Sum of numbers in CTE - sql

Question

For this CTE show counts of working/not working days.
with a(id, MON, TUE, WED, THUR, FRI, SAT, SUN) as (values (1,0,0,1,1,1,0,0),(2,1,1,1,1,0,0,0))
select * from a
I got this result but I changed CTE.
My request:
with a(id, days) as (values (1,0),(1,0),(1,1),(1,1),(1,1),(1,0),(1,0),(2,1),(2,1),(2,1),(2,1),(2,0),(2,0),(2,0))
select id, 'Working' as day_type, sum(days) "COUNT" from a group by shop_id union select id, 'Non-working' as day_type, count(days) - sum(days) "COUNT" from a group by id order by id, day_type

Answer 1

If I understand your question, you want to be able to generate the output from your second query without altering the initial CTE a (which presumably represents an actual table or something).
There will be multiple ways of doing this, but one possibility is something like:
with a(shop_id, MON, TUE, WED, THUR, FRI, SAT, SUN) as (values (1,0,0,1,1,1,0,0),(2,1,1,1,1,0,0,0))
, b as (SELECT shop_id, MON + TUE + WED + THUR + FRI + SAT + SUN cnt FROM a)
SELECT shop_id, 'Working', cnt
FROM b
GROUP BY shop_id, cnt
UNION ALL
SELECT shop_id, 'Non-working', 7-cnt
FROM b
GROUP BY shop_id, cnt
Here, the CTE b contains the sum of working days for each shop_id. This is then unioned together with the non-working days (7-working). Using the second CTE isn't necessary, but lets us avoid repeating the bit that adds all the days together. If you prefer, you could do:
with a(shop_id, MON, TUE, WED, THUR, FRI, SAT, SUN) as (values (1,0,0,1,1,1,0,0),(2,1,1,1,1,0,0,0))
SELECT shop_id, 'Working', MON + TUE + WED + THUR + FRI + SAT + SUN cnt
FROM a
UNION ALL
SELECT shop_id, 'Non-working', 7-(MON + TUE + WED + THUR + FRI + SAT + SUN)
FROM a
Another options is to actually unpivot the table (convert the columns into rows) and then group by the shop_id and day_type. Something like:
with a(shop_id, MON, TUE, WED, THUR, FRI, SAT, SUN) as (values (1,0,0,1,1,1,0,0),(2,1,1,1,1,0,0,0))
,
b AS (SELECT shop_id, CASE P.w WHEN 0 THEN 'Non-working' ELSE 'Working' END day_type
FROM a, TABLE (VALUES(a.MON),
(a.TUE),
(a.WED),
(a.THUR),
(a.FRI),
(a.SAT),
(a.SUN)) AS P(w))
SELECT shop_id, day_type, count(*) cnt
FROM b
GROUP BY shop_id, day_type
In all cases above, you can use an ORDER BY to get the rows in the order you want them.
Here is a Fiddle of these working.