I have a query that works just fine in SQL Server but I would like some help with the required syntax modifications to make it work at Synapse SQL. Any help would be appreciated! The id's are unix timestamps. I want to count the id's of the previous day filtering by time range using the unix timestamps
SELECT COUNT(Id)
FROM [dbo].[name]
WHERE Id >= CONVERT(bigint, DATEDIFF(SECOND,'1970-01-01', CONVERT(date,dateadd(d, -1, GETDATE()))))*1000
and Id < CONVERT(bigint, DATEDIFF(SECOND,'1970-01-01', CONVERT(date,GETDATE())))*1000
When SQL servers and Azure Synapse are in different time zones, the results of Query will be varying. Azure Synapse will be in UTC time zone.
In order to convert current date value to local datetime value in azure synapse, User defined function is created as in below script.
Create FUNCTION [dbo].[CurrentLocalTime]( #TimeZoneName sysname )
RETURNS datetime
AS
BEGIN
RETURN DATEADD(hour,
TRY_CAST((SELECT REPLACE(current_utc_offset, N':', N'.')
FROM sys.time_zone_info
WHERE [name] = #TimeZoneName) AS decimal(18,2)),
SYSDATETIME());
END;
Instead of using getdate() of function, the above function is used in the query.
Query
SELECT COUNT(Id) FROM sample1
WHERE Id >= CONVERT(bigint, DATEDIFF(SECOND,'1970-01-01', CONVERT(date,dateadd(d, -1, dbo.CurrentLocalTime('AUS Eastern Standard Time' )))))*1000
and Id < CONVERT(bigint, DATEDIFF(SECOND,'1970-01-01', CONVERT(date,dbo.CurrentLocalTime('AUS Eastern Standard Time' ))))*1000
The time zone can be replaced in the query as per the requirement.
Results for Sample data:
Related
I am trying to convert a string into DateTimeOffset (in SQL Server) through a ETL job. Basically, my string would look something like '2017-10-15' and I want this to be converted into a DatetimeOffset (from the current DB server).
SELECT
SWITCHOFFSET(DATEADD(mi, DATEDIFF(MI, GETDATE(), GETUTCDATE()), CAST(#DateInString + ' 00:00:00' AS DATETIMEOFFSET)), DATENAME(tzoffset, SYSDATETIMEOFFSET()))
I have been getting some weird issues with this statement as the final output would fall either +1 / -1 minute than the expected ones. This happens for at least every 10 records/million. I tried to nail down the issue and I could see the problem was with the DATEDIFF() method returning +/-1 minute.
SELECT DATEDIFF(MI, GETDATE(), GETUTCDATE())
This should exactly return -600 (since my DB server UTC is +10). However, it returns either -599 or 601 for few records. I execute them as a single select statement in my Stored Procedure and return it as a parameter.
This is weird on how SQL could detect two different datetime values for GETDATE() and GETUTCDATE() on the same select statement.
Is there a way to force SQL to get exactly same dates in those DATEDIFF parameters or am I missing something here? Thanks in advance
I am using SQL Server 2014 (v12.0).
Stored procedure:
CREATE PROCEDURE dbo.SPConvertDateTimeOffset
#DateInString VARCHAR(10),
#DateTimeOffset_Value DATETIMEOFFSET OUTPUT,
#Datediff_Value INT OUTPUT
AS
BEGIN
-- This line returns +/- 1
SELECT #Datediff_Value = DATEDIFF(MI, GETDATE(), GETUTCDATE())
SELECT #DateTimeOffset_Value = SWITCHOFFSET(DATEADD(mi, #Datediff_Value, CAST(#DateInString + ' 00:00:00' AS DATETIMEOFFSET)), DATENAME(tzoffset, SYSDATETIMEOFFSET()))
END
#GordonLinoff has explained why this happens: since functions are executed at slightly different times, they may return a different minute.
