What is the correct expression to use for todays date plus 1 year.
I assume it starts with Now()+ but im unsure from there
This page has lots of great examples, including:
=DateAdd(DateInterval.Month, 6, Parameters!StartDate.Value)
From that and the example before it, it looks like you want:
=DateAdd(DateInterval.Year, 1, Today())
this should be what your looking for:
--midnight last day of last month
select DateAdd(mm,-0,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of this month
select DateAdd(mm,+1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of last month 1 year ago
select DateAdd(yy,-1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0))))
--midnight last day of this month 1 year ago
select DateAdd(yy,-1,DateAdd(mm,+1,(DATEADD(s,-1,DATEADD(mm, DATEDIFF(m,0,GETDATE()),0)))))
Related
I google data studio, I have a field called week that contains the week number the value is string 'Week 2' for example. How can I extract the last day of the week based on the week number. In this case I want to get 2023-01-14 which is the last day of week 2?
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Have you tried the last_day function?
I would build from the using the date using last_day, because from the week number it would require a bit more code.
SELECT *,
LAST_DAY(today, WEEK) AS last_day_of_week,
EXTRACT(WEEK FROM today) AS week_number
FROM (SELECT CURRENT_DATE() AS today)
But if you need to go with just the week number, I recommend taking a look into this other question How to create date based on year, week number and day in bigquery .
The following code works:
DATEtime_ADD(DATEtime_TRUNC(DATEtime_ADD(DATEtime_TRUNC(date, WEEK), INTERVAL (week-1) * 1 DAY), WEEK), INTERVAL 6 DAY)
What I need is break down the date by month and the week of that month. For example, for '2020-01-06' I want to see January, 1 week, or for '2020-01-13', I want to see January, 2nd week.
Here is the code that wrote:
.....
distinct t1.incidentid
,t1.status as [CW_Staus],
t1.title
,t1.createddatetime
,datename(MM,t1.createddatetime) as Month
,datename(ww,t1.createddatetime) as Week
.....
Now, what I see is this
However, with the start of each month, I want to restart the week count. for '2020-02-01', I want to see Feb, 1week.
What am I missing in the code?
Thank you
You could try taking the day of the month and divide by 7:
SELECT DISTINCT
t1.incidentid,
t1.status AS [CW_Staus],
t1.title,
t1.createddatetime,
DATENAME(MM, t1.createddatetime) AS Month,
1 + ((DATEPART(day, t1.createddatetime)-1) / 7) AS WeekOfMonth
...
Keep in mind that the above logic assumes that you actually want to reset the count of weeks for each month, at the start of each month. More typically, there are ISO standard ways of counting the week in the year. There are edge cases to be considered, as any given year may not have an whole number of weeks.
I have inherited a query from an old MS Access DB and cannot for the life of me figure out what was trying to be done in this date parameter function. I normally only use SQL and this seems a bit different. Can any one assist in describing what this logic is doing?
use pdx_sap_user
go
select po_number,
po_issue_date
from vw_po_header
where po_issue_date > getDate() And PO_issue_date < DateAdd("d",-1,DateAdd("m",8,DateAdd("d",-(Day(getDate())-1),getDate())))
You can de-obfuscate it a lot by using DateSerial:
where
po_issue_date > getDate() And
po_issue_date < DateSerial(Year(getDate()), Month(getDate()) + 8, 0)
First: there is no getDate() function in Access. Probably it should be Date() which returns the current date.
Now starting from the inner expression:
Day(Date()) returns the current day as an integer 1-31.
So in DateAdd("d", -(Day(Date())-1), Date()) from the current date are subtracted as many days as needed to return the 1st of the current month.
Then:
DateAdd("m", 8, DateAdd("d", -(Day(Date())-1), Date()))
adds 8 months to the the 1st of the current month returning the 1st of the month of the date after 8 months.
Finally:
DateAdd("d", -1,...)
subtracts 1 day from the date returned by the previous expression, returning the last day of the previous month of that date.
So if you run today 13-Sep-2019 this code, the result will be:
30-Apr-2020
because this is the last day of the previous month after 8 months.
I think the following:
Take the current date
Substract the current day of month -1 to get the first day of current month
Add 8 month to this
Substract 1 day to get the last day of the previous month
So it calculates some deadline in approx 8 months.
But I wonder how a PO issue date can be in the future...
I have a date in sql which will always fall on a Monday and I'm subtracting 13 weeks to get a weekly report. I am trying to get the same 13 week report but for last year's figures as well.
At the moment, I'm using the following:
calendar_date >= TRUNC(sysdate) - 91
which is working fine.
I need the same for last year.
However, when I split this into calendar weeks, there will also be a partially complete week as it will include 1 or 2 days from the previous week. I need only whole weeks.
e.g. the dates that will be returned for last year will be 14-Feb-2015 to 16-May-2015. I need it to start on the Monday and be 16-Feb-2015. This will change each week as I am only interested in complete weeks...
I would do this:
Get the date by substracting 91 days as you're already doing.
Get the number of the day of the week with TO_CHAR(DATE,'d')
Add the number of days until the next monday to the date.
Something like this:
SELECT TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/YYYY')-91 + MOD(7 - TO_NUMBER(TO_CHAR(TO_DATE(TO_DATE('16/05/2015','DD/MM/YYYY'),'DD/MM/RRRR')-91,'d'))+1,7) d
FROM dual
next_day - returns date of first weekday named by char.
with dates as (select to_date('16/05/2015','DD/MM/YYYY') d from dual)
select
trunc(next_day( trunc(d-91) - interval '1' second,'MONDAY'))
from dates;
I want to get next monday from calculated date. In situation when calculated date is monday i have to move back to previous week ( -1 second).
I'm pretty new to SQL so I hope this isn't a dumb question, tried to google but couldn't find anything.
I'm summing sales of departments per week in SQL and am using TD_SYSFNLIB.WEEKNUMBER_OF_YEAR (trans_dt) to get the week number.
I think everything is working except I'd like to change the format of the weeks to the start date of the week, e.g. week 1 = 1/4/15
Also, i'm not sure how to handle the very first of the year week 0 since I think that should be grouped up with week 52 of last year.
The following date math trick should get you Beginning of Week as an actual date without having to join to the SYS_CALENDAR view or using a function:
SELECT CURRENT_DATE - ((CURRENT_DATE - DATE '0001-01-07) MOD 7) AS BOW;
Starting with TD14 there's NEXT_DAY which returns the following weekday, if you subtract 7 days you get the previous day:
next_day(trans_dt - 7, 'sunday')