Data Analysis in SQLite: Monthly revenue from RECURRING sales (subscription) - sql

I am doing a case for a subscription-based company that wants an overview of their monthly sales. This means that I need to sum up the revenue from all active subscriptions, grouped by month. I have managed to work my way through the data to create a table that looks like the one below. Each row is a contract with a start date, end date, proposition (either standard or discount), and the corresponding price per month.
ContractStartDate
ContractEndDate
PropositionReference
PropositionPrice
2018-01-03
NULL
Standard
4.5
2019-01-17
NULL
Discount
2
2018-02-09
2019-01-17
Standard
4.5
...
...
...
...
I want to have the revenue for each month, starting from the minimum ContractStartDate (the first time they received any revenue), for both Standard and Discount propositions. So I would like to have something that looks like this:
Month
RevenueStandard
RevenueDiscount
2017-07
90
30
2017-08
85.5
80
2017-09
180
60
...
2022-10
3862
1136
For each month and each proposition (Standard or Discount), I would need to go over every contract and sum up the proposition price if the startdate was after that month and the enddate was before that month (or there is no enddate).
This is the code I tried, but I feel like I am really far off the solution:
SELECT
MonthYear, PropositionReference,
SUM(CASE WHEN STRFTIME("%m %Y", ContractStartDate) <= MonthYear
AND (ContractEndDate IS NULL OR STRFTIME("%m %Y", ContractEndDate) >= MonthYear)
AND PropositionReference = "Standard"
THEN PropositionPrice ELSE 0 END) AS RevenueStandard,
SUM(CASE WHEN STRFTIME("%m %Y", ContractStartDate) <= MonthYear
AND (ContractEndDate IS NULL OR STRFTIME("%m %Y", ContractEndDate) >= MonthYear)
AND PropositionReference = "Discount"
THEN PropositionPrice ELSE 0 END) AS RevenueDiscount
FROM (SELECT *, STRFTIME("%m %Y", ContractStartDate) AS MonthYear FROM Combined)
GROUP BY MonthYear, PropositionReference
ORDER BY MonthYear, PropositionReference

The following could be the basis if your question has been interpreted correctly.
WITH
range AS (
SELECT min(contractstartdate) AS low, max(coalesce(contractenddate,date('now'))) AS high FROM combined
),
t AS (
SELECT
low AS month,
(
SELECT
coalesce(sum(propositionprice),0)
FROM combined
WHERE propositionreference = 'Standard'
AND strftime('%s',low) BETWEEN strftime('%s',contractStartDate) AND strftime('%s',coalesce(contractEndDate,date('now')))
)
AS stnd,
(
SELECT
coalesce(sum(propositionprice),0)
FROM combined
WHERE propositionreference = 'Discount'
AND strftime('%s',low) BETWEEN strftime('%s',contractStartDate) AND strftime('%s',coalesce(contractEndDate,date('now')))
)
AS dscnt
FROM range
UNION ALL
SELECT date(month,'+1 month'),
(
SELECT
coalesce(sum(propositionprice),0)
FROM combined
WHERE propositionreference = 'Standard'
AND strftime('%s',date(month,'+1 month')) BETWEEN strftime('%s',contractStartDate) AND strftime('%s',coalesce(contractEndDate,date('now')))
)
AS stnd,
(
SELECT
coalesce(sum(propositionprice),0)
FROM combined
WHERE propositionreference = 'Discount'
AND strftime('%s',date(month,'+1 month')) BETWEEN strftime('%s',contractStartDate) AND strftime('%s',coalesce(contractEndDate,date('now')))
)
AS dscnt
FROM t
WHERE date(month,'+1 month') < (SELECT max(coalesce(contractenddate,date('now'))) FROM combined)
LIMIT 500 /* just in case to stop continuous loop */
)
SELECT * FROM t;
So this is
first creating a CTE (Common Table Expression (temp table that exists during the execution)) that consists of a single row with two values the lowest started date and the highest end date (if any null then current date ).
second creating another cte, but a recursive one where the first row is the first month, the second the next month .... until the last month (or in this case for a maximum of 500 iterations (to prevent accidental endless loop)).
each iteration retrieves the sum of the respective type for rows from the combined table that include the date being processed.
As a demo, based upon your data then:-
DROP TABLE IF EXISTS combined;
CREATE TABLE IF NOT EXISTS combined (ContractStartDate TEXT,ContractEndDate TEXT,PropositionReference TEXT,PropositionPrice REAL);
INSERT INTO combined VALUES
('2018-01-03', NULL, 'Standard', 4.5)
,('2019-01-17', NULL, 'Discount', 2)
,('2018-02-09', '2019-01-17', 'Standard', 4.5)
;
WITH
range AS (
SELECT min(contractstartdate) AS low, max(coalesce(contractenddate,date('now'))) AS high FROM combined
),
t AS (
SELECT
low AS month,
(
SELECT
coalesce(sum(propositionprice),0)
FROM combined
WHERE propositionreference = 'Standard'
AND strftime('%s',low) BETWEEN strftime('%s',contractStartDate) AND strftime('%s',coalesce(contractEndDate,date('now')))
)
AS stnd,
(
SELECT
coalesce(sum(propositionprice),0)
FROM combined
WHERE propositionreference = 'Discount'
AND strftime('%s',low) BETWEEN strftime('%s',contractStartDate) AND strftime('%s',coalesce(contractEndDate,date('now')))
)
AS dscnt
FROM range
UNION ALL
SELECT date(month,'+1 month'),
(
SELECT
coalesce(sum(propositionprice),0)
FROM combined
WHERE propositionreference = 'Standard'
AND strftime('%s',date(month,'+1 month')) BETWEEN strftime('%s',contractStartDate) AND strftime('%s',coalesce(contractEndDate,date('now')))
)
AS stnd,
(
SELECT
coalesce(sum(propositionprice),0)
FROM combined
WHERE propositionreference = 'Discount'
AND strftime('%s',date(month,'+1 month')) BETWEEN strftime('%s',contractStartDate) AND strftime('%s',coalesce(contractEndDate,date('now')))
)
AS dscnt
FROM t
WHERE date(month,'+1 month') < (SELECT max(coalesce(contractenddate,date('now'))) FROM combined)
LIMIT 500 /* just in case to stop continuous loop */
)
SELECT * FROM t;
DROP TABLE IF EXISTS combined;
results in :-

