I hope someone could help me on this.
I want to add a month to a database date, but I want to prevent two jumping over month on those days at the end.
For instance I may have:
Jan 31 2009
And I want to get
Feb 28 2009
and not
March 2 2009
Next date would be
March 28 2009
Jun 28 2009
etc.
Is there a function that already perform this kind of operation in oracle?
EDIT
Yeap. I want to copy each month all the records with some status to the next ( so the user don't have to enter again 2,000 rows each month )
I can fetch all the records and update the date manually ( well in an imperative way ) but I would rather let the SQL do the job.
Something like:
insert into the_table
select f1,f2,f3, f_date + 30 /* sort of ... :S */ from the_Table where date > ?
But the problem comes with the last day.
Any idea before I have to code something like this?
for each record in
createObject( record )
object.date + date blabala
if( date > 29 and if februrary and the moon and the stars etc etc 9
end
update.... et
EDIT:2
Add months did the trick.
now I just have this:
insert into my_table
select f1, add_months( f2, 1 ) from my_table where status = etc etc
Thanks for the help.
Oracle has a built-in function ADD_MONTHS that does exactly that:
SQL> select add_months(date '2008-01-31',1) from dual;
ADD_MONTHS(
-----------
29-FEB-2008
SQL> select add_months(date '2008-02-29',1) from dual;
ADD_MONTHS(
-----------
31-MAR-2008
I think you're looking for LAST_DAY:
http://download.oracle.com/docs/cd/B28359_01/olap.111/b28126/dml_functions_2006.htm
I just did:
select add_months(TO_DATE('30-DEC-08'), 2) from dual
and got
28-FEB-2009
No need to use LAST_DAY. If you went that route, you could create a function that:
1. takes a date
2. Changes the day to the first of the month.
3. Add a month.
4. Changes the day to the LAST_DAY for that month.
I think you'll have to write it on your own, My advice is first to evaluate the "last day of the month" with this method:
Add one month (not 30 days, one month!)
Find first day of the month (should be easy)
substract one day
Then compare it to your "plus x days" value, and choose the lowest one (I understood the logic behind the jump from 31/Jan to 28/Feb, but I don't get it for the jump from 28-Feb to 28-Mar)
It sounds like you want the current month plus one (with appropriate rollover in December)
and the minimum of the last day of that month and the current day.
Related
I am brand new to Oracle. I have figured out most of what I need but one field is driving me absolutely crazy. Seems like it should be simple but I think my brain is fried and I just can't get my head around it. I am trying to produce a Sales report. I am doing all kinds of crazy things based on the Invoice Date. The last thing I need to do is to be able to create a Week Number so I can report on weekly sales year vs year. For purposes of this report my fiscal year starts exactly on December 1 (regardless of day of week it falls on) every year. For example, Dec 1-7 will be week 1, etc. I can get the week number using various functions but all of them are based on either calendar year or ISO weeks. How can I easily generate a field that will give me the number of the week since December 1? Thanks so much for your help.
Forget about the default week number formats as that won't work for this specific requirement. I'd probably subtract the previous 1 December from invoice date and divide that by 7. Round down, add 1 and you should be fine.
select floor(
(
trunc(invoiceDate) -
case
-- if December is current month, than use 1st of this month
when to_char(invoiceDate, 'MM') = '12' then trunc(invoiceDate, 'MM')
-- else, use 1st December of previous year
else add_months(trunc(invoiceDate, 'YYYY'), -1)
end
) / 7
) + 1
from dual;
I have a query which uses needs to know how many days passed since 1st of January in the current year.
Which means that if the query runs for example in:
2nd Jan 2017 than it should return 2 (as 2 days passed since 1st Jan
2017).
10th Feb 2016 than it should return 41 (as 41 days passed since 1st
Jan 2016).
basically it needs to take Current Year from Curent Date and count the days since 1/1/(Year).
i have the current year with: SELECT EXTRACT(year FROM CURRENT_DATE);
I created the 1st of Jan with:
select (SELECT EXTRACT(year FROM CURRENT_DATE)::text || '-01-01')::date
How do I get the difference from this date to Current_Date?
Basically this question can be Given two dates, how many days between them?
Something like age(timestamp '2016-01-01', timestamp '2016-06-15') isn't good because I need the result only in days. while age gives in years,months and days.
