First-of-all I apologise because I'm new to this concept of redux haha so bare with me here :)
I have implemented a very simple redux in my app
I have one screen here ListAnItem
Here there is a button.
Add size when pressing this they get navigated to another screen called SizeSelector
SizeSelector
here there is a button called dispatch size when they press this button it runs the following.
dispatch({type: "ADD_SIZE", payload: size })
this works perfectly with useSelector.
once this dispatch has been run I use navigation.goBack() to send the user back to the ListAnItem screen.
but once they come to this screen I want to add this useSelector redux state value to a useState hook something like this;
const [sizeState, setSizeState] = React.useState(null)
how can I change this state the minute something has been added to useSelector value of ADD_SIZE.
if that makes sense 😂.
Thanks,
Arnav.
Related
I'm creating an app which passes some crucial info via AsyncStorage, but now have a problem when updating it on another screen.... Let's see:
On Screen 1 :
Load data from AsyncStorage on componentDidMount
componentDidMount() {
AsyncStorage.getItem("userChats").then((value) => {
this.setState({userChats: JSON.parse(value)});
});
}
then on Screen 2 I modify userChats.....
I'll like that when coming back again to Screen 1, the changes made on Screen 2 be reflected on Screen 1 but there are NOT as componentDidMount is not trigged again...........
What's the correct way to do it?
Thanks
componentDidMount is a life-cycle method. Navigating from Screen1 to Screen2 does NOT unmount Screen1. So, when you come back from Screen 2 to Screen 1, the Screen 1 does not mounting because it was NOT unmounted. Hence, componentDidMount is not called.
Whats's the correct way of doing this?
You should use Context API. When you load from AsyncStorage, set that value to Context as well. When you update the value, write changes to both AsyncStorage and Context.
PS: The AsyncStorage may not needed. It depends on your requirement. Most probably, you will be able to achieve this only with Context API.
Please check the following snack. It is done using hooks. You can do the same using class components.
https://snack.expo.io/3L9QSqWqt
UPDATE:
If the data to be handled is too large, it is not recommended to use Context since it saves all the data in the device RAM and consuming too much RAM may result in app crash.
To do this without using context:
(1) Define a function to retrieve data from AsyncStorage.
loadData() {
AsyncStorage.getItem("userChats").then((value) => {
this.setState({userChats: JSON.parse(value)});
});
}
(2) Call it in componentDidMount.
componentDidMount() {
this.loadData()
}
(3) When navigating to the Screen2, pass a callback function as a prop to call loadData function.
this.props.navigation.navigate('Screen2', {
onGoBack: () => this.loadData(),
});
(4) Then in the Screen2, before goBack, you can do this:
await AsyncStorage.setItem('userChats', updatedData);
this.props.navigation.state.params.onGoBack();
this.props.navigation.goBack();
Then, the loadData function is called in the screen2.
PS: Since you use state to store the retrieved data from the AsyncStorage, you can also directly load them into the Context and use. But, keep in mind that, using too much of RAM may cause app crash.
In my react-native project, I have three checkboxes, I need to track the state of those checkboxes so I use an object with key-value (value is boolean) to represent the states of all three checkboxes and use useState hook to manage them. Here is my code:
import React, { useState, useEffect } from 'react';
...
const MyScreen = ({ navigation }) => {
// initially, all checkboxes are checked
const initialCheckBoxState = {
0: true,
1: true,
2: true,
};
const [checkBoxesState, setCheckBoxesState] = useState(initialCheckBoxState);
useEffect(() => {
return () => {
console.log('Screen did unmount');
};
}, [checkBoxesState]);
return (
<View>
...
<SectionList
sections={options}
renderItem={({ index, item }) => (
<CheckBox
onPress={() => {
const checkBoxesStateCopy = { ...checkBoxesState };
checkBoxesStateCopy[index] = !checkBoxesStateCopy[index];
setCheckBoxesState(checkBoxesStateCopy);
}}
/>
)}
/>
...
</View>
);
};
I omitted code that is not the concern of my problem. As you can see, for each item I draw one CheckBox component.
