View of a table
ID
kWh
1
3
1
10
1
8
1
11
2
12
2
4
2
7
2
8
3
3
3
4
3
5
I want to recive
ID
kWh
1
32
2
31
3
12
The table itself is more complex and larger. But the point is this. How can this be done? And I can't know in advance the ID numbers of the first column.
SELECT T.ID,SUM(T.KWH)SUM_KWH
FROM YOUR_TABLE T
GROUP BY T.ID
Do you need this one?
Let's assume your database name is 'testdb' and table name is 'table1'.
SELECT * FROM testdb.table1;
SELECT id, SUM(kwh) AS "kwh2"
FROM stack.table1
WHERE id = 1
keep running the query will all (ids). you will get output.
By following this query you will get desired output.
Hope this helps.
Related
For example, lets say I have
id
values
1
10
1
12
1
10
2
2
2
5
2
4
then i would want sql to return
id
values
1
32
2
11
This is very basic sql.
select id, sum(values) as values
from foo
group by id
Select ID,sum(values)
From table
Group by ID;
There is a table with values as below,
Id Value
1 1
2 1
3 2
4 2
5 3
6 4
7 4
now need to write a query to retrieve value from the table and output should look as
ID Value
1 1
3 2
5 3
6 4
any suggestion ?
The query you want is nothing to do with being distinct, it's a simple aggregation of value with the minimum ID for each:
select Min(id) Id, value
from table
group by value
I want to group records by row numbers.
Like from row 1-3 in group 1 , 4-6 in group 2 , 7-9 in group 3 and so on.
Suppose below is the table structure:
Row NumberDataValue
1 A 10
2 A 5
3 A 1
4 A 33
5 A 2
6 A 127
1 B 1
2 B 0
3 B 7
4 B 7
5 B 5
6 B 8
7 B 1
8 B 0
I want a output like this:
GroupValue
1 10
1 5
1 1
2 33
2 2
2 127
1 1
1 0
1 7
2 7
2 5
2 8
3 1
3 0
I am using Oracle 11G.
I can achieve this using PL/SQL. But I have to use SQL only. As I have to use this query in a reporting tool.
If this is a duplicate question please provide the link of the answered question.
Subtract 1 from the column "RowNumber" and divide by 3.
Then use TRUNC() to get the integer part:
SELECT TRUNC(("RowNumber" - 1) / 3) + 1 "Group",
"Value"
FROM tablename
See the demo.
I would assume the name of the first column is ordering.
You can do:
select
1 + trunc(row_number() over(partition by data order by ordering) - 1) / 3,
value
from t
What you show looks like the output from something like this:
select ceil(rn/3) as grp, value
from your_table
order by rn;
Note that "row number" and "group" are reserved words/phrases which should not be used as column names. I used rn and grp instead.
I think the ceiling function is the simplest way to arrive at what you want. If you want to base it on the RowNumber column:
select ceil( RowNumber / 3.0) as grouping
If you want to calculate it yourself using row_number():
select ceil( row_number() over (order by RowNumber) / 3.0 ) as grouping
The first six balls mean first over, next six balls mean second over & so on than how to get average runs for each over.
input as
Ball no Runs
1 4
2 6
3 3
4 2
5 6
6 1
1 2
2 4
3 6
4 3
5 1
6 1
1 2
output should be:
Over no avg runs
1 3.66
2 2.83
As Gordon Linoff suggested, SQL table represents unordered sets, So you have to use an ordered column in your table. If you can use such a column you may use below query -
SELECT Over_no AVG(Runs) avg_runs
FROM (SELECT Ball_no, Runs, CEIL(ROW_NUMBER() OVER(ORDER BY ORDER_COLUMN, Ball_no) RN / 6) Over_no
FROM YOUR_TABLE)
GROUP BY Over_no;
I have managed to solve my problem with the following query:
SELECT ROWNUM OVER_NO, AVG_RUNS
FROM(
SELECT ROWNUM RN,
ROUND(AVG(RUNS)OVER(ORDER BY ROWNUM RANGE BETWEEN CURRENT ROW AND 5 FOLLOWING),2) AVG_RUNS
FROM TABLE_NAME
)
WHERE RN=1 OR RN=7;
I need to combine all values by one column depends on the key from another column. Can someone help me to get out of this problem please?
here is the short example of my problem.
CUST_ID CUST_REL_ID
100 1
100 2
100 3
100 4
200 5
200 6
200 7
CUST_ID CUST_REL_ID
1 1
1 2
1 3
1 4
2 1
2 2
2 3
2 4
...
5 5
5 6
5 7
I think you just want a self-join:
select t1.cust_rel_id, t2.cust_rel_id
from t t1 join
t t2
on t1.cust_id = t2.cust_id
order by t1.cust_rel_id, t2.cust_rel_id;
I don't understand your naming conventions. The column called cust_id in the result set looks nothing like the column called cust_id in the source data. But this appears to be what you want to do.