I am writing an SQL query to get data from more than 3 tables, but for simplifying the question here I am using a similar scenario with 3 tables.
Table1 Customer (PK-CustomerID, Name)
CustomerID
Name
1
John
2
Tina
3
Sam
Table2 Sales (FK-Id, SalePrice)
ID
SalePrice
1
200.00
2
300.00
3
400.00
Table3 Order (PK-Id, FK-CustomerID, Date, Amount)
Id
CustomerID
Date
Amount
101
1
25-09-2021
30.0
102
1
27-09-2021
40.0
103
2
19-09-2021
60.0
In the output, Date and Amount should be the from most recent Order (latest Date), for a customer
My approach was
Select c.CustomerID, c.Name, s.SalePrice, RecentOrder.Date, RecentOrder.Amount from
Customer as c
LEFT JOIN Sales s ON c.CustomerID = s.ID
LEFT JOIN (SELECT top 1 o.Date, o.Amount, o.CustomerID
FROM Order o, Customer c1 WHERE c1.CustomerID = o.CustomerID ORDER BY o.Date DESC)
RecentOrder ON c.CustomerID = RecentOrder.CustomerID
Output I get
CustomerID, Name, SalePrice, Date, Amount
CustomerID
Name
SalePrice
Date
Amount
1
John
200.00
27-09-2021
40.0
2
Tina
300.00
null
null
3
Sam
400.00
null
null
The output I get includes the most recent order out of all the orders. But I want to get the recent order out of the orders made by that customer
Output Required
CustomerID, Name, SalePrice, Date, Amount
CustomerID
Name
SalePrice
Date
Amount
1
John
200.00
27-09-2021
40.0
2
Tina
300.00
19-09-2021
60.0
3
Sam
400.00
null
null
Instead of subquery in left join, you can check with outer apply.
Check following way
Select c.CustomerID, c.Name, s.SalePrice, RecentOrder.Date, RecentOrder.Amount
from Customer c
LEFT JOIN Sales s ON c.CustomerID = s.ID
OUTER APPLY (
SELECT top 1 o.Date, o.Amount, o.CustomerID
FROM [Order] o
WHERE o.CustomerID = c.CustomerID ORDER BY o.Date DESC) RecentOrder`
You need to pre-aggregate or identify the most recent order for each customer order, your query is selecting 1 row for all orders.
Try the following (untested!)
select c.CustomerID, c.Name, s.SalePrice, o.Date, o.Amount
from Customer c
left join Sales s on c.CustomerID = s.ID
outer apply (
select top (1) date, amount
from [order] o
where o.CustomerId=c.CustomerId
order by Id desc
)o
Related
I've two tables tblOrder and tblOrderDetails. I want to get order no, total price per order (Quantity*UnitCost) and OrderDate as given below.
Order No
Total
OrderDate
ORD 1
3000
01/01/2021
ORD 2
2750
01/03/2021
What I've tried is giving me quantity is not a part of aggregate function.
SELECT tblOrder.OrderNo, tblOrderDetails.UnitCost*tblOrderDetails.Quantity AS Total, OrderDate
FROM tblOrderDetails INNER JOIN tblOrder ON tblOrderDetails.OrderId = tblOrder .OrderId
GROUP BY tblOrder.OrderNo;
Table structures and data
Table tblOrder:
OrderId
OrderNo
OrderDate
1
ORD 1
01/01/2021
2
ORD 2
01/03/2021
Table tblOrderDetails:
OrderDetailId
Quantity
UnitCost
OrderId
1
100
30
1
2
50
40
2
2
10
15
2
2
20
30
2
select o.OrderNo
,od.total
,o.OrderDate
from
(
select OrderId
,sum(Quantity*UnitCost) as total
from tblOrderDetails
group by OrderId
) od join tblOrder o on o.OrderId = od.OrderId
OrderNo
total
OrderDate
ORD 1
3000
2021-01-01
ORD 2
2750
2021-01-03
Fiddle
Your requirements are not 100% clear, but maybe, you can just do this, without any subquery:
SELECT tblOrder.OrderNo,
SUM(tblOrderDetails.UnitCost*tblOrderDetails.Quantity) AS Total,
OrderDate
FROM tblOrderDetails
INNER JOIN tblOrder ON tblOrderDetails.OrderId = tblOrder.OrderId
GROUP BY tblOrder.OrderNo,OrderDate;
To see the difference to Danny's answer - which might also be fine - have a look here: db<>fiddle
I am new at programming and SQL, so sorry if I do not include enough info.
