How to extract a specific line strings using awk - awk

Question

I need to extract from this line:
Susan Dalsass:[phone]:250:60:50 ----> (the line is in the susan.txt file)
only this strings:
Susan Dalsass [phone]
using awk and regex pattern. Maybe someone knows how to do it?
I tried to do something like this but it didn't work:
awk '/(Susan)[[:space:]](Dalsass).?([0-9]{3})[[:space:]]([0-9]{3}-[0-9]{4})/{print $1,$2,$3,$4}' susan.txt

Answer 1

Assumptions:
the line(s) of interest are of the form <name>:<phone>:<rest_of_line>
matching will be based solely on the name (first) field
the full name (spelling and case) is known in advance otherwise we need to look at modifying the match logic to work on a) a substring and/or b) case sensitivity
Setup:
$ cat susan.txt
ignore this line
Susan Dalsass:[phone]:250:60:50
ignore this line
For this particular case there's really no need to use a (complicated?) regex when we can use some basic string matching capabilities of awk ...
Exact match on first field:
$ awk -F':' '$1=="Susan Dalsass" { print $1,$2 }' susan.txt
Susan Dalsass [phone]
Match on leading part of the input line:
$ awk -F':' '/^Susan Dalsass/ { print $1,$2 }' susan.txt
Susan Dalsass [phone]
Using a bash variable for an exact match on the name:
$ fullname="Susan Dalsass"
$ awk -v name="${fullname}" -F':' '$1==name { print $1,$2 }' susan.txt
Susan Dalsass [phone]
Using a bash variable to do a partial match on the name:
$ partname="Susan"
$ awk -v name="${partname}" -F':' '$1~name { print $1,$2 }' susan.txt
Susan Dalsass [phone]
Using a bash variable to do a partial, case-sensitive match on the name:
$ partname="saSS"
$ awk -v name="${partname}" -F':' 'tolower($1)~tolower(name) { print $1,$2 }' susan.txt
Susan Dalsass [phone]