I've two tables tblOrder and tblOrderDetails. I want to get order no, total price per order (Quantity*UnitCost) and OrderDate as given below.
Order No
Total
OrderDate
ORD 1
3000
01/01/2021
ORD 2
2750
01/03/2021
What I've tried is giving me quantity is not a part of aggregate function.
SELECT tblOrder.OrderNo, tblOrderDetails.UnitCost*tblOrderDetails.Quantity AS Total, OrderDate
FROM tblOrderDetails INNER JOIN tblOrder ON tblOrderDetails.OrderId = tblOrder .OrderId
GROUP BY tblOrder.OrderNo;
Table structures and data
Table tblOrder:
OrderId
OrderNo
OrderDate
1
ORD 1
01/01/2021
2
ORD 2
01/03/2021
Table tblOrderDetails:
OrderDetailId
Quantity
UnitCost
OrderId
1
100
30
1
2
50
40
2
2
10
15
2
2
20
30
2
select o.OrderNo
,od.total
,o.OrderDate
from
(
select OrderId
,sum(Quantity*UnitCost) as total
from tblOrderDetails
group by OrderId
) od join tblOrder o on o.OrderId = od.OrderId
OrderNo
total
OrderDate
ORD 1
3000
2021-01-01
ORD 2
2750
2021-01-03
Fiddle
Your requirements are not 100% clear, but maybe, you can just do this, without any subquery:
SELECT tblOrder.OrderNo,
SUM(tblOrderDetails.UnitCost*tblOrderDetails.Quantity) AS Total,
OrderDate
FROM tblOrderDetails
INNER JOIN tblOrder ON tblOrderDetails.OrderId = tblOrder.OrderId
GROUP BY tblOrder.OrderNo,OrderDate;
To see the difference to Danny's answer - which might also be fine - have a look here: db<>fiddle
Related
I want to write a query to locate a group of clients whose purchased specific 2 product categories, at the same time, getting the information of first transaction date and first item they purchased. Since I used group by function, I could only get customer id but not first item purchase due to the nature of group by. Any thoughts to solve this problem?
What I have are transaction tables(t), customer_id tables(c) and product tables(p). Mine is SQL server 2008.
Update
SELECT t.customer_id
,t.product_category
,MIN(t.transaction_date) AS FIRST_TRANSACTION_DATE
,SUM(t.quantity) AS TOTAL_QTY
,SUM(t.sales) AS TOTAL_SALES
FROM transaction t
WHERE t.product_category IN ('VEGETABLES', 'FRUITS')
AND t.transaction_date BETWEEN '2020/01/01' AND '2022/09/30'
GROUP BY t.customer_id
HAVING COUNT(DISTINCT t.product_category) = 2
**Customer_id** **transaction_date** **product_category** **quantity** **sales**
1 2022-05-30 VEGETABLES 1 100
1 2022-08-30 VEGETABLES 1 100
2 2022-07-30 VEGETABLES 1 100
2 2022-07-30 FRUITS 1 50
2 2022-07-30 VEGETABLES 2 200
3 2022-07-30 VEGETABLES 3 300
3 2022-08-01 FRUITS 1 50
3 2022-08-05 FRUITS 1 50
4 2022-08-07 FRUITS 1 50
4 2022-09-05 FRUITS 2 100
In the above, what I want to show after executing the SQL query is
**Customer_id** **FIRST_TRANSACTION_DATE** **first_product_category** **TOTAL_QUANTITY** **TOTAL_SALES**
2 2022-07-30 VEGETABLES, FRUITS 4 350
3 2022-07-30 VEGETABLES 5 400
Customer_id 1 and 4 will not be shown as they only purchased either vegetables or fruits but not both
Check now, BTW need find logic with product_category
select CustomerId, transaction_date, product_category, quantity, sales
from(
select CustomerId, transaction_date, product_category , sum(quantity) over(partition by CustomerId ) as quantity , sum(sales) over(partition by CustomerId ) as sales, row_number() over(partition by CustomerId order by transaction_date ASC) rn
from(
select CustomerId, transaction_date, product_category, quantity, sales
from tablee t
where (product_category = 'FRUITS' and
EXISTS (select CustomerId
from tablee tt
where product_category = 'VEGETABLES'
and t.CustomerId = tt.CustomerId)) OR
(product_category = 'VEGETABLES' and
EXISTS (select CustomerId
from tablee tt
where product_category = 'FRUITS'
and t.CustomerId = tt.CustomerId)))x)over_all
where rn = 1;
HERE is FIDDLE
I am writing an SQL query to get data from more than 3 tables, but for simplifying the question here I am using a similar scenario with 3 tables.