An easier approach may be to extract the day of year ("doy") field from the date:
db=> SELECT EXTRACT(DOY FROM CURRENT_DATE);
date_part
-----------
41
And if you need it as a number, you could just cast it:
db=> SELECT EXTRACT(DOY FROM CURRENT_DATE)::int;
date_part
-----------
41
Note: The result 41 was produced by running the query today, February 9th.
Given two dates, how many days between them
Just subtract one from the other.
In your case you could just round the current_date to the start of the year and subtract that from the current date:
select current_date - date_trunc('year', current_date)::date
The ::date cast is necessary to get the result as an integer, otherwise the result will be an interval.
Another solution is to use DATEDIFF
SELECT DATE_PART('day', now()::timestamp - '2016-01-01 00:00:00'::timestamp);
Getting the month for the current date is, obviously, straight forward, but I'm needing to get the month name with a different end date.
I need to get the month name with the start date of the month being the first Thursday after the first Wednesday of the month and the end date of the month being the first Wednesday of the following month. It's for an accounting thing, so I'm not going to argue with the spec!
e.g. for 2014, January would run from 9th Jan - 5th Feb, February would run from 6th February - 5th March, March would run from 6th March - 2nd April.
I would suggest that you create a table with your 'accounting months' in it, having a start date, end date and month name columns.
You could then query this to find the row where your date is between the start and end dates and return the month name. Putting this into a scalar function would then allow it to be reusable and relatively easily updated for next years months as well.
I think, as per Paddy's answer, a lookup table is the simplest thing to do. Here's one way to generate the rows for it:
; With Numbers(n) as (
select 4 union all select 5
), Months as (
select CONVERT(date,'20010104') as StartDt,CONVERT(date,'20010207') as EndDt,
DATENAME(month,'20010103') as Month
union all
select DATEADD(week,n1.n,StartDt),DATEADD(week,n2.n,EndDt),
DATENAME(month,DATEADD(week,n1.n,StartDt))
from Months,Numbers n1,Numbers n2 --Old-skool join, just for once
where DATEPART(day,DATEADD(week,n1.n,StartDt)) between 2 and 8 and
DATEPART(day,DATEADD(week,n2.n,EndDt)) between 1 and 7 and
StartDt < '21000101'
)
select * from Months option (maxrecursion 0)
(CW since this is effectively just an extension to Paddy's answer but I don't want to edit their answer, nor is it suitable for a comment
I am trying to write a query to generate automated report. This report is to run for last month's transactions it should run on 1st of every month. I have job to run this report to run 1st of every month. But how can I make this query to choose no of days in a month? (some months will have 30 and some will have 31 and in feb no of days changes based on leap year).
Here one more requirement is I only have to pass one parameter in the query. below is example of query that I have now
select id,name,address,trans_dt from tab1 where trans_dt between to_date('&1','MM-DD-YYYY')-30 AND to_date('&1','MM-DD-YYYY');
The above query is generating last 30 days transactions, but it will be wrong if no days for month is 31 or 28. I am using oracle 11r2 as database. Please help in writing this.
mySQL
SELECT
id,
NAME,
address,
trans_dt
FROM
tab1
WHERE
MONTH(trans_dt) = 02 /* Param for month passed in */
AND
YEAR(trans_dt) = YEAR(CURDATE())
Oracle
SELECT
id,
NAME,
address,
trans_dt
FROM
tab1
WHERE
to_char( dt_column, 'mm' ) = 02 /* Param for month passed in */
AND
EXTRACT(YEAR FROM DATE trans_dt) = trunc(sysdate, 'YEAR')
Maybe this can work? I only really know mySQL
Found solution but forget to reply here. Here is my solution
select id,name,address,trans_dt from tab1 where trans_dt between trunc(trunc(sysdate,'MM')-1,'MM') and trunc(sysdate,'MM');
above will give you report from 1st day of month to last day of month from calender.
select id
,name
,address
,trans_dt from tab1
where trans_dt between to_date(p_dt,'yyyy-mmm-dd') and add_months(to_date(p_dt,'yyyy-mmm-dd'))
I have a MySQL member table, with a DOB field which stores all members' dates of birth in DATE format (Notice: it has the "Year" part)
I'm trying to find the correct SQL to:
List all birthdays within the next 14 days
and another query to:
List all birthdays within the previous 14 days
Directly comparing the current date by:
(DATEDIFF(DOB, now()) <= 14 and DATEDIFF(DOB, now()) >= 0)
will fetch nothing since the current year and the DOB year is different.