To work around, try this:
DECLARE #DateTimeOffset_Value Datetimeoffset
DECLARE #Datediff_Value INT, #DateInString VARCHAR( 10 )
SET #DateInString = CONVERT( VARCHAR, GETDATE(), 112 )
SET #DateTimeOffset_Value = TODATETIMEOFFSET( #DateInString, DATENAME(tzoffset,SYSDATETIMEOFFSET()))
SET #Datediff_Value = DATEDIFF( MI, #DateInString, #DateTimeOffset_Value )
SELECT #DateInString, #DateTimeOffset_Value, #Datediff_Value
It does not use current date comparisons.
Note: that during the time when day light saving changes you may get a different value from the expected, depending on when exactly the code was run.
Have a look at https://dba.stackexchange.com/questions/28187/how-can-i-get-the-correct-offset-between-utc-and-local-times-for-a-date-that-is for more solutions about how to handle DTS changes.
The two functions are not executed simultaneously. So about 1 time in 100,000 (in your test) the times are on opposite sides of a minute boundary.
If you just want the timezone, you could try:
select datepart(tz, SYSDATETIMEOFFSET())
I have a table with data being inserted into from a procedure, which then I use for a Javascript chart. My problem is, I only want today's data all the time. I tried dateadd and datediff but I was still getting the same result when I did a select statement.
[![Procedure][2]][2]
If your time column is of type datetime then this simple where will work
select * from throughput
where time = cast(cast(GetDate() as Date) as datetime)
If time column isn't of type datetime then you need to cast it to date as well and use the following query
select *,cast(GetDate() as Date) from throughput
where cast(time as date) = cast(GetDate() as Date)
I have created a fiddle to demonstrate both of the scenario
SQL Fiddle Demo
How would I be able to extract the time part of a DateTime field in SQL? For my project I have to return data that has a timestamp of 5pm of a DateTime field no matter what the date is
This will return the time-Only
For SQL Server:
SELECT convert(varchar(8), getdate(), 108)
Explanation:
getDate() is giving current date and time.
108 is formatting/giving us the required portion i.e time in this case.
varchar(8) gives us the number of characters from that portion.
Like:
If you wrote varchar(7) there, it will give you 00:00:0
If you wrote varchar(6) there, it will give you 00:00:
If you wrote varchar(15) there, it will still give you 00:00:00 because it is giving output of just time portion.
SQLFiddle Demo
For MySQL:
SELECT DATE_FORMAT(NOW(), '%H:%i:%s')
SQLFiddle Demo
In SQL Server if you need only the hh:mi, you can use:
DECLARE #datetime datetime
SELECT #datetime = GETDATE()
SELECT RIGHT('0'+CAST(DATEPART(hour, #datetime) as varchar(2)),2) + ':' +
RIGHT('0'+CAST(DATEPART(minute, #datetime)as varchar(2)),2)
If you want only the hour of your datetime, then you can use DATEPART() - SQL Server:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select datepart(hour, #dt) -- returns 8
In SQL Server 2008+ you can CAST() as time:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select CAST(#dt as time) -- returns 08:25:53
I know this is an old question, but since the other answers all
return strings (rather than datetimes),
rely on the internal representation of dates (conversion to float, int, and back) or
require SQL Server 2008 or beyond,
I thought I'd add a "pure" option which only requires datetime operations and works with SQL Server 2005+:
SELECT DATEADD(dd, -DATEDIFF(dd, 0, mydatetime), mydatetime)
This calculates the difference (in whole days) between date zero (1900-01-01) and the given date and then subtracts that number of days from the given date, thereby setting its date component to zero.
Try this in SQL Server 2008:
select *
from some_table t
where convert(time,t.some_datetime_column) = '5pm'
If you want take a random datetime value and adjust it so the time component is 5pm, then in SQL Server 2008 there are a number of ways. First you need start-of-day (e.g., 2011-09-30 00:00:00.000).
