I have been using SQL for years, but have mostly been using the query designer within SQL Studio (etc.) to put together my queries. I've recently found some time to actually "learn" what everything is doing and have set myself the following fairly simple tasks. Before I begin, I'd like to ask the SOF community their thoughts on the questions, possible answers and any tips they may have.
The questions are;
Find all records w/ a duplicate in a particular column (e.g. a linking id is in more than 1 record throughout table)
SUM price from a linked table within the same query (select within a select?)
Explain the difference between the 4 joins; LEFT, RIGHT, OUTER, INNER
Copy data from one table to another based on SELECT and WHERE criteria
Input welcomed & appreciated.
Chris
I recommend that you start by following some tutorials on this topic. Your questions are not uncommon questions for someone moving from a beginner to intermediate level in SQL. SQLZoo is an excellent resource for learning SQL so consider following that.
In response to your questions:
1) Find all records with a duplicate in a particular column
There are two steps here: find duplicate records and select those records. To find the duplicate records you should be doing something along the lines of:
select possible_duplicate_field, count(*)
from table
group by possible_duplicate_field
having count(*) > 1
What we're doing here is selecting everything from a table, then grouping it by the field we want to check for duplicates. The count function then gives me a count of the number of items within that group. The HAVING clause indicates that we want to filter AFTER the grouping to only show the groups which have more than one entry.
This is all fine in itself but it doesn't give you the actual records that have those values on them. If you knew the duplicate values then you'd write this:
select * from table where possible_duplicate_field = 'known_duplicate_value'
We can use the SELECT within a select to get a list of the matches:
select *
from table
where possible_duplicate_field in (
select possible_duplicate_field
from table
group by possible_duplicate_field
having count(*) > 1
)
2) SUM price from a linked table within the same query
This is a simple JOIN between two tables with a SUM of the two:
select sum(tableA.X + tableB.Y)
from tableA
join tableB on tableA.keyA = tableB.keyB
What you're doing here is joining two tables together where those two tables are linked by a key field. In this case, this is a natural join which operates as you would expect (i.e. get me everything from the left table which has a matching record in the right table).
3) Explain the difference between the 4 joins; LEFT, RIGHT, OUTER, INNER
Consider two tables A and B. The concept of "LEFT" and "RIGHT" in this case are slightly clearer if you read your SQL from left to right. So, when I say:
select x from A join B ...
The left table is "A" and the right table is "B". Now, when you explicitly say "LEFT" the SQL statement you are declaring which of the two tables you are joining is the primary table. What I mean by this is: Which table do I scan through first? Incidentally, if you omit the LEFT or RIGHT, then SQL implicitly uses LEFT.
For INNER and OUTER you are declaring what to do when matches don't exist in one of the tables. INNER declares that you want everything in the primary table (as declared using LEFT or RIGHT) where there is a matching record in the secondary table. Hence, if the primary table contains keys "X", "Y" and "Z", and the secondary table contains keys "X" and "Z", then an INNER will only return "X" and "Z" records from the two tables.
When OUTER is used, we're saying: Give me everything from the primary table and anything that matches from the secondary table. Hence, in the previous example, we'd get "X", "Y" and "Z" records in the output record set. However, there would be NULLs in the fields which should have come from the secondary table for key value "Y" as it doesn't exist in the secondary table.
4) Copy data from one table to another based on SELECT and WHERE criteria
This is pretty trivial and I'm surprised you've never encountered it. It's a simple nested SELECT in an INSERT statement (this may not be supported by your database - if not, try the next option):
insert into new_table select * from old_table where x = y
This assumes the tables have the same structure. If you have different structures then you'll need to specify the columns:
insert into new_table (list, of, fields)
select list, of, fields from old_table where x = y
Let's say you have 2 tables named :
[OrderLine] with the columns [Id, OrderId, ProductId, Qty, Status]
[Product] with [Id, Name, Price]
1) all orderline of command having more than 1 line (it's technically the same as looking for duplicates on OrderId :) :
select OrderId, count(*)
from OrderLine
group by OrderId
having count(*) > 1
2) total price for all order line of the order 1000
select sum(p.Price * ol.Qty) as Price
from OrderLine ol
inner join Product p on ol.ProductId = p.Id
where ol.OrderId = 1000
3) difference between joins:
a inner join b => take all a that has a match with b. if b is not found, a will be not be returned
a left join b => take all a, match them with b, include a even if b is not found
a righ join b => b left join a
a outer join b => (a left join b) union ( a right join b)
4) copy order lines to a history table :
insert into OrderLinesHistory
(CopiedOn, OrderLineId, OrderId, ProductId, Qty)
select
getDate(), Id, OrderId, ProductId, Qty
from
OrderLine
where
status = 'Closed'
To answer #4 and to perhaps show at least some understanding of SQL and the fact this isn't HW, just me trying to learn best practise;
SET NOCOUNT ON;
DECLARE #rc int
if #what = 1
BEGIN
select id from color_mapper where product = #productid and color = #colorid;
select #rc = ##rowcount
if #rc = 0
BEGIN
exec doSavingSPROC #colorid, #productid;
END
END
END
Related
I have broken my head with syntax error response from Access Jet engine.