Table1 Customer (PK-CustomerID, Name)
CustomerID
Name
1
John
2
Tina
3
Sam
Table2 Sales (FK-Id, SalePrice)
ID
SalePrice
1
200.00
2
300.00
3
400.00
Table3 Order (PK-Id, FK-CustomerID, Date, Amount)
Id
CustomerID
Date
Amount
101
1
25-09-2021
30.0
102
1
27-09-2021
40.0
103
2
19-09-2021
60.0
In the output, Date and Amount should be the from most recent Order (latest Date), for a customer
My approach was
Select c.CustomerID, c.Name, s.SalePrice, RecentOrder.Date, RecentOrder.Amount from
Customer as c
LEFT JOIN Sales s ON c.CustomerID = s.ID
LEFT JOIN (SELECT top 1 o.Date, o.Amount, o.CustomerID
FROM Order o, Customer c1 WHERE c1.CustomerID = o.CustomerID ORDER BY o.Date DESC)
RecentOrder ON c.CustomerID = RecentOrder.CustomerID
Output I get
CustomerID, Name, SalePrice, Date, Amount
CustomerID
Name
SalePrice
Date
Amount
1
John
200.00
27-09-2021
40.0
2
Tina
300.00
null
null
3
Sam
400.00
null
null
The output I get includes the most recent order out of all the orders. But I want to get the recent order out of the orders made by that customer
Output Required
CustomerID, Name, SalePrice, Date, Amount
CustomerID
Name
SalePrice
Date
Amount
1
John
200.00
27-09-2021
40.0
2
Tina
300.00
19-09-2021
60.0
3
Sam
400.00
null
null
Instead of subquery in left join, you can check with outer apply.
Check following way
Select c.CustomerID, c.Name, s.SalePrice, RecentOrder.Date, RecentOrder.Amount
from Customer c
LEFT JOIN Sales s ON c.CustomerID = s.ID
OUTER APPLY (
SELECT top 1 o.Date, o.Amount, o.CustomerID
FROM [Order] o
WHERE o.CustomerID = c.CustomerID ORDER BY o.Date DESC) RecentOrder`
You need to pre-aggregate or identify the most recent order for each customer order, your query is selecting 1 row for all orders.
Try the following (untested!)
select c.CustomerID, c.Name, s.SalePrice, o.Date, o.Amount
from Customer c
left join Sales s on c.CustomerID = s.ID
outer apply (
select top (1) date, amount
from [order] o
where o.CustomerId=c.CustomerId
order by Id desc
)o
I am new at programming and SQL, so sorry if I do not include enough info.
[I have these 2 tables that are linked by an OrderID. Table1 includes OrderIDs and customer information such as FirstName, LastName, and Address. Table2 includes OrderIDs and order details such as ItemName, Price, and Quantity.
Each OrderID in Table2 might have multiple ItemName entries with the same OrderID.]1
CustInfo
OrderID FirstName LastName Address
1 Bob Pratt 123
2 Jane Doe 456
3 John Smith 789
4 Barbara Walters 147
Orders
OrderID ItemName Price Quantity
1 Milk 4.00 1
1 Eggs 5.00 2
2 Cheese 5.00 1
2 Bread 5.00 1
3 Milk 4.00 2
4 Yogurt 5.00 2
I'm trying to make a query that will send back a list of every Order, listing the OrderID and ItemName among other info, as long as the order doesn't include a specific type of item (which would be in ItemName). So if an OrderID contains 2 ItemName, one of which is the one I do not want, the entire order (OrderID) should not show up in my result.
For example, based off the img included, if I wanted to show all orders as long as they do not have Milk as an ItemName, the result should only show OrderID 2 and 4.
2 Cheese 5.00 1
2 Bread 5.00 1
4 Yogurt 5.00 2
This is what I have tried but this would return OrderIDs even though Milk is technically part of that OrderID.
