Hello I would like to know the highest count of consecutive days a user has trained for.
My logs table that stores the records looks like this:
id
user_id
day
ground_id
created_at
1
1
1
1
2023-01-24 10:00:00
2
1
2
1
2023-01-25 10:00:00
3
1
3
1
2023-01-26 10:00:00
4
1
4
1
2023-01-27 10:00:00
5
1
5
1
2023-01-28 10:00:00
The closest I could get is with this query, which does work only if the user has trained on one ground at a day.
SELECT COUNT(*) AS days_in_row
FROM (SELECT row_number() OVER (ORDER BY day) - day AS grp
FROM logs
WHERE created_at >= '2023-01-24 00:00:00'
AND user_id = 1) x
GROUP BY grp
logs table:
id
user_id
day
ground_id
created_at
1
1
1
1
2023-01-24 10:00:00
2
1
2
1
2023-01-25 10:00:00
3
1
3
1
2023-01-26 10:00:00
4
1
4
1
2023-01-27 10:00:00
5
1
5
1
2023-01-28 10:00:00
This query would return a count of 5 consecutive days which is correct.
However my query doesn't work once a user trains multiple times on different training grounds in one day:
logs table:
id
user_id
day
ground_id
created_at
1
1
1
1
2023-01-24 10:00:00
2
1
2
1
2023-01-25 10:00:00
3
1
3
1
2023-01-26 10:00:00
4
1
3
2
2023-01-26 10:00:00
5
1
4
1
2023-01-27 10:00:00
Than the query from above would return a count of 2 consecutive days which is not what I expect instead I would expect the number four because the user has trained the following days in row (1,2,3,4).
Thank you for reading.
Select only distinct data of interest first
SELECT min(created_at) start, COUNT(*) AS days_in_row
FROM (SELECT created_at, row_number() OVER (ORDER BY day) - day AS grp
FROM (
select distinct day, created_at
from logs
where created_at >= '2023-01-24 00:00:00'
AND user_id = 1) t
) x
GROUP BY grp
Related
I aim to first achieve this
id
employee
Datelog
TimeIn
TimeOut
Hours
Count
5
Two
2022-08-10
09:00:00
16:00:00
07:00:00
1
4
Two
2022-08-09
09:00:00
16:00:00
07:00:00
1
3
Two
2022-08-08
09:00:00
16:00:00
07:00:00
1
2
One
2022-08-05
09:00:00
16:00:00
07:00:00
1
1
Two
2022-08-04
09:00:00
10:00:00
01:00:00
0
and now my main objective here is to give a bonus of 2k to employees whose Totalcount per month >=3.
employee
Month
TotalCount
Bonus
Two
August
3
2000
One
August
1
0
Here's the answer using Postgres. It's pretty much generic other than extracting the month out of datelog that might have a slightly different syntax.
select employee
,max(date_part('month', datelog ))
,count(*)
,case when count(*) >= 3 then 2000 else 0 end as bonus
from t
where hours >= time '06:00:00'
group by employee
employee
max
count
bonus
Two
8
3
2000
One
8
1
0
Fiddle
Suppose I have one table (table_1) and one table stream (stream_1) that gets changes made to table_1, in my case only inserts of new rows. And once I have acted on these changes, the rowes will be removed from stream_1 but remain in table_1.
From that I would like to calculate delta values for var1 (var1 - lag(var1) as delta_var1) partitioned on a customer and just leave var2 as it is. So the data in table_1 could look something like this:
timemessage
customerid
var1
var2
2021-04-01 06:00:00
1
10
5
2021-04-01 07:00:00
2
100
7
2021-04-01 08:00:00
1
20
10
2021-04-01 09:00:00
1
40
3
2021-04-01 15:00:00
2
150
5
2021-04-01 23:00:00
1
50
6
2021-04-02 06:00:00
2
180
2
2021-04-02 07:00:00
1
55
9
2021-04-02 08:00:00
2
200
4
And the data in stream_1 that I want to act on could looks like this:
timemessage
customerid
var1
var2
2021-04-01 23:00:00
1
50
6
2021-04-02 06:00:00
2
180
2
2021-04-02 07:00:00
1
55
9
2021-04-02 08:00:00
2
200
4
But to be able to calculate delta_var1 for all customers I would need the previous row in time for each customer before the ones in stream_1.
