BASH script to create SQL statement ignore last column - sql

Question

I am trying to create a bash script that will generate an SQL CREATE TABLE statement from a CSV file.
#!/bin/bash
# Check if the user provided a CSV file
if [ $# -eq 0 ]
then
echo "No CSV file provided."
exit 1
fi
# Check if the CSV file exists
if [ ! -f $1 ]
then
echo "CSV file does not exist."
exit 1
fi
# Get the table name from the CSV file name
table_name=$(basename $1 .csv)
# Extract the header row from the CSV file
header=$(head -n 1 $1)
# Split the header row into column names
IFS=',' read -r -a columns <<< "$header"
# Generate the PostgreSQL `CREATE TABLE` statement
echo "CREATE TABLE $table_name ("
for column in "${columns[#]}"
do
echo " $column TEXT,"
done
echo ");"
If I have a CSV file with three columns(aa,bb,cc), the generated statement does not have the last column for some reason.
Any idea what could be wrong?
If I do:
for a in "${array[#]}"
do
echo "$a"
done
I am getting:
aaa
bbb
ccc
But when add something into the string:
for a in "${array[#]}"
do
echo "$a SOMETHING"
done
I get:
aaa SOMETHING
bbb SOMETHING
SOMETHING
Thanks.

Answer 1

Your csv file has a '\r`
Try the next block for reproducing the problem.
printf -v header "%s,%s,%s\r\n" "aaa" "bbb" "ccc"
IFS=',' read -r -a columns <<< "$header"
echo "Show array"
for a in "${columns[#]}"; do echo "$a"; done
echo "Now with something extra"
for a in "${columns[#]}"; do echo "$a SOMETHING"; done
You should remove the '\r', what can be done with
IFS=',' read -r -a columns < <(tr -d '\r' <<< "${header}")