Samples\\artifacts\\Web\\"

For me, the soultion was to escape the path.
Instead of:
/p:PublishUrl="C:\Apps\"
Put:
/p:PublishUrl="C:\\Apps\\"

Related

MSBuild ignores changes inside *.wpp.target

I have following *.wpp.target file:
<PropertyGroup>
<CopyAllFilesToSingleFolderForMsdeployDependsOn>
ExcludeCustomFilesOrFolders;
$(CopyAllFilesToSingleFolderForPackageDependsOn);
</CopyAllFilesToSingleFolderForMsdeployDependsOn>
</PropertyGroup>
<Target Name="ExcludeCustomFilesOrFolders" BeforeTargets="ExcludeFilesFromPackage">
<ItemGroup>
<ExcludeFromPackageFolders Include="$(MSBuildProjectDirectory)\Media" />
</ItemGroup>
<Message Text="Custom Exclude From %0D Folders: #(ExcludeFromPackageFolders)%0D Files: #(ExcludeFromPackageFiles)" Importance="high"/>
</Target>
If I run it for the first time out of visual studio 17 Media folder is ignored and not published.
After when I comment the line with ExcludeFromPackageFolders node and publish again Media folder is still ignored. It seems that visual studio or msbuild does not refresh changes made inside *.wpp.target file. Do I miss here something or is VS or MSbuild just buggy?
Can you try to add /PROFILE to the linker option? Might fix the problem: https://developercommunity.visualstudio.com/content/problem/136703/wpp-trace-missing-from-pdb-files-in-vs-2017.html
You have to restart visual studio and reload solution everytime you change it. VS caches it.

MSBuild Issue while deploying files

I am deploying some files on the server. But when I am doing this, build is deleting all the files and folder which are residing at that location. I don't want to delete all the files from the server. I want to exclude one folder (folder name is Temp) from the destination folder. Temp folder should not get deleted while deleting other files. How to do that?
Here is TFS Build Definition
<PropertyGroup Condition=" '$(DeployEnvironment)' == 'Dev' ">
<DeployPath>\\server1\D$\temp\reports</DeployPath>
</PropertyGroup>
<Target Name="CoreCompileSolution" />
<Target Name="AfterCompile">
<Message Importance ="high" Text="Solution Root: $(SolutionRoot)" />
<Message Importance ="high" Text="Out Dir: $(OutDir)" />
<Copy SourceFiles="#(RPTFiles)" DestinationFolder="$(OutDir)_PublishedWebsites\Reports\" />
</Target>
<Target Name="AfterDropBuild" >
<CreateItem Exclude="$(DeployPath)\Temp*.*">
<Output ItemName="PreviousDeployment" TaskParameter="Include" />
</CreateItem>
</Target>
Why are you using a Copy task? I think it is intended to be used for local manipulations during build, rather than deployment (because it does not give you a chance to easily configure behaviour).
I suggest that instead of copy tsak you use one of the following options
Non-web applications - use Robocopy:
/XD dirs [dirs]... : eXclude Directories matching given names/paths.
XF and XD can be used in combination e.g.
ROBOCOPY c:\source d:\dest /XF *.doc *.xls /XD c:\unwanted /S
see this link for usage guide. You either run it from the command line (using <Exec Command="" > task, or employ MBuiild Community Tasksproject which has a nice wrapper.
Web applications: you should use Web Deploy for your deployments. You an either use MSBuild integration (VS 2010 and later, see this blog series for guidance on setup and configure on VS2010 NB: it has been much simplified in VS 2012, but I don't have a link to share at the moment) or run it from command line (prior to VS 2010):
<Exec Command=""$(WebDeployToolPath)" -verb:sync - source:dirPath='$(MSBuildProjectDirectory)\Published\' -dest:dirPath='$(DeployDirectoryLocalPath)',computerName=$(DeployTargetURL),userName='$(DeployUserName)',password='$(Password)',authType='Basic' -skip:skipaction='Delete',objectname='filePath',absolutepath='app_offline.htm' -skip:skipaction='Delete',objectname='filePath',absolutepath='logs\\.*' -skip:skipaction='Delete',objectname='dirPath',absolutepath='logs\\.*' -skip:skipaction='Delete',objectname='filePath',absolutepath='UserFiles\\.*' -skip:skipaction='Delete',objectname='dirPath',absolutepath='UserFiles\\.*' -verbose -allowUntrusted" />
NB using skip:skipaction='Delete.. to skip removing files and folders.
Update
It looks like I've undestood this a bit incorrect (I supposed, deployment happenned in AfterCompile target, however, as I see now, TFS uses CoreDropBuild target to do the deployment.
So I think, what you need is to override CoreDropBuild target as described: here. (although, I've never tried this).
You can either use Copy task as the author of the thread, or go with Robocopy/webdeploy based on your personal preference.