One technique that works for all versions of Microsoft SQL Server as well as all versions of Sybase is to use convert/3 to convert the datetime value to a varchar that lacks a time component and then back into a datetime value:
select convert(datetime,convert(varchar,current_timestamp,112),112)
The above gives you start-of-day for the current day.
In SQL Server 2008, though, you can say something like this:
select start_of_day = t.some_datetime_column
- convert(time, t.some_datetime_column ) ,
from some_table t
which is likely faster.
Once you have start-of-day, getting to 5pm is easy. Just add 17 hours to your start-of-day value:
select five_pm = dateadd(hour,17, t.some_datetime_column
- convert(time,t.some_datetime_column)
)
from some_table t
Note that from MS SQL 2012 onwards you can use FORMAT(value,'format')
e.g. WHERE FORMAT(YourDatetime,'HH:mm') = '17:00'
"For my project, I have to return data that has a timestamp of 5pm of a DateTime field, No matter what the date is."
So I think what you meant was that you needed the date, not the time. You can do something like this to get a date with 5:00 as the time:
SELECT CONVERT(VARCHAR(10), GetDate(), 110) + ' 05:00:00'
This should strip away the date part:
select convert(datetime,convert(float, getdate()) - convert(int,getdate())), getdate()
and return a datetime with a default date of 1900-01-01.
you can use CONVERT(TIME,GETDATE()) in this case:
INSERT INTO infoTbl
(itDate, itTime)
VALUES (GETDATE(),CONVERT(TIME,GETDATE()))
or if you want print it or return that time use like this:
DECLARE #dt TIME
SET #dt = CONVERT(TIME,GETDATE())
PRINT #dt
select cast(getdate() as time(0))
returns for example :- 15:19:43
replace getdate() with the date time you want to extract just time from!
SELECT DISTINCT
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108)
FROM
CONSOLIDATED_LIST AS A
WHERE
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108) BETWEEN '15:00:00' AND '15:45:00'
declare #datetime as datetime
set #datetime = getdate()
select cast(cast(#datetime as time) as varchar(8))
For year:
SELECT DATEPART(YEAR, '2021-03-21' );
For hour:
SELECT DATEPART(HOUR, '2021-03-21 08:50:30' );
How would I be able to extract the time part of a DateTime field in SQL? For my project I have to return data that has a timestamp of 5pm of a DateTime field no matter what the date is
This will return the time-Only
For SQL Server:
SELECT convert(varchar(8), getdate(), 108)
Explanation:
getDate() is giving current date and time.
108 is formatting/giving us the required portion i.e time in this case.
varchar(8) gives us the number of characters from that portion.
Like:
If you wrote varchar(7) there, it will give you 00:00:0
If you wrote varchar(6) there, it will give you 00:00:
If you wrote varchar(15) there, it will still give you 00:00:00 because it is giving output of just time portion.
SQLFiddle Demo
For MySQL:
SELECT DATE_FORMAT(NOW(), '%H:%i:%s')
SQLFiddle Demo
In SQL Server if you need only the hh:mi, you can use:
DECLARE #datetime datetime
SELECT #datetime = GETDATE()
SELECT RIGHT('0'+CAST(DATEPART(hour, #datetime) as varchar(2)),2) + ':' +
RIGHT('0'+CAST(DATEPART(minute, #datetime)as varchar(2)),2)
If you want only the hour of your datetime, then you can use DATEPART() - SQL Server:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select datepart(hour, #dt) -- returns 8
In SQL Server 2008+ you can CAST() as time:
declare #dt datetime
set #dt = '2012-09-10 08:25:53'
select CAST(#dt as time) -- returns 08:25:53
I know this is an old question, but since the other answers all
return strings (rather than datetimes),
rely on the internal representation of dates (conversion to float, int, and back) or
require SQL Server 2008 or beyond,
I thought I'd add a "pure" option which only requires datetime operations and works with SQL Server 2005+:
SELECT DATEADD(dd, -DATEDIFF(dd, 0, mydatetime), mydatetime)
This calculates the difference (in whole days) between date zero (1900-01-01) and the given date and then subtracts that number of days from the given date, thereby setting its date component to zero.
