How can I select a XPath that contains a text with both quote & comma character?
I have to find an element if the text contains =Yes, It's OK
My XPath does not save in ranorex tool even though if i put the text inside the double quotes like below
//span[text()="Yes, It's OK"]
So how can I save this xpath that uses "".in Ranorex
your use of double-quotes is correct. if
//span[text()="Yes, It's OK"]
doesn't match, it might be because the xpath engine has a lowercase bug (i have encountered PHP+DOMXPath+libxml2 systems where it would only match lowercase text even for text with uppercase characters, never quite figured out the problem there), or it might be because the text has hidden whitespace you're not aware of, maybe it actually has a hard-to-spot whitespace at the start or the end? anyway maybe contains() will work:
//span[contains(text(),"Yes, It's OK"]
or.. if it has the lowercase-issue i have encountered in the wild once before, maybe this will work:
//span[contains(text(),"yes, it's ok"]
(that really shouldn't be required, but i have been in that situation once before, and that was years ago, and that was... probably php5)
Related
When deleting words (ctrl+backspace or ctrl+delete) in IntelliJ it treats whitespace as a word until it hits a newline character. I want to treat every sequence of space/tab and newline[sequences] as one word.
Essentially this is the reverse problem of this question in IntelliJ.
Sadly i did not find any setting to do that so far.
There exists a "Hungry Backspace" action.
Yet there exists no "Hungry Delete" out of the box.
And it does not work for non-whitespace words.
All.
I am used to programming VBA in Excel, but am new to the structures in Word.
I am working through a library of text files to update them. Many of them are either OCR documents, or were manually entered.
Each has a recurring pattern, the most common of which is unnecessary carriage returns.
For example, I am looking at several text files where there is a double return after each line. A search and replace of all double carriage returns removes all paragraph distinctions.
However, each line is approximately 30 characters long, and if I manually perform the following logic, it gives me a functional document.
If there is a double carriage return after 30+ characters, I replace them with a space.
If there were less than 30 characters prior to the double return, I replace them with a single return.
Can anyone help me with some rudimentary code that would help me get started on that? I could then modify it for each "pattern" of text documents I have.
e.g.
In this case, there are more than
thirty characters per line. And I
will keep going to illustrate this
example.
This would be a new paragraph, and
would be separated by another of
the single returns.
I want code that would return:
In this case, there are more than thirty character returns. And I will keep going to illustrate this example.
This would be a new paragraph, and would be separated by another of the single returns.
Let me know if anyone can throw something out that I can play with!
You can do this without code (which RegEx requires), simply using Word's own wildcard Find/Replace tools, where:
Find = ([!^13]{30,})[^13]{1,}
Replace = \1^32
and, to clean up the residual multi-paragraph breaks:
Find = [^13]{2,}
Replace = ^p
You could, of course, record the above as a macro...
Here is a RegEx that might work for you:
(\n\n)(?<!\.(\n\n))
The substitution is just a plain space, you can try it out (and modify / tweak it) here: https://regex101.com/r/zG9GPw/4
This 'pattern' tells the RegEx engine to look for the newline character \n which occurs x2 like this \n\n (worth noting this is from your question and might be different in your files, e.g. could be \r\n) and it assumes that a valid line break will be proceeded by a full stop: \..
In RegEx the full stop symbol is a single character wild card so it needs to be escaped with the '\' (n and r are normal characters, escaping them tells the RegEx engine they represent newline and return characters).
So... the expression is looking for a group of x2 newline characters but then uses a negative look-behind to exclude any matches where the previous character was a full stop.
Anyway, it's all explained on the site:
Here is how you could do a RegEx find and replace using NotePad++ (I'm not sure if it comes with RegEx or if a plugin is needed, either way it is easy). But you can set a location, filters (to target specific file types), and other options (such as search in sub-directories).