For example: To be able to calculate how much var1 has increased for customerid = 1 between 2021-04-01 09:00:00 and 2021-04-01 23:00:00 I want to include the 2021-04-01 09:00:00 row for customerid = 1 in my output.
So I would like to create a select containing all rows in stream_1 + the previous row in time for each customerid from table_1: The wanted output is the following in regard to the mentioned table_1 and stream_1.
timemessage
customerid
var1
var2
2021-04-01 09:00:00
1
40
3
2021-04-01 15:00:00
2
150
5
2021-04-01 23:00:00
1
50
6
2021-04-02 06:00:00
2
180
2
2021-04-02 07:00:00
1
55
9
2021-04-02 08:00:00
2
200
4
So given you have the "last value per day" in your wanted output, you are want a QUALIFY to keep only the wanted rows and using ROW_NUMBER partitioned by customerid and timemessage. Assuming the accumulator it positive only you can order by accumulatedvalue thus:
WITH data(timemessage, customerid, accumulatedvalue) AS (
SELECT * FROM VALUES
('2021-04-01', 1, 10)
,('2021-04-01', 2, 100)
,('2021-04-02', 1, 20)
,('2021-04-03', 1, 40)
,('2021-04-03', 2, 150)
,('2021-04-04', 1, 50)
,('2021-04-04', 2, 180)
,('2021-04-05', 1, 55)
,('2021-04-05', 2, 200)
)
SELECT * FROM data
QUALIFY ROW_NUMBER() OVER (PARTITION BY customerid,timemessage ORDER BY accumulatedvalue DESC) = 1
ORDER BY 1,2;
gives:
TIMEMESSAGE CUSTOMERID ACCUMULATEDVALUE
2021-04-01 1 10
2021-04-01 2 100
2021-04-02 1 20
2021-04-03 1 40
2021-04-03 2 150
2021-04-04 1 50
2021-04-04 2 180
2021-04-05 1 55
2021-04-05 2 200
if you can trust your data and data in table2 starts right after data in table1 then you can just get the last records for each customer from table1 and union with table2:
select * from table1
qualify row_number() over (partitioned by customerid order by timemessage desc) = 1
union all
select * from table2
if not
select a.* from table1 a
join table2 b
on a.customerid = b.customerid
and a.timemessage < b.timemessage
qualify row_number() over (partitioned by a.customerid order by a.timemessage desc) = 1
union all
select * from table2
also you can add a condition to not look to data for more than 1 day (or 1 hour or whatever safe interval is to look at) for better performance
I'm trying to find a way to do a sequence for date periods and quarters(not sure if this is the correct term).
Basically this will help people to navigate dates based on weeks, periods, and quarters once I join this to our sales data. For example, if I just want to know the sales from last week, I could just use WHERE WeekSequence = -1... Another example is, a manager wants to get the sales data for the past quarter, I could just use WHERE QuarterSequence = -1... something like that.
My current table:
WeekStartDate WeekEndDate CurrentWeek Period Quarter WeekSequence
----------------------------------------------------------------------
2020-08-03 2020-08-09 0 2 1 -5
2020-08-10 2020-08-16 0 2 1 -4
2020-08-17 2020-08-23 0 2 1 -3
2020-08-24 2020-08-30 0 2 1 -2
2020-08-31 2020-09-06 0 2 1 -1
2020-09-07 2020-09-13 1 3 1 0
2020-09-14 2020-09-20 0 3 1 1
2020-09-21 2020-09-27 0 3 1 2
2020-09-28 2020-10-04 0 3 1 3
2020-10-05 2020-10-11 0 4 2 4
2020-10-12 2020-10-18 0 4 2 5
What I want it to look like(highlighted):
If I understand correctly, just use window functions:
select t.*,
(period -
max(case when currentweek = 1 then period end) over ()
) as periodsequence,
(quarter -
max(case when currentweek = 1 then quarter end) over ()
) as quartersequence
from t;
You can include this in a view rather than putting it in a table.
I am trying to collapse data that is in a sequence sorted by date. While grouping on the person and the type.
