Split Geometry / LineString by vertex and not on intersect - sql

I would like to cut the lines by vertex. It does not work as I wish because there are lines that cross. The current query that I split the lines by vertex and also as soon as the lines intersect.
I only want it to cut at vertices and not at line crossings.
Thank you
Here is the SQL
WITH gpx_line AS (
SELECT uuid, ST_AsText(ST_MakeLine(lag((pt).geom, 1, NULL) OVER (PARTITION BY uuid ORDER by uuid, (pt).path), (pt).geom)) AS wkb_geometry
FROM (SELECT uuid, ST_DumpPoints(wkb_geometry) AS pt FROM public.points_gpx_to_line) as dumps
)
SELECT * FROM gpx_line WHERE wkb_geometry IS NOT NULL;

Without sample data and the expected results it is hard to know for sure what you're trying to achieve, but I believe what you described can be done with ST_DumpSegments:
A set-returning function (SRF) that extracts the coordinates (vertices) of a geometry. It returns a set of geometry_dump rows, each containing a geometry (geom field) and an array of integers (path field).
SELECT
ST_AsText(
(ST_DumpSegments('LINESTRING(1 1,2 2,3 3,4 4)'::geometry)).geom);
st_astext
---------------------
LINESTRING(1 1,2 2)
LINESTRING(2 2,3 3)
LINESTRING(3 3,4 4)
(3 rows)

