How to replace SQL with bash variable of SQL command output - sql

Question

I am working on a program in bash that checks for valid JSON files before loading them into a table. The process first runs f_check_valid_json to verify the JSON. This process runs f_exe_sql_stmnt() that returns a column of bad files, stored in variable bad_fl_list. I would like to be able to input bad_fl_list in the WHERE clause of my update and delete sections of the function.
Right now, the SQL fails when there is more than one JSON file ID in bad_fl_list
f_exe_sql_stmnt(){
db=$1
sql_str=$2
psql -d "$db" -Atc "$sql_str"
if [ $? -gt 0 ]
then
echo "======================================================================="
echo "***Error: Database error while executing sql statement($sql_str)..."
exit 123
fi
}
f_check_valid_json() {
echo "*** checking for valid JSON format***"
sql_stmnt="Select json_fl_id from json_stgng where is_valid_json(json_datarec_fl) = false;"
bad_fl_list=$(f_exe_sql_stmnt "$t_db" "${sql_stmnt}")
echo "BAD FILE LIST: ${bad_fl_list}"
if [ ! -z "$bad_fl_list" ]
then
echo "BAD JSON LIST IS NOT EMPTY"
echo "*** updating balancing table to reflect bad file ***"
updt_bal_log_str="UPDATE ${bal_log_tbl} SET trgt_load_stus_cd ='F' where json_fl_id in ($bad_fl_list);"
f_exe_sql_stmnt "$DB" "$updt_bal_log_str"
echo "*** deleting bad JSON file record from staging with file ID: ${bad_fl_list}"
delete_stmnt="delete from ${stg_tbl} where json_fl_id in ($bad_fl_list);"
f_exe_sql_stmnt "$t_db" "${delete_stmnt}"
fi
}
Here is some example output from the logs:
+ psql -d dedw -Atc 'UPDATE json_load_bal_dtl_log SET trgt_load_stus_cd ='\''F'\'' where json_fl_id in (O21181043417
O21181043417
O21181003641);'
ERROR: syntax error at or near "O21181043417"
LINE 2: O21181043417
^