Change working directory of msbuild.exe

I am executing MSBuild from a batch file. The MSBuild script is in a different directory than the directory I want MSBuild to consider the working directory when running the script. When invoking MSBuild.exe, how do I change its working directory?
Edit: More details
Let's say I have an MSBuild script located on some other server. I want to run a command thusly:
msbuild.exe \\my_server\c$\My\Path\To\Scripts\TestScript.msbuild
I run that command with my command prompt at c:\temp. Let's say my TestScript.msbuild has a task to create a file. The file has no path just a filename. I would expect that the file gets created inside c:\temp. But it doesn't it gets created next to the msbuild file that is sitting on the server. This is the behavior I want to change.
Edit #2
Here is the script I'm using in my test:
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<ItemGroup>
<Files Include="HelloWorld.txt" />
</ItemGroup>
<Target Name="TouchFiles">
<Touch Files="#(Files)" AlwaysCreate="True" />
</Target>
</Project>
I am going into a command shell CDing into c:\temp and then executing the script. With or without the /p:OutDir switch that #Nick Nieslanik mentions, the HelloWorld.txt file appears in the folder where the *.msbuild file is and not c:\temp.
I ran across this while looking for a solution to my problem. Here's my solution (build script):
<?xml version="1.0" encoding="utf-8"?>
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<Target Name="Default">
<Exec Command="build.bat" WorkingDirectory="..\[your dir]\" />
</Target>
</Project>
I believe that's more what you were originally looking for?
My problem was that my batch file called another that it expected to be in the same directory, but since my ms build script was being run elsewhere, the batch file failed to find the second batch file.
#jkohlhepp - I see now. You are doing the opposite of what I described in my comment to some degree.
MSBuild common targets use the MSBuildProjectDirectory to determine the output folder unless you override that. So in your case, you could run
msbuild.exe \\my_server\c$\My\Pat\To\Scripts\TestScript.msbuild /p:OutDir=c:\temp
to force the output to be dropped in that location.
EDIT:
Given the project file above, you'd need to edit it to do something like the following for this to work:
<Project xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<OutDir Condition=" '$(OutDir)' == '' ">bin\debug\</OutDir>
</PropertyGroup>
<ItemGroup>
<!-- Without prefacing files with paths, they are assumed relative to the proj file -->
<FilesToCreate Include="$(OutDir)HelloWorld.txt" />
</ItemGroup>
<Target Name="TouchFiles">
<Touch Files="#(FilesToCreate)" AlwaysCreate="True" />
</Target>
</Project>
In current versions of MSBuild the well-known property MSBuildStartupDirectory can be used in the msbuild file to retrieve the absolute path of the folder where MSBuild is called.
https://learn.microsoft.com/en-us/visualstudio/msbuild/msbuild-reserved-and-well-known-properties?view=vs-2019
This option perhaps did not exist in msbuild around the time when the question was asked. I didn't want to spend too much time investigating it.

