I am using mssql and am having trouble using a subquery. The real query is quite complicated, but it has the same structure as this:
select
customerName,
customerId,
(
select count(*)
from Purchases
where Purchases.customerId=customerData.customerId
) as numberTransactions
from customerData
And what I want to do is order the table by the number of transactions, but when I use
order by numberTransactions
It tells me there is no such field. Is it possible to do this? Should I be using some sort of special keyword, such as this, or self?
use the field number, in this case:
order by 3
Sometimes you have to wrestle with SQL's syntax (expected scope of clauses)
SELECT *
FROM
(
select
customerName,
customerId,
(
select count(*)
from Purchases
where Purchases.customerId=customerData.customerId
) as numberTransactions
from customerData
) as sub
order by sub.numberTransactions
Also, a solution using JOIN is correct. Look at the query plan, SQL Server should give identical plans for both solutions.
Do an inner join. It's much easier and more readable.
select
customerName,
customerID,
count(*) as numberTransactions
from
customerdata c inner join purchases p on c.customerID = p.customerID
group by customerName,customerID
order by numberTransactions
EDIT: Hey Nathan,
You realize you can inner join this whole table as a sub right?
Select T.*, T2.*
From T inner join
(select
customerName,
customerID,
count(*) as numberTransactions
from
customerdata c inner join purchases p on c.customerID = p.customerID
group by customerName,customerID
) T2 on T.CustomerID = T2.CustomerID
order by T2.numberTransactions
Or if that's no good you can construct your queries using temporary tables (#T1 etc)
There are better ways to get your result but just from your example query this will work on SQL2000 or better.
If you wrap your alias in single ticks 'numberTransactions' and then call ORDER BY 'numberTransactions'
select
customerName,
customerId,
(
select count(*)
from Purchases
where Purchases.customerId=customerData.customerId
) as 'numberTransactions'
from customerData
ORDER BY 'numberTransactions'
The same thing could be achieved by using GROUP BY and a JOIN, and you'll be rid of the subquery. This might be faster too.
I think you can do this in SQL2005, but not SQL2000.
You need to duplicate your logic. SQL Server isn't very smart at columns that you've named but aren't part of the dataset in your FROM statement.
So use
select
customerName,
customerId,
(
select count(*)
from Purchases p
where p.customerId = c.customerId
) as numberTransactions
from customerData c
order by (select count(*) from purchases p where p.customerID = c.customerid)
Also, use aliases, they make your code easier to read and maintain. ;)
Related
I have a table here in which I want to write a SELECT query in SQL Server that allows me to get the following:
For each unique combination of SalesPerson x Country, get only the rows with the latest Upload_DateTime
However, I am trying to do a group-by and inner join, but to no avail. My code is something like this:
SELECT t1.[SalesPerson], t1.[Country], MAX(t1.[Upload_DateTime]) as [Upload_DateTime]
FROM [dbo].[CommentTable] AS t1
GROUP BY t1.[SalesPerson], t1.[Country]
INNER JOIN SELECT * FROM [dbo].[CommentTable] as t2 ON t1.[SalesPerson] = t2.[SalesPerson], t1.[Country] = t2.[Country]
It seems like the GROUP BY needs to be done outside of the INNER JOIN? How does that work? I get an error when I run the query and it seems my SQL is not right.
Basically, this subquery will fetch the person, the country and the latest date:
SELECT
SalesPerson, Country, MAX(uplodaed_datetime)
FROM CommentTable
GROUP BY SalesPerson, Country;
This can be used on a lot of ways (for example with JOIN or with an IN clause).
The main query will add the remaing columns to the result.
Since you tried a JOIN, here the JOIN option:
SELECT
c.id, c.SalesPerson, c.Country,
c.Comment, c.uplodaed_datetime
FROM
CommentTable AS c
INNER JOIN
(SELECT
SalesPerson, Country,
MAX(uplodaed_datetime) AS uplodaed_datetime
FROM CommentTable
GROUP BY SalesPerson, Country) AS sub
ON c.SalesPerson = sub.SalesPerson
AND c.Country = sub.Country
AND c.uplodaed_datetime = sub.uplodaed_datetime
ORDER BY c.id;
Try out: db<>fiddle
Imagine I have a product table and an orders table. I want to list out the most recent order for each product
I imagine something like this
select name, description, price, max(date)
from product
join order on order.item = product.name
group by order.item
But my postgres DB complains that I cant have raw fields (sqlite doesnt complain) I need to have aggregate function. I can put min() for each column but that seems like a waste, given that all the values for a particular product are always the same. I wondered about 'distinct' but that doesnt seem to help here
NOTE - I need standard portable SQL , not specific to any given engine.
In Postgres, you can use distinct on:
select distinct on (o.item) p.name, description, price, date
from product p join
order o
on o.item = p.name
order by o.item, date desc;
I added aliases into the query. I strongly advise you to always qualify all column names. I would do that but I don't know where they come from in most cases.
If you require standard ANSI SQL you can use a window function:
select *
from (
select p.name, p.description, p.price,
o.date,
max(o.date) over (partition by o.item) as last_date
from product p
join "order" o on o.item = p.name
) t
where date = last_date;
But in Postgres distinct on () is usually a lot faster.
If it was Oracle or MS you would need to group by all the fields in your select that aren't aggregate functions.
It would be an extra line before "order by" with "group by p.name, description, price, date" ...