Related

Bigquery SQL: convert array to columns

I have a table with a field A where each entry is a fixed length array A of integers (say length=1000). I want to know how to convert it into 1000 columns, with column name given by index_i, for i=0,1,2,...,999, and each element is the corresponding integer. I can have it done by something like
A[OFFSET(0)] as index_0,
A[OFFSET(1)] as index_1
A[OFFSET(2)] as index_2,
A[OFFSET(3)] as index_3,
A[OFFSET(4)] as index_4,
...
A[OFFSET(999)] as index_999,
I want to know what would be an elegant way of doing this. thanks!
The first thing to say is that, sadly, this is going to be much more complicated than most people expect. It can be conceptually easier to pass the values into a scripting language (e.g. Python) and work there, but clearly keeping things inside BigQuery is going to be much more performant. So here is an approach.
Cross-joining to turn array fields into long-format tables
I think the first thing you're going to want to do is get the values out of the arrays and into rows.
Typically in BigQuery this is accomplished using CROSS JOIN. The syntax is a tad unintuitive:
WITH raw AS (
SELECT "A" AS name, [1,2,3,4,5] AS a
UNION ALL
SELECT "B" AS name, [5,4,3,2,1] AS a
),
long_format AS (
SELECT name, vals
FROM raw
CROSS JOIN UNNEST(raw.a) AS vals
)
SELECT * FROM long_format
UNNEST(raw.a) is taking those arrays of values and turning each array into a set of (five) rows, every single one of which is then joined to the corresponding value of name (the definition of a CROSS JOIN). In this way we can 'unwrap' a table with an array field.
This will yields results like
name | vals
-------------
A | 1
A | 2
A | 3
A | 4
A | 5
B | 5
B | 4
B | 3
B | 2
B | 1
Confusingly, there is a shorthand for this syntax in which CROSS JOIN is replaced with a simple comma:
WITH raw AS (
SELECT "A" AS name, [1,2,3,4,5] AS a
UNION ALL
SELECT "B" AS name, [5,4,3,2,1] AS a
),
long_format AS (
SELECT name, vals
FROM raw, UNNEST(raw.a) AS vals
)
SELECT * FROM long_format
This is more compact but may be confusing if you haven't seen it before.
Typically this is where we stop. We have a long-format table, created without any requirement that the original arrays all had the same length. What you're asking for is harder to produce - you want a wide-format table containing the same information (relying on the fact that each array was the same length.
Pivot tables in BigQuery
The good news is that BigQuery now has a PIVOT function! That makes this kind of operation possible, albeit non-trivial:
WITH raw AS (
SELECT "A" AS name, [1,2,3,4,5] AS a
UNION ALL
SELECT "B" AS name, [5,4,3,2,1] AS a
),
long_format AS (
SELECT name, vals, offset
FROM raw, UNNEST(raw.a) AS vals WITH OFFSET
)
SELECT *
FROM long_format PIVOT(
ANY_VALUE(vals) AS vals
FOR offset IN (0,1,2,3,4)
)
This makes use of WITH OFFSET to generate an extra offset column (so that we know which order the values in the array originally had).
Also, in general pivoting requires us to aggregate the values returned in each cell. But here we expect exactly one value for each combination of name and offset, so we simply use the aggregation function ANY_VALUE, which non-deterministically selects a value from the group you're aggregating over. Since, in this case, each group has exactly one value, that's the value retrieved.
The query yields results like:
name vals_0 vals_1 vals_2 vals_3 vals_4
----------------------------------------------
A 1 2 3 4 5
B 5 4 3 2 1
This is starting to look pretty good, but we have a fundamental issue, in that the column names are still hard-coded. You wanted them generated dynamically.
Unfortunately expressions for the pivot column values aren't something PIVOT can accept out-of-the-box. Note that BigQuery has no way to know that your long-format table will resolve neatly to a fixed number of columns (it relies on offset having the values 0-4 for each and every set of records).
Dynamically building/executing the pivot
And yet, there is a way. We will have to leave behind the comfort of standard SQL and move into the realm of BigQuery Procedural Language.
What we must do is use the expression EXECUTE IMMEDIATE, which allows us to dynamically construct and execute a standard SQL query!
(as an aside, I bet you - OP or future searchers - weren't expecting this rabbit hole...)
This is, of course, inelegant to say the least. But here is the above toy example, implemented using EXECUTE IMMEDIATE. The trick is that the executed query is defined as a string, so we just have to use an expression to inject the full range of values you want into this string.
Recall that || can be used as a string concatenation operator.
EXECUTE IMMEDIATE """
WITH raw AS (
SELECT "A" AS name, [1,2,3,4,5] AS a
UNION ALL
SELECT "B" AS name, [5,4,3,2,1] AS a
),
long_format AS (
SELECT name, vals, offset
FROM raw, UNNEST(raw.a) AS vals WITH OFFSET
)
SELECT *
FROM long_format PIVOT(
ANY_VALUE(vals) AS vals
FOR offset IN ("""
|| (SELECT STRING_AGG(CAST(x AS STRING)) FROM UNNEST(GENERATE_ARRAY(0,4)) AS x)
|| """
)
)
"""
Ouch. I've tried to make that as readable as possible. Near the bottom there is an expression that generates the list of column suffices (pivoted values of offset):
(SELECT STRING_AGG(CAST(x AS STRING)) FROM UNNEST(GENERATE_ARRAY(0,4)) AS x)
This generates the string "0,1,2,3,4" which is then concatenated to give us ...FOR offset IN (0,1,2,3,4)... in our final query (as in the hard-coded example before).
REALLY dynamically executing the pivot
It hasn't escaped my notice that this is still technically insisting on your knowing up-front how long those arrays are! It's a big improvement (in the narrow sense of avoiding painful repetitive code) to use GENERATE_ARRAY(0,4), but it's not quite what was requested.
Unfortunately, I can't provide a working toy example, but I can tell you how to do it. You would simply replace the pivot values expression with
(SELECT STRING_AGG(DISTINCT CAST(offset AS STRING)) FROM long_format)
But doing this in the example above won't work, because long_format is a Common Table Expression that is only defined inside the EXECUTE IMMEDIATE block. The statement in that block won't be executed until after building it, so at build-time long_format has yet to be defined.
Yet all is not lost. This will work just fine:
SELECT *
FROM d.long_format PIVOT(
ANY_VALUE(vals) AS vals
FOR offset IN ("""
|| (SELECT STRING_AGG(DISTINCT CAST(offset AS STRING)) FROM d.long_format)
|| """
)
)
... provided you first define a BigQuery VIEW (for example) called long_format (or, better, some more expressive name) in a dataset d. That way, both the job that builds the query and the job that runs it will have access to the values.
If successful, you should see both jobs execute and succeed. You should then click 'VIEW RESULTS' on the job that ran the query.
As a final aside, this assumes you are working from the BigQuery console. If you're instead working from a scripting language, that gives you plenty of options to either load and manipulate the data, or build the query in your scripting language rather than massaging BigQuery into doing it for you.
Consider below approach
execute immediate ( select '''
select * except(id) from (
select to_json_string(A) id, * except(A)
from your_table, unnest(A) value with offset
)
pivot (any_value(value) index for offset in ('''
|| (select string_agg('' || val order by offset) from unnest(generate_array(0,999)) val with offset) || '))'
)
If to apply to dummy data like below (with 10 instead of 1000 elements)
select [10,11,12,13,14,15,16,17,18,19] as A union all
select [20,21,22,23,24,25,26,27,28,29] as A union all
select [30,31,32,33,34,35,36,37,38,39] as A
the output is