SELECT OrderID, FirstName, LastName, ItemName, Price, Quantity
FROM CustInfo
JOIN Orders
ON CustInfo.OrderID = Orders.OrderID
WHERE ItemName != 'Milk'
Can you help?
select o.OrderID, o.ItemName, c.FirstName, c.LastName -- include other fields if needed
from Orders o
left join CustInfo c on o.OrderID = c.OrderID
where o.OrderID not in (
select OrderID from Orders where ItemName = 'Milk'
)
If you want the whole order to not show up, rather than just individual rows, you can use WHERE NOT EXISTS:
SELECT o.OrderID, d.ItemName, d.Price, d.Quantity
FROM Orders o
JOIN OrderDetails d ON o.OrderID=d.OrderID
WHERE NOT EXISTS
(
SELECT * FROM OrderDetails d2
WHERE o.OrderID=d2.OrderID
AND d.ItemName = 'Milk'
)
SELECT T1.OrderID, T1.FirstName, T1.LastName, T1.Address, T2.OrderID, T2.ItemName, T2.Price, T2.Quantity
FROM Table2 as T2
LEFT JOIN Table1 as T1 ON T1.OrderID = T2.OrderID
WHERE T2.OrderID <> (SELECT OrderID FROM Table2 WHERE ItemName='Milk');
Hi lets say i have the following tow tables
first table is Orders which consist of following columns
Order_ID OrderDate
1 2016-01-20
2 2016-01-21
and the second table is OrderDetails which consist of following columns
Order_ID ProductID UnitPrice Quantity
1 1 5.00 1
1 3 20.00 3
2 2 10.00 2
How can i get the following out put
Order_ID OrderDate OrderTotalamount
1 2016-01-20 65.00
2 2016-01-21 20.00
Would you mind trying something like this out?
SELECT ORD.Order_ID, ORD.OrderDate, SUM(ORDD.UnitPrice * ORDD.Quanity) AS OrderTotalAmount
FROM Orders ORD
INNER JOIN OrderDetails ORDD
ON ORDD.Order_ID = ORD.Order_ID
GROUP BY ORD.Order_ID, ORD.OrderDate
You can try this
SELECT a.Order_ID, a.OrderDate, SUM(Quantity*UnitPrice) as OrderTotalamout
FROM Orders a JOIN OrderDetains ON (a.Order_ID = OrderDetails.Order_ID)
GROUP BY 1, 2;
I hope it works fine for you.
YOU CAN USE
SELECT TABLE1.Order_ID, TABLE1.OrderDate, SUM(TABLE2.Quantity*TABLE2.UnitPrice) as TotalPrice
FROM TABLE1 JOIN TABLE2 WHERE(TABLE1.Order_ID = TABLE2.Order_ID);
I'm trying to write a query that gets the value of one field that's associated with the maximum value of another field (or fields). Let's say I have the following table of data:
OrderID CustomerID OrderDate LocationID
1 4 1/1/2001 1001
2 4 1/2/2001 1003
3 4 1/3/2001 1001
4 5 1/4/2001 1001
5 5 1/5/2001 1001
6 5 1/6/2001 1003
7 5 1/7/2001 1002
8 5 1/8/2001 1003
9 5 1/8/2001 1002
Grouping by CustomerID, I want to get the maximum OrderDate and then the LocationID associated with whatever is the maximum OrderDate. If there are several records that share the maximum order date, then take the LocationID associated with the maximum OrderID from among those records with the maximum date.
The final set of data should look like this:
CustomerID OrderDate LocationID
4 1/3/2001 1001
5 1/8/2001 1002
I had been trying to write a query with lots of nested subqueries and ugly joins, but I'm not really getting anywhere. What SQL do I need to write to help me get this result.
with cte As
(
select *,
row_number() over (partition by CustomerID
order by OrderDate desc, OrderId desc) as rn
from yourtable
)
select CustomerID, OrderDate,LocationID
from cte
where rn=1;
SELECT
C.Name,
C.CustomerID,
X.*
FROM
Customers C
CROSS APPLY (
SELECT TOP 1 OrderDate, LocationID
FROM Orders O
WHERE C.CustomerID = O.CustomerID
ORDER BY OrderDate Desc, OrderID Desc
) X
If you will pull any columns from the Customers table, this will probably outperform other methods.
If not, then the Row_Number answer, pulling only from Orders, will probably be best. But if you restrict by Customer in any way, then the CROSS APPLY will again be best. Possibly by a big margin.
The trick is to use a subquery as a value, not as a join:
select customerId,orderDate,locationId
from orders o1
where orderDate = (
select top 1 orderdate
from orders o2
where o1.customerId = o2.customerId
order by orderdate desc
)