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I have a date column Time in the database which i want to convert into 4 new columns
Week
day
month
year
I am using something like this on my test database
SELECT DATEPART(wk,`Time`), DATEPART(dd,`Time`),DATEPART(mm,`Time`),DATEPART(wk,`yyyy`), FROM `Test` WHERE 1
What is wrong in it?
In Sql server, you don't wrap your identifiers with `.
However, since Time is a data type in sql server, I've wrapped it with []:
Try this query instead:
SELECT DATEPART(Week,[Time]) As [Week],
DATEPART(Day,[Time]) As [Day],
DATEPART(Month,[Time]) As [Month],
DATEPART(Year,[Time]) As [Year]
FROM Test
Also, there was an extra comma after the last element in the select clause,
and the Where clause was meaningless, so I've removed it.
You have wrong syntax to fetch year and also extra (,) before From clause
Try as below:
SELECT DATEPART(wk,GETDATE()), DATEPART(dd,GETDATE()),DATEPART(mm,GETDATE()),DATEPART(yy,GETDATE())
SELECT DATEPART(week,GETDATE()), DATEPART(day,GETDATE()),DATEPART(month,GETDATE()),DATEPART(year,GETDATE())
SELECT DATEPART(wk,[Time]), DATEPART(dd,[Time]),DATEPART(mm,[Time]),DATEPART(yy,[Time]) From TableName
select datepart(week,GETDATE()) as [week]
, datepart(DAY,GETDATE()) as [DAY]
, datepart(month,GETDATE()) as [month]
,datepart(year,GETDATE()) as [year]
You could also simplify it by using YEAR,MONTH,DAY like this:
SELECT
YEAR(GETDATE()),
MONTH(GETDATE()),
DAY(GETDATE()),
DATEPART(WEEK,GETDATE())
I have a table TEST with a DATETIME field, like this:
ID NAME DATE
1 TESTING 2014-03-19 20:05:20.000
What I need a query returning this row and every row with date 03/19/2014, no matter what the time is. I tried using
select * from test where date = '03/19/2014';
But it returns no rows. The only way to make it work that I found is to also provide the time portion of the date:
select * from test where date = '03/19/2014 20:03:02.000';
use range, or DateDiff function
select * from test
where date between '03/19/2014' and '03/19/2014 23:59:59'
or
select * from test
where datediff(day, date, '03/19/2014') = 0
Other options are:
If you have control over the database schema, and you don't need the
time data, take it out.
or, if you must keep it, add a computed column attribute that has the time portion of the date value stripped off...
Alter table Test
Add DateOnly As
DateAdd(day, datediff(day, 0, date), 0)
or, in more recent versions of SQL Server...
Alter table Test
Add DateOnly As
Cast(DateAdd(day, datediff(day, 0, date), 0) as Date)
then, you can write your query as simply:
select * from test
where DateOnly = '03/19/2014'
Simple answer;
select * from test where cast ([date] as date) = '03/19/2014';
I am using MySQL 5.6 and there is a DATE function to extract only the date part from date time. So the simple solution to the question is -
select * from test where DATE(date) = '2014-03-19';
http://dev.mysql.com/doc/refman/5.6/en/date-and-time-functions.html
This works for me for MS SQL server:
select * from test
where
year(date) = 2015
and month(date) = 10
and day(date)= 28 ;
select * from test
where date between '03/19/2014' and '03/19/2014 23:59:59'
This is a realy bad answer. For two reasons.
1.
What happens with times like 23.59.59.700 etc.
There are times larger than 23:59:59 and the next day.
2.
The behaviour depends on the datatype.
The query behaves differently for datetime/date/datetime2 types.
Testing with 23:59:59.999 makes it even worse because depending on the datetype you get different roundings.
select convert (varchar(40),convert(date , '2014-03-19 23:59:59.999'))
select convert (varchar(40),convert(datetime , '2014-03-19 23:59:59.999'))
select convert (varchar(40),convert(datetime2 , '2014-03-19 23:59:59.999'))
-- For date the value is 'chopped'.
-- For datetime the value is rounded up to the next date. (Nearest value).
-- For datetime2 the value is precise.
use this
select * from TableName where DateTimeField > date() and DateTimeField < date() + 1
Try this
select * from test where Convert(varchar, date,111)= '03/19/2014'
you can try this
select * from test where DATEADD(dd, 0, DATEDIFF(dd, 0, date)) = '03/19/2014';
There is a problem with dates and languages and the way to avoid it is asking for dates with this format YYYYMMDD.
This way below should be the fastest according to the link below. I checked in SQL Server 2012 and I agree with the link.
select * from test where date >= '20141903' AND date < DATEADD(DAY, 1, '20141903');
Bad habits to kick : mis-handling date / range queries
You can use this approach which truncates the time part:
select * from test
where convert(datetime,'03/19/2014',102) = DATEADD(dd, DATEDIFF(dd, 0, date), 0)
-- Reverse the date format
-- this false:
select * from test where date = '28/10/2015'
-- this true:
select * from test where date = '2015/10/28'
Simply use this in your WHERE clause.