I have three tables.
First one "tblMstItem" is the master table for Item details contains two columns "colITemID" PK and "colItemName"
Second one "tblStocks" is the table where the purchases are maintained. This table has a column "colRQty" which keeps the quantity of the particular item purchased. "colItemID" FK from "tblMstItem"
Third one "tblSales" is the table where the sales are maintained. This table has a column "colSoldQty" which keeps the quantity of the particular item sold. "colItemID" FK from "tblMstItem"
Therefore "colItemID" is common in all the three tables and has links created.
My requirement is I need all the Items listed in the "tblMstItem" table columns are "colItemID" "colItemName" and if there is any item purchased or any item sold should be shown as sum of that particular item.
I have used Left Join shown in the following select statement but it always giving me an error message.
Select statement as follows:
SELECT
i.colItemID,
i.colItemName,
s.rqty,
n.soldqty
from tblMstItem i
left join
( select sum( colRQty ) as rqty from tblStocks group by colItemID ) s
on i.colItemID = s.colItemID
left join
( select sum( colSoldQty ) as soldqty from tblSales group by colItemID ) n
on i.colItemID=n.colItemID``
I tried the above given code with many different syntax but every time I get syntax error. It is making me to doubt do MS Access support three table joins, I am sure I am wrong.
See the error Message below
Table columns and table link shown below
I would be very thankful to get any help on this. Access sql please because this I am able to get results in SQL Server.
Thanks in Advance
MS Access has a picky syntax. For instance, joins need extra parentheses. So, try this:
select i.colItemID, i.colItemName,
s.rqty, n.soldqty
from (tblMstItem as i left join
(select colItemID, sum(colRQty ) as rqty
from tblStocks
group by colItemID
) as s
on i.colItemID = s.colItemID
) left join
(select colItemID, sum( colSoldQty ) as soldqty
from tblSales
group by colItemID
) as n
on i.colItemID = n.colItemID;
You also need to select colItemID in the subqueries.
I am trying to join two tables and update the results in the third table.
So table A is the results table and it has the columns customer number and score.
Table B has customer number and ind_code and table C has ind_code and ind_score.
So the output of the query should be such that the ind_code in table B and C should join together based on the first two digits and ind_score should be updated in Table A in the score column. Table A and Table B should be joined on the basis of customer number.
Could anyone please help. I tried multiple queries but nothing seems to work. i am using oracle sql developer
Generally, the JOIN operation mustn't cut field information but if your structure (for me not correct) is that ...
If I understand better:
UPDATE TableA
SET score =
(SELECT MAX(C.ind_score)
FROM TableC C
JOIN TableB B
ON C.ind_code = SUBSTRING(B.ind_code, 1, 2)
WHERE B.customernumber = TableA.customernumber)
I use on subquery MAX aggregate function, because I don't know if your cut of ind_code of TableB can be not unique (i.e. you have ind_code 5555 and 5554)
I read this FAQ http://www.firebirdfaq.org/faq289/ and I want to use select to count detail record from current record so I tried this
((
select count(*) from detail_table where detail_table.id = id
))
But I did not get correct values I got numbers like 19 where in fact it is the total number of records in detail_table! How can I get only the count of records related to current master record in master table?
