I'm trying to get the record count from multiple tables, like this.
Select count(*)
From
(
Select Hist.Common_Name,
Veg.ID,
EDSH.ID
From Hist_Event_View as Hist
Inner Join Vegtables as Veg
ON Hist.Common_Name = Veg.ID
INNER JOIN Final as Final
ON Hist.Common_Name = Final.ID) as Sub
The problem is that ID is being used multiple times, so SQL Server can't resolve which ID is coming from which table in the outer query, I think. How can I handle this issue?
Your assumption is correct, the duplicate ID's are the problem. You can handle this by giving the ID's an alias in the subquery:
Select count(*)
From
(
Select Hist.Common_Name,
Veg.ID as Veg_ID,
EDSH.ID as EDSH_ID
From Hist_Event_View as Hist
Inner Join Vegtables as Veg
ON Hist.Common_Name = Veg.ID
INNER JOIN Final as Final
ON Hist.Common_Name = Final.ID) as Sub
I think this could be fixed by using an alias
https://www.w3schools.com/sql/sql_alias.asp
But why do you need an outer select?
Why not just write:
Select count(*)
From Hist_Event_View as Hist
Inner Join Vegtables as Veg
ON Hist.Common_Name = Veg.ID
INNER JOIN Final as Final
ON Hist.Common_Name = Final.ID
Related
In my query I want total file count and total closed files in the same table.
My first query:
select hi.eksper_id,ef.ad, count(hi.eksper_id) as total_files
from hasar_ihbar as hi
left outer join eksper_firma ef on ef.id=hi.eksper_id
group by hi.eksper_id,ef.ad
My second query:
select ef.id as eksper_id,ef.ad,count(ef.id) closed_files
from hasar_ihbar_rapor hir
left outer join hasar_ihbar hi on hi.id = hir.hasar_ihbar_id
left outer join eksper_firma ef on ef.id = hi.eksper_id
where hir.rapor_tipi = 3 group by ef.id,ef.ad
I want both combined and this is my code:
select ef.id as eksper_id,ef.ad,count(ef.id) closed_files, count(hi.id) AS total_files
from hasar_ihbar_rapor hir
left outer join hasar_ihbar hi on hi.id = hir.hasar_ihbar_id
left outer join eksper_firma ef on ef.id = hi.eksper_id
where hir.rapor_tipi = 3 group by ef.id,ef.ad
I don't know what I did wrong. Thanks for your help.
The double joins effect your counts since there are more rows.
A better way to combine both counts is to create a query that has two subqueries for each count.
SELECT id,
(SELECT COUNT(*)...) total_files,
(SELECT COUNT(*)...) closed_files
FROM ...
Im trying to show all columns from my t1_elem table and join 2 columns in which I use COUNT.
I used query:
SELECT p.*,COUNT(t4_id) as ile_publikacji, COUNT(t7_id) as ile_fitow
FROM t1_elem p
LEFT OUTER JOIN t4_autorzy ON p.t1_id=t4_autorzy.t4_t1_id
LEFT JOIN t7_pliki ON p.t1_id=t7_pliki.t7_t1_id
GROUP BY t1_id
But the results are bad. What I'm doing wrong?
Probably you have multiple matches. As stated, the two counts will be the same. The simplest solution is probably to use distinct:
SELECT p.*, COUNT(DISTINCT t4_id) as ile_publikacji, COUNT(DISTINCT t7_id) as ile_fitow
FROM t1_elem p LEFT JOIn
t4_autorzy
ON p.t1_id = t4_autorzy.t4_t1_id LEFT JOIN
t7_pliki
ON p.t1_id=t7_pliki.t7_t1_id
GROUP BY t1_id
Outputted Date
I have a seperate Members table which has all the members ID's and I want to list all those but get rid of the ones that are displayed in this list.
SELECT DISTINCT tbl_classregistration.ClassID, tbl_classregistration.MemberID
FROM tbl_member INNER JOIN (tbl_classes
INNER JOIN tbl_classregistration ON
tbl_classes.ClassID = tbl_classregistration.ClassID) ON
tbl_member.MemberID = tbl_classregistration.MemberID
GROUP BY tbl_classregistration.ClassID, tbl_classregistration.MemberID
HAVING (((tbl_classregistration.ClassID)=[Enter ClassID]));
Thats the SQL View
Use not in:
select memberid from members where memberid not in (SELECT DISTINCT tbl_classregistration.MemberID
FROM tbl_member INNER JOIN (tbl_classes INNER JOIN tbl_classregistration ON tbl_classes.ClassID = tbl_classregistration.ClassID) ON tbl_member.MemberID = tbl_classregistration.MemberID
GROUP BY tbl_classregistration.ClassID, tbl_classregistration.MemberID
HAVING (((tbl_classregistration.ClassID)=[Enter ClassID])))
I wrote a stored procedure that join three tables to fetch province title from it's table. This is my code:
BEGIN
select TbProvince.title, count(TbProvince.title) as cnt
from TbProvince
where TbProvince.provinceId IN (select TbCustomerUser.provinceId
from TbCustomerUser INNER JOIN
TbDeals
on TbCustomerUser.UserId = TbDeals.sellerUserID
where TbDeals.buyerUserID = 1
)
group by TbProvince.title
end
Description: I have three tables for deals, customers and provinces. I want to retrieve province title and the count of that for customers that were sellers.
The above code have no problem, but only return 1 as a count. The number of customers is more than one.
Can anybody help me solve my problem?
Your query is filtering the rows of TbProvince and then aggregating that table -- and only that table.
