can I join to all rows in a reference table as a kind of template? - sql

Question

I am working on an app that has some scheduling functionality. As part of this, I need to select a list of people and whether or not they have have something scheduled in a certain period of the week.
The number of periods in the week are variable so they are stored in a reference table, for example:
Period Reference Table
id name start end day
------------------------------------------------------------------
1 Morning 1900-01-01 4:00:00 1900-01-01 11:00:00 MON
2 Afternoon 1900-01-01 14:00:00 1900-01-01 20:00:00 MON
3 Night 1900-01-01 20:00:00 1900-01-01 24:00:00 MON
4 Morning 1900-01-01 4:00:00 1900-01-01 11:00:00 TUE
5 Afternoon 1900-01-01 14:00:00 1900-01-01 20:00:00 TUE
6 Night 1900-01-01 20:00:00 1900-01-01 24:00:00 TUE
I also have a "person reference" table and a "person schedule" table.
The "person schedule" table only stores a record if a person has something scheduled in a period, here is a simplified example:
Person Schedule Table
id person_id period_id
------------------------------
1 1 2
2 1 3
3 2 2
4 2 3
5 2 4
Now I need to select from these three tables a full list of periods for each person and whether they have a schedule record in the period or not (1 or 0). In other words, I need to get this resultset for the example data above:
person_id period_id is_scheduled
----------------------------------------
1 1 0
1 2 1
1 3 1
1 4 0
1 5 0
1 6 0
2 1 0
2 2 1
2 3 1
2 4 1
2 5 0
2 6 0
Is it possible to do this with a select statement without getting into dynamic SQL?
This is all done using SQL Server 2000

Answer 1

SELECT
people.person_id, period_id = periods.id, is_scheduled = CASE
WHEN schedule.person_id IS NOT NULL THEN 1 ELSE 0 END
FROM dbo.[period reference table] AS periods
CROSS JOIN
(
SELECT person_id
FROM dbo.[person schedule table]
GROUP BY person_id
) AS people
LEFT OUTER JOIN
dbo.[person schedule table] AS schedule
ON people.person_id = schedule.person_id
AND periods.id = schedule.period_id
ORDER BY
people.person_id, p.id;