I google data studio, I have a field called week that contains the week number the value is string 'Week 2' for example. How can I extract the last day of the week based on the week number. In this case I want to get 2023-01-14 which is the last day of week 2?
enter image description here
Have you tried the last_day function?
I would build from the using the date using last_day, because from the week number it would require a bit more code.
SELECT *,
LAST_DAY(today, WEEK) AS last_day_of_week,
EXTRACT(WEEK FROM today) AS week_number
FROM (SELECT CURRENT_DATE() AS today)
But if you need to go with just the week number, I recommend taking a look into this other question How to create date based on year, week number and day in bigquery .
The following code works:
DATEtime_ADD(DATEtime_TRUNC(DATEtime_ADD(DATEtime_TRUNC(date, WEEK), INTERVAL (week-1) * 1 DAY), WEEK), INTERVAL 6 DAY)
Related
I have a below query that I run to extract material movements from the last 7 days.
Purpose is to get the data for the last calender week for certain reports.
select
*
From
redshift
where
posting_date between CURRENT_DATE - 7 and CURRENT_DATE - 1
That means I need to run the query on every Monday to get the data for the former week.
Sometimes I am too busy on Monday or its vacation/bank holiday. In that case I would need to change the query or pull the data via SAP.
Question:
Is there a function for redshift that pulls out the data for the last calender week regardless when I run the query?
I already found following solution
SELECT id FROM table1
WHERE YEARWEEK(date) = YEARWEEK(NOW() - INTERVAL 1 WEEK)
But this doesnt seem to be working for redshift sql
Thanks a lot for your help.
Redshift offers a DATE_TRUNC('week', datestamp) function. Given any datestamp value, either a date or datetime, it gives back the date of the preceding Sunday.
So this might work for you. It filters rows from the Sunday before last, up until but not including, the last Sunday, and so gets a full week.
SELECT id
FROM table1
WHERE date >= DATE_TRUNC('week', NOW()) - INTERVAL 1 WEEK
AND date < DATE_TRUNC('week', NOW())
Pro tip: Every minute you spend learning your DBMS's date/time functions will save you an hour in programming.
I was wondering if it is possible in SQL to read in a date column and based on that date create a new column and automatically have the Week number as well. For example today is 4/7/2020 , so the query would have Week 15 populated for that?
]1
In the picture the week column would ideally be populated beside 'datestr'.
Thank you]2
In redshift, you can use date_part() with the w specifier to get the week number of a date or timestamp:
select t.*, date_part(w, datestr) week_number from mytable t
Note that weeks starts on Monday in Redshift. If you want the week to start on Sunday:
select t.*, date_part(w, datestr + interval '1' day) week_number from mytable t
You could use extract. I am not 100% sure if weeks in Redshift start from Sunday or Monday, but you can adjust the interval to test the edge cases.
select datestr, extract(week from datestr + interval '1 day') as weeknum
from your_table
I am trying to run a query in AWS Athena to get the week number from a date. I need the week to start on Sunday.
I have tried the below query and it works but it considers the week starts from Monday.
Extract(week from date) as week_number
Google bigquery has an option where you can specify the week start. Eg:
Extract(week(Sunday) from date) as week_number
Is there something similar in Athena?
Request assistance.
Thank you.
If there isn't, you can add one day:
extract(week from date + interval '1' day) as week_number
I'm pretty new to SQL so I hope this isn't a dumb question, tried to google but couldn't find anything.
I'm summing sales of departments per week in SQL and am using TD_SYSFNLIB.WEEKNUMBER_OF_YEAR (trans_dt) to get the week number.
I think everything is working except I'd like to change the format of the weeks to the start date of the week, e.g. week 1 = 1/4/15
Also, i'm not sure how to handle the very first of the year week 0 since I think that should be grouped up with week 52 of last year.
The following date math trick should get you Beginning of Week as an actual date without having to join to the SYS_CALENDAR view or using a function:
SELECT CURRENT_DATE - ((CURRENT_DATE - DATE '0001-01-07) MOD 7) AS BOW;
Starting with TD14 there's NEXT_DAY which returns the following weekday, if you subtract 7 days you get the previous day:
next_day(trans_dt - 7, 'sunday')
What is the correct expression to use for todays date plus 1 year.
I assume it starts with Now()+ but im unsure from there
This page has lots of great examples, including:
=DateAdd(DateInterval.Month, 6, Parameters!StartDate.Value)
From that and the example before it, it looks like you want:
=DateAdd(DateInterval.Year, 1, Today())
this should be what your looking for:
--midnight last day of last month
select DateAdd(mm,-0,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of this month
select DateAdd(mm,+1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of last month 1 year ago
select DateAdd(yy,-1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of this month 1 year ago
select DateAdd(yy,-1,DateAdd(mm,+1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0)))))