I get garbage value on this jagged array - oop

I get garbage value on this jagged array, that takes input size from another array's last value which must be -111(if not ten add one index to put in -111).
i know i have missed some cout statements but dont know why i get garbage vals
'''
int jaggedArr(int** arr2, int r, int c)
{
int* numbers = nullptr;
numbers = new int[r]; /// array to store no of columns
int** jagArr = new int* [r]; /// jagged array
for (int i = 0; i < r; i++)
{
int tempNum;
for (int j = 0; j < c; j++)
{ //store size of cols in arr4 to put int new array (arr3)
if (arr2[i][j] == -111)
{
tempNum = j;
numbers[i] = tempNum;//if -111 is present then dont change size just copy
}
else if (arr2[i][j] != -111)
{
tempNum = j + 1;
numbers[i] =tempNum;//else if -111 is not present then dont change size just copy
}
tempNum = 0;
}
}
for (int i = 0; i < r; i++)
{
jagArr[i] = new int[numbers[i]];
}
for (int i = 0; i < r; i++)
{
for (int j = 0; j < 10; j++)//remove 10
{
jagArr[i] = new int[numbers[i]];
}
}
cout << "Showing all the Inputed data in a matrix form" << endl;
for (int i = 0; i < r; i++) {
for (int j = 0; j < numbers[i]; j++)
{
//if (jagArr[i][j] >= 0 && jagArr[i][j] <= 9)
//{
// cout << jagArr[i][j] << " |";
//}
//else if (jagArr[i][j] == -111)
//{
// cout << jagArr[i][j] << "|";
//}
//else
//{
// cout << jagArr[i][j] << " |";
//}
cout << jagArr[i][j];
}
cout << "\n";
}
return **arr2;
}
'''

Related

How I can sort an ArrayList of int arrays?

I have this code. I'm dealing with the N-Queen problem.
The problem is when I wanna show results by screen, the arrays are not ordered. But in this code I can't order them using Comparator. It's very strange because in other Class it works perfectly using Comparator, but here it doesn't work. Hope anyone could help me. Thanks in advance.
import java.util.*;
public class NReinas {
public static void resolverReinas(int n){
String[][] tablero;
tablero = generarTablero(n);
ubicarReina(tablero, 0, n);
}
public static void ubicarReina(String[][] tablero, int etapa, int n){
ArrayList <int[]> resultados = new ArrayList<>();
for(int i = 0; i < tablero.length; i++){
if(isValido(tablero, i, etapa)){
tablero[i][etapa] = "R";
if(etapa < tablero.length - 1){
ubicarReina(tablero, etapa + 1, n); //Recursividad
}else {
resultados.add(devolverSolucion(tablero, n));
}
tablero[i][etapa] = " "; //Backtracking: vaciamos el tablero
}
}
//The ArrayList I want to order by int arrays
for (int[] r : resultados) {
System.out.println(Arrays.toString(r));
}
}
public static boolean isValido(String[][] tablero, int i, int etapa){
for(int x = 0; x < etapa; x++){
if(tablero[i][x].equals("R")){
return false;
}
}
for(int j = 0; j < tablero.length && (i-j) >= 0 && (etapa-j) >=0; j++){
if(tablero[i - j][etapa - j].equals("R")){
return false;
}
}
for(int j = 0; j < tablero.length && (i + j) < tablero.length && etapa - j >= 0; j++){
if(tablero[i + j][etapa - j].equals("R")){
return false;
}
}
return true;
}
public static String[][] generarTablero(int length){
String[][]res = new String[length][length];
for (int i = 0; i < res.length; i++) {
for (int j = 0; j < res.length; j++) {
res[i][j] = " ";
}
}
return res;
}
public static int[] devolverSolucion(String[][] tablero, int n){
int[] solucion = new int[n];
for (int i = 0; i < tablero.length; i++) {
for (int j = 0; j < tablero.length; j++) {
if(tablero[i][j] == "R"){
solucion[i] = j;
}
}
}
return solucion;
}
}
Try Using Integer instead of int and save array values on List instead, so you can use sort them
List<Integer> list = Arrays.asList(solucion);
Collections.sort(list);
If you insist in using and array you can reconverti the list to an array
(Integer[]) list.toArray();

How to generate binary tree dot file for Graphviz from C++

I have implemented a Binary Search Tree in C++ which support dynamically creating and deleting nodes. To visualize the tree, I firstly tried displaying edges with / and \. However, this gives really awful visualization, as the position of / and \ needs to be calculated precisely. The current figures are as follows:
So I found a tool called Graphviz. The raw language supported by Graphviz is dot language, which I am not familiar with.
