Unsure of Control flow in Pandas - pandas

Question

I've been working on a Pandas project in Python and am confused a bit on how to accomplish a condition in Pandas.
The code at the below shows how i sort of propose to calculate business_minutes and calendar_minutes between a close_date and a open_date. It works great except when close_date has not yet been recorded or that it is null.
I'm thinking I can use control logic something like the following except I know the logic is not sound. Is there a way to do what i'd like to do but correctly?
if close_date:
df_incident['Bus_Mins'] = df_incident.apply(lambda x: bduration(x['Open_Date'], x['Close_Date']), axis=1)
df_incident['Cal_Mins'] = (df_incident['Close_Date'] - df_incident['Open_Date']).dt.total_seconds()/60
elif:
now = dt.now(timezone.utc)
df_incident['Bus_Mins'] = df_incident.apply(lambda x: bduration(x['Open_Date'], now), axis=1)
df_incident['Cal_Mins'] = (now - df_incident['Open_Date']).dt.total_seconds()/60
# get current utc time
now = dt.now(timezone.utc)
# set start and stop times of business day
#Specify Business Working hours (7am - 5pm)
start_time = dt.time(7,00,0)
end_time = dt.time(17,0,0)
us_holidays = pyholidays.US()
unit='min'
# Create a partial function as a shortcut
bduration = partial(bd.businessDuration, starttime=start_time, endtime=end_time, holidaylist=us_holidays, unit=unit)
df_incident['Bus_Mins'] = df_incident.apply(lambda x: bduration(x['Open_Date'], x['Close_Date']), axis=1)
df_incident['Cal_Mins'] = (df_incident['Close_Date'] - df_incident['Open_Date']).dt.total_seconds()/60
Have I presented my need clearly? Is it possible to do?
Thanks,
Jeff

Answer 1

As written, your code will not work because you call bduration() before defining it. Also, you assign to Bus_Mins and Cal_Mins twice in the body of the else condition. The second assignment will probably not work because close date is null. It is a syntax error to have an elif without a condition, so else: should be used instead. Something like the following might work:
# set start and stop times of business day
#Specify Business Working hours (7am - 5pm)
start_time = dt.time(7,00,0)
end_time = dt.time(17,0,0)
us_holidays = pyholidays.US()
unit='min'
# Create a partial function as a shortcut
bduration = partial(bd.businessDuration, starttime=start_time, endtime=end_time, holidaylist=us_holidays, unit=unit)
if close_date:
df_incident['Bus_Mins'] = df_incident.apply(lambda x: bduration(x['Open_Date'], x['Close_Date']), axis=1)
df_incident['Cal_Mins'] = (df_incident['Close_Date'] - df_incident['Open_Date']).dt.total_seconds()/60
else:
# get current utc time
now = dt.now(timezone.utc)
df_incident['Bus_Mins'] = df_incident.apply(lambda x: bduration(x['Open_Date'], now), axis=1)
df_incident['Cal_Mins'] = (now - df_incident['Open_Date']).dt.total_seconds()/60