[I have these 2 tables that are linked by an OrderID. Table1 includes OrderIDs and customer information such as FirstName, LastName, and Address. Table2 includes OrderIDs and order details such as ItemName, Price, and Quantity.
Each OrderID in Table2 might have multiple ItemName entries with the same OrderID.]1
CustInfo
OrderID FirstName LastName Address
1 Bob Pratt 123
2 Jane Doe 456
3 John Smith 789
4 Barbara Walters 147
Orders
OrderID ItemName Price Quantity
1 Milk 4.00 1
1 Eggs 5.00 2
2 Cheese 5.00 1
2 Bread 5.00 1
3 Milk 4.00 2
4 Yogurt 5.00 2
I'm trying to make a query that will send back a list of every Order, listing the OrderID and ItemName among other info, as long as the order doesn't include a specific type of item (which would be in ItemName). So if an OrderID contains 2 ItemName, one of which is the one I do not want, the entire order (OrderID) should not show up in my result.
For example, based off the img included, if I wanted to show all orders as long as they do not have Milk as an ItemName, the result should only show OrderID 2 and 4.
2 Cheese 5.00 1
2 Bread 5.00 1
4 Yogurt 5.00 2
This is what I have tried but this would return OrderIDs even though Milk is technically part of that OrderID.
SELECT OrderID, FirstName, LastName, ItemName, Price, Quantity
FROM CustInfo
JOIN Orders
ON CustInfo.OrderID = Orders.OrderID
WHERE ItemName != 'Milk'
Can you help?
select o.OrderID, o.ItemName, c.FirstName, c.LastName -- include other fields if needed
from Orders o
left join CustInfo c on o.OrderID = c.OrderID
where o.OrderID not in (
select OrderID from Orders where ItemName = 'Milk'
)
If you want the whole order to not show up, rather than just individual rows, you can use WHERE NOT EXISTS:
SELECT o.OrderID, d.ItemName, d.Price, d.Quantity
FROM Orders o
JOIN OrderDetails d ON o.OrderID=d.OrderID
WHERE NOT EXISTS
(
SELECT * FROM OrderDetails d2
WHERE o.OrderID=d2.OrderID
AND d.ItemName = 'Milk'
)
SELECT T1.OrderID, T1.FirstName, T1.LastName, T1.Address, T2.OrderID, T2.ItemName, T2.Price, T2.Quantity
FROM Table2 as T2
LEFT JOIN Table1 as T1 ON T1.OrderID = T2.OrderID
WHERE T2.OrderID <> (SELECT OrderID FROM Table2 WHERE ItemName='Milk');
I have a schema with Customer table and Order table. A customer can place order in multiple dates. I need to have previous order_date for every order_date corresponding to a customer.
Say a customer placed 4 orders, then for newest order(4th order) - it must pull current order_date and previous order_date(3rd order). For 3rd order placed by customer, it must pull 3rd order_date as current order_date and previous order_date(2nd order) as so on.
I am using below query to get previous order_date and then joining with current_query to get result::
select customerid, orderid, order_date as previous_order_date
from (
select c.customerid, o.orderid, o.order_date,
row_number() over (partition by c.customerid, o.orderid
order by o.order_date) rown
from customers c join orders o on c.customerid = o.customerid
) a
where rown = 2
But the issue is, I am getting a single date corresponding to a customerid whereas the requirement is - just previous order_date corresponding to current order_date for a customer.
Any suggestion would help! Thanks
Try with LAG() window function per customerid:
select
c.customerid, o.orderid, o.order_date,
lag(o.order_date) over (partition by c.customerid order by o.order_date) AS prev_order_date
from customers c
join orders o on c.customerid = o.customerid
For the earliest order of every customer prev_order_date will be null.
Sample result (don't mind orderid, it's just for the example):
customerid | orderid | order_date | prev_order_date
------------+---------+------------+-----------------
1 | 6 | 2015-02-08 |
1 | 2 | 2016-02-05 | 2015-02-08
1 | 3 | 2016-02-08 | 2016-02-05
1 | 1 | 2016-03-05 | 2016-02-08
2 | 5 | 2016-07-01 |
2 | 4 | 2016-07-08 | 2016-07-01
If one customer can place the same order within different dates (weird, but this seems to be your case) add o.orderid to the PARTITION BY clause.