I read the documentation and found the dot language easy to write and read, but I still want to use my C++ code to generate the tree as this contains much content such as inserting according to user's input.
Is there any chance to use some function to generate the dot file?
The code of my binary tree:
//BTNode.h
#include <iostream>
using namespace std;
template<class T>
struct BTNode{
BTNode(){
lChild = rChild = NULL;
}
BTNode(const T& x){
element = x;
lChild = rChild = NULL;
}
BTNode(const T& x, BTNode<T>* l, BTNode<T>* r){
element = x;
lChild = l;
rChild = r;
}
T element;
int digit, row;
BTNode<T>* lChild, *rChild;
};
//BSTree.h
#include"ResultCode.h"
#include "BTNode.h"
#include "seqqueue.h"
#include <math.h>
template <class T>
class BSTree
{
public:
BSTree(){ root = NULL; }
ResultCode SearchByRecursion(T& x)const;
ResultCode Insert(T& x);
ResultCode Remove(T& x);
void InOrder(void(*Visit)(T& x));
ResultCode SearchByIteration(T& x);
void GradeOrder(void(*Visit)(T &x), BTNode<T> *t, int height);
BTNode<T>* root;
void printSpace(int num);
int GetHeight();
int GetHeight(BTNode<T> *t);
int **A;
private:
ResultCode SearchByRecursion(BTNode<T> *p, T& x)const;
void InOrder(void(*Visit)(T& x), BTNode<T> *t);
};
template <class T>
ResultCode BSTree<T>::SearchByRecursion(T &x)const{
return SearchByRecursion(root, x);
}
template <class T>
ResultCode BSTree<T>::SearchByRecursion(BTNode<T> *p, T& x)const{
if (!p) return NotPresent;
else if (x < p->element) return SearchByRecursion(p->lChild, x);
else if (x > p->element) return SearchByRecursion(p->rChild, x);
else{
x = p->element;
return Success;
}
}
template <class T>
ResultCode BSTree<T>::SearchByIteration(T& x){
BTNode<T> *p = root;
while (p)
if (x < p->element) p = p->lChild;
else if (x > p->element) p = p->rChild;
else{
x = p->element;
return Success;
}
return NotPresent;
}
template<class T>
ResultCode BSTree<T>::Insert(T& x){
BTNode<T> *p = root, *q = NULL;
while (p){
q = p;
if (x < p->element) p = p->lChild;
else if (x > p->element) p = p->rChild;
else { x = p->element; return Duplicate; }
}
p = new BTNode<T>(x);
if (!root) root = p;
else if (x < q->element) q->lChild = p;
else q->rChild = p;
return Success;
}
template <class T>
ResultCode BSTree<T>::Remove(T& x){
BTNode<T> *c, *s, *r, *p = root, *q = NULL;
while (p && p->element != x){
q = p;
if (x < p->element) p = p->lChild;
else p = p->rChild;
}
if (!p) return NotPresent;
x = p->element;
if (p->lChild&&p->rChild)
{
s = p->rChild;
r = p;
while (s->lChild){
r = s; s = s->lChild;
}
p->element = s->element;
p = s; q = r;
}
if (p->lChild)
c = p->lChild;
else c = p->rChild;
if (p == root)
root = c;
else if (p == q->lChild)
q->lChild = c;
else q->rChild = c;
delete p;
return Success;
}
template <class T>
void BSTree<T>::InOrder(void(*Visit)(T &x)){
InOrder(Visit, root);
}
template <class T>
void BSTree<T>::InOrder(void(*Visit)(T &x), BTNode<T> *t){
if (t){
InOrder(Visit, t->lChild);
Visit(t->element);
InOrder(Visit, t->rChild);
}
}
template <class T>
void BSTree<T>::GradeOrder(void(*Visit)(T &x), BTNode<T> *t, int height)
{
A = new int*[height];
for (int i = 0; i < height; i++){
A[i] = new int[(int)pow(2, height) - 1];
}
for (int i = 0; i < height; i++)
for (int j = 0; j < (int)pow(2, height) - 1; j++){
A[i][j] = -1;
}
SeqQueue<BTNode<T>*> OrderQueue(10);
BTNode<T> * loc = t;
loc->row = 0;
loc->digit = 0;
if (loc){
OrderQueue.EnQueue(loc);