In practice, there are always three items (i.e. three check boxes to show). At the beginning I declared initialCheckBoxState, each key-pair represents the state of the checkbox of each. In the onPress callback of Checkbox I toggle each check box state & update the checkBoxesState by hook method setCheckBoxesState as a whole.
Everything works fine at runtime, my screen is re-rendered when toggling checkbox state, UI shows the status of checkboxes correctly. But issue comes when I navigate back to the previous screen and navigate back to this screen, all checkboxes states are back to the initial states.
So, why the checkboxes states are not reserved?
P.S. previous screen and MyScreen are under the same stack navigator. User press a button of previous screen to navigate to MyScreen. From MyScreen user can go to previous screen by pressing the "headerLeft" button
First lets answer the question:
why the checkboxes states are not reserved?
This component is handling its state completely independent, the state is created & handled inside and no values are passed-in from outside. what does it mean? this component has its initial state value inside of itself, it doesn't use any prop or anything else to initialize the state. everytime this component gets created, state is again initialized with that value. so that's the reason you lose all changes done to checkboxes, because when you leave this screen(component) , it gets unmounted(we'll talk about this in next question) and because all values are just handled inside, every data (containing checkboxes state) will be lost.
So now lets talk about this:
is react-native supposed to reserve the state when come back to the screen?
short answer is No. Every component is destroyed when unmounted including their state and data.
Now lets answer why
screens are still on the stack in memory, not destroyed?
Usually developers use a package like react-navigation or RNRF(which is built on top of react-navigation) for react navigation, most of times we don't care about how they handle this navigation logic, we just use the interface the provided us. each of these packages may have their own way to handle navigation. providing full answer to determine why exactly the screen in still in memory needs full code review and sure lots of debugging but i guess there are 2 possibilities. first as i said maybe the package you are using keeps the unmounted screens in memory at least for a while for some reason. the 2nd is a common react community issue which is Unmounted component still in memory which you can check at: https://github.com/facebook/react/issues/16138
And at last lets answer the question:
how do i keep checkboxes state even with navigating back and losing component containing their state?
This doesn't have just one way to that but simple and short answer is move your state out of the that component, e.g move it out to the parent component or a global variable.
to make it more clear lets explain like this: imagine screen A is always mounted, then you go in B and there you can see some checkboxes and you can modify the states. if the state is handled completely inside B, if you navigate back from screen B to A you lose all changes because B is now unmounted. so what you should do it to put checkboxes states in A screen then pass the values down to B. and when modifying the values, you modify A state. so when B gets unmounted all changes are persistant because you have them in A.
other approached exists as well, you can create a global singleton object named globalState. then put values needed to share between multiple screens there. if you prefer redux or mobx you can use them. one of their usages is when you have some data that you need to share between mutiple screens, these data are independent from where you are at and will persist.
This explanation is from official react-navigation documentation:
Consider a stack navigator with screens A and B. After navigating to
A, its componentDidMount is called. When pushing B, its
componentDidMount is also called, but A remains mounted on the stack
and its componentWillUnmount is therefore not called.
When going back from B to A, componentWillUnmount of B is called, but
componentDidMount of A is not because A remained mounted the whole
time.
https://reactnavigation.org/docs/navigation-lifecycle/#example-scenario
Your MyScreen screen is equivalent to screen B from the example, which means you can expect your screen to stay mounted if you navigate forward, but not backwards.
Its simple, just add a keyExtractor to your SectionList component, which would uniquely identify each checkbox, so that react knows which one to re-render on update.
You'll want to use AsyncStorage to persist data to the device. State variables will be cleared any time the component unmounts.
AsyncStorage docs:
https://react-native-community.github.io/asaync-storage/
import AsyncStorage from '#react-native-community/async-storage';
//You can only store string values so convert objects to strings:
const storeData = async (value) => {
try {
const jsonValue = JSON.stringify(value)
await AsyncStorage.setItem('#storage_Key', jsonValue)
} catch (e) {
// saving error
}
}
const getData = async () => {
try {
const jsonValue = await AsyncStorage.getItem('#storage_Key')
return jsonValue != null ? JSON.parse(jsonValue) : null;
} catch(e) {
// error reading value
}
}
UPDATE -
State is not being persisted due to the nature of React Component lifecycles. Specifically, when you navigate away from a screen the lifecycle method componentWillUnmount is called.
