I have a problem with solving this problem. I have to extract the IDs of data from a table that has been changed only today. My current solution is
SELECT DISTINCT id
FROM changes_table
WHERE valid_to > (SELECT TO_DATE(CURRENT_DATE, 'DD-MON-RR') FROM DUAL)
This works in BDeaver but not in my application, there I get "ORA-01843:"
So is it possible to use CURRENT_TIMESTAMP, but it take timestamp from now. Is it possible to change it to format DD-MON-RR with 00:00:00 time?
Or is there any other solution?
I can send only one SQL command.
You may simply use SYSDATE here truncated to midnight:
SELECT DISTINCT id
FROM changes_table
WHERE valid_to > TRUNC(SYSDATE); -- RHS is today at midnight
Note that the above should work whether valid_to be a date or a timestamp.
Related
Usecase: Query to select the records for a whole day and it should run regularly.
This is my query.
Select to_char(in_date + interval '12' hour, 'DD-MON-YYYY HH24:MI:SS')
from my_table
where incoming_date > sysdate-2 and incoming_date < sysdate
I need to select yesterday's data only. Because of the conversion in the select statement I got today's data also. How do I select only yesterday's data? My DB is in UTC+7.00 standard. I need to display it in local standard so that I did a conversion in select statement. And how do I display only yesterday's data?
I'm stuck. Please help me
To get all data from yesterday you should use
SELECT TO_CHAR(IN_DATE + INTERVAL '12' HOUR, 'DD-MON-YYYY HH24:MI:SS')
FROM MY_TABLE
WHERE INCOMING_DATE BETWEEN TRUNC(SYSDATE) - INTERVAL '1' DAY
AND TRUNC(SYSDATE) - INTERVAL '1' SECOND
If, for example, SYSDATE is 05-NOV-2017 18:56:35, the time interval used in the BETWEEN comparison will be from 04-NOV-2017 00:00:00 to 04-NOV-2017 23:59:59. BETWEEN comparisons are inclusive of both endpoints so this will only return data with an INCOMING_DATE of sometime on 04-NOV-2017, in this example.
Best of luck.
only to get the
yesterday's data
make your
WHERE condition as
incoming_date between trunc(sysdate) - interval '1' day and trunc(sysdate) - interval '1' second
My DB is in UTC+7.00 standard. I need to display it in local standard so that I did a conversion in select statement.
Using a magic value (INTERVAL '12' HOUR) does not describe what it means or the assumptions you made when chosing that value. Instead you can better describe the process by using FROM_TS( timestampvalue, timezonestring ) to convert the value from a TIMESTAMP to a TIMESTAMP WITH TIME ZONE data type and then use AT LOCAL TIME to convert it to the local time. Then if you have daylight savings time or port the query to another international location then it will still display in the current local time. Like this:
SELECT TO_CHAR(
FROM_TZ( CAST( in_date AS TIMESTAMP ), '+07:00' ) AT LOCAL TIME,
'DD-MON-YYYY HH24:MI:SS'
)
FROM my_table
WHERE incoming_date >= TRUNC( SYSDATE ) - INTERVAL '1' DAY
AND incoming_date < TRUNC( SYSDATE )
And how do I display only yesterday's data?
TRUNC( SYSDATE ) will truncate today's date back to midnight. To get yesterday's data then you can get values that are greater or equal to TRUNC( SYSDATE ) - INTERVAL '1' DAY (one day before midnight today) and also less than TRUNC( SYSDATE ) (midnight today).
I'm not exactly sure I get your question, but I think I can explain some stuff.
I'll be assuming your table is a bit like this:
date_added | some_data | some_more_data
------------|-----------|----------------
date | data1 | data2
As I understand your goal is to fetch all the rows that were added to a table the day before the query is run using a select statement. but your current attempt fails at doing so by also returning today's results.
Here is what's happening (I think):
SYSDATE doesn't just give you the current date, it also gives you the time. You can see that for your self by simply altering your current session and setting the date/time format to one that includes both time and date
ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-YYYY HH24:MI:SS';
The reason why you would be getting today's rows is simple, your query is asking for all the rows who's date_added field is between right now and right now - 24 hours. Not today and today - 24 hours.
So what is the solution?
Use the TRUNC function to trim the SYSDATE to the day instead!
https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions201.htm
SELECT
T.*
FROM
MY_TABLE T
WHERE
T.DATE_ADDED BETWEEN (TRUNC(SYSDATE,'day') - 1) AND TRUNC(SYSDATE,'day');
As you did mention timezones being a thing keep in mind that SYSDATE returns the date on the server itself and not your computer's.
More on that here: https://stackoverflow.com/a/17925834/7655979
Usually I compare the date only using Trunc.
WHERE trunc(incoming_date) = trunc(sysdate-1)
I'm in PostgreSQL.
I need to print all mailing with creation date strictly more that 2015-04-04. I tried the following queries:
SELECT *
FROM mailing.mailing
WHERE creation_date > '2015-04-04';
and
SELECT *
FROM mailing.mailing
WHERE creation_date >= '2015-04-04';
But they produced the same result set(including '2015-04-04'). Is it possible to write such a query without explicitly saying WHERE creation_date >= '2015-04-05';
UPD: The column's type is timestamp without time zone.