About Postgres I am not so sure, but probably it will work.
You can use correlated subquery :
select p.name, p.description, p.price, o.date
from product p inner join
order o
on o.item = p.name
where o.date = (select max(o1.date)
from order o1
where o1.item = p.name
);
I'm an entry level trying to learn more about SQL,
I have a question "can we use order by in subquery?" I did look for some article says no we could not use.
But on the other hand, I saw examples using top(n) with order by in subquery:
select c.CustomerId,
c.OrderId
from CustomerOrder c
inner join (
select top 2
with TIES CustomerId,
COUNT(distinct OrderId) as Count
from CustomerOrder
group by CustomerId
order by Count desc
) b on c.CustomerId = b.CustomerId
So now I'm bit confused.
Could anyone advise?
Thank you very much.
Yes, you are right we cannot use order by in a inner query. Because it is acting as a table. A table in itself needs to be sorted when queried for different purposes.
In your query itself the inner query is select some records using Top 2. Eventhough these are top 2 records only, they form a table with 2 records which is enough for it to recognized as a table and join it with another table
The right query will be:-
SELECT * FROM
(
SELECT c.CustomerId, c.OrderId, DENSE_RANK() OVER(ORDER BY b.count DESC) AS RANK
FROM CustomerOrder c
INNER JOIN
(SELECT CustomerId, COUNT(distinct OrderId) as Count
FROM CustomerOrder GROUP BY CustomerId) b
ON c.CustomerId = b.CustomerId
) a
WHERE RANK IN (1,2);
Hope I have answered your question.
Yes we can use order by clause in sub query, for example i have a table named as product (check the screen shot of table http://prntscr.com/f15j3z). Chek this query on your side and revert me in case of any doubt.
select p1.* from product as p1 where product_id = (select p2.product_id from product as p2 order by product_id limit 0,1)
yes we can use order by in subquery,but it is pointless to use it.
It is better to use it in the outer query.There is no use of ordering the result of subquery, because result of inner query will become the input for outer query and it does not have to do any thing with the order of the result of subquery.
At http://www.dofactory.com/sql/sandbox I'm experimenting with submitting my own SQL queries against their sample database to become better at SQL. What I want to do is to select all countries from Customer that have exactly the fewest number of tuples. Here is my query attempt:
SELECT a.Country
FROM [Customer] a, (SELECT COUNT(*) AS Tot
FROM [Customer]
GROUP BY Country) b
GROUP BY a.Country
HAVING COUNT(*) = MIN(b.Tot)
However, the website returns an empty table instead of the correct result which is (Ireland, Norway, Poland). The correct result is easily realized by grouping the table by country and using COUNT(*), and then looking at the countries that have the smallest COUNT(*) value out of all COUNT(*) values. I would like some advice on how to generate the correct result without any assumptions about the table's data.
I would do this using SELECT TOP 1 WITH TIES:
SELECT TOP 1 WITH TIES c.Country
FROM Customer c
GROUP BY c.Country
ORDER BY COUNT(*) ASC;
Two notes:
When using table aliases, make them abbreviations for the tables. This makes the query much easier to follow.
Never use commas in the FROM clause. Always use proper, explicit JOIN syntax.
Learned somtihing new(WITH TIES) from Gordon Linoff, again...
Here my solution without it...
Select a.Country from [Customer] a
group by a.Country
having count(*) = (select min(b.Tot) from (SELECT COUNT(*) AS Tot FROM [Customer] GROUP BY Country) b)
If you are not using sql 2012 then,
declare #Fewer int=2
;With CTE as
(
select c.*
,ROW_NUMBER()over(partition by countryid order by customerid)rn
from dbo.Customers C
)
select * from cte
where rn<=#Fewer
Please note that I have seen a similar query here, but think my query is different enough to merit a separate question.
Suppose that there is a database with the following tables:
customer_table with customer_ID (key field), customer_name
orders_table with order_ID (key field), customer_ID, product_ID
Now suppose I would like to find the names of all the customers who have ordered more than 10 different types of product, and the number of types of products they ordered. Multiple orders of the same product does not count.
I think the query below should work, but have the following questions:
Is the use of count(distinct xxx) generally allowed with a "group by" statement?
Is the method I use the standard way? Does anybody have any better ideas (e.g. without involving temporary tables)?
Below is my query
select T1.customer_name, T1.customer_ID, T2.number_of_products_ordered
from customer_table T1
inner join
(
select cust.customer_ID as customer_identity, count(distinct ord.product_ID) as number_of_products_ordered
from customer_table cust
inner join order_table ord on cust.customer_ID=ord.customer_ID
group by ord.customer_ID, ord.product_ID
having count(distinct ord.product_ID) > 10
) T2
on T1.customer_ID=T2.customer_identity
order by T2.number_of_products_ordered, T1.customer_name
Isn't that what you are looking for? Seems to be a little bit simpler. Tested it on SQL Server - works fine.
SELECT customer_name, COUNT(DISTINCT product_ID) as products_count FROM customer_table
INNER JOIN orders_table ON customer_table.customer_ID = orders_table.customer_ID
GROUP BY customer_table.customer_ID, customer_name
HAVING COUNT(DISTINCT product_ID) > 10
You could do it more simply:
select
c.id,
c.cname,
count(distinct o.pid) as `uniques`
from o join c
on c.id = o.cid
group by c.id
having `uniques` > 10