How can I write this SQL query for date and time? - sql

I'm trying to make a query that will look like
SELECT * from `table` WHERE args
I need to have my args the date from 'yesterday' and time 23:00 until date'Today' and time 22:59.
I'm very bad at writing SQL and I will need masters help for this one.
I know how to write basic SQL and I'm not sure how to write.
Date and time are 2 different rows.
Basic SQL stuff.
Expecting all data from date yesterday starting with time 23:00 until date = today and time = 22:59
Logically is simple, I'm just bad at writing SQL logic.
Date has to be always generated based on current date, time will be static.
SELECT * from `table` WHERE date= Yesterday And time= 23:00 TO date=today time=22:59
Edit:
Database is MariaDB from Xamp

Assuming this is MySQL (MariaDB) and there are in fact two columns called date and time this could be written as
SELECT * FROM `table` WHERE
(date = SUBDATE(CURDATE(), 1) AND time >= '23:00') OR (date = CURDATE() AND time < '23:00');
This is a bit unusual though. Usually you would have as single column of type datetime or timestamp instead of two columns, and they should not be called date or time because these are keywords.

You may try the below query:
SELECT * FROM `table` WHERE date BETWEEN CONCAT(date_sub(curdate(),interval 1 day),' 23:00') AND CONCAT(curdate(),' 22:59');
Please double check your database timezone.

Related

Previous day of current_date() in Hue hive

I'm trying to write a query to return records from a column called "businessdate" (which is in the YYYY-MM-DD format, and it is a string data type), using the previous days "businessdate" records and am stuck. I've tried different things, and I get error messages ranging from argument or matching method, etc. It's probably simple, and I feel dumb. Please help!
Query;
Select businessdate from dbname
Where businessdate = current_date - 1
Use date_sub function to subtract one day from current_date:
select businessdate
from dbname.tablename
where businessdate = date_sub(current_date,1)

Sql Server Table date query showing incorrect result

I have a Sql server table which contains below Date values(4th october)
Now Below query is not showing any result
select
*
from [dbo].[TB_AUDIT] TBA
where TBA.ActionDate >= '10/01/2018' and TBA.ActionDate <= '10/04/2018' which is not correct.
But If I write
select
*
from [dbo].[TB_AUDIT] TBA
where TBA.ActionDate >= '10/01/2018' and TBA.ActionDate <= '10/05/2018' it is returning me all results.
What I am doing wrong.
There are two problems with this query. The first, is that it's using a localized string. To me, it looks like it's asking for rows between January and April. The unambiguous date format is YYYYMMDD. YYYY-MM-DD by itself may not work in SQL server as it's still affected by the language. The ODBC date literal, {d'YYYY-MM-DD'} also works unambiguously.
Second, the date parameters have no time which defaults to 00:00. The stored dates though have a time element which means they are outside the search range, even if the date parameter was recognized.
The query should change to :
select
*
from [dbo].[TB_AUDIT] TBA
where
cast(TBA.ActionDate as date) between '20181001' and '20181004'
or
cast(TBA.ActionDate as date) between {d'2018-10-01'} and {d'2018-10-04'}
Normally, applying a function to a field prevents the server from using any indexes. SQL Server is smart enough though to convert this to a query that covers the entire date, essentially similar to
where
TBA.ActionDate >='2018:10:01T00:00' and TBA.ActionDate <'2018-10-05T00:00:00'
When you don't specify a time component for a DATETIME, SQL Server defaults it to midnight. So in your first query, you're asking for all results <='2018-10-04T00:00:00.000'. All of the data points in your table are greater than '2018-10-04T00:00:00.000', so nothing is returned.
You want
TBA.ActionDate >= '2018-10-01T00:00:00.000' and TBA.ActionDate < '2018-10-05T00:00:00.000'`
Use properly formatted dates!
select *
from [dbo].[TB_AUDIT] TBA
where TBA.ActionDate >= '2018-10-01' and TBA.ActionDate <= '2018-10-04'
YYYY-MM-DD isn't just a good idea. It is the ISO standard for date formats, recognized by most databases.
when you just filter by the date, it is with regard to the time as per the standard.

Issue querying date from oracle.

