I have a table with date column in it. I need to fetch the records from it based on
the given date.
Currently when i used the query:
select * from workingemployee_data where created_date like '20-Jan-2012'
I am getting those records which have created_date on 20-Jan-2012
But i want to get the records those were created 10 days earlier to a given
date (i.e) 20-Jan-2012.
Please suggest me on this.
This gives all records between today and 10 days ago:
SELECT *
FROM workingemployee
WHERE created_date BETWEEN sysdate - INTERVAL '10' DAY
AND sysdate
This gives all records entered exactly 10 days ago:
SELECT *
FROM workingemployee
WHERE created_date = sysdate - INTERVAL '10' DAY
Replace sysdate with exact date if you want.
Why do you use like and not = ?
Assuming that created_date is of type DATE, it's bad practice to rely on implicit conversion according to NLS_DATE_FORMAT (this is what happens when you compare a date and a string)
dd-mon-yyyy isn't a good format for querying since it deffers according to NLS_LANGUAGE better use mm for months numbers
So, either use #mvp's answer or do something like this:
SELECT *
FROM workingemployee
WHERE trunc(created_date) = to_date('20-01-2013', 'dd-mm-yyyy') - 10
SELECT *
FROM workingemployee
WHERE created_date > sysdate - INTERVAL '10' DAY;
Related
I have below select query where i am trying to get the data only for today date but its not returning anything:
select * from V_TER
where SYSTEM_INSERTED_AT = SYSDATE;
The SYSTEM_INSERTED_DATE is of Date datatype and the value is stored in this fields as for example 2021-01-15 15:17:13
The problem in Oracle is that dates can have time components both in the data and sysdate itself.
I would recommend checking for any time on the current date:
where system_inserted_at >= trunc(sysdate) and
system_inserted_at < trunc(sysdate) + interval '1' day
This is generally optimizer-friendly. If you don't care about that, then:
where trunc(system_inserted_at) = trunc(sysdate)
I'm querying a table to get some date, like so:
SELECT date - INTERVAL '10 day' AS date
FROM example_table
WHERE username = 'Bob'
LIMIT 1;
The date column in the example_table does not have a timestamp. All dates in the column are stored in the following manner:
YYYY-MM-DD
The query above will return a result like so:
2016-11-20 00:00:00.000000
It takes the date found, goes back 10 days, and returns that date. But I want it to return the date without adding the timestamp, like so:
2016-11-20
If I use INTERVAL it always seems to add a timestamp. Is there a way to only get the date?
Your query is fine (but can be simplified, as demonstrated by a_horse_with_no_name). What you are seeing is a display issue. You can format your date to a string in the relevant format using to_char():
SELECT to_char("date" - INTERVAL '10 day', 'yyyy-mm-dd') AS "date"
FROM example_table
WHERE username = 'Bob'
LIMIT 1;
Note: LIMIT without an ORDER BY does not make sense: if there is more than one record in the resultset, you actually get a random record out of them.
You can use the interval notation and convert back to a date:
SELECT (date - INTERVAL '10 day')::date AS date
You can subtract (or add) an integer from a date. That integer represents the number of days:
SELECT "date" - 10 AS "date"
FROM example_table
WHERE username = 'Bob'
LIMIT 1;
I am trying to query some records and am looking to return only records that have a date of today, but also are before the current time.
I have the first part sorted out by using the following clause to return only records for today.
WHERE TRUNC(my_date_time) = TRUNC(sysdate)
How would I modify this to only get records before the current system time as well?
How about inequalities?
WHERE my_date_time >= TRUNC(sysdate) AND
my_date_time < sysdate
Try this.
Select * from table Where
TRUNC(my_date_time) =
TRUNC(sysdate) And
TO_CHAR(my_date_time,
'HH24:MI:SS' ) <=
TO_CHAR(sysdate,
' HH24:MI:SS' )
If column "my_date_time" is of type DATE, and need compare using SYSDATE function then you only need:
WHERE my_date_time<=sysdate
If column "my_date_time" is of type DATE, and need compare with other variable or column of type DATE for example named "other_date"
where my_date_time>=trunc(other_date)
and my_date_time<trunc(other_date)+1
Usecase: Query to select the records for a whole day and it should run regularly.
This is my query.
Select to_char(in_date + interval '12' hour, 'DD-MON-YYYY HH24:MI:SS')
from my_table
where incoming_date > sysdate-2 and incoming_date < sysdate
I need to select yesterday's data only. Because of the conversion in the select statement I got today's data also. How do I select only yesterday's data? My DB is in UTC+7.00 standard. I need to display it in local standard so that I did a conversion in select statement. And how do I display only yesterday's data?
