I need SQL code for a query I need to do in Access. I have a table with multiple fields but I only need 2 fields for the query. 1 is a date field. let's call that one DateField. the other is a field that contains text, let's call lit TextField. I need a query that returns the following:
The COUNT of DateField (i.e. how many there are regardless of what the value is)
The COUNT of TextField WHERE its value = "ThisText"
The COUNT of TextField WHERE its value = "ThatText"
Results GROUP BY Year
the same query again (will be a separate Q) but with results GROUP BY Month
Many thanks in advance for all your wonderful help.
I believe you can only SELECT a given aggregate function once per per query. That is to say you cannot request the COUNT two different fields in a single query. Here's the reference for the count function in JET SQL. At best you can count the number of non-NULL values of a certain field in a grouped result set under some WHERE clause.
SELECT YEAR/MONTH(DateField), COUNT(DateField),
SUM(IIF(TextField='ThisText', 1, 0)),
SUM(IIF(TextField='ThatText', 1, 0))
FROM MyTable
GROUP BY YEAR/MONTH(DateField)
How about:
SELECT
Year
,COUNT(DISTINCT DateField) AS NumDateFields
,COUNT(CASE WHEN TextField = 'ThisText' THEN 1 END) AS ThisTextCount
,COUNT(CASE WHEN TextField = 'ThatText' THEN 1 END) AS ThisTextCount
GROUP BY Year;
Or... GROUP BY Month
Related
I am looking for a way to write an SQL statement that selects data for each month of the year, separately.
In the SQL statement below, I am trying to count the number of instances in the TOTAL_PRECIP_IN and TOTAL_SNOWFALL_IN columns when either column is greater than 0. In my data table, I have information for those two columns ("TOTAL_PRECIP_IN" and "TOTAL_SNOWFALL_IN") for each day of the year (365 total entries).
I want to break up my data by each calendar month, but am not sure of the best way to do this. In the statement below, I am using a UNION statement to break up the months of January and February. If I keep using UNION statements for the remaining months of the year, I can get the answer I am looking for. However, using 11 different UNION statements cannot be the optimal solution.
Can anyone give me a suggestion how I can edit my SQL statement to measure from the first day of the month, to the last day of the month for every month of the year?
select monthname(OBSERVATION_DATE) as "Month", sum(case when TOTAL_PRECIP_IN or TOTAL_SNOWFALL_IN > 0 then 1 else 0 end) AS "Days of Rain" from EMP_BASIC
where OBSERVATION_DATE between '2019-01-01' and '2019-01-31'
and CITY = 'Olympia'
group by "Month"
UNION
select monthname(OBSERVATION_DATE) as "Month", sum(case when TOTAL_PRECIP_IN or TOTAL_SNOWFALL_IN > 0 then 1 else 0 end) from EMP_BASIC
where OBSERVATION_DATE between '2019-02-01' and '2019-02-28'
and CITY = 'Olympia'
group by "Month"```
Your table structure is too unclear to tell you the exact query you will need. But a general easy idea is to build the sum of your value and then group by monthname and/or by month. Sice you wrote you only want sum values greater 0, you can just put this condition in the where clause. So your query will be something like this:
SELECT MONTHNAME(yourdate) AS month,
MONTH(yourdate) AS monthnr,
SUM(yourvalue) AS yoursum
FROM yourtable
WHERE yourvalue > 0
GROUP BY MONTHNAME(yourdate), MONTH(yourdate)
ORDER BY MONTH(yourdate);
I created an example here: db<>fiddle
You might need to modify this general construct for your concrete purpose (maybe take care of different years, of NULL values etc.). And note this is an example for a MYSQL DB because you wrote about MONTHNAME() which is in most cases used in MYSQL databases. If you are using another DB type, maybe you need to do some modifications. To make sure that answers match your DB type, tag it in your question, please.
I am trying to use columns that I created in this query to create another column.
Let me first my messy query. The query looks like this:
SELECT tb.team, tb.player, tb.type, tb.date, ToChar(Current Date-1, 'DD-MON-YY') as yesterday,
CASE WHEN to_date(tb.date) = yesterday then 1 else 0 end dateindicator,
FROM (
COUNT DISTINCT(*)
FROM TABLE_A, dual
where dateindicator = 1
Group by tb.team
)
What I am trying to do here is:
creating a column with "Yesterday's date"
Using the "Yesterday" column to create another column called dateindicator indicating each row is yesterday's data or not.
then using that dateindicator, I want to count the distinct number of player for each team that has 1 of the dateindicator column.