However, transforming the DOB to 'this year' won't work at all, because today could be Jan 1 and the candidate could have a DOB of Dec 31 (or vice versa)
It will be great if you can give a hand to help, many thanks! :)
#Eli had a good response, but hardcoding 351 makes it a little confusing and gets off by 1 during leap years.
This checks if birthday (dob) is within next 14 days. First check is if in same year. Second check is if its say Dec 27, you'll want to include Jan dates too.
With DAYOFYEAR( CONCAT(YEAR(NOW()),'-12-31') ), we are deciding whether to use 365 or 366 based on the current year (for leap year).
SELECT dob
FROM birthdays
WHERE DAYOFYEAR(dob) - DAYOFYEAR(NOW()) BETWEEN 0 AND 14
OR
DAYOFYEAR( CONCAT(YEAR(NOW()),'-12-31') ) - ( DAYOFYEAR(NOW()) - DAYOFYEAR(dob) ) BETWEEN 0 AND 14
Here's the simplest code to get the upcoming birthdays for the next x days and previous x days
this query is also not affected by leap-years
SELECT name, date_of_birty
FROM users
WHERE DATE(CONCAT(YEAR(CURDATE()), RIGHT(date_of_birty, 6)))
BETWEEN
DATE_SUB(CURDATE(), INTERVAL 14 DAY)
AND
DATE_ADD(CURDATE(), INTERVAL 14 DAY)
My first thought was it would be easy to just to use DAYOFYEAR and take the difference, but that actually gets kinda trick near the start/end of a yeay. However:
WHERE
DAYOFYEAR(NOW()) - DAYOFYEAR(dob) BETWEEN 0 AND 14
OR DAYOFYEAR(dob) - DAYOFYEAR(NOW()) > 351
Should work, depending on how much you care about leap years. A "better" answer would probably be to extract the DAY() and MONTH() from the dob and use MAKEDATE() to build a date in the current (or potential past/following) year and compare to that.
Easy,
We can obtain the nearer birthday (ie the birthday of this year) by this code:
dateadd(year,datediff(year,dob,getdate()),DOB)
use this in your compares ! it will work.
There are a number of options, I would first try to transform by number of years between current year and row's year (i.e. Add their age).
Another option is day number within the year (but then you have still to worry about the rollover arithmetic or modulo).
This is my query for the 30 days before check:
select id from users where
((TO_DAYS(concat(DATE_FORMAT(NOW(),'%Y'), '-', DATE_FORMAT(date_of_birth, '%m-%d')))-TO_DAYS(NOW()))>=-30
AND (TO_DAYS(concat(DATE_FORMAT(NOW(),'%Y'), '-', DATE_FORMAT(date_of_birth, '%m-%d')))-TO_DAYS(NOW()))<=0)
OR (TO_DAYS(concat(DATE_FORMAT(NOW(),'%Y'), '-', DATE_FORMAT(date_of_birth, '%m-%d')))-TO_DAYS(NOW()))>=(365-31)
and 30 days after:
select id from users where
((TO_DAYS(NOW())-TO_DAYS(concat(DATE_FORMAT(NOW(),'%Y'), '-', DATE_FORMAT(date_of_birth, '%m-%d'))))>=-31
AND (TO_DAYS(NOW())-TO_DAYS(concat(DATE_FORMAT(NOW(),'%Y'), '-', DATE_FORMAT(date_of_birth, '%m-%d'))))<=0)
OR (TO_DAYS(NOW())-TO_DAYS(concat(DATE_FORMAT(NOW(),'%Y'), '-', DATE_FORMAT(date_of_birth, '%m-%d'))))>=(365-30)
My solution is as follow:
select cm.id from users cm where
date(concat(
year(curdate()) - (year(subdate(curdate(), 14)) < year(curdate())
and month(curdate()) < month(cm.birthday)) + (year(adddate(curdate(), 14)) > year(curdate())
and month(curdate()) > month(cm.birthday)), date_format(cm.birthday, '-%m-%d'))) between subdate(curdate(), 14)
and adddate(curdate(), 14);
It looks like it works fine when the period captures the current and next year or the current and previous year