Related

How to spread month to day with amount value divided by total days per month

I have data with an amount of 1 month and want to change it to 30 days.
if 1 month the amount is 20000 then per day is 666.67
The following are sample data and results:
Account
Project
Date
Segment
Amount
Acc1
1
September 2022
Actual
20000
Result :
I need a query using sql server
You may try a set-based approach using an appropriate number table and a calculation with windowed COUNT().
Data:
SELECT *
INTO Data
FROM (VALUES
('Acc1', 1, CONVERT(date, '20220901'), 'Actual', 20000.00)
) v (Account, Project, [Date], Segment, Amount)
Statement for all versions, starting from SQL Server 2016 (the number table is generated using JSON-based approach with OPENJSON()):
SELECT d.Account, d.Project, a.[Date], d.Segment, a.Amount
FROM Data d
CROSS APPLY (
SELECT
d.Amount / COUNT(*) OVER (ORDER BY (SELECT NULL)),
DATEADD(day, CONVERT(int, [key]), d.[Date])
FROM OPENJSON('[1' + REPLICATE(',1', DATEDIFF(day, d.[Date], EOMONTH(d.[Date]))) + ']')
) a (Amount, Date)
Statement for SQL Server 2022 (the number table is generated with GENERATE_SERIES()):
SELECT d.Account, d.Project, a.[Date], d.Segment, a.Amount
FROM Data d
CROSS APPLY (
SELECT
d.Amount / COUNT(*) OVER (ORDER BY (SELECT NULL)),
DATEADD(day, [value], d.[Date])
FROM GENERATE_SERIES(0, DATEDIFF(day, d.[Date], EOMONTH(d.[Date])))
) a (Amount, Date)
Notes:
Both approaches calculate the days for each month. If you always want 30 days per month, replace DATEDIFF(day, d.[Date], EOMONTH(d.[Date])) with 29.
There is a rounding issue with this calculation. You may need to implement an additional calculation for the last day of the month.
You can use a recursive CTE to generate each day of the month and then divide the amount by the number of days in the month to achive the required output
DECLARE #Amount NUMERIC(18,2) = 20000,
#MonthStart DATE = '2022-09-01'
;WITH CTE
AS
(
SELECT
CurrentDate = #MonthStart,
DayAmount = CAST(#Amount/DAY(EOMONTH(#MonthStart)) AS NUMERIC(18,2)),
RemainingAmount = CAST(#Amount - (#Amount/DAY(EOMONTH(#MonthStart))) AS NUMERIC(18,2))
UNION ALL
SELECT
CurrentDate = DATEADD(DAY,1,CurrentDate),
DayAmount = CASE WHEN DATEADD(DAY,1,CurrentDate) = EOMONTH(#MonthStart)
THEN RemainingAmount
ELSE DayAmount END,
RemainingAmount = CASE WHEN DATEADD(DAY,1,CurrentDate) = EOMONTH(#MonthStart)
THEN 0
ELSE CAST(RemainingAmount-DayAmount AS NUMERIC(18,2)) END
FROM CTE
WHERE CurrentDate < EOMONTH(#MonthStart)
)
SELECT
CurrentDate,
DayAmount
FROM CTE
In case you want an equal split without rounding errors and without loops you can use this calculation. It spreads the rounding error across all entries, so they are all as equal as possible.
DECLARE #Amount NUMERIC(18,2) = 20000,
#MonthStart DATE = '20220901'
SELECT DATEADD(DAY,Numbers.i - 1,#MonthStart)
, ShareSplit.Calculated_Share
, SUM(ShareSplit.Calculated_Share) OVER (ORDER BY (SELECT NULL)) AS Calculated_Total
FROM (SELECT DISTINCT number FROM master..spt_values WHERE number BETWEEN 1 AND DAY(EOMONTH(#MonthStart)))Numbers(i)
CROSS APPLY(SELECT CAST(ROUND(#Amount * 100 / DAY(EOMONTH(#MonthStart)),0) * 0.01
+ CASE
WHEN Numbers.i
<= ABS((#Amount - (ROUND(#Amount * 100 / DAY(EOMONTH(#MonthStart)),0) / 100.0 * DAY(EOMONTH(#MonthStart)))) * 100)
THEN 0.01 * SIGN(#Amount - (ROUND(#Amount * 100 / DAY(EOMONTH(#MonthStart)),0) / 100.0 * DAY(EOMONTH(#MonthStart))))
ELSE 0
END AS DEC(18,2)) AS Calculated_Share
)ShareSplit

