Creating an NSArray initialized with count N, all of the same object - objective-c

Question

I want to create an NSArray with objects of the same value (say NSNumber all initialized to 1) but the count is based on another variable. There doesn't seem to be a way to do this with any of the intializers for NSArray except for one that deals with C-style array.
Any idea if there is a short way to do this?
This is what I am looking for:
NSArray *array = [[NSArray alloc] initWithObject:[NSNumber numberWithInt:0]
count:anIntVariable];
NSNumber is just one example here, it could essentially be any NSObject.

Answer 1

The tightest code I've been able to write for this is:
id numbers[n];
for (int x = 0; x < n; ++x)
numbers[x] = [NSNumber numberWithInt:0];
id array = [NSArray arrayWithObjects:numbers count:n];
This works because you can create runtime length determined C-arrays with C99 which Xcode uses by default.
If they are all the same value, you could also use memset (though the cast to int is naughty):
id numbers[n];
memset(numbers, (int)[NSNumber numberWithInt:0], n);
id array = [NSArray arrayWithObjects:numbers count:n];
If you know how many objects you need, then this code should work, though I haven't tested it:
id array = [NSArray arrayWithObjects:(id[5]){[NSNumber numberWithInt:0]} count:5];

Answer 2

I can't see any reason why this structure in a non-mutable format would be useful, but I am certain that you have your reasons.
I don't think that you have any choice but to use a NSMutableArray, build it with a for loop, and if it's really important that the result not be mutable, construct a NSArray and use arrayWithArray:

Answer 3

I agree with #mmc, make sure you have a valid reason to have such a structure (instead of just using the same object N times), but I'll assume you do.
There is another way to construct an immutable array which would be slightly faster, but it requires creating a C array of objects and passing it to NSArray's +arrayWithObject:count: method (which returns an autoreleased array, mind you) as follows:
id anObject = [NSNumber numberWithInt:0];
id* buffer = (id*) malloc(sizeof(id) * anIntVariable);
for (int i = 0; i < anIntVariable; i++)
buffer[i] = anObject;
NSArray* array = [NSArray arrayWithObjects:buffer count:anIntVariable];
free(buffer);
You could accomplish the same thing with even trickier pointer math, but the gains are fairly trivial. Comment if you're interested anyway.

Answer 4

Probably the reason there is no such method on NSArray is that the semantics are not well defined. For your case, with an immutable NSNumber, then all the different semantics are equivalent, but imagine if the object you were adding was a mutable object, like NSMutableString for example.
There are three different semantics:
retain — You'd end up with ten pointers to the same mutable string, and changing any one would change all ten.
copy — You'd end up with ten pointers to the same immutable string, or possibly ten different pointers to immeduable strings with the same value, but either way you'd not be able to change any of them.
mutableCopy — You'd end up with ten different mutable string objects, any of which you could change independently.
So Apple could write three variants of the method, or have some sort of parameter to control the semantics, both of which are ugly, so instead they left it to you to write the code. If you want, you can add it as an NSArray category method, just be sure you understand the semantic options and make it clear.
The method:
-(id)initWithArray:(NSArray *)array copyItems:(BOOL)flag
has this same issue.
Quinn's solution using arrayWithObjects:count: is a reasonably good one, probably about the best you can get for the general case. Put it in an NSArray category and that's about as good as it is going to get.