If your creation_date field is of type datetimetry comparing it to '2015-04-04 23:59:59' instead, as '2015-04-04 08:30:00' seems to be greater than '2015-04-04'.
Assuming your default date format for your database is 'YYYY-MM-DD' and creation_date field is a date type, your query will actually be converted automatically to something like:
SELECT *
FROM mailing.mailing
WHERE creation_date > to_date('2015-04-04', 'YYYY-MM-DD');
The date value you have provided represents the first second of that day, that's why you see no difference between your queries. (Your first query would exclude the first second of the day though.)
What you could do to avoid this is:
where creation_date >= to_date('2015-04-05 00:00:00', 'YYYY-MM-DD HH24:MI:SS')
or
where date_trunc(creation_date-1) = '2015-04-04'
Why is the results not include '2013-10-14'
select *
from table t
where t.f_date between to_date('2013-10-20', 'yyyy-mm-dd') and
to_date('2013-10-14', 'yyyy-mm-dd')
Does d.f_date include a time component? If it does, the only records that will be returned by between will be those whose time is exactly 00:00:00. All others will be greater that 2013-10-14.
When comparing dates, a date without a time component is assumed to have a 00:00:00 time component
This could be caused by the time component issue mentioned in other answers, however you will also need to change your between to have the earliest date first, otherwise it will never return anything.
e.g.
SELECT *
FROM dual
WHERE SYSDATE BETWEEN SYSDATE AND SYSDATE + 1;
will return a 1 record, but
SELECT *
FROM dual
WHERE SYSDATE BETWEEN SYSDATE + 1 AND SYSDATE;
will not.
I have a table with date column in it. I need to fetch the records from it based on
the given date.
Currently when i used the query:
select * from workingemployee_data where created_date like '20-Jan-2012'
I am getting those records which have created_date on 20-Jan-2012
But i want to get the records those were created 10 days earlier to a given
date (i.e) 20-Jan-2012.
Please suggest me on this.
This gives all records between today and 10 days ago:
SELECT *
FROM workingemployee
WHERE created_date BETWEEN sysdate - INTERVAL '10' DAY
AND sysdate
This gives all records entered exactly 10 days ago:
SELECT *
FROM workingemployee
WHERE created_date = sysdate - INTERVAL '10' DAY
Replace sysdate with exact date if you want.
Why do you use like and not = ?
Assuming that created_date is of type DATE, it's bad practice to rely on implicit conversion according to NLS_DATE_FORMAT (this is what happens when you compare a date and a string)
dd-mon-yyyy isn't a good format for querying since it deffers according to NLS_LANGUAGE better use mm for months numbers
So, either use #mvp's answer or do something like this:
SELECT *
FROM workingemployee
WHERE trunc(created_date) = to_date('20-01-2013', 'dd-mm-yyyy') - 10
SELECT *
FROM workingemployee
WHERE created_date > sysdate - INTERVAL '10' DAY;
I'm trying to retrieve records from table by knowing the date in column contains date and time.
Suppose I have table called t1 which contains only two column name and date respectively.
The data stored in column date like this 8/3/2010 12:34:20 PM.
I want to retrieve this record by this query for example (note I don't put the time):
Select * From t1 Where date="8/3/2010"
This query give me nothing !
How can I retrieve date by knowing only date without the time?
DATE is a reserved keyword in Oracle, so I'm using column-name your_date instead.
If you have an index on your_date, I would use
WHERE your_date >= TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND your_date < TO_DATE('2010-08-04', 'YYYY-MM-DD')
or BETWEEN:
WHERE your_date BETWEEN TO_DATE('2010-08-03', 'YYYY-MM-DD')
AND TO_DATE('2010-08-03 23:59:59', 'YYYY-MM-DD HH24:MI:SS')
If there is no index or if there are not too many records
WHERE TRUNC(your_date) = TO_DATE('2010-08-03', 'YYYY-MM-DD')
should be sufficient. TRUNC without parameter removes hours, minutes and seconds from a DATE.
If performance really matters, consider putting a Function Based Index on that column:
CREATE INDEX trunc_date_idx ON t1(TRUNC(your_date));
Personally, I usually go with:
select *
from t1
where date between trunc( :somedate ) -- 00:00:00
and trunc( :somedate ) + .99999 -- 23:59:59
Convert your date column to the correct format and compare:
SELECT * From my_table WHERE to_char(my_table.my_date_col,'MM/dd/yyyy') = '8/3/2010'
This part
to_char(my_table.my_date_col,'MM/dd/yyyy')
Will result in string '8/3/2010'
You could use the between function to get all records between 2010-08-03 00:00:00:000 AND 2010-08-03 23:59:59:000
trunc(my_date,'DD') will give you just the date and not the time in Oracle.
Simply use this one:
select * from t1 where to_date(date_column)='8/3/2010'
Try the following way.
Select * from t1 where date(col_name)="8/3/2010"