The data is stored in an SQL server and looks like the following -
seq person date type
--- ------ ------------------- ----
1 1 2018-02-10 08:00:00 1
2 1 2018-02-11 08:00:00 1
3 1 2018-02-12 08:00:00 1
4 1 2018-02-14 16:00:00 1
5 1 2018-02-15 16:00:00 1
6 1 2018-02-16 16:00:00 1
7 1 2018-02-20 08:00:00 2
8 1 2018-02-21 08:00:00 2
9 1 2018-02-22 08:00:00 2
10 1 2018-02-23 08:00:00 1
11 1 2018-02-24 08:00:00 1
12 1 2018-02-25 08:00:00 2
13 2 2018-02-10 08:00:00 1
14 2 2018-02-11 08:00:00 1
15 2 2018-02-12 08:00:00 1
16 2 2018-02-14 16:00:00 3
17 2 2018-02-15 16:00:00 3
18 2 2018-02-16 16:00:00 3
This data set contains about 1.2 million records that resemble the above.
The result that I would like to get from this would be -
person start type
------ ------------------- ----
1 2018-02-10 08:00:00 1
1 2018-02-20 08:00:00 2
1 2018-02-23 08:00:00 1
1 2018-02-25 08:00:00 2
2 2018-02-10 08:00:00 1
2 2018-02-14 16:00:00 3
I have the data in the first format by running the following query -
select
ROW_NUMBER() OVER (ORDER BY date) AS seq
person,
date,
type,
from table
group by person, date, type
I am just not sure how to keep the minimum date with the other distinct values from person and type.
This is a gaps-and-islands problem so, you can use differences of row_number() & use them in grouping :
select person, min(date) as start, type
from (select *,
row_number() over (partition by person order by seq) seq1,
row_number() over (partition by person, type order by seq) seq2
from table
) t
group by person, type, (seq1 - seq2)
order by person, start;
The correct solution using the difference of row numbers is:
select person, type, min(date) as start
from (select t.*,
row_number() over (partition by person order by seq) as seqnum_p,
row_number() over (partition by person, type order by seq) as seqnum_pt
from t
) t
group by person, type, (seqnum_p - seqnum_pt)
order by person, start;
type needs to be included in the GROUP BY.
I am working on an app that has some scheduling functionality. As part of this, I need to select a list of people and whether or not they have have something scheduled in a certain period of the week.
The number of periods in the week are variable so they are stored in a reference table, for example:
Period Reference Table
id name start end day
------------------------------------------------------------------
1 Morning 1900-01-01 4:00:00 1900-01-01 11:00:00 MON
2 Afternoon 1900-01-01 14:00:00 1900-01-01 20:00:00 MON
3 Night 1900-01-01 20:00:00 1900-01-01 24:00:00 MON
4 Morning 1900-01-01 4:00:00 1900-01-01 11:00:00 TUE
5 Afternoon 1900-01-01 14:00:00 1900-01-01 20:00:00 TUE
6 Night 1900-01-01 20:00:00 1900-01-01 24:00:00 TUE
I also have a "person reference" table and a "person schedule" table.
The "person schedule" table only stores a record if a person has something scheduled in a period, here is a simplified example:
Person Schedule Table
id person_id period_id
------------------------------
1 1 2
2 1 3
3 2 2
4 2 3
5 2 4
Now I need to select from these three tables a full list of periods for each person and whether they have a schedule record in the period or not (1 or 0). In other words, I need to get this resultset for the example data above:
person_id period_id is_scheduled
----------------------------------------
1 1 0
1 2 1
1 3 1
1 4 0
1 5 0
1 6 0
2 1 0
2 2 1
2 3 1
2 4 1
2 5 0
2 6 0
Is it possible to do this with a select statement without getting into dynamic SQL?
This is all done using SQL Server 2000
SELECT
people.person_id, period_id = periods.id, is_scheduled = CASE
WHEN schedule.person_id IS NOT NULL THEN 1 ELSE 0 END
FROM dbo.[period reference table] AS periods
CROSS JOIN
(
SELECT person_id
FROM dbo.[person schedule table]
GROUP BY person_id
) AS people
LEFT OUTER JOIN
dbo.[person schedule table] AS schedule
ON people.person_id = schedule.person_id
AND periods.id = schedule.period_id
ORDER BY
people.person_id, p.id;