The "SubmitDate" portion below is the column name, so insert your own.
This will return only the "Year" portion of the results, omitting the mins etc.
Where datepart(year, SubmitDate) = '2017'
select *, cast ([col1] as date) <name of the column> from test where date = 'mm/dd/yyyy'
"col1" is name of the column with date and time
<name of the column> here you can change name as desired
select *
from invoice
where TRUNC(created_date) <=TRUNC(to_date('04-MAR-18 15:00:00','dd-mon-yy hh24:mi:ss'));
Test this query.
SELECT *,DATE(chat_reg_date) AS is_date,TIME(chat_reg_time) AS is_time FROM chat WHERE chat_inbox_key='$chat_key'
ORDER BY is_date DESC, is_time DESC
select * from invoice where TRANS_DATE_D>= to_date ('20170831115959','YYYYMMDDHH24MISS')
and TRANS_DATE_D<= to_date ('20171031115959','YYYYMMDDHH24MISS');
SELECT * FROM test where DATEPART(year,[TIMESTAMP]) = '2018' and DATEPART(day,[TIMESTAMP]) = '16' and DATEPART(month,[TIMESTAMP]) = '11'
use trunc(column).
select * from test t where trunc(t.date) = TO_DATE('2018/06/08', 'YYYY/MM/DD')
The CreatedDateTime is the table I am trying to filter by, using SQL
SELECT( * ) COUNT
FROM TABLE
WHERE CreatedDateTime like '2015''-''01''-''29%'
Return 0 Records
even though I have two records that have a CreatedDateTime of the following
CreatedDateTime
2015-01-29 07:33:25.700
2015-01-29 02:01:54.713
However the below works
like '%' + CONVERT(VARCHAR(12), GETDATE(), 0) + '%'
What am I doing incorrect here?
Datetime is not a string, Wildcard % is used to look for a pattern in a string value.
to get all the values in particular day you can simply cast it to date and that will ignore the time part and will bring back all the records for that particular date. Something like .....
SELECT COUNT(*)
FROM TABLE
WHERE CAST(CreatedDateTime AS DATE) = '20150129' --<-- use ASNI YYYYMMDD
Also always stick to ANSI standards, will protect you against environment specific issues.
Assuming it's stored as a proper datetime you can strip the time portion and use equivalence, since wildcard matching is for strings:
SELECT COUNT(*)
FROM TABLE
WHERE CAST(CreatedDateTime AS DATE) = '2015-01-29'
Try this..
SELECT( * ) COUNT
FROM TABLE
WHERE (DATEPART(yy, CreatedDateTime) = 2015
AND DATEPART(mm, CreatedDateTime) = 01
AND DATEPART(dd, CreatedDateTime) = 29)
I have a table as
NUM | TDATE
1 | 200712
2 | 200708
3 | 200704
4 | 20081210
where mytable is created as
mytable
(
num int,
tdate char(8) -- legacy
);
The format of tdate is YYYYMMDD.. sometimes the date part is optional.
So a date such as "200712" can be interpreted as 2007-12-01.
I want to write query such that i can treat tdate as a Date column and apply date comparison.
like
select num, tdate from mytable where tdate
between '2007-12-31 00:00:00' and '2007-05-01 00:00:00'
So far i tried this
select num, tdate,
CAST(LEFT(tdate,6)
+ COALESCE(NULLIF(SUBSTRING(CAST(tdate AS VARCHAR(8)),7,8),''),'01') AS Date)
from mytable
SQL Fiddle
How can I use the above converted date (3rd column ) for comparison? (needs a join?)
Also is there a better way to do this?
Edit: I have no control over the table scheme for now.. we have suggested the change to the DB team..for now have to stick with char(8) .
I think this a better way to get your fixed date:
SELECT CAST(LEFT(RTRIM(tdate) + '01',8) AS DATE)
You can create a subquery/cte with the date cast properly:
;WITH cte AS (select num, tdate,CAST(LEFT(RTRIM(tdate)+ '01',8) AS DATE)'FixedDate'
from mytable )
select num, FixedDate
from cte
where FixedDate
between '2007-12-31' and '2007-05-01'
Or you can just use your fixed date in the query directly:
select num, tdate
from mytable
where CAST(LEFT(RTRIM(tdate)+ '01',8) AS DATE) between '2007-12-31' and '2007-05-01'
Ideally you would add the fixed date field to your table so that queries can benefit from indexing the date.
Note: Be wary of BETWEEN with DATETIME as the time portion can result in undesired results if you really only care about the DATE portion.
'2007-12-31 00:00:00' > '2007-05-01 00:00:00', so your BETWEEN clause will never return any records.