How to retrieve default value even when do no exist record in database

Querying data as showed below there is no record on database for day 2021-10-03.
date
value
2021-10-01
100
2021-10-02
90
2021-10-04
10
2021-10-05
40
I would like to execute the query using date between as SELECT ... WHERE date BETWEEN '2021-10-01' AND '2021-10-05' and in case of do not exist data for a specific day, to retrieve zero as exemplified below:
date
value
2021-10-01
100
2021-10-02
90
2021-10-03
10
2021-10-04
10
2021-10-05
40
Is it possible? in bigQuery?
I tried the query below, but retrieved duplicated values.
WITH `project.myproject` AS (
SELECT
DATA_VENDA AS date,
CAST(SUM(VLR_VENDA_TABELA) AS FLOAT64) AS total,
FROM `project.myproject`
WHERE
(DATA_VENDA BETWEEN '2020-10-02'
AND '2020-10-07')
AND COD_CP = '0000010232'
GROUP BY
DATA_VENDA
ORDER BY
DATA_VENDA
),
dates AS (
SELECT total, date
FROM `project.myproject`, UNNEST(GENERATE_DATE_ARRAY(date('2020-10-02'), date('2020-10-07'))) AS date
)
SELECT d.date, IFNULL(t.total, 0) total
FROM dates d
LEFT JOIN `project.myproject` t
ON d.date = t.date
AND d.total = t.total
ORDER BY d.date
I found out the answers running command below. The difference from that to this is that in this new one I removed the line AND d.total = t.total, who was responsible for creating duplicated data. The final answer follow below:
WITH `project.myproject` AS (
SELECT
DATA_VENDA AS date,
CAST(SUM(VLR_VENDA_TABELA) AS FLOAT64) AS total,
FROM `project.myproject`
WHERE
(DATA_VENDA BETWEEN '2020-10-02'
AND '2020-10-07')
AND COD_CP = '0000010232'
GROUP BY
DATA_VENDA
ORDER BY
DATA_VENDA
),
dates AS (
SELECT total, date
FROM `project.myproject`, UNNEST(GENERATE_DATE_ARRAY(date('2020-10-02'), date('2020-10-07'))) AS date
)
SELECT d.date, IFNULL(t.total, 0) total
FROM dates d
LEFT JOIN `project.myproject` t
ON d.date = t.date
ORDER BY d.date
You can simply do that with the common table expression(CTE) as shown below.
DECLARE #Datatemp TABLE (
Id INT IDENTITY(1,1) NOT NULL,
CDate DATETIME,
Val INT
)
INSERT INTO #Datatemp SELECT '2021-10-01',10
INSERT INTO #Datatemp SELECT '2021-10-02',50
INSERT INTO #Datatemp SELECT '2021-10-04',24
INSERT INTO #Datatemp SELECT '2021-10-05',18
;WITH DateTemp(Date) AS (
SELECT CAST('2021-10-01' AS DATETIME)
UNION ALL
SELECT [Date]+1
FROM DateTemp
WHERE [Date] < '2021-10-05'
)
SELECT DateTemp.[Date] CDat
,ISNULL(t.Val, 0) Val
FROM DateTemp
LEFT JOIN #Datatemp t ON t.CDate = DateTemp.[Date]
ORDER BY DateTemp.[Date]
--OPTION (MAXRECURSION 0)
By default number of iterations for recursive CTE is 100. As long as this number is exceeded, the query will be interrupted and an error will be generated. If you want to remove this restriction, you can specify MAXRECURSION 0.

