I know this question has been answered before, but I can't understand from those examples.
There is a file called in the backend which executes functions.
This is my code:
def execGenion(self):
#if self.CN_exec_pushButton.clicked == True:
subprocess.check_call([path,"genion","-s",cntprf,"-o",cnoutf,"-p",cntopof,"-pname",posi,"-nname",negi,"-neutral"])
#Button for this function -
self.CN_exec_pushButton.clicked.connect(self.execGenion)
Now when this button is pressed on the GUI the control is transferred to the backend file where it asks for another input. But the GUI freezes and I can't give the next input. How do I fix this?
I tried using the examples on RealPython and certain different platforms but couldn't solve my problem.
Related
I made a code through python to operate a preview of my PiCamera, I have set the time to 10 seconds, then automatically turns off. However I am unsure how I would be able to have a keystroke to stop the camera and return to the previous screen?
At the moment I am able to view for 10 seconds, and nothing else, the usual ctrl-c and various other keys does not work.
How would I be able to integrate a keystroke into the code following to stop the script and return to normal screen?
from picamera import PiCamera
from time import sleep
camera = PiCamera()
camera.start_preview()
sleep(10)
camera.stop_preview()
Subprocess module you can check on the official page:
https://docs.python.org/2/library/subprocess.html#subprocess.Popen
A possible way to implement with subprocess.Popen is here on SO:
Controlling a python script from another script
Another possibility is to use multiprocesses or multithreading module. For instance creation of a thread can be done and you can take care of an ID :-)
All the possibility will lead you to learn a bit more of python!
My better suggestion will be to create easily a thread (https://docs.python.org/3/library/threading.html --> here for python 3), get the ID and leave it run.
If you want to terminate the camera running, then terminate the thread :-)
I'm new to PyopenGL and i'm currently working on a code originally based on the pyggel library, but now I'd like to add some features from GLUT (menu & text) and I'm not really sure how I should join both (if possible).
In GLUT, running glutMainLoop() is required, but on the other hand I have this run() routine:
def run(self):
while 1:
self.clock.tick(60)
self.getInput()
self.processInput()
pyggel.view.clear_screen()
self.mouse_over_object = self.scene.render(self.camera)
pyggel.view.refresh_screen()
#glutMainLoop()
Putting the GLUT routine inside my run() doesn't work (it crashes when it gets to the glutMainLoop).
So, how can I join both loops? Can I? I'm guessing that's what I need to make both things work.
Thanks in advance!
You likely are not going to find this easy to do. Pyggel is based on the Pygame GUI framework, while GLUT is its own GUI framework. You may be able to get text-rendering working, as under the covers GLUT is just doing regular OpenGL for that, but the menus are not going to easily work under Pyggel.
Pyggel has both text-rendering and a GUI framework that includes menus, frames, buttons, labels, etc. You likely want to use that if you're using Pyggel in your project there is an example of GUI usage here:
http://code.google.com/p/pyggel/source/browse/trunk/examples_and_tutorials/tut8-gui.py
I started creating my first GUI with PyQt4 a few hours ago and I've caught a snag. I've researched all over the web and while some resources have come close they've never really answered my question.
Basically I want to know if it is possible to take user input text from a widget and store that text into a variable from a button click.
So far I have looked into QLineEdit methods but have not found what I am looking for. Is there a better way to accomplish this?
Maybe something like this?
...
def __init__(self):
...
self.button.clicked.connect(self.on_button_click)
...
def on_button_click(self):
self.variable = self.line_edit.text()
print(self.variable)
...
So I have been pulling my hair out all day at this, and I am out of patience.
Basically I have a pygtk program that is built from glade. At the bottom of the main window, there is a status bar that I use to display usage errors, and status messages about the connected hardware and they use the functions below. So all of the calls to displayError come from within my object based on user interaction, and they all seem to work. In testing I tried making calls to displayCurrent and it works as well. The problem comes when the hardware process tries to use displayCurrent. The way the system works is that one of the members of my main window class is an interface object to the hardware. This has a separate process, using multiprocessing.Process, which sends a signal every time it gets data with the data being the message to output. Does anyone have any ideas? I'll be happy to explain anything in more depth if needed, it's just a LOT of code to post to get all the details.
def displayCurrent(self, message):
print message
if self.lastMess:
self.statusBar.remove(self.normalID, self.lastMess)
self.lastMess = self.statusBar.push(self.normalID, message)
def displayError(self, message, timeout = 5):
"""
Function that takes an error message and raises it to the user via the statusbar
timeout seconds later.
"""
print message
mess = self.statusBar.push(self.urgentID, message)
# clear statusbar
gobject.timeout_add_seconds(timeout, self.clearStatus, self.urgentID, mess)
def clearStatus(self, cID, mID):
#time.sleep(timeout)
self.statusBar.remove(cID, mID)
#print self.statusBar.remove_all(self.urgentID)
print 'popped'
return False
Post the whole code.
In general, this won't work if you are in a separate process. GTK (and everything else) has been forked. You need to use some form of interprocess communication. Multiprocessing module handles it for you. There are also hacks you can do in GTK such as using a window title (like Vim) or perhaps a plug and socket to communicate; don't be tempted by these.
I'm using a gtk.Image widget to display a picture in a gtk window. I can set the image to be displayed before I call window.main(), but after I've done that the image won't change any more. Basically:
import pygtk
pygtk.require('2.0')
import gtk
(...)
window= Window()
window.canvas= gtk.Image()
window.window.add(sprite.window.canvas)
window.canvas.show()
window.canvas.set_from_file("pic1.gif")
window.main()
window.canvas.set_from_file("pic2.gif")
pic1.gif will be displayed. Is there a proper way of changing the image (I don't care if I have to use a widget other than gtk.Image)? All I can think of is destroying the window and creating a new one.
Edit:
I realized my mistake... I called window.main() for every window and any window's destroy event called gtk.main_quit(). Had to make slight adjustments, but it works now. Even after calling window.main() :)
As Rawing hasn't yet accepted his own answer, I'll post it to get this off the top of the unanswered questions page, and to help out anyone skimming this from a search engine clickthrough by providing a comprehensive answer. (Rawing, feel free to post your answer yourself, all the same.)
In your code, you're declaring window as Window(), as opposed to gtk.Window. If you're building in one window, you should not need to do this every time. Create the window once, add what you need to it. If you need additional windows, declare them separately in this module, and call them from code (instead of from main).
Furthermore, don't name your objects with a "window." at the beginning...that just gets overly confusing. Give it a simple name, add it where you need it. Python will do the rest.
A cleaned up version of your code above would probably look like this:
window = gtk.Window()
#You may need additional arguments above, such as to make it top level.
canvas = gtk.Image()
window.add(canvas)
canvas.show()
canvas.set_from_file("pic1.gif")
Now, just change the image in an event or another "def", like this:
def ChangePicture():
canvas.set_from_file("pic2.gif")
Canvas should update the picture automatically.