Problems using MsBuild using command line for Publish Click Once

I have Windows application in csproj in my solution, and I want generate Publish using command line (bat, cmd).
My script is (I put \r\n for better reading):
SET MSBUILD="%SystemRoot%\Microsoft.NET\Framework\v3.5\MSBuild.exe"
SET CARWIN="..\..\Security.CarWin.csproj"
rem msbuild para publish
%MSBUILD% /target:rebuild;publish %CARWIN%
/p:ApplicationVersion="1.0.0.0"
/p:Configuration=release
/p:PublishUrl="C:\ClickOnce\CarWin.WebInstall\Publicacion\"
/p:InstallUrl="http://desserver/carwinclickonce/Publicacion/"
/p:PublishDir="C:\ClickOnce\CarWin.WebInstall\Publicacion\"
note: I'll try too using /target:publish
But in path PublishDir or PublishUrl (C:\ClickOnce\CarWin.WebInstall\Publicacion) not generates any files.
I have seen many posts in this site and google but I not found any solution.
Use PublishDir instead of PublishUrl when running from command line.
msbuild /target:publish /p:Configuration=Release;PublishDir=c:\playground\
You can also change version, like ApplicationRevision=666;MinimumRequiredVersion=1.1
Take a look at this Stack Overflow question. Basically the PublishUrl property is ignored when running ClickOnce from the command line. But you can easily add the behaviour with an additional MSBuild-task.
I've created an additional MSBuild-File, for example a build.csproj. This contains a publish-task. This task first invokes the regular MS-Build of the target-project. Afterwards it copies the result to the publish-directory. Now I invoke the 'build.csproj' instead of the reguar project-file from the command-line:
<?xml version="1.0" encoding="utf-8"?>
<Project ToolsVersion="3.5" DefaultTargets="Publish" xmlns="http://schemas.microsoft.com/developer/msbuild/2003">
<PropertyGroup>
<!-- project name-->
<ProjectName>MyExampleProject</ProjectName>
<!--properties for the project-build-->
<DefaultBuildProperties>Configuration=Release</DefaultBuildProperties>
<!-- location of the click-once stuff, relative to the project -->
<ProjectPublishLocation>.\bin\Release\app.publish</ProjectPublishLocation>
<!-- Location you want to copy the click-once-deployment. Here an windows-share-->
<ProjectClickOnceFolder>\\TargetServer\deployments</ProjectClickOnceFolder>
</PropertyGroup>
<Target Name="Publish" DependsOnTargets="Clean">
<Message Text="Publish-Build started for build no $(ApplicationRevision)" />
<!-- run the original build of the project -->
<MSBuild Projects="./$(ProjectName).csproj"
Properties="$(DefaultBuildProperties)"
Targets="Publish"/>
<!-- define the files required for click-once-->
<ItemGroup>
<SetupFiles Include="$(ProjectPublishLocation)\*.*"/>
<UpdateFiles Include="$(ProjectPublishLocation)\Application Files\**\*.*"/>
</ItemGroup>
<!-- and copy them -->
<Copy
SourceFiles="#(SetupFiles)"
DestinationFolder="$(ProjectClickOnceFolder)\"/>
<Copy
SourceFiles="#(UpdateFiles)"
DestinationFolder="$(ProjectClickOnceFolder)\Application Files\%(RecursiveDir)"/>
</Target>
<Target Name="Clean">
<Message Text="Clean project" />
<MSBuild Projects="./$(ProjectName).csproj"
Properties="$(DefaultBuildProperties)"
Targets="Clean"/>
</Target>
</Project>
I don't know if this is a problem, but I noticed that you pass the /target parameter twice?
you could you use a semi-colon delimited example:
/target:rebuild;publish
MSDN Documentation on command line parameters and MSBuild
If that also does not work you could perhaps try to debug it by passing
/verbosity:diag

MSBuild and _PublishedWebsites

After MSbuild has built my solution (with an asp.net website), and the webdeployment project has built and put the website in the directory _PublishedWebsites:
c:\mybuilds\buildName\Daily_20090519.3\Release_PublishedWebsites\MyWebsite.
How do I copy this to the fixed directory where IIS points to for the test website?
I have found loads of code snippets, but I cannot seem to find one that will take into account the fact that this directory name changes.
This is pretty easy. You can edit the project and insert something similar to the following.
<PropertyGroup>
<OutputDest>$(MSBuildProjectDirectory)\..\OutputCopy\</OutputDest>
</PropertyGroup>
<Target Name="AfterBuild">
<!-- Create an item with all the output files -->
<ItemGroup>
<_OutputFiles Include="$(OutputPath)**\*" Exclude="$(OutputPath)obj\**\*" />
</ItemGroup>
<!-- You probably don't want to include the files in the obj folder so exclude them. -->
<Message Text="OutputDest : $(OutputDest)" />
<Copy SourceFiles="#(_OutputFiles)"
DestinationFiles="#(_OutputFiles->'$(OutputDest)%(RecursiveDir)%(Filename)%(Extension)')"/>
</Target>
Is this what you are looking for?
My Book: Inside the Microsoft Build Engine : Using MSBuild and Team Foundation Build
I'm using different technique.
<PropertyGroup>
<BinariesRoot>c:\BinariesForIis\</BinariesRoot>
</PropertyGroup>
The c:\BinariesForIis\ will be used for direct output compiled binaries (before copy to ...\Daily_20090519.3\Release_ ...).