Bash purge script - sql

Question

I'm trying to create a script that removes my images that are not in DB
There is my code (Updated):
I have 1 problems:
Problem with the like syntax like '%$f%'
#!/bin/bash
db="intranet_carc_development"
user="benjamin"
for f in public/uploads/files/*
do
if [[ -f "$f" ]]
then
psql $db $user -t -v "ON_ERROR_STOP=1" \
-c 'select * from public.articles where content like "%'"$(basename "$f")"'%"' | grep . \
&& echo "exist" \
|| echo "doesn't exist"
fi
done
And I have the following error :
ERROR: column "%1YOLV3M4-VFb2Hydb0VFMw.png%" does not exist
LINE 1: select * from public.articles where content like "%1YOLV3M4-...
^
doesn't exist
ERROR: column "%wnj8EEd8wuJp4TdUwqrJtA.png%" does not exist
LINE 1: select * from public.articles where content like "%wnj8EEd8w...
EDIT : if i use \'%$f%\' for the like :
/purge_files.sh: line 12: unexpected EOF while looking for matching `"'
./purge_files.sh: line 16: syntax error: unexpected end of file

Answer 1

There are several issues with your code :
$f is public/uploads/files/FILENAME and i want only the FILENAME
You can use basename to circumvent that, by writing :
f="$(basename "$f")"
psql $db $user -c "select * from public.articles where content like '%$f%'"...
(The extra quotes are here to prevent issues if you have spaces and special characters in your file name)
your psql request will always return true even if no rows are found
your psql command will return true even if the request fails, unless you set the variable 'ON_ERROR_STOP' to 1
As shown in the linked questions, you can use the following syntax :
#!/bin/bash
set -o pipefail #needed because of the pipe to grep later on
db="intranet_carc_development"
user="benjamin"
for f in public/uploads/files/*
do
if [[ -f "$f" ]]
then
f="$(basename "$f")"
psql $db $user -t -v "ON_ERROR_STOP=1" \
-c "select * from public.articles where content like '%$f%'" | grep . \
&& echo "exist" \
|| echo "doesn't exist"
fi
done