I'm stuck. Please help me
To get all data from yesterday you should use
SELECT TO_CHAR(IN_DATE + INTERVAL '12' HOUR, 'DD-MON-YYYY HH24:MI:SS')
FROM MY_TABLE
WHERE INCOMING_DATE BETWEEN TRUNC(SYSDATE) - INTERVAL '1' DAY
AND TRUNC(SYSDATE) - INTERVAL '1' SECOND
If, for example, SYSDATE is 05-NOV-2017 18:56:35, the time interval used in the BETWEEN comparison will be from 04-NOV-2017 00:00:00 to 04-NOV-2017 23:59:59. BETWEEN comparisons are inclusive of both endpoints so this will only return data with an INCOMING_DATE of sometime on 04-NOV-2017, in this example.
Best of luck.
only to get the
yesterday's data
make your
WHERE condition as
incoming_date between trunc(sysdate) - interval '1' day and trunc(sysdate) - interval '1' second
My DB is in UTC+7.00 standard. I need to display it in local standard so that I did a conversion in select statement.
Using a magic value (INTERVAL '12' HOUR) does not describe what it means or the assumptions you made when chosing that value. Instead you can better describe the process by using FROM_TS( timestampvalue, timezonestring ) to convert the value from a TIMESTAMP to a TIMESTAMP WITH TIME ZONE data type and then use AT LOCAL TIME to convert it to the local time. Then if you have daylight savings time or port the query to another international location then it will still display in the current local time. Like this:
SELECT TO_CHAR(
FROM_TZ( CAST( in_date AS TIMESTAMP ), '+07:00' ) AT LOCAL TIME,
'DD-MON-YYYY HH24:MI:SS'
)
FROM my_table
WHERE incoming_date >= TRUNC( SYSDATE ) - INTERVAL '1' DAY
AND incoming_date < TRUNC( SYSDATE )
And how do I display only yesterday's data?
TRUNC( SYSDATE ) will truncate today's date back to midnight. To get yesterday's data then you can get values that are greater or equal to TRUNC( SYSDATE ) - INTERVAL '1' DAY (one day before midnight today) and also less than TRUNC( SYSDATE ) (midnight today).
I'm not exactly sure I get your question, but I think I can explain some stuff.
I'll be assuming your table is a bit like this:
date_added | some_data | some_more_data
------------|-----------|----------------
date | data1 | data2
As I understand your goal is to fetch all the rows that were added to a table the day before the query is run using a select statement. but your current attempt fails at doing so by also returning today's results.
Here is what's happening (I think):
SYSDATE doesn't just give you the current date, it also gives you the time. You can see that for your self by simply altering your current session and setting the date/time format to one that includes both time and date
ALTER SESSION SET NLS_DATE_FORMAT = 'DD-MON-YYYY HH24:MI:SS';
The reason why you would be getting today's rows is simple, your query is asking for all the rows who's date_added field is between right now and right now - 24 hours. Not today and today - 24 hours.
So what is the solution?
Use the TRUNC function to trim the SYSDATE to the day instead!
https://docs.oracle.com/cd/B19306_01/server.102/b14200/functions201.htm
SELECT
T.*
FROM
MY_TABLE T
WHERE
T.DATE_ADDED BETWEEN (TRUNC(SYSDATE,'day') - 1) AND TRUNC(SYSDATE,'day');
As you did mention timezones being a thing keep in mind that SYSDATE returns the date on the server itself and not your computer's.
More on that here: https://stackoverflow.com/a/17925834/7655979
Usually I compare the date only using Trunc.
WHERE trunc(incoming_date) = trunc(sysdate-1)
I want to display in my gridview all data whose timestamp is not older than 1 years from current date.
My timestamp is formatted like so: 20110125-071830 or yyyymmdd-hhmmss
I have tried to reference :
Retrieve rows less than a day old:
Select * from table_name WHERE DATE(timestampVal) > DATE(NOW() - INTERVAL 1 YEAR);
but got missing expression flag
I also tried various others; however, my timestampVal is different simply by how it is formatted.
Like for example: https://community.oracle.com/thread/2207956
With coding: Select * from table_name WHERE timestampVal < sysdate - interval '1' year ;
but get error: literal does not match format string which means sysdate can't read how mine is formatted.
How do I query my timestamp to pull all that are a year or less old?
FYI: timestampVal is string type [varchar]
It looks like the following should work:
Select *
from table_name
WHERE TO_DATE(timestampVal, 'YYYYMMDD-HH24MISS') > sysdate - interval '1' year;
Also note that I reversed the comparison: you indicated that you want rows where timestampVal is not older than 1 year ago - so timestampVal should be greater (newer) than current time minus one year.
Give that a try.
Best of luck.