A[loc->row][loc->digit] = loc->element;
}
while (!OrderQueue.IsEmpty())
{
OrderQueue.Front(loc);
OrderQueue.DeQueue();
if (loc->lChild)
{
A[(loc->row) + 1][2 * (loc->digit)] = loc->lChild->element;
loc->lChild->row = (loc->row) + 1;
(loc->lChild->digit) = (loc->digit) * 2;
OrderQueue.EnQueue(loc->lChild);
}
if (loc->rChild)
{
A[(loc->row) + 1][2 * (loc->digit) + 1] = loc->rChild->element;
loc->rChild->row = (loc->row) + 1;
(loc->rChild->digit) = (loc->digit) * 2 + 1;
OrderQueue.EnQueue(loc->rChild);
}
}
cout << endl;
int total = (int)(pow(2, height)) - 1;
for (int i = 0; i < height; i++){
if (i != 0){
cout << endl;
}
int space1 = (total / (int)(pow(2, i + 1)));
int space2;
if (i == 0){
space2 = 0;
}
else{
space2 = (total - 2 * space1 - (int)pow(2, i)) / (int)(pow(2, i) - 1);
}
printSpace(space1);
for (int j = 0; j < (int)pow(2, i); j++){
if (A[i][j] != -1){
cout << A[i][j];
}
else{
cout << " ";
}
printSpace(space2);
}
printSpace(space1);
cout << endl;
}
}
template <class T>
void BSTree<T>::printSpace(int num){
for (int i = 0; i < num; i++){
cout << " ";
}
}
template<class T>
int BSTree<T>::GetHeight()
{
return GetHeight(root);
}
template<class T>
int BSTree<T>::GetHeight(BTNode<T> *t)
{
if (!t)return 0;
if ((!t->lChild) && (!t->rChild)) return 1;
int lHeight = GetHeight(t->lChild);
int rHeight = GetHeight(t->rChild);
return (lHeight > rHeight ? lHeight : rHeight) + 1;
}
template <class T>
void Visit(T& x){
cout << x << " ";
}
//main.cpp
#include <iostream>
#include "BSTree4.h"
#include<Windows.h>
int getDigit(int x);
int main(){
BSTree<int> bt;
int number;
// char choice;
cout << "Welcome to BSTree System, to begin with, you need to create a tree!(Press enter to continue...)" << endl;
getchar();
cout << "Please enter the size of the Binary Search Tree:";
cin >> number;
int *ToBeInserted = new int[number];
cout << "Enter the number of each Node(size:" << number << "):";
for (int i = 0; i < number; i++){
cin >> ToBeInserted[i];
}
cout << "OK,now the tree will be created!" << endl;
for (int i = 0; i < number; i++){
cout << "Inserting Node " << i;
for (int k = 0; k < 3; k++){
cout << ".";
//Sleep(200);
}
showResultCode(bt.Insert(ToBeInserted[i]));
//Sleep(500);
}
cout << "Done." << endl;
//Sleep(500);
int height = bt.GetHeight();
bt.GradeOrder(Visit, bt.root,height);
int a;
cout << "please enter the number to search:";
cin>>a;
showResultCode(bt.SearchByRecursion(a));
bt.GradeOrder(Visit, bt.root,height);
if (bt.SearchByRecursion(a) == 7){
cout << "Now delete the number" << "..." << endl;
showResultCode(bt.Remove(a));
bt.GetHeight();
cout << "Deleted!Now the tree is:" << endl;
bt.GradeOrder(Visit, bt.root, height);
bt.InOrder(Visit);
cout << endl;
}
return 0;
}
//resultcode.h
#include<iostream>
using namespace std;
enum ResultCode{ NoMemory, OutOfBounds, Underflow, Overflow, Failure,
NotPresent, Duplicate, Success };
void showResultCode(ResultCode result)
{
int r = (int)result;
switch (result)
{
case 0:cout << "NoMemory" << endl; break;
case 1:cout << "OutOfBounds" << endl; break;
case 2:cout << "Underflow" << endl; break;
case 3:cout << "Overflow" << endl; break;
case 4:cout << "Failure" << endl; break;
case 5:cout << "NotPresent" << endl; break;
case 6:cout << "Duplicate" << endl; break;
case 7:cout << "Success" << endl; break;
default: cout << "Exception occured:unknown resultcode" << endl;
}
}
Update: I have solved the problem myself, check the answer below.