Here's an excerpt from the docs:
componentWillUnmount() is invoked immediately before a component is unmounted and destroyed. Perform any necessary cleanup in this method, such as invalidating timers, canceling network requests, or cleaning up any subscriptions that were created in componentDidMount().
...Once a component instance is unmounted, it will never be mounted again.
This means any values stored in state will be destroyed as well and upon navigating back to the screen ComponentDidMount will be called which is where you may want to assign persisted values back to state.
Two possible approaches aside from AsyncStorage that may work for some use cases to persist data across screens is using Context or a singleton.
I would like to know if it's possible to set the state to the initial state values whenever we press back the button in the tabBar ? At the moment, when I leave the tabBar and come back after a few navigation in the app, the infos that the user enter in TextField persist.
Thanks !
You could use React hooks to achieve similar results to lifecycle methods in class functions.
The useEffect method runs on component render. You can set the state in there.
const [currentState, setCurrentState] = useState(null);
useEffect(()=>{
// This will run after 1st render
setCurrentState("");
},[]);
I am getting an object undefined exception during a transition from one screen to another. I have a pretty good idea what is happening, I am just not sure if there is a clean way of handling it without just checking for undefined everywhere.
Here is my scenario:
Source screen references a user object in a Redux store
Navigation is initiated from the source screen to the destination screen.
The destination screen componentDidMount() is called where I clear the user object from the Redux store.
The source screen render() gets called again and the undefined error occurs because I cleared user from the store.
I am assuming that the source and destination screens have some overlap due to the transition. I have tried adding listeners with no luck. I can only get listener handlers to fire for type = action,
I am probably making this more complicated than it is, but I would like to find out if there is a standard way of dealing with this or if I am going about it in a completely wrong way.
Also, my react-navigation is integrated with Redux as per the instructions on React Navigation's website and the Redux React Navigation sample code.
Here is the basic code.
Screen 1
componentDidMount() {
// This is a Redux action that sets an object called user to null
clearUser();
{
Screen 2
render() {
return (
// Other code here
// user is null here because render gets called after Screen1#componentDidMount() gets called
<Text>{user.firstName + ' ' + user.lastName}</Text>
<TouchableOpacity
onPress={() => navigation.dispatch({ type:'NAV_SCREEN_1' })}
>
// button code here
</TouchableOpacity>
// Other code here
)
}
The type of error is "TypeError: Cannot read property 'firstName' of null"
I understand the error and why I am getting it. The user object has been set to null by my Redux action in componentDidMount() of Screen 1 and then Redux causes render of Screen 2 to get called which is referencing a user object which is null.
My question is, is there a special way to accommodate this behavior without having to check if the user object is null every place I need to use it ? Should I call clearUser() somewhere else ?
For the newest version of react-navigation, you can use either addListener, withNavigationFocus or isFocused to detect transition state of the screens.
Another unofficial way is to catch action type NavigationActions.COMPLETE_TRANSITION, in case of using middleware like redux-saga.
As an alternative, you can simply make your Redux-connected screen handle undefined or null state. I had a similar problem and I ended up rendering a loader instead of the screen content when user state is undefined. When I log out, the screen shows a loader for a fraction of a second, then the app navigates away.
I am new in React Native ...just want ask nub question, my App wont triggered componentWillMount and componentDidMount when navigate back to other page,
I use react-native-router-flux for navigator
componentWillMount() {
this.props.searchRequest();
}
exp: I have homescreen and categories, from home I want go to categories: on categories I have that code, but sometime when I back to previouse page (homescreen) and back again on categories componentWillMount not triggered sometime,
I think my categories scene not unmounted
We can detect props change with
componentWillReceiveProps()
but we need set state to accommodate new props value,