Unfortunately, LAG() didn't work when used in SQL node for reporting purpose. I tried using below query and got desired result:
SELECT c.customer_code, o.customer_sid, o.order_id, o.order_no,
o.order_created_date,
(SELECT MAX (o1.order_created_date)
FROM d_customer c1 LEFT JOIN f_order o1
ON c1.customer_sid =
o1.customer_sid
WHERE c1.customer_sid = c.customer_sid
AND o1.order_created_date < o.order_created_date
AND EXISTS (SELECT 1
FROM f_invoice i
WHERE i.order_id = o1.order_id))
AS prev_order_created_date,
t.financial_year, t.financial_month_no
FROM d_customer c JOIN f_order o
ON c.customer_sid = o.customer_sid
AND c.customer_type = 'PATIENT'
AND c.customer_country = 'UNITED STATES'
AND o.customer_type = 'PATIENT'
AND o.bill_to_country = 'UNITED STATES'
AND o.order_status = 'SHIPPED'
AND o.order_type = 'SALES'
AND o.order_group = 'REVENUE'
-- AND c.customer_code = '233379PT'
LEFT JOIN d_time t ON t.time_sid = o.order_created_date_sid
ORDER BY order_created_date DESC
I have 3 tables
collecton, paymentdata, payment
Payment table is computed table and it has only one product data
So, rcvamt and restamt get from payment table
I have following data
Collection:
id(PK) clientid company Client product total note
1 2001 Company1 Client1 Product1 50000 note1
2 2002 Company2 Client2 Product2 60000 note2
3 2003 Company3 Client3 Product3 70000 note3
PaymentData:
wid(PK)wcid(FK) clientid product rcvamt restamt rcvdate nxtdate Note
1 1 2001 Product1 500 49500 10-1-2015 11-2-2015 abc1
2 1 2001 Product1 800 48700 11-2-2015 12-3-2015 xyz1
3 2 2002 Product2 1500 58500 5-3-2015 6-4-2015 qwe1
Payment
id(PK) wid(FK) clientid product rcvamt restamt
1 2 2001 Product1 1300 48700
2 3 2002 Product2 1500 58500
I want to show a report like
clientid company procudt total rcvamt restamt rcvdate nxtdate note
2001 Company1 Product1 50000 1300 48700 11-2-2015 12-3-2015 xyz1
2002 Company2 Product2 60000 1500 58500 5-3-2015 6-4-2015 qwe1
2003 Company3 Product3 70000 - - - - -
I tried to make it simple:
SELECT DISTINCT
C.clientid
, C.company
, C.product
, C.total
, P.rcvamt
, P.restamt
, ( SELECT TOP 1 rcvdate FROM PaymentData AS PD1 WHERE PD1.ClientID=PD.ClientID AND PD1.Product=PD.Product ORDER BY rcvdate DESC)
, ( SELECT TOP 1 nxtdate FROM PaymentData AS PD1 WHERE PD1.ClientID=PD.ClientID AND PD1.Product=PD.Product ORDER BY rcvdate DESC)
, ( SELECT TOP 1 Note FROM PaymentData AS PD1 WHERE PD1.ClientID=PD.ClientID AND PD1.Product=PD.Product ORDER BY rcvdate DESC)
FROM
Collection C
LEFT OUTER JOIN Payment P
ON C.clientid = P.clientid
LEFT OUTER JOIN PaymentData PD
ON P.clientid = PD.clientid
But I don't know all the relationships between the tables.
The Answer to your Question could look like this
Select Collection.clientid
,Collection.company
,Collection.product
,Collection.total
,Payment.rcvamt
,Payment.restamt
,PaymentData.rcvdate
,PaymentData.nxtdate
,PaymentData.Note
From PaymentData
Inner Join (Select wcid
,Max(PaymentData.rcvdate) as rcvdate
,Max(PaymentData.nxtdate) as nxtdate
FROM PaymentData
GROUP BY wcid) AS SubSelect ON PaymentData.wcid = SubSelect.wcid
AND PaymentData.rcvdate = SubSelect.rcvdate
AND PaymentData.nxtdate = SubSelect.nxtdate
Inner Join Payment on PaymentData.wcid = Payment.id
RIGHT OUTER JOIN Collection ON PaymentData.clientid = Collection.clientid
Here the sqlfiddle to prove my Answer.