I understand that querying a date will fail as its comparing a string to date and that can cause an issue.
Oracle 11.2 G
Unicode DB
NLS_DATE_FORMAT DD-MON-RR
select * from table where Q_date='16-Mar-09';
It can be solved by
select * from table where trunc(Q_date) = TO_DATE('16-MAR-09', 'DD-MON-YY');
What I don't get is why this works.
select* from table where Q_date='07-JAN-08';
If anyone can please elaborate or correct my mindset.
Thanks
Oracle does allow date literals, but they depend on the installation (particularly the value of NLS_DATE_FORMAT as explained here). Hence, there is not a universal format for interpreting a single string as a date (unless you use the DATE keyword).
The default format is DD-MM-YY, which seems to be the format for your server. So, your statement:
where Q_date = '07-JAN-08'
is interpreted using this format.
I prefer to use the DATE keyword with the ISO standard YYYY-MM-DD format:
where Q_Date = DATE '2008-01-07'
If this gets no rows returned:
select * from table where Q_date='16-Mar-09';
but this does see data:
select * from table where trunc(Q_date) = TO_DATE('16-MAR-09', 'DD-MON-YY');
then you have rows which have a time other than midnight. At this point in the century DD-MON-RR and DD-MON-YY are equivalent, and both will see 09 as 2009, so the date part is right. But the first will only find rows where the time is midnight, while the second is stripping the time off via the trunc, meaning the dates on both sides are at midnight, and therefore equal.
And since this also finds data:
select* from table where Q_date='07-JAN-08';
... then you have rows at midnight on that date. You might also have rows with other times, so checking the count with the trunc version might be useful.
You can check the times you actually have with:
select to_char(q_date, 'YYYY-MM-DD HH24:MI:SS') from table;
If you do want to make sure you catch all times within the day you can use a range:
select * from table where
q_date >= date '2009-03-16'
and q_date < date '2009-03-17';
Quick SQL Fiddle demo.
Although it sounds like you're expecting all the times to be midnight, which might indicate a data problem.

How can I return data in a SQLite result set based on date range? [duplicate]