Other than that, as #MacroPod pointed out you could also do this with MS Word, document by document, not using any code :)
This is a bit of a puzzler for me. I have a string that looks like:
fanspd<fanspd>3</fanspd>
doorinprocess<doorinprocess>0</doorinprocess>
timeremaining<timeremaining>0</timeremaining>
macaddr<macaddr>60:CB:FB:99:99:C1</macaddr>
ipaddr<ipaddr>10.0.0.6</ipaddr>
model<model>4.4eWHF</model>
softver: <softver>2.14.2</softver>
interlock1: <interlock1>0</interlock1>
interlock2: <interlock2>0</interlock2>
cfm: <cfm>2200</cfm>
power: <power>120</power>
inside: <house_temp>-99</house_temp>
<DNS1>10.0.0.1</DNS1>
attic: <attic_temp>76</attic_temp>
OA: <oa_temp>-99</oa_temp>
server response: <server_response>Ó£àêEE²ç©þ]kõ «jsÐ</server_response>
DIP Switches: <DIPS>11100</DIPS>
Remote Switch: <switch2>1111</switch2>
Setpoint:<Setpoint>0</Setpoint>
The string includes the "/n" so I have split it into corrisponding lines that look like
fanspd<fanspd>0</fanspd>
All I really want is the char(s) in the middle of the line. In the above example it would be 0.
I can match everything with regular expressions but by doing the following:
(.*)(<[a-z]+>)(.*)(</[a-z]+>)
But what I'd like is something more that would exclude or strip away or remove all the junk and grab the middle chars.
(!(.*)(!<[a-z]+>))(.*)(!(</[a-z]+>))
I've tried this and it does not work. I've also thought of doing another [NSstring componentsSeparatedByString:#"(with either < or or >"] but that would leave be with more parsing yet to do and I think there should be a way to get just the chars inbetween the tags with either regular expressions or string compare or some such way to parse out the
Any suggestions or help would be greatly appreciated.
Thanks
Two things.
Your regular expression does not escape the forward slash.
Your regular expression seems overly complicated for what you are trying to do.
If all you want is that lone middle character with regular expressions,
Try this:
<[a-z]+>(.*)<\/[a-z]+>
Here's a great tool to play around with:
http://rubular.com
Heck you could probably even get away with:
<[a-z]+>(.*)<\/
EDIT:
I figured out your problem partially, some of the tags part way down contain characters other than a through z. So here you go:
<.+>(.*)<\/.+>
Im doing some screen scraping and im getting back a string that appears to end with whitespace but neither string.strip or strip.gsub(/\s/u, '') removes the character.
Im guessing it's a character encoding issue. Any suggestions?
I think, there are a lot of "space characters".
You can use something like this:
my_string.gsub("\302\240", ' ').strip
You can try this: my_string.gsub(/\A[[:space:]]+|[[:space:]]+\z/, '')
This should remove all space characters from the beginning and the end of string, including all possible unicode space variations.
Figure out the character code of the last character (str[-1].ord) and explicitly search and destroy it. Rinse/repeat if there exist more unwanted characters after that. After doing this, report back here what the invisible character was. (Perhaps it's only invisible because the font you are using does not have that glyph?)
I'm using Redmine and I'm trying to insert the special character | inside a table in a Redmine wiki page. I don't want this character to be parsed as a column separator.
I've achieved this by doing a <code>|</code> around this character, but I don't want to use the code tag, since this character will gain code attributes, namely the courier new font.
Is there a tag for displaying plain text and avoid the parsing from the Redmine wiki engine?
I'm reading the redmine wiki formatting documentation but it is very poor and points me to textile formatting which doesn't seem to include this special case.
I could not get the exclimation point to work, but this works for me.
<notextile>|</notextile>
The only way I found out to overcome this problem is to insert the HTML code for the character I want to isolate. For instance, instead of putting an underscore and make the wiki think I'm starting an italic word, I have to put the HTML code for it:
_
Example:
this is a _test - _text comment here_
Without the underscore code (_) redmine wiki engine will think that italic starts at test and this is the wrong result:
this is a test - text comment here
So, putting the ASCII code for the underscore corrects this problem. Unfortunately, this parsing is not very clever (yet I hope).
Here is a link for an ASCII code table with many symbols and characters:
http://www.ascii.cl/htmlcodes.htm