But I am getting the "invalid identifier" error. I am new to this oracle SQL, and trying to learn here.
You cannot use an Alias in your Select statement.
see here: SQL: Alias Column Name for Use in CASE Statement
you need to use the full toChar(.. in the CASE WHEN.
Also:
Your WHERE-condition (Line 5) doesnt belong there.. it should be:
SELECT DISTINCT .>. FROM .>. WHERE. you have to specify the table first. then you can filter it with where.
If I follow your explanation correctly: for each team, you want to count the number of players whose date column is yesterday.
If so, you can just filter and aggregate:
select team, count(*) as cnt
from mytable
where mydate >= trunc(sysdate) - 1 and mydate < trunc(sysdate)
group by team
This assumes that the dates are stored in column mydate, that is of date datatype.
I am unsure what you mean by counting distinct players; presumably, a given player appears just once per team, so I used count(*). If you really need to, you can change that to count(distinct player).
Finally: if you want to allow teams where no player matches, you can move the filtering logic within the aggregate function:
select team,
sum(case when mydate >= trunc(sysdate) - 1 and mydate < trunc(sysdate) then 1 else 0 end) as cnt
from mytable
group by team
I have a use case function that needs to returns a single row only for every end of month.
I tried using select distinct and it is showing multiple records for the same end of month
SELECT DISTINCT CASE
WHEN eff_interest_balance < 0.01 THEN trial_balance_date
WHEN date_paid < trial_balance_date THEN date_paid
END as A
, period
FROM dbo.Intpayments[enter image description here][1]
WHERE loan_number = 60023
ORDER BY period ASC
Each row should return single date for each month
Distinct is returning unique rows, not grouping them. You are looking to aggregate rows. This means using some combination of aggregate functions and group by.
What your current query is missing is some sort of logic for aggregating the rows that are in the same period. Do you want to compare the sum of these values? The min, the max?
In any case, the basic idea of aggregating and grouping would look like this - I don't think this summing is what you want, but the query shows the basic idea of aggregating and grouping:
SELECT
period
, SUM(eff_interest_balance) AS SumOfBalance
FROM dbo.Intpayments
WHERE loan_number = 60023
GROUP BY period
here is my query
select narr,vocno,count(*)
from KontenLedger
WHERE VOCDT>'2018-07-01'
group by narr,vocno
having count(*)<'3'
actually if i wright as i given above ,the result which calculates two fields ('narr' and 'vocno') if i remove the field ('narr') answer is correct. i need to view the field 'narr' also without counting
Without knowing your database, nor having some limited sample date, nor expected output?
SELECT
vocno,
COUNT(*) AS total,
MAX(narr) AS max_narr
FROM KontenLedger
WHERE vocdt > '2018-07-01'
GROUP BY vocno
HAVING COUNT(*) < 3
I need to do an user level analysis. As the data has a lot of different rows per user (related to different events), I need to group by user and create some calculated fields that represent the different rows. One of the fields is a calculation of the number of days since the last purchase of the user (today - last purchase date). I already tried a lot of different codes and also did a lot of research, but could not find the solution.
The codes that for me makes more sense but did not work are below:
Using case when statement
SELECT CASE WHEN LAST(tr_orderid <> "") THEN
DATEDIFF(CURRENT_DATE(),event_date) ELSE NULL END AS recency_lastbooking
FROM df
GROUP BY domain_userid
Using IF statement
SELECT IF(LAST(tr_total > 0), DATEDIFF(CURRENT_DATE(),event_date), NULL)
AS recency_lastbooking
FROM df
GROUP BY domain_userid
The error that I get is: Expression 'event_date' is not present in the GROUP BY list
I think if I use LAST(event_date) the query will return the last date in all the lines of the specific user, instead of return the last day the user had a purchase event.
P.S: I can use tr_total (total transaction) > 0 or tr_orderid (transaction order id) <> ""
Thank you!
I think you just want a window function:
SELECT DATE_DIFF(CURRENT_DATE,
MAX(tr_orderid) OVER (PARTITION BY domain_userid),
day
) AS recency_lastbooking
FROM df;