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I'm using Microsoft SQL Server and I"m having issues writing a command for MIN and MAX functions.
It seems simple. The data type of the column is date time and the requested information is to find oldest/newest employee.
Below is the query I wrote:
select max(date_hired)
from staff;
select min(date_hired)
from staff;
But it seems like they are working in reverse. Min is giving me oldest and max is giving me youngest.
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SQL Newbie here ...
Service_plan table has a record per customer with PKEY service_plan_id
SERVICE_PLAN_ID table keeps track of version changes with same PKEY
When I run this query [other selects omitted for brevity] in Oracle 10.2.0 iSQL command line, I get an error:
select S1.service_plan_id as TN,V1.VERSION_ID as Version
from Service_plan S1
inner join
(select distinct service_plan_id, max(VERSION_ID)
from SERVICE_PLAN_VERSION
where service_ID='COLL'
group by service_plan_id) as V1
on V1.SERVICE_PLAN_ID = S1.SERVICE_PLAN_ID
where S1.SERVICE_ID='COLL';
Error: missing key word on the "group by service_plan_id) as V1" line - it points to the "as" as the problem.
Any thoughts? Thx
Tried the standalone select and it works fine
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I'm fairly new at writing SQL commands so I don't exactly know where I'm going wrong here. I closed all the parentheses, but I still get the following error message:
Syntax error: Expected ")" but got keyword AND at [18:5]
Code:
goals as (
select sum(cast(goal as int64)) as goal
from seed.seed_ads_goals
goal_total
and extract(month from [daterange_start]) = month
)
Any hints?
WHERE Clause is missing :
select sum(cast(goal as int64)) as goal
from seed.seed_ads_goals as goal_total
where extract(month from [daterange_start]) = month
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I am trying to run the query below but I am getting an error ERROR: column "test.pdf" does not exist . I dont know why I am getting this error. I search for various links on stackover but none solved my problem like this PostgreSQL query -- column does not exist, Postgres error updating column data. Please help me find the problem.
bill is a type string field in bills table.
update bills
set bill = "test.pdf"
where id=3;
Change the double quotes you have around test.pdf to single quotes.
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I am trying to write an SQL code in MS Access 2010 as follows:-
select WOWPerformanceData_tbl.Style,
WOWPerformanceData_tbl.FY,
WOWPerformanceData_tbl.Month,
PrintPromotions.[Type of Offer],
PrintPromotions.Start,
PrintPromotions.End
from WOWPerformanceData_tbl
right join PrintPromtions
on WOWPerformanceData_tbl.Style=PrintPromotions.Style
where (WOWPerformanceData_tbl.Style=[Enter Style nr:]);
Upon running the code, Access returns an error in the join operation pointing to the fourth line and selects PrintPromotions
Any feedback will be appreciated..
Thank you.
Should that be PrintPromotions and not PrintPromtions ?
This is fine as the where clause is an evaluation on the entire set.
SELECT WOWPerformanceData_tbl.Style,
WOWPerformanceData_tbl.FY,
WOWPerformanceData_tbl.Month,
PrintPromotions.[Type of Offer],
PrintPromotions.Start,
PrintPromotions.End
from WOWPerformanceData_tbl
LEFT join PrintPromtions
on WOWPerformanceData_tbl.Style=PrintPromotions.Style
where (WOWPerformanceData_tbl.Style=[Enter Style nr:]);
This would exclude records from printPromotions that were not in wowPerformanceData_tbl, which negates the right join.:
SELECT WOWPerformanceData_tbl.Style,
WOWPerformanceData_tbl.FY,
WOWPerformanceData_tbl.Month,
PrintPromotions.[Type of Offer],
PrintPromotions.Start,
PrintPromotions.End
from WOWPerformanceData_tbl
right join PrintPromtions
on WOWPerformanceData_tbl.Style=PrintPromotions.Style
where (WOWPerformanceData_tbl.Style=[Enter Style nr:]);
This is how you would do it to keep all records from PrintPromotions and those that matched in wowperofrmanceData_tbl.
SELECT WOWPerformanceData_tbl.Style,
WOWPerformanceData_tbl.FY,
WOWPerformanceData_tbl.Month,
PrintPromotions.[Type of Offer],
PrintPromotions.Start,
PrintPromotions.End
from WOWPerformanceData_tbl
right join PrintPromtions
on WOWPerformanceData_tbl.Style=PrintPromotions.Style
AND (WOWPerformanceData_tbl.Style=[Enter Style nr:]);