I have the following data on SQL
EntryID
PersonID
JobID
JobSalary
1
1
1
270000
2
1
2
500000
3
2
3
320000
4
3
4
180000
5
2
3
320000
6
1
3
85000
7
1
1
270000
8
1
2
500000
9
2
3
320000
10
3
4
180000
For each entry, I want to have a column that calculates the total salary (of all jobs) of the specific person.
The tricky part is that multiple entries can refer to the same person and/or the same job, but I only want to sum up each job for each person once.
The output would be:
EntryID
PersonID
JobID
JobSalary
PersonTotalSalaryAllJobs
1
1
1
270000
855000
2
1
2
500000
855000
3
2
3
320000
320000
4
3
4
180000
180000
5
2
3
320000
320000
6
1
3
85000
855000
7
1
1
270000
855000
8
1
2
500000
855000
9
2
3
320000
320000
10
3
4
180000
180000
Any ideas on how to do this?
Thanks!
To get what you want you can use a query like this
SELECT
s.*,
pjts.total_salary
FROM salary s
LEFT JOIN (
SELECT
*,
SUM(jobsalary) OVER (PARTITION BY personid) AS total_salary
FROM (
SELECT DISTINCT
personid,
jobid,
jobsalary
FROM salary
) pjs
) pjts ON s.personid = pjts.personid AND s.jobid = pjts.jobid
You can check a working demo here
Or even simplier using only one subquery like this
SELECT
s.*,
pjts.total_salary
FROM salary s
LEFT JOIN (
SELECT
personid,
jobid,
SUM(jobsalary) OVER (PARTITION BY personid) AS total_salary
FROM salary
GROUP BY personid, jobid, jobsalary
) pjts ON s.personid = pjts.personid AND s.jobid = pjts.jobid
You can check a working demo here
Related
Hi Experts I have a table like this
T1
Order_no
Qty
1
3
2
5
3
1
4
3
I need to generate a column 'serial no' having values based on 'qty'
Output needed
OrderNo
Qty
SerailNo
1
3
1
1
3
2
1
3
3
2
5
1
2
5
2
2
5
3
2
5
4
2
5
5
3
1
1
4
3
1
4
3
2
4
3
3
Any suggestions?
Thanks in advance!!
You don't mention the specific database so I'll assume you are using PostgreSQL, aren't you?
You can use a Recursive CTE to expand the rows. For example:
with recursive
n as (
select order_no, qty, 1 as serial_no from t1
union all
select order_no, qty, serial_no + 1
from n
where serial_no < qty
)
select * from n order by order_no, serial_no
Result:
order_no qty serial_no
--------- ---- ---------
1 3 1
1 3 2
1 3 3
2 5 1
2 5 2
2 5 3
2 5 4
2 5 5
3 1 1
4 3 1
4 3 2
4 3 3
See running example at DB Fiddle.
EDIT FOR ORACLE
If you are using Oracle the query changes a bit to:
with
n (order_no, qty, serial_no) as (
select order_no, qty, 1 from t1
union all
select order_no, qty, serial_no + 1
from n
where serial_no < qty
)
select * from n order by order_no, serial_no
Result:
ORDER_NO QTY SERIAL_NO
--------- ---- ---------
1 3 1
1 3 2
1 3 3
2 5 1
2 5 2
2 5 3
2 5 4
2 5 5
3 1 1
4 3 1
4 3 2
4 3 3
See running example at db<>fiddle.
You should first provide the database you're using. Whether it's oracle, Sql Server, PostGreSQL will determine which procedural language to use. It's very likely that you'll need to do this in two steps:
1st: Duplicate the number of rows based on the column Qty using a decreasing loop
2nd: You'll need to create a sequential partionned column based on the Qty column
1.I have data as follows (just a subset - there are 20K records)
sku,id
1 1
1 2
1 2
1 2
1 3
1 4
1 1
1 2
1 3
1 4
1 4
1 4
1 5
1 6
1 6
2 1
2 1
2 2
2 3
2 3
2 3
2 4
2 4
2 5
2 5
2 6
2 7
2 1
2 2
2 3
The above values translate to
1 = 4 records
1 = 6 records
2 = 7 records
2 = 3 records
The MAX would just give me 6 for one and 7 for 2
The actual total is 1 = 10 and 2 = 10
How do I sum up to get the correct values?
You can use order by and some way of limiting rows. In standard SQL this would be:
select t.*
from t
order by id desc
fetch first 2 rows only;
However, some databases might use limit or select top or some other method.
No handling of ties here. Thousands of other questions handle this topic.
select sku, id
from (
select *, row_number() over (order by id desc) rn
from T
) t
where rn <= 2
order by rn desc;
I am trying to do count of client locations that are count > 1, which seems to work fine as indicated in the first query.
select clientID,count(clientlocations)clientcount
from db.schema.table
group by clientid
having count(clientid) > 1
clientid clientcount
1 5
2 7
3 8
But in order for me to join with the revenue I need to bring in the revenueid which fragments the clientcount.
select reveneueid,clientID,
count(clientlocations)clientcount
from db.schema.table
group by revenueid,clientid
having count(clientid) > 1
revenueid clientid clientcount
5000 1 4
6144 1 1
4651 2 3
4785 2 1
8745 2 3
7869 3 5
4963 3 3
A client can have multiple `revenueid'.
I want to have constant count of the client likewise below.