PostGIS query to Select all Polygons from Polygon table having an intersecting geometry with one or more point in passed list of GeoCoordinates

I have a polygons table in Postgres (using PostGIS extension) named polygon having two fields (geom, id).
If I want to query the id of the polygon which intersects with the geometry of input geo-coordinate then I can do it with the below query.
SELECT id, geom
FROM polygon
WHERE ST_Intersects(polygon.%s, ST_GeometryFromText(POINT(latitude logitude), 4326));
But now I have a use case where I am getting a lot of geo-coordinates in request(~60k), now I am breaking this into lists of 1k Geo-coordinate each and querying the id of the polygon intersecting with each geo-coordinate.
I am struggling with how to write. a query for this, or if anyone has a better solution for this please suggest.
Keep in mind that the right order of coordinate pairs is lon, lat, so creating a point with lat, lon in your query will return wrong results. Your query also misses the single quotes ' around the WKT coordinate, e.g. 'POINT(1 2)'.
That all being said, you could simply paginate your result sets using ORDER BY, LIMIT and OFFSET, e.g.
Getting the first 1000 records
SELECT id, geom FROM polygon
WHERE ST_Intersects(geom, 'SRID=4326;POINT(1 2)')
ORDER BY id
LIMIT 1000 OFFSET 0;
By changing the OFFSET value you are able to retrieve the next pages.
LIMIT 1000 OFFSET 1000;
and so on ..
LIMIT 1000 OFFSET 2000;
EDIT: One way to apply this query using multiple input points is to use a CTE / subquery (see comments), e.g.
WITH j(g) AS (
VALUES
('SRID=4326;POINT(1 1)'),
('SRID=4326;POINT(1 2)')
-- ... add as many geometries as you want
)
SELECT id, geom FROM polygon, j
WHERE ST_Intersects(geom, g::geometry)