Querying the same column for 3 different values

I'm trying hard to extract the data in the format I need, but unsuccessful til now.
I have the following table
id_ticket, date_ticket, office_ticket, status_ticket
I need the query to return me, for EVERY MONTH, and always for the same OFFICE:
the number of tickets (COUNT) with any status
the number of tickets (COUNT) with status = 5
the number of tickets (COUNT) with status = 6
Month
Year
The query I made to return ONLY the total amount of tickets with any status was this. It worked!
SELECT
COUNT (id_ticket) as TotalTicketsPerMonth,
'sYear' = YEAR (date_ticket),
'sMonth' = MONTH (date_ticket)
FROM crm_vw_Tickets
WHERE office_ticket = 1
GROUP BY
YEAR (date_ticket), MONTH (date_ticket)
ORDER BY sYear ASC, sMonth ASC
Returning the total amount of ticket with status=5
SELECT
COUNT (id_ticket) as TotalTicketsPerMonth,
'sYear' = YEAR (date_ticket),
'sMonth' = MONTH (date_ticket)
FROM crm_vw_Tickets
WHERE office_ticket = 1 AND status_ticket = 5
GROUP BY
YEAR (date_ticket), MONTH (date_ticket)
ORDER BY sYear ASC, sMonth ASC
But I need the return to be something like:
Year Month Total Status5 Status6
2018 1 15 5 3
2018 2 14 4 5
2018 3 19 2 8
Thank you for your help.
You are close. You can use a CASE Expression to get what you need:
SELECT
COUNT (id_ticket) as TotalTicketsPerMonth,
SUM(CASE WHEN status_ticket = 5 THEN 1 END) as Status5,
SUM(CASE WHEN status_ticket = 6 THEN 1 END) as Status6,
'sYear' = YEAR (date_ticket),
'sMonth' = MONTH (date_ticket)
FROM crm_vw_Tickets
WHERE office_ticket = 1
GROUP BY YEAR (date_ticket), MONTH (date_ticket)
ORDER BY sYear ASC, sMonth ASC
The following code builds off JNevill's answer to include summary rows for "missing" months, i.e. those with no tickets, as well as months with tickets. The basic idea is to create a table of all of the months from the first to the last ticket, outer join the ticket data with the months and then summarize the data. (Tally table, numbers table and calendar table are more or less applicable terms.)
It is a Common Table Expression (CTE) that contains several queries that work step-by-step toward the result. You can see the results of the intermediate steps by replacing the final select statement with one of the ones commented out above it.
-- Sample data.
declare #crm_vw_Tickets as Table ( id_ticket Int Identity, date_ticket Date, office_ticket Int, status_ticket Int );
insert into #crm_vw_Tickets ( date_ticket, office_ticket, status_ticket ) values
( '20190305', 1, 6 ), -- Shrove Tuesday.
( '20190501', 1, 5 ), -- May Day.
( '20190525', 1, 5 ); -- Towel Day.
select * from #crm_vw_Tickets;
-- Summarize the data.
with
-- Get the minimum and maximum ticket dates for office_ticket 1.
Limits as (
select Min( date_ticket ) as MinDateTicket, Max( date_ticket ) as MaxDateTicket
from #crm_vw_Tickets
where office_ticket = 1 ),
-- 0 to 9.
Ten ( Number ) as ( select * from ( values (0), (1), (2), (3), (4), (5), (6), (7), (8), (9) ) as Digits( Number ) ),
-- 100 rows.
TenUp2 ( Number ) as ( select 42 from Ten as L cross join Ten as R ),
-- 10000 rows. We'll assume that 10,000 months should cover the reporting range.
TenUp4 ( Number ) as ( select 42 from TenUp2 as L cross join TenUp2 as R ),
-- 1 to the number of months to summarize.
Numbers ( Number ) as ( select top ( select DateDiff( month, MinDateTicket, MaxDateTicket ) + 1 from Limits ) Row_Number() over ( order by ( select NULL ) ) from TenUp4 ),
-- Starting date of each month to summarize.
Months as (
select DateAdd( month, N.Number - 1, DateAdd( day, 1 - Day( L.MinDateTicket ), L.MinDateTicket ) ) as StartOfMonth
from Limits as L cross join
Numbers as N ),
-- All tickets assigned to the appropriate month and a row with NULL ticket data
-- for each month without tickets.
MonthsAndTickets as (
select M.StartOfMonth, T.*
from Months as M left outer join
#crm_vw_Tickets as T on M.StartOfMonth <= T.date_ticket and T.date_ticket < DateAdd( month, 1, M.StartOfMonth ) )
-- Use one of the following select statements to see the intermediate or final results:
--select * from Limits;
--select * from Ten;
--select * from TenUp2;
--select * from TenUp4;
--select * from Numbers;
--select * from Months;
--select * from MonthsAndTickets;
select Year( StartOfMonth ) as SummaryYear, Month( StartOfMonth ) as SummaryMonth,
Count( id_ticket ) as TotalTickets,
Coalesce( Sum( case when status_ticket = 5 then 1 end ), 0 ) as Status5Tickets,
Coalesce( Sum( case when status_ticket = 6 then 1 end ), 0 ) as Status6Tickets
from MonthsAndTickets
where office_ticket = 1 or office_ticket is NULL -- Handle months with no tickets.
group by StartOfMonth
order by StartOfMonth;
Note that the final select uses Count( id_ticket ), Coalesce and an explicit check for NULL to produce appropriate output values (0) for months with no tickets.