Requested:
select reveneueid,clientID,
count(clientlocations)clientcount
from db.schema.table
group by revenueid,clientid
having count(clientid) > 1
revenueid clientid clientcount
5000 1 5
6144 1 5
4651 2 7
4785 2 7
8745 2 7
7869 3 8
4963 3 8
I am using SQL Server 2016.
You could use windowed SUM per clientid
select reveneueid,clientID,
SUM(count(clientlocations)) OVER(PARITION BY clientid) AS clientcount
from db.schema.table
group by revenueid,clientid
having count(clientid) > 1
I have 4 tables here, I need to multiply newly entered row value in a table with another row and find the total sum using CustomerId:
CustomerTable:
CustomerId Name EmailId
-------------------------
1 Paul r#r.com
2 John J#j.com
LoyaltyPointTable:
LoyaltyPointsId LoyaltyType Points
---------------------------------------
1 Registration 10
2 Loginstatus 1
3 Downloading 10
4 Redemming 1
5 Sharing 20
6 Refer 10
LoyaltyDetailsTable:
LoyaltyDetailsId LoyaltyPointsId CustomerId Dates
-------------------------------------------------
1 1 1 2015-01-22
2 2 1 2015-01-22
3 3 2 2015-01-22
4 3 1 2015-01-22
5 4 1 2015-01-22
6 4 1 2015-01-24
7 5 1 2015-01-24
This query works fine for the total sum for each LoyaltyType
SELECT
LoayaltyPointsTable.LoyaltyType,
COUNT(CustomerTable.CustomerId) AS UserActions,
SUM(LoayaltyPointsTable.Points) AS TotalPoints
FROM
LoayaltyPointsTable
JOIN
LoyaltyDetailsTable ON LoayaltyPointsTable.LoyaltyPointsId = LoyaltyDetailsTable.LoyaltyPointsId
JOIN
CustomerTable ON CustomerTable.CustomerId = LoyaltyDetailsTable.CustomerId
WHERE
CustomerTable.CustomerId = 1
GROUP BY
LoyaltyDetailsTable.CustomerId ,LoayaltyPointsTable.LoyaltyType
below RedeemPointsTable is created with relation to row redeeming in LoyaltyPointTable:
RedeemPointsTable:
RedeemPointsId CustomerId ShopName BillNo Amount
------------------------------------------------
1 1 Mall x 4757 100
3 1 Mall y SH43 50
4 1 Mall x 7743 10
6 1 Mall x s34a 60
What I am expecting is before calculating the total sum, I want column Amount sum (100+50+10+60) * 1 in Redeeming in LoyaltyPointTable to be added with total points for each CustomerId
Expected output
LoyaltyType UserActions TotalPoints
-------------------------------------
Downloading 1 10
Loginstatus 1 1
Redemming 4 (100+50+10+60)*1(here using Amount in RedeemPointsTable)
Refer 1 10
Registration 1 10
Sharing 1 20
User actions count is 4, it is based on the Amount he entered in RedeemPointsTable
Should I need to make changes in adding a foreign key column in RedeemPointsTable or can you point out my mistake?
Any help would be great.
This is the query which returns desired result:
SELECT
LoyaltyPointTable.LoyaltyType,
CASE
WHEN LoyaltyPointTable.LoyaltyPointsId=4 THEN (SELECT COUNT(amount) FROM RedeemPointsTable where CustomerId=1)
ELSE COUNT(CustomerTable.CustomerId)
END as UserActions,
CASE
WHEN LoyaltyPointTable.LoyaltyPointsId=4 THEN (SELECT SUM(amount) FROM RedeemPointsTable where CustomerId=1)*Points
ELSE SUM(LoyaltyPointTable.Points)
END as TotalPoints
FROM
LoyaltyPointTable
JOIN
LoyaltyDetailsTable ON LoyaltyPointTable.LoyaltyPointsId = LoyaltyDetailsTable.LoyaltyPointsId
JOIN
CustomerTable ON CustomerTable.CustomerId = LoyaltyDetailsTable.CustomerId
WHERE
CustomerTable.CustomerId = 1
GROUP BY
LoyaltyDetailsTable.CustomerId ,LoyaltyPointTable.LoyaltyType
You can check it here
I have a table which rank the items which i have.
I need a queries which will pick up only the top 2 ranks for a given item, the rank may not be in sequential order.
I need to fetch the item with least two ranks, there will same rank for two items as well.
Here is the snap shot of my table.
Item Id Supp Id Rank
1 2 2
1 1 7
1 7 5
1 9 11
2 67 4
2 9 14
2 10 14
2 34 4
2 25 3
2 60 3
2 79 5
my requirement is if I enter 2 i should get the result as below
Item Id Supp_id Rank
2 25 3
2 60 3
2 67 4
2 34 4
I am using oracle 10g version.
As one of the approaches it can be done as follows. Here we are using dense_rank() over() analytic function to assign a rank for a row in a ordered by rank group of rows .
select t.item_id
, t.supp_id
, t.rank
from (select item_id
, supp_id
, rank
, dense_rank() over(partition by item_id
order by rank) as rn
from t1
where item_id = 2
) t
where t.rn <= 2
Result:
ITEM_ID SUPP_ID RANK
---------- ---------- ----------
2 25 3
2 60 3
2 67 4
2 34 4
SQLFiddle Demo