How to get the intersection length of touching geometries with ST_Touches

I am trying to develop a query in Postgis, where it can solve this problem:
I have a geometry and I wanna know which of the polygons that touches it, there is the highest contact area of this geometry. After I recognize this polygon I will take its value in a specific column and put this value in the same column but in my geometry.
Someone know how can I do that? I am a new user in postgresql/postgis.
As pointed out by #JGH in the comments, the overlapping area will be zero if you use ST_Touches alone. What you can do is to filter out only the geometries that do touch your reference geometry and then use ST_Intersection to get the intersection area, so that you can finally calculate the length of the intersection with ST_Length.
Data Sample
The geometry values depicted above are inside the CTE:
WITH j (id,geom) AS (
VALUES
(1,'POLYGON((-4.64 54.19,-4.59 54.19,-4.59 54.17,-4.64 54.17,-4.64 54.19))'),
(2,'POLYGON((-4.59 54.19,-4.56 54.19,-4.56 54.17,-4.59 54.17,-4.59 54.19))'),
(3,'LINESTRING(-4.65 54.19,-4.57 54.21)'),
(4,'POLYGON((-4.66 54.21,-4.60 54.21,-4.60 54.20,-4.66 54.20,-4.66 54.21))'),
(5,'POINT(-4.57 54.20)')
)
SELECT
id,
ST_Length(
ST_Intersection(
geom,
'POLYGON((-4.62 54.22,-4.58 54.22,-4.58 54.19,
-4.62 54.19,-4.62 54.22))')) AS touch_length
FROM j
WHERE
ST_Touches(
geom,
'POLYGON((-4.62 54.22,-4.58 54.22,-4.58 54.19,
-4.62 54.19,-4.62 54.22))')
ORDER BY touch_length DESC
LIMIT 1;
id | touch_length
----+---------------------
1 | 0.03000000000000025
(1 Zeile)

Selecting a start line with where geom returns different geom

I have a table with multilinestrings and I would like to find a line which starts at a certain point. I am using:
gis=> select * from (select gid, ST_StartPoint(ST_LineMerge((geom))) as start from aw_pipes) s where s.start = '0101000020E6100000D050E433E678D73F71F37608AF284A40' order by gid;
gid | start
------+----------------------------------------------------
1458 | 0101000020E6100000809BB933E678D73FE3D07608AF284A40
(1 row)
The problem here is the result has different geom. It is not what I asked for. It doesn't event contain the geom I was searching for.
gis=> select geom from aw_pipes where gid = 1458;
geom
--------------------------------------------------------------------------------------------------------------
0105000020E610000001000000010200000002000000809BB933E678D73FE3D07608AF284A40CDD4B35E4E7BD73F62DB7D83AD284A40
(1 row)
gis=> select ST_DumpPoints('0105000020E610000001000000010200000002000000809BB933E678D73FE3D07608AF284A40CDD4B35E4E7BD73F62DB7D83AD284A40');
st_dumppoints
--------------------------------------------------------------
("{1,1}",0101000020E6100000809BB933E678D73FE3D07608AF284A40)
("{1,2}",0101000020E6100000CDD4B35E4E7BD73F62DB7D83AD284A40)
(2 rows)
My postgis version is:
gis=> select PostGIS_Version ();
postgis_version
---------------------------------------
2.3 USE_GEOS=1 USE_PROJ=1 USE_STATS=1
Any idea what I am doing wrong or any suggestion what I may change in my query?
Comparing geometries using = might not lead to the result you would expect. Before PostGIS 2.4, the equality is based on the geometry bounding box, not on the vertices themselves, and likely truncate insignificant digits. Check this excellent article.
You could replace = by ST_Equals, which checks every vertices for exact spatial equality.
That being said, your expectations might be a bit too high. The distance between your geometry and the line starting point is 1.266e-005 m, so about 10 micrometers... most GIS user/software would consider the two points as being equal.

Finding the pair of points whose distance from each other is maximal

I have a very small database which includes 6 points, with those columns id, the_geom, descr. And my aim to write a PL/pgSQL function which finds the the pair of points whose distance from each other is maximal. As an output, I would like to show the id or descr of two points and also the distance between them.
I have tried to do a function with returns table but setof text would be better solution?
You may try something like a cross join to find all combinations, then order by the difference. If your table name was foo something similar to:
SELECT set1.id, set2.id, abs(set1.the_geom - set2.the_geom) --- May want to use earth_distance extension ehre
FROM foo set1, foo set2
WHERE set1.id != set2.id
ORDER BY 3 DESC;
And if you need earth distance to calculate the distance itself - http://www.postgresql.org/docs/9.3/static/earthdistance.html