I can't seem to get reliable results from the query against a sqlite database using a datetime string as a comparison as so:
select *
from table_1
where mydate >= '1/1/2009' and mydate <= '5/5/2009'
how should I handle datetime comparisons to sqlite?
update:
field mydate is a DateTime datatype
To solve this problem, I store dates as YYYYMMDD. Thus,
where mydate >= '20090101' and mydate <= '20050505'
It just plain WORKS all the time. You may only need to write a parser to handle how users might enter their dates so you can convert them to YYYYMMDD.
SQLite doesn't have dedicated datetime types, but does have a few datetime functions. Follow the string representation formats (actually only formats 1-10) understood by those functions (storing the value as a string) and then you can use them, plus lexicographical comparison on the strings will match datetime comparison (as long as you don't try to compare dates to times or datetimes to times, which doesn't make a whole lot of sense anyway).
Depending on which language you use, you can even get automatic conversion. (Which doesn't apply to comparisons in SQL statements like the example, but will make your life easier.)
I had the same issue recently, and I solved it like this:
SELECT * FROM table WHERE
strftime('%s', date) BETWEEN strftime('%s', start_date) AND strftime('%s', end_date)
The following is working fine for me using SQLite:
SELECT *
FROM ingresosgastos
WHERE fecharegistro BETWEEN "2010-01-01" AND "2013-01-01"
Following worked for me.
SELECT *
FROM table_log
WHERE DATE(start_time) <= '2017-01-09' AND DATE(start_time) >= '2016-12-21'
Sqlite can not compare on dates. we need to convert into seconds and cast it as integer.
Example
SELECT * FROM Table
WHERE
CAST(strftime('%s', date_field) AS integer) <=CAST(strftime('%s', '2015-01-01') AS integer) ;
I have a situation where I want data from up to two days ago and up until the end of today.
I arrived at the following.
WHERE dateTimeRecorded between date('now', 'start of day','-2 days')
and date('now', 'start of day', '+1 day')
Ok, technically I also pull in midnight on tomorrow like the original poster, if there was any data, but my data is all historical.
The key thing to remember, the initial poster excluded all data after 2009-11-15 00:00:00. So, any data that was recorded at midnight on the 15th was included but any data after midnight on the 15th was not.
If their query was,
select *
from table_1
where mydate between Datetime('2009-11-13 00:00:00')
and Datetime('2009-11-15 23:59:59')
Use of the between clause for clarity.
It would have been slightly better. It still does not take into account leap seconds in which an hour can actually have more than 60 seconds, but good enough for discussions here :)
I had to store the time with the time-zone information in it, and was able to get queries working with the following format:
"SELECT * FROM events WHERE datetime(date_added) BETWEEN
datetime('2015-03-06 20:11:00 -04:00') AND datetime('2015-03-06 20:13:00 -04:00')"
The time is stored in the database as regular TEXT in the following format:
2015-03-06 20:12:15 -04:00
Right now i am developing using System.Data.SQlite NuGet package (version 1.0.109.2). Which using SQLite version 3.24.0.
And this works for me.
SELECT * FROM tables WHERE datetime
BETWEEN '2018-10-01 00:00:00' AND '2018-10-10 23:59:59';
I don't need to use the datetime() function. Perhaps they already updated the SQL query on that SQLite version.
Below are the methods to compare the dates but before that we need to identify the format of date stored in DB
I have dates stored in MM/DD/YYYY HH:MM format so it has to be compared in that format
Below query compares the convert the date into MM/DD/YYY format and get data from last five days till today. BETWEEN operator will help and you can simply specify start date AND end date.
select * from myTable where myColumn BETWEEN strftime('%m/%d/%Y %H:%M', datetime('now','localtime'), '-5 day') AND strftime('%m/%d/%Y %H:%M',datetime('now','localtime'));
Below query will use greater than operator (>).
select * from myTable where myColumn > strftime('%m/%d/%Y %H:%M', datetime('now','localtime'), '-5 day');
All the computation I have done is using current time, you can change the format and date as per your need.
Hope this will help you
Summved
You could also write up your own user functions to handle dates in the format you choose. SQLite has a fairly simple method for writing your own user functions. For example, I wrote a few to add time durations together.
My query I did as follows:
SELECT COUNT(carSold)
FROM cars_sales_tbl
WHERE date
BETWEEN '2015-04-01' AND '2015-04-30'
AND carType = "Hybrid"
I got the hint by #ifredy's answer. The all I did is, I wanted this query to be run in iOS, using Objective-C. And it works!
Hope someone who does iOS Development, will get use out of this answer too!
Here is a working example in C# in three ways:
string tableName = "TestTable";
var startDate = DateTime.Today.ToString("yyyy-MM-dd 00:00:00"); \\From today midnight
var endDate = date.AddDays(1).ToString("yyyy-MM-dd HH:mm:ss"); \\ Whole day
string way1 /*long way*/ = $"SELECT * FROM {tableName} WHERE strftime(\'%s\', DateTime)
BETWEEN strftime('%s', \'{startDate}\') AND strftime('%s', \'{endDate}\')";
string way2= $"SELECT * FROM {tableName} WHERE DateTime BETWEEN \'{startDate}\' AND \'{endDate}\'";
string way3= $"SELECT * FROM {tableName} WHERE DateTime >= \'{startDate}\' AND DateTime <=\'{endDate}\'";
select *
from table_1
where date(mydate) >= '1/1/2009' and date(mydate) <= '5/5/2009'
This work for me

pgsql time diffrence?

How to write a query to find the time difference ?
time format is like this
2009-08-12 02:59:59
i want to compare
this time with
2009-08-12 02:59:10
how to check these two
i want to return some row having the time difference is 30sec
how to write a SQL statement ??
select date_part('second',date1) - date_part('second',date2)
In SQL you can do like this which give you output in seconds
SELECT * FROM your_table WHERE time1_column - time2_column = interval '30s'
Sorry this is the best I can do, given your description of the problem...
if both the times are columns in database table, you can directly use
relational operators (>, < and =)
Ex. if you have a table like
Test
(
id bigint,
starttime timestamp,
endtime timestamp
);
then you can have queries like
select * from test where starttime > end time
etc..
If you want to compare two dates in query, you can first convert text to time and then compare them
you can use: datetime function of pgsql
see: http://www.postgresql.org/docs/6.3/static/c10.htm
for more details