Im trying to add some short file names to a Wise installer to fix validation errors, which is simple for the most part. However if I have the following two files:
LongFile1.dll
LongFile1.EN.dll
Should these be:
LongFi~1.dll and
LongFi~2.dll ? Or do I have to do anything special becuase of the .EN.dll?
Yes, they are named LONGFI~1.DLL and LONGFI~2.DLL (all letters capitalized in 8.3 file format). Which is which is determined by the order they are created.
In a cmd window you can type dir /x to view the short file names as well.
Related
I'm using sql developer.
I want to run some scripts.
I don't want to have to include the folder name in the call to each script.
But I also want to use a variable to include the directory to look in (the working directory).
I can do this but i am having trouble with folder names with spaces (this is in windows).
Can anyone help me work out how to do this without having to rename my folder to remove spaces?
define dir="c:\Users\xx\Google Drive\Analytics\Recruitment\NSL\2. Data Understanding\Code"
#&dir\cb_nsl_impairments.sql;
Returns error
SP2-0310: Unable to open file: "c:\Users\xx\Google.sql"
Oops. Solved it.
Just needed double quotes around the script call:
#"&dir\cb_nsl_impairments.sql"
I just downloaded psychopy this morning and have spent the day trying to figure out how to work with builder view. I watched the youtube video "Build your first PsychoPy experiment (Stroop task)" by Jon Pierce. In his video he was explaining how to make a conditions file with excel that would be used in his experiment. I wanted to make a very similar test where images would appear and subjects would be required to give a yes or no answer to them (the correct answer is already predefined). In his conditions file he had the columns 'word' 'colour' and 'corrANS'. I was wondering if instead of a 'word' column, I can have an 'image' column. In this column I would like to upload all my images to them in the same way I would words, and have them correlated to a correct answer of either 'yes' or 'no'. We tried doing this and uploaded images to the conditions file, but we haven't had any success in running the test successfully and were hoping somebody could help us.
Thank you in advance.
P.S. we are not familiar with python, or code in general, so we were hoping to get this running using the builder view.
EDIT: Here is the error message we are receiving when running the program
#### Running: C:\Users\mr00004\Desktop\New folder\1_lastrun.py
4.8397 ERROR Couldn't find image file 'C:/Users/mr00004/Desktop/New folder/PPT Retention 1/ Slide102.JPG'; check path?
Traceback (most recent call last):
File "C:\Users\mr00004\Desktop\New folder\1_lastrun.py", line 174, in
image.setImage(images)
File "C:\Program Files (x86)\PsychoPy2\lib\site-packages\psychopy-1.80.03-py2.7.egg\psychopy\visual\image.py", line 271, in setImage
maskParams=self.maskParams, forcePOW2=False)
File "C:\Program Files (x86)\PsychoPy2\lib\site-packages\psychopy-1.80.03-py2.7.egg\psychopy\visual\basevisual.py", line 652, in createTexture
% (tex, os.path.abspath(tex))#ensure we quit
OSError: Couldn't find image file 'C:/Users/mr00004/Desktop/New folder/PPT Retention 1/ Slide102.JPG'; check path? (tried: C:\Users\mr00004\Desktop\New folder\PPT Retention 1\ Slide102.JPG)
Yes, certainly, that is exactly how PsychoPy is designed to work. Simply place the image names in a column in your conditions file. You can then use the name of that column in the Builder Image component's "Image" field. The appropriate image file for a given trial will be selected.
It is difficult to help you further, though, as you haven't specified what went wrong. "we haven't had any success" doesn't give us much to go on.
Common problems:
(1) Make sure you use full filenames, including extensions (.jpg, .png, etc). These aren't always visible in Windows at least I think, but they are needed by Python.
(2) Have the images in the right place. If you just use a bare filename (e.g. image01.jpg), then PsychoPy will expect that the file is in the same directory as your Builder .psyexp file. If you want to tidy the images away, you could put them in a subfolder. If so, you need to specify a relative path along with the filename (e.g. images/image01.jpg).
