I have 2 tables Employee and Company_Employee.
Employee:
ID, FirstName
Company_Employee:
ID, Company_ID, Employee_ID
I want to do a search by First Name. I was thinking my query would look like:
select FirstName, ID from Employee where FirstName LIKE '%John%' and ID in (select id from Company_Employee)
This query returns no rows. Does anyone know how I can get the rows with a like by FirstName with these 2 tables?
Thanks!
Your query compares a company_employee.id with an employee.id. It should probably compare employee.id with company_employee.employee_id.
You can rewrite the query more clearly with a join:
select *
from employee e
join company_employee ce
on e.id = ce.Employee_ID
where e.FirstName like '%John%'
Something like this
SELECT
*
FROM
Employee e
INNER JOIN Company_Employee ce JOIN ON e.Id = ce.Id)
WHERE
FirstName LIKE '%JOHN%'
Related
I am running a query against a PeopleSoft database, and am unsure whether it is possible to get information from the same table, based on the initial query, in a single call. For example, the table I am hitting returns EmployeeID, FullName, FirstName, LastName, Position_NBR, and ReportsTo. But the ReportsTo is in the form of the manager's Position_NBR (found in same table), and I would like to get it in the name format. I would like to do something like this, but not sure if it is possible:
SELECT Employee_ID, FullName, FirstName, LastName, Position_NBR
,(Select Name From Employee Where Position_NBR='12345') As Manager
From Employee
Where EmployeeID='8675309'
Is this even possible, or do I need to fully return the first piece before I can use the second?
Yes, you can refer to the first table and it's best to limit the result of the subquery to 1 result (just in case the employee has 2 o more managers)
SELECT Employee_ID, FullName, FirstName, LastName, Position_NBR
,(Select Top 1 E2.Name From Employee as E2 Where E2.Position_NBR=Employee.Position_NBR) As Manager
From Employee
Where EmployeeID='8675309'
(T-SQL Syntax)
You should be able to do this by linking fields.
Here are some examples using the Oracle Database:
e.g.
SELECT
table1.Employee_ID, table1.Name, table1.Boss_ID
,(select table2.name from Employee table2 where table1.Boss_ID = table2.Employee_ID) As Manager
From
Employee table1
Where
table1.Employee_ID='333'
/
Alternately, try a SQL JOIN.
SELECT
table1.Employee_ID, table1.Name, table1.Boss_ID
,table2.Name As Manager
From
Employee table1
inner join Employee table2
on table1.Boss_ID = table2.Employee_ID
Where
table1.Employee_ID='333'
/
Here is a link to a working example with some fake data:
http://sqlfiddle.com/#!4/210580/7
I have a T-SQL query that has a subquery listing 2 names:
Coop
Bro
Code:
Select LastName
From Managers
Where Type = prefix;
I need to have the outer query use this above sub-query in something like an 'IN' statement, but it's not an exact match, but rather a BEGINS WITH. Something like the following with + '%':
Select *
From Employees
Where LastName In (Select LastName + '%'
From Managers
Where Type = prefix)
Desired query would return back outer query results such as:
Cooper
Coopersmith
Coopmoth
Brown
Brownly
Bronnan
...but, this is not working. I get 0 results.
You can use exists. Presumably, you intend something like this:
Select e.*
from Employees e
where exists (select 1
from managers m
where type = prefix and
e.LastName like m.LastName + '%'
)
Got it with similar to:
select * from employees e
inner join Managers m on e.lastname like m.lastname + '%' and m.type = prefix
I need to join two tables together to create a table with columns for employee id, employee name and their boss' name.
The 'hier' table
The 'employees' table
The query I wrote is almost working, putting an employee name in the right spot, but not the right employee:
SELECT em.emp_id, em.emp_name, em.emp_name AS boss_name
FROM employees em
LEFT JOIN hier h ON (h.boss_id = em.emp_name)
Which outputs:
I need to have each person's boss to have the right name, and in the case of Big Boss, 'N/A'. Like so:
You need a self join with Employee table
SELECT em.emp_id, em.emp_name, e1.emp_name AS boss_name
FROM employees em
LEFT JOIN employees em1 ON em.boss_id = em1.emp_id
I have a user table that stores the employeeId, lastName, firstName, department, hire date and mostRecentLogin.
I have another table that stores the employeeId, emailAddress.
The emailAddress table can have multiple rows for an employee if they have multiple email addresses.
I'm trying to return results that only show one row for each employee. I don't care which email address, just as long as it only picks one.
But all the queries I've tried always return all possible rows.
Here is my most recent attempt:
select *
from EmployeeInfo i
left join EmployeeEmail e ON i.employeeId = e.employeeId
where i.hireDate = 2015
and employeeId IN (
SELECT MIN(employeeId)
FROM EmployeeInfo
GROUP BY employeeId
)
But then again, this returns all possible rows.
Is there a way to get this to work?
Use a sub-query instead of a join:
select *
, (select top 1 E.EmailAddress from EmplyeeEmail E where E.employeeId = I.employeeId)
from EmployeeInfo I
where I.hireDate = 2015;
Note: If you change your mind and decide you do have a preference as to which email address is returned then just add an order by to the sub-query - otherwise it is truly unknown which one you will get.
This should work.
SELECT *
FROM EmployeeInfo
Left JOIN EmployeeEmail
ON EmployeeInfo.employeeId = EmployeeEmail.employeeId
WHERE EmployeeInfo.hireDate = '2015'
GROUP BY EmployeeInfo.employeeId;
I am trying to write a query that lists the name of a manager and the number of people they manage.
In the Manager table we have the managers name and id.
In the Employee table we have the employees name, id and managerID.
I don't understand how to get the count of the employees that a manager manages.
SELECT COUNT(e.EmpID), m.ManagerID
FROM Employee e
INNER JOIN Manager m
ON e.ManagerID= m.ManagerID
GROUP BY m.ManagerID
SELECT m.Name, COUNT(e.id) AS NumberOfEmployeesManaged
FROM Manager m INNER JOIN Employee e ON m.id = e.managerID
GROUP BY m.Name
That should do it I think, just a simple count of the employee ids after joining the manager and employee tables, grouped on manager name.
SELECT count(emp.empid), mgr.managerid
FROM Employee emp
INNER JOIN Manager mgr ON emp.managerid=mgr.managerid
GROUP BY mgr.managerid;
I don't know if you can use the COUNT aggregator in a JOIN. But you can run 2 queries. One would select the manager's name & id. The 2nd would look like this:
$id = the manager's id
SELECT COUNT(*) FROM Employee WHERE managerID=$id
Alternately, you could not use COUNT and run a query like this:
SELECT id FROM Employee WHERE managerID=$id
Then the # of resulting rows would be the count of employees managed by the manager.