Try this in SQL Server 2008:
select *
from some_table t
where convert(time,t.some_datetime_column) = '5pm'
If you want take a random datetime value and adjust it so the time component is 5pm, then in SQL Server 2008 there are a number of ways. First you need start-of-day (e.g., 2011-09-30 00:00:00.000).
One technique that works for all versions of Microsoft SQL Server as well as all versions of Sybase is to use convert/3 to convert the datetime value to a varchar that lacks a time component and then back into a datetime value:
select convert(datetime,convert(varchar,current_timestamp,112),112)
The above gives you start-of-day for the current day.
In SQL Server 2008, though, you can say something like this:
select start_of_day = t.some_datetime_column
- convert(time, t.some_datetime_column ) ,
from some_table t
which is likely faster.
Once you have start-of-day, getting to 5pm is easy. Just add 17 hours to your start-of-day value:
select five_pm = dateadd(hour,17, t.some_datetime_column
- convert(time,t.some_datetime_column)
)
from some_table t
Note that from MS SQL 2012 onwards you can use FORMAT(value,'format')
e.g. WHERE FORMAT(YourDatetime,'HH:mm') = '17:00'
"For my project, I have to return data that has a timestamp of 5pm of a DateTime field, No matter what the date is."
So I think what you meant was that you needed the date, not the time. You can do something like this to get a date with 5:00 as the time:
SELECT CONVERT(VARCHAR(10), GetDate(), 110) + ' 05:00:00'
This should strip away the date part:
select convert(datetime,convert(float, getdate()) - convert(int,getdate())), getdate()
and return a datetime with a default date of 1900-01-01.
you can use CONVERT(TIME,GETDATE()) in this case:
INSERT INTO infoTbl
(itDate, itTime)
VALUES (GETDATE(),CONVERT(TIME,GETDATE()))
or if you want print it or return that time use like this:
DECLARE #dt TIME
SET #dt = CONVERT(TIME,GETDATE())
PRINT #dt
select cast(getdate() as time(0))
returns for example :- 15:19:43
replace getdate() with the date time you want to extract just time from!
SELECT DISTINCT
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108)
FROM
CONSOLIDATED_LIST AS A
WHERE
CONVERT(VARCHAR(17), A.SOURCE_DEPARTURE_TIME, 108) BETWEEN '15:00:00' AND '15:45:00'
declare #datetime as datetime
set #datetime = getdate()
select cast(cast(#datetime as time) as varchar(8))
For year:
SELECT DATEPART(YEAR, '2021-03-21' );
For hour:
SELECT DATEPART(HOUR, '2021-03-21 08:50:30' );
I have a DateTime field in SQL Server 2008 R2. I have some views that query that field such as
SELECT *
FROM table1
WHERE CONVERT(DATE, TransactionDate) = 'April 10 2012'.
The servertime is set to texas time, and I want to query this data using EST. In other words
SELECT *
FROM Table1
WHERE TransactionDate = 'April 10 2012 Eastern Standard Time'
What is the best way to achieve this?
Give this a shot.
"DATETIMEOFFSET Datatype
Currently when saving the date and time in a column, it will not indicate what time zone that date and time belongs to. This can be especially important when you are dealing with data including several different countries with different time zones. The new datatype DATETIMEOFFSET defines a date that is combined with a time of a day that has time zone awareness and is based on a 24-hour clock. The following script illustrates the usage of the DATETIMEOFFSET datatype.
DECLARE #dt DATETIMEOFFSET(0)
SET #dt = '2007-10-29 22:50:55 -1:00'
DECLARE #dt1 DATETIMEOFFSET(0)
SET #dt1 = '2007-10-29 22:50:55 +5:00'
SELECT DATEDIFF(hh,#dt,#Dt1)
http://www.sql-server-performance.com/2007/datetime-2008/