Create series of counting for each employee by date - sql

Question

I am trying to list out a count of how many times an employeeid shows up for each date separated by lines and in the 0000 format.
Each time the specific employeeid occurs on a specific date, the count goes up. So EmployeeId 143 happens twice on 2023-01-18, so the first row is 0001, second is 0002
SELECT
FORMAT(COUNT(e.EmployeeId), '0000') AS [Count]
, e.EmployeeId
, c.CheckDate
FROM dbo.Check c
JOIN dbo.Employees e
ON e.EmployeeId = c.CreatedBy
GROUP BY c.CheckDate, e.EmployeeId
ORDER BY c.CheckDate DESC;
What I'm currently getting:
COUNT
EmployeeId
CheckDate
0002
143
2023-01-18 00:00:00.000
0002
143
2023-01-17 00:00:00.000
0002
427
2023-01-17 00:00:00.000
0007
607
2023-01-17 00:00:00.000
What I am wanting is:
COUNT
EmployeeId
CheckDate
0001
143
2023-01-18 00:00:00.000
0002
143
2023-01-18 00:00:00.000
0001
143
2023-01-17 00:00:00.000
0002
143
2023-01-17 00:00:00.000
0001
427
2023-01-17 00:00:00.000
0002
427
2023-01-17 00:00:00.000
etc.

Answer 1

My take of your issue here is that you are aggregating while you need a window function really.
To ensure unique values for your couples <CheckDate, EmployeeId> duplicates, you can try using the ROW_NUMBER window function.
SELECT FORMAT(ROW_NUMBER() OVER(
PARTITION BY c.CheckDate, e.EmployeeId
ORDER BY e.EmployeeId
), '0000') AS [Count]
, e.EmployeeId
, c.CheckDate
FROM dbo.Check c
INNER JOIN dbo.Employees e
ON e.EmployeeId = c.CreatedBy
ORDER BY c.CheckDate DESC;