The key elements in dot language file in this problem are nodes and edges. Basically the dot file structure for a binary tree would be like the following:
digraph g {
//all the nodes
node0[label="<f0>|<f1> value |<f2>"]
node1[label="<f0>|<f1> value |<f2>"]
node2[label="<f0>|<f1> value |<f2>"]
...
//all the edges
"node0":f2->"node4":f1;
"node0":f0->"node1":f1;
"node1":f0->"node2":f1;
"node1":f2->"node3":f1;
...
}
The following output of the dot file can be used to understand the structure:
Explanation for the dot file:
For the node part node0[label="<f0>|<f1> value |<f2>"] means the node called node0 has three parts: <f0> is the left part, <f1> is the middle part with a value, <f2> is the right part. This just corresponds to leftchild, value and rightchild in a binary node.
For the edges part, "node0":f2->"node4":f1; means the right part of node0(i.e.<f2>) points to the middle part of node4 (i.e. <f1>).
Therefore, the way to generate the dot file is simply through a traverse of a binary tree. Any method is fine. (BFS,DFS...) All we need is to add the code to write the nodes and corresponding edges into file when we do the traverse. I personally used BFS with level order traverse of a binary tree to implement which is shown below as a function called showTree.
void showTree(BSTree<int> &bst,int total,int *Inserted){
char filename[] = "D:\\a.gv"; // filename
ofstream fout(filename);
fout << "digraph g{" << endl;
fout << "node [shape = record,height = .1];" << endl;
SeqQueue<BTNode<int>*> OrderQueue(1000);
BTNode<int> * loc = bst.root;
loc->row = 0;
loc->digit = 0;
int num = 0;
if (loc){
OrderQueue.EnQueue(loc);
loc->ID = num++;
fout << " node" << loc->ID << "[label = \"<f0> |<f1>" << loc->element << "|<f2>\"];" << endl;
}
while (!OrderQueue.IsEmpty())
{
OrderQueue.Front(loc);
OrderQueue.DeQueue();
if (loc->lChild)
{
loc->lChild->row = (loc->row) + 1;
(loc->lChild->digit) = (loc->digit) * 2;
OrderQueue.EnQueue(loc->lChild);
loc->lChild ->ID= (num++);
fout << " node" << loc->lChild->ID << "[label = \"<f0> |<f1>" << loc->lChild->element << "|<f2>\"];" << endl;
//cout << loc->ID;
}
if (loc->rChild)
{
loc->rChild->row = (loc->row) + 1;
(loc->rChild->digit) = (loc->digit) * 2 + 1;
OrderQueue.EnQueue(loc->rChild);
loc->rChild->ID = (num++);
fout << " node" << loc->rChild->ID << "[label = \"<f0> |<f1>" << loc->rChild->element << "|<f2>\"];" << endl;
//cout << loc->ID;
}
}
//begin to draw!
SeqQueue<BTNode<int>*> OrderQueue2(1000);
BTNode<int> * loc2 = bst.root;
loc2->row = 0;
loc2->digit = 0;
if (loc2){
OrderQueue2.EnQueue(loc2);
}
while (!OrderQueue2.IsEmpty())
{
OrderQueue2.Front(loc2);
OrderQueue2.DeQueue();
if (loc2->lChild)
{
loc2->lChild->row = (loc2->row) + 1;
(loc2->lChild->digit) = (loc2->digit) * 2;
OrderQueue2.EnQueue(loc2->lChild);
cout << "\"node" << loc2->ID << "\":f0->\"node" << loc2->lChild->ID << "\":f1;" << endl;
cout << loc2->lChild->element << endl;
fout << "\"node" << loc2->ID << "\":f0->\"node" << loc2->lChild->ID << "\":f1;" << endl;
}
if (loc2->rChild)
{
loc