Something like this should work. It appears you want an aggregation on the restamt, both other fields are the last payment received. I also assume this is SQL Server due to your name. If it's a different db, please provide the
UPDATE: Changed to LEFT JOIN to handle client 3 without products, fixed typo in product. SQL Fiddle: http://sqlfiddle.com/#!3/8ad566/19/0
SELECT
c.clientid,
c.company,
c.product,
c.total,
SUM(pd.rcvamt) AS rcvamt,
LastPayment.restamt,
LastPayment.rcvdate,
LastPayment.nxtDate,
LastPayment.note
FROM Collection c
LEFT OUTER JOIN PaymentData pd
ON pd.wcid = c.id
LEFT OUTER JOIN (
SELECT
wcid,
restamt,
rcvdate,
nxtdate,
Note,
ROW_NUMBER() OVER (PARTITION BY wcid ORDER BY rcvdate DESC) AS RowNum
FROM PaymentData
) LastPayment
ON LastPayment.wcid = c.id
AND LastPayment.RowNum = 1 -- Get last payment info
GROUP BY
c.clientid,
c.company,
c.product,
c.total,
LastPayment.restamt,
LastPayment.rcvdate,
LastPayment.nxtDate,
LastPayment.note
ORDER BY
c.clientid
I am trying to export data from a database and am joining the "customers" table with the "orders" table. It's a one to many relationship where customers can have multiple orders. I'm trying to write a query that returns basic customer info from the customers table - email_address, firstname, lastname, but to also include the date of the last order they placed.
customers as c
- customer_id
- firstname
- lastname
- email_address
orders as o
- orders_id
- customers_id
- purchase_date
I want the result to return a single result for each customer where the purchase date is the last purchase that customer made.
c.firstname, c.lastname, c.email_address, o.purchase_date
What is the correct SQL syntax to make this happen?
select c.*, o.LastOrderDate
from customers c
LEFT JOIN
(select customers_id, max(purchase_date) as LastOrderDate
from orders
group by customers_id) o on o.customers_id=c.customers_id
Will get all customers and the date of the last order, if one exists.
What about:
SELECT c.firstname, c.lastname, c.email_address, MAX(o.purchase_date)
FROM customers AS c
JOIN orders AS o ON o.customers_id = c.customer_id
GROUP BY c.firstname, c.lastname, c.email_address
This only lists customers who have placed at least one order. If you want all customers, then you should be able to use a LEFT JOIN instead of a simple (INNER) JOIN as shown.
This returns all Customers, regardless of whether they have any Orders:
SQL> select c.name
2 , c.email_address
3 , ( select max (o.order_date) from orders o
4 where o.customer_no = c.customer_no )as last_order
5 from customers c
6 /
NAME EMAIL_ADDRESS LAST_ORDE
-------------------- ------------------------- ---------
ACME Industries info#acme.com 07-APR-10
Tyrell Corporation accounts#tyrellcorp.com 26-MAR-10
Lorax Textiles Co the.lorax#hotmail.com
SQL>
It is equivalent to the LEFT OUTER JOIN:
SQL> select c.name
2 , c.email_address
3 , o.last_order_date
4 from customers c
5 left join ( select o.customer_no
6 , max (o.order_date) as last_order_date
7 from orders o
8 group by o.customer_no ) o
9 on o.customer_no = c.customer_no
10 /
NAME EMAIL_ADDRESS LAST_ORDE
-------------------- ------------------------- ---------
ACME Industries info#acme.com 07-APR-10
Tyrell Corporation accounts#tyrellcorp.com 26-MAR-10
Lorax Textiles Co the.lorax#hotmail.com
SQL>
A RIGHT OUTER JOIN would only return rows for Customers with Orders. Assuming an Order must have a Customer (i.e. enforced foreign key) then that would be the same as an INNER JOIN.
If your flavour of database supports analytic functions then RANK() offers an alternative way of solving it...
SQL> select name
2 , email_address
3 , order_date
4 from (
5 select c.name
6 , c.email_address
7 , o.order_date
8 , rank () over (partition by c.customer_no
9 order by o.order_date desc ) as rnk
10 from customers c
11 join orders o
12 on ( o.customer_no = c.customer_no)
13 )
14 where rnk = 1
15 /
NAME EMAIL_ADDRESS ORDER_DAT
-------------------- ------------------------- ---------
ACME Industries info#acme.com 07-APR-10
Tyrell Corporation accounts#tyrellcorp.com 26-MAR-10
SQL>
This also only returns rows for Customers with Orders.