Group by in columns and rows, counts and percentages per day

I have a table that has data like following.
attr |time
----------------|--------------------------
abc |2018-08-06 10:17:25.282546
def |2018-08-06 10:17:25.325676
pqr |2018-08-05 10:17:25.366823
abc |2018-08-06 10:17:25.407941
def |2018-08-05 10:17:25.449249
I want to group them and count by attr column row wise and also create additional columns in to show their counts per day and percentages as shown below.
attr |day1_count| day1_%| day2_count| day2_%
----------------|----------|-------|-----------|-------
abc |2 |66.6% | 0 | 0.0%
def |1 |33.3% | 1 | 50.0%
pqr |0 |0.0% | 1 | 50.0%
I'm able to display one count by using group by but unable to find out how to even seperate them to multiple columns. I tried to generate day1 percentage with
SELECT attr, count(attr), count(attr) / sum(sub.day1_count) * 100 as percentage from (
SELECT attr, count(*) as day1_count FROM my_table WHERE DATEPART(week, time) = DATEPART(day, GETDate()) GROUP BY attr) as sub
GROUP BY attr;
But this also is not giving me correct answer, I'm getting all zeroes for percentage and count as 1. Any help is appreciated. I'm trying to do this in Redshift which follows postgresql syntax.
Let's nail the logic before presenting:
with CTE1 as
(
select attr, DATEPART(day, time) as theday, count(*) as thecount
from MyTable
)
, CTE2 as
(
select theday, sum(thecount) as daytotal
from CTE1
group by theday
)
select t1.attr, t1.theday, t1.thecount, t1.thecount/t2.daytotal as percentofday
from CTE1 t1
inner join CTE2 t2
on t1.theday = t2.theday
From here you can pivot to create a day by day if you feel the need
I am trying to enhance the query #johnHC btw if you needs for 7days then you have to those days in case when
with CTE1 as
(
select attr, time::date as theday, count(*) as thecount
from t group by attr,time::date
)
, CTE2 as
(
select theday, sum(thecount) as daytotal
from CTE1
group by theday
)
,
CTE3 as
(
select t1.attr, EXTRACT(DOW FROM t1.theday) as day_nmbr,t1.theday, t1.thecount, t1.thecount/t2.daytotal as percentofday
from CTE1 t1
inner join CTE2 t2
on t1.theday = t2.theday
)
select CTE3.attr,
max(case when day_nmbr=0 then CTE3.thecount end) as day1Cnt,
max(case when day_nmbr=0 then percentofday end) as day1,
max(case when day_nmbr=1 then CTE3.thecount end) as day2Cnt,
max( case when day_nmbr=1 then percentofday end) day2
from CTE3 group by CTE3.attr
http://sqlfiddle.com/#!17/54ace/20
In case that you have only 2 days:
http://sqlfiddle.com/#!17/3bdad/3 (days descending as in your example from left to right)
http://sqlfiddle.com/#!17/3bdad/5 (days ascending)
The main idea is already mentioned in the other answers. Instead of joining the CTEs for calculating the values I am using window functions which is a bit shorter and more readable I think. The pivot is done the same way.
SELECT