This will work, with a subquery, and with the dates flipped:
select num, tdate, formattedDate
from
(
select num, tdate
,
CAST(LEFT(tdate,6) + COALESCE(NULLIF(SUBSTRING(CAST(tdate AS VARCHAR(8)),7,8),''),'01') AS Date) as formattedDate
from mytable
) a
where formattedDate between '2007-05-01 00:00:00' and '2007-12-31 00:00:00'
sqlFiddle here
I think you should avoid storing date in string type fields. If that is something you have to live with try following solution.
Since you are having yyyymmdd or yyyymm format you can first get them all in yyyymmdd format which is Culture independent ISO format and then use style 112 to convert into Date for comparison:
--Culture independent solution
;with cte as (
select num, tdate,
convert(date,left(rtrim(tdate) + '01',8),112) mydate --yyyymmdd format
from mytable
)
select num,tdate,mydate
from cte
where mydate between convert(date,'20071231',112) and --Values are in yyyymmdd format
convert(date,'20070501',112)
Yet another way to turn your string values into dates would be to use REPLACE:
SELECT num, tdate
FROM mytable
WHERE CAST(REPLACE(tdate, ' ', '01') AS date) BETWEEN #date1 AND #date2
;
If you really want to both return the converted date value and use it for filtering, you can employ CROSS APPLY to avoid repeating the logic:
SELECT t.num, t.tdate, x.date
FROM mytable AS t
CROSS APPLY (SELECT CAST(REPLACE(t.tdate, ' ', '01') AS date)) AS x (date)
WHERE x.date BETWEEN #date1 AND #date2
;
This method assumes that your char(8) strings are formatted as either YYYYMMDD or YYYYMM, although the method will work without any changes if you decide to start using values formatted as just YYYY in addition to the other two formats (to imply the beginning of a year, just like a YYYYMM implies the beginning of a month).
with date_cte(num,date)as
(select num,CAST(LEFT(tdate,6)
+ COALESCE(NULLIF(SUBSTRING(CAST(tdate AS VARCHAR(8)),7,8),''),'01') AS Date)
from mytable)
select t1.num, t1.tdate,t2.date
from mytable t1 join date_cte t2 on t1.num=t2.num
where t2.date
between '2007-12-31 00:00:00' and '2007-05-01 00:00:00'
I don't have the time to test right now, but something like this may work...
select num, tdate
from mytable
WHERE CAST(LEFT(tdate,6)
+ COALESCE(NULLIF(SUBSTRING(CAST(tdate AS VARCHAR(8)),7,8),''),'01') AS Date) BETWEEN CAST('2007-12-31 00:00:00' as smalldatetime) and CAST('2007-05-01 00:00:00' as smalldatetime)
My proposal would be to add a date field to your table. If your table is regularly updated, fill it from the legacy field through a stored proc on a regular schedule (either trigger or job).
You'll then be able to use the date as ... a date, without all these tricks, turnarounds, and other approximations which are all potential source for confusion, mistakes and questionable results.
I am trying to get the number of bookings and their total value by date for every day within a given date range.
My table looks like:
BookingId (int)
BookingFare (decimal)
BookingDateTime (datetime)
I can convert BookingDateTime to a date only by using:
SELECT CONVERT(varchar(8), BookingDateTime, 112) as BookingDateOnly
FROM [TaxiBookingOnline].[dbo].[Bookings]
What I'm after is something like this:
Date Bookings Value
2013-07-10 10 256.24
2013-07-11 12 321.44
2013-07-12 14 311.53
I get the feeling I should be aliasing the table, joining it to itself and then using 'GROUP BY' but I am failing to get this to work.
Any help would be much appreciated.
Thanks.
How about
select
cast(BookingDateTime as date) [Date],
count(*) [Bookings],
sum(BookingFare) [Value]
from t
group by cast(BookingDateTime as date)
SELECT CONVERT(VARCHAR(8), BookingsDateTime, 112) AS [Date],
COUNT(*) AS [Bookings],
SUM(BookingsFare AS [Value]
FROM MyTable
GROUP BY DATEADD(dd, 0, DATEDIFF(dd, 0, BookingDateTime))
Group by SELECT DATEADD(dd, 0, DATEDIFF(dd, 0, dateColumn)) which will effectively get the date portion of the datetime, then you can use count or sum as necessary on the grouped values.
EDIT: If you're using SQL Server >= 2008, you can cast to date (like #AlexK has done) otherwise you have to hack around it using DATEADD.
Following is the code. Replace Date1 and Date2 with the date range values:
SELECT
CONVERT(varchar(8), BookingDateTime, 112) as BookingDateOnly, BookingID Bookings,Sum(BookingFare)Value
FROM
[TaxiBookingOnline].[dbo].[Bookings]
WHERE BookingDateTime Between 'Date1' and 'Date2'
GROUP BY
BookingDateTime,BookingID
SELECT
CONVERT(DATE,BookingDateTime) BookingDate,
COUNT(BookingID) Bookings,
SUM(BookingFare) BookingFare
FROM TaxiBookingOnline.dbo.Bookings