The problem is that id refers to the id column of detail_table and not of the master table. So it is the equivalent of:
select count(*) from detail_table where detail_table.id = detail_table.id
Which means you are simply counting all rows. Instead - assuming the master table is master_table - you should use:
select count(*) from detail_table where detail_table.id = master_table.id
Note that, as also mentioned in the FAQ you link to, you should really consider using a view instead of a computed column when referencing other tables as it is not very good for performance.
The view equivalent would be something like
CREATE OR ALTER VIEW master_with_detail_count
AS
SELECT master_table.id, coalesce(c.detail_count, 0) as detail_count
FROM master_table
LEFT JOIN (SELECT id, count(*) as detail_count FROM detail GROUP BY id) c
ON c.id = master.id
I have two tables. Table 1 has about 750,000 rows and table 2 has 4 million rows. Table two has an extra ID field in which I am interested, so I want to write a query that will check if the 750,000 table 1 records exist in table 2. For all those rows in table 1 that exist in table 2, I want the respective ID based on same SSN. I tried the following query:
SELECT distinct b.UID, a.*
FROM [Analysis].[dbo].[Table1] A, [Proteus_8_2].dbo.Table2 B
where a.ssn = b.ssn
Instead of getting 750,000 rows in the output, I am getting 5.4 million records. Where am i going wrong?
Please help?
You're requesting all the rows in your select if b.UID is a unique field in column two.
Also if SSN is not unique in table one you can get the higher row count than the total row count for table 2.
You need to consider what you want from table 2 again.
EDIT
You can try this to return distinct combinations of ssn and uid when ssn is found in table 2 provided that ssn and uid have a cardinality of 1:1, i.e., every unique ssn has a single unique uid.
select distinct
a.ssn,b.[UID]
from [Analysis].[dbo].[Table1] a
cross apply
( select top 1 [uid] from [Proteus_8_2].[dbo].[Table2] where ssn = a.ssn ) b
where b.[UID] is not null
Try with LEFT JOIN
SELECT distinct b.UID, a.*
FROM [Analysis].[dbo].[Table1] A LEFT JOIN [Proteus_8_2].dbo.Table2 B
on a.ssn = b.ssn
Since the order detail table is in a one-many relationship to the order table, that is the expected result of any join. If you want something different, you need to define for us the business rule that will tell us how to select only one record from the Order detail table. You cannot effectively write SQL code without understanding the business rules that of what you are trying to achieve. You should never just willy nilly select one record out of the many, you need to understand which one you want.
I have 3 data tables.
In the entries data table I have entries with ID (entryId as primary key).
I have another table called EntryUsersRatings in there are multiple entries that have entryId field and a rating value (from 1 to 5).
(ratings are stored multiple times for one entryId).
Columns: ratingId (primary key), entryId, rating (integer value).
In the third data table I have translations of entries in the first table (with entryId, languageId and title - translation).
What I would like to do is select all entries from first data table with their titles (by language ID).
On a top of that I want average rating of each entry (which can be stored multiple times) that is stored in EntryUsersRatings.
I have tried this:
SELECT entries.entryId, EntryTranslations.title, AVG(EntryUsersRatings.rating) AS AverageRating
FROM entries
LEFT OUTER JOIN
EntryTranslations ON entries.entryId = EntryTranslations.entryId AND EntryTranslations.languageId = 1
LEFT OUTER JOIN
EntryUsersRatings ON entries.entryId = EntryUsersRatings.entryId
WHERE entries.isDraft=0
GROUP BY title, entries.entryId
isDraft is just something that means that entries are not stored with all information needed (just incomplete data - irrelevant for our case here).
Any help would be greatly appreciated.
EDIT: my solution gives me null values for rating.
Edit1: this query is working perfectly OK, I was looking into wrong database.
We also came to another solution, which gives us the same result (I hope someone will find this useful):
SELECT entries.entryId, COALESCE(x.EntryUsersRatings, 0) as averageRating
FROM entries
LEFT JOIN(
SELECT rr.entryId, AVG(rating) AS entryRating
FROM EntryUsersRatings rr
GROUP BY rr.entryId) x ON x.entryId = entries.entryId
#CyberHawk: as you are using left outer join with entries, your result will give all records from left table and matching record with your join condition from right table. but for unmatching records it will give you a null value .
check out following link for the deta:
http://msdn.microsoft.com/en-us/library/ms187518(v=sql.105).aspx