(3) Avoid full paths (starting at the root level of your disk): they are prone to errors, and stop the experiment being portable to different locations or computers.
(4) Regardless of platform, use forward slashes (/) not backslashes (\) in your paths.
make a new folder in H drive and fill in the column of image in psychopy as e.g. 'H:\psych\cat.jpg' it works for me
I thought for sure there would be an SO question on this, but I haven't been able to find one.
I have 2 SQL files, myFile1.sql and myFile2.sql. myFile1.sql calls myFile2.sql like so:
-- In myFile1.sql:
#scripts/myFile2
This works with no problem, but now I'd like to pass an argument to the file. I've tried doing the following, with no success (results in a File Not Found exception):
#scripts/myFile2 'ImAnArgument'
Does anyone know what the syntax would be to do this?
I'm guessing your problem is that scripts/myFile2.sql is a relative path from the script it is located in. If that is so, then it is following that path from the directory where SQL*Plus was started (the current working directory). If this is the problem, then it's not the parameter that is the issue, but rather that SQL*Plus can't find the file. In this case, you should use ##, which invokes the path relative to the file it's located in.
The parameter should work just as you proposed (documentation). Parameters provided when invoking a file are placed into substitution variables (rather than bind variables) and can be referenced by using an ampersand followed by the argument number. In your example, 'ImAnArgument' would be &1.
After many attempts, I wasn't able to pass a parameter in (and I still don't understand why not). But here is what I did to get the same affect:
-- In myFile1.sql:
DEFINE my_arg = 'ImAnArgument';
#scripts/myFile2
Then
-- In myFile2.sql
-- Do stuff using the variable my_arg, such as
SELECT my_arg FROM my_table;
i try to rename a file using vb.net in this way:
my.computer.filesyste.rename(oldname,newname)
But if i use a software to recover files deleted, i find a file named :"_ldname", and if i recovery the file "_ldname" i have, in this way, two files equals.
Can i do this without have a duplicate of my file?
Best regards
Sebastiano
You cannot, this is a windows filesystem limitation and nothing to do with programming. Two files cannot have the same name in the same location.
The recovery software should be forcing a rename to Myfile(1).txt or something like that to distinguish between the two files.
You could always use:
If File.Exists(path) = False Then
To make sure the file doesn't already exists. Then if it does exist you could add a "(1)" to the file name.
By default AutoCAD installs a text based file called acad2010.lsp at the set location below
Dim FILE_NAME As String = "C:\Program Files\AutoCAD 2010\Support\acad2010.lsp"
However it my be that the user/ administrator/ or third party has changed the location of this file. Is it possible to then locate it using the following
Dim FILE_NAME As String = "C:\*\acad2010.lsp"
In other words search the entire c:\ drive for file acad2010.lsp?
If this doesn't work can you please let me know what would?
You could search for it with an FSO. It's not going to be fast however you do it but this is the fastest way I can think of.
http://www.microbion.co.uk/developers/fso.htm should give you a rough idea of how it's done.
Your solution will not work. Is not possible to locate it using *. (BTW is possible in ms-builds scripts). The only way of doing it is:
1- Create a FindFile function (check for example
http://xlvba.3.forumer.com/index.php?showtopic=125)
2- Use it to locate the exact path of the file. (It could be really time
consuming)
3- From this point your code is the same...
Unfortunately, you can't use wildcards in a filepath. You have two options:
Prompt the user for the file location using the "Open File" dialog. The code to do this varies based on which Office product you are using. In Excel, you would use the Application.FindFile method (more info here).
Write your own function to search the filesystem for the file. Microsoft provides an example here.
If that file is used by internal functions of the application, the installer will have recorded a registry key for the file's location.
Open regedit.exe and search for the file name and path.
You can read a registry entry using this VBA one-liner:
CreateObject("WScript.Shell").RegRead(strRegPath)
You may need a terminating backslash on the key address, but that's a safe and simple registry access method. More details on the MSDN site:
https://msdn.microsoft.com/en-us/library/x05fawxd%28v=vs.84%29.aspx