Instead, you want to join the tables together to count the customers not the provinces. The query is much simpler to write and read if you use table aliases:
select p.Title, count(*)
from TbCustomerUser cu join
TbDeals d
on cu.UserId = d.sellerUserID join
TbProvince p
on p.provinceId = cu.provinceId
where d.buyerUserID = 1
group by p.Title;
You have to perform the JOIN with customer table. If you use semi join (expressed by IN construct in your case) then you avoid duplicates that are expected in your case.
SELECT TbProvince.title,
COUNT(TbProvince.title) AS cnt
FROM TbProvince
JOIN TbCustomerUser ON TbProvince.provinceId = TbCustomerUser.provinceId
JOIN TbDeals ON TbCustomerUser.UserId = TbDeals.sellerUserID
WHERE TbDeals.buyerUserID = 1
GROUP BY TbProvince.title;
It should be as simple as:
You won't need the subselect. Just join all three tables and you'll receive your desired result.
SELECT TbProvince.title,
count(TbProvince.title) as cnt
FROM TbProvince
INNER JOIN TbCustomerUser
ON TbProvince.provinceId = TbCustomerUser.provinceId
INNER JOIN TbDeals
ON TbCustomerUser.UserId = TbDeals.sellerUserID
AND TbDeals.buyerUserID = 1
GROUP BY TbProvince.title
Why did your solution not work?
You subselect will return a "list" of provinceIDs from TbCustomerUser combinated with TbDeals with your restriction TbDeals.buyerUserID = 1.
The outer select will now return all rows from TbProvince IN this list.
But it's not returning a row for each Customer who had a deal.
That's why you have to JOIN all three tables at once.
I have 2 tables AP and INV where both have the columns [PROJECT] and [Value].
I want a query to return something like this :
PROJECT | SUM_AP | SUM_INV
I came up with the code below but it's returning the wrong results ( sum is wrong ).
SELECT AP.[PROJECT],
SUM(AP.Value) AS SUM_AP,
SUM(INV.Value) AS SUM_INV
FROM AP INNER JOIN INV ON (AP.[PROJECT] =INV.[PROJECT])
WHERE AP.[PROJECT] = 'XXXXX'
GROUP BY AP.[PROJECT]
The results from your query are wrong because the values you are trying to summarize are being grouped, which causes duplicate values to be included in the SUM.
You could solve it with a couple of sub-selects:
SELECT
AP1.[PROJECT],
(SELECT SUM(AP2.Value) FROM AP AS AP2 WHERE AP2.PROJECT = AP1.PROJECT) AS SUM_AP,
(SELECT SUM(INV2.Value) FROM INV AS INV2 WHERE INV2.PROJECT = AP1.PROJECT) AS SUM_INV
FROM AP AS AP1
INNER JOIN INV AS INV1
ON (AP1.[PROJECT] =INV1.[PROJECT])
WHERE AP1.[PROJECT] = 'XXXXX'
GROUP BY AP1.[PROJECT]
If you have N rows in AP with a given project ID, and M rows in INV with that ID, then the join between the two tables on the project ID will have a total of N*M rows for that project, because the same row in AP will be repeated for every row in INV that has that project ID, and vice versa. Hence why your counts are most likely off (because it's counting the same row in a given table multiple times due to repetition from the join).
Instead, you might want to try doing a join between the results of two subqueries, one which groups the first table by project ID and does that its sum, and the second which groups the other table by project ID and does that sum - then joining once you only have 1 row with sum for each project ID.
If PROJECT is the parent table, you should select FROM the project table, and do a left outer join on the two child tables:
SELECT PROJECT.PROJECT_ID, SUM(AP.Value) AS SUM_AP, SUM(INV.Value) AS SUM_INV
FROM PROJECT
LEFT OUTER JOIN AP ON (AP.[PROJECT] = PROJECT.[PROJECT_ID])
LEFT OUTER JOIN INV ON (INV.[PROJECT] = PROJECT.[PROJECT_ID])
WHERE PROJECT.[PROJECT_ID] = 'XXXXX'
GROUP BY PROJECT.[PROJECT_ID]
You could separate the two sum calculations. One way I can think of is to move the inventory calculation to a subquery, like:
SELECT
AP.[PROJECT]
, SUM(AP.Value) AS SUM_AP
, SummedInv as SUM_INV
FROM AP
LEFT JOIN (
SELECT PROJECT, SUM(Value) AS SUM_INV
FROM INV
GROUP BY PROJECT
) SummedInv ON SummedInv.Project = AP.Project
GROUP BY AP.PROJECT, SummedInv.SUM_INV
Because the SummedInv subquery is grouped on project, it's safe to group on SummedInv.SUM_INV in the outer query as well.
how about this query :
select SUM(gpCutBody.actualQty) as cutQty , SUM(gpSewBody.quantity) as sewQty
from jobOrder
inner join gpCutHead on gpCutHead.joNum = jobOrder.joNum
inner join gpSewHead on gpSewHead.joNum = jobOrder.joNum
inner join gpCutBody on gpCutBody.gpCutID = gpCutHead.gpCutID
inner join gpSewBody on gpSewBody.gpSewID = gpSewHead.gpSewID
where jobOrder.joNum = '36'
here is the link to the ERD: http://dl.dropbox.com/u/18794525/AUG%207%20DUMP%20STAN.png
Try:
SELECT AP.[PROJECT] AS PROJECT, SUM(AP.[Value]) AS SUM_AP, SUM(INV.[Value]) AS SUM_INV
FROM AP, INV
WHERE AP.[PROJECT] = INV.[PROJECT]
AND AP.[PROJECT] = 'XXXXX'
GROUP BY AP.[PROJECT]