attr,
COALESCE(max(count) FILTER (WHERE day_number = 0), 0) as day1_count, -- D
COALESCE(max(percent) FILTER (WHERE day_number = 0), 0) as day1_percent,
COALESCE(max(count) FILTER (WHERE day_number = 1), 0) as day2_count,
COALESCE(max(percent) FILTER (WHERE day_number = 1), 0) as day2_percent
/*
Add more days here
*/
FROM(
SELECT *, (count::float/count_per_day)::decimal(5, 2) as percent -- C
FROM (
SELECT DISTINCT
attr,
MAX(time::date) OVER () - time::date as day_number, -- B
count(*) OVER (partition by time::date, attr) as count, -- A
count(*) OVER (partition by time::date) as count_per_day
FROM test_table
)s
)s
GROUP BY attr
ORDER BY attr
A counting the rows per day and counting the rows per day AND attr
B for more readability I convert the date into numbers. Here I take the difference between current date of the row and the maximum date available in the table. So I get a counter from 0 (first day) up to n - 1 (last day)
C calculating the percentage and rounding
D pivot by filter the day numbers. The COALESCE avoids the NULL values and switched them into 0. To add more days you can multiply these columns.
Edit: Made the day counter more flexible for more days; new SQL Fiddle
Basically, I see this as conditional aggregation. But you need to get an enumerator for the date for the pivoting. So:
SELECT attr,
COUNT(*) FILTER (WHERE day_number = 1) as day1_count,
COUNT(*) FILTER (WHERE day_number = 1) / cnt as day1_percent,
COUNT(*) FILTER (WHERE day_number = 2) as day2_count,
COUNT(*) FILTER (WHERE day_number = 2) / cnt as day2_percent
FROM (SELECT attr,
DENSE_RANK() OVER (ORDER BY time::date DESC) as day_number,
1.0 * COUNT(*) OVER (PARTITION BY attr) as cnt
FROM test_table
) s
GROUP BY attr, cnt
ORDER BY attr;
Here is a SQL Fiddle.

Retrieve records by continuation of days in oracle

I want to retrieve records where cash deposits are more than 4 totaling to 1000000 during a day and continues for more than 5 days.
I have came up with below query.
SELECT COUNT(a.txamt) AS "txcount"
, SUM(a.txamt) AS "txsum"
, b.custcd
, a.txdate
FROM tb_transactions a
INNER JOIN tb_accounts b
ON a.acctno = b.acctno
WHERE a.cashflowtype = 'CR'
GROUP BY b.custcd, a.txdate
HAVING COUNT(a.txamt)>4 and SUM(a.txamt)>='1000000'
ORDER BY a.txdate;
But I'm stuck on how to fetch the records if the pattern continues for 5 days.
How to achieve the desired result?
Something like:
SELECT *
FROM (
SELECT t.*,
COUNT( txdate ) OVER ( PARTITION BY custcd
ORDER BY txdate
RANGE BETWEEN INTERVAL '0' DAY PRECEDING
AND INTERVAL '4' DAY FOLLOWING ) AS
num_days
FROM (
select count(a.txamt) as "txcount",
sum(a.txamt) as "txsum",
b.custcd,
a.txdate
from tb_transactions a inner join tb_accounts b on a.acctno=b.acctno
where a.cashflowtype='CR'
group by b.custcd, a.txdate
having count(a.txamt)>4 and sum(a.txamt)>=1000000
) t
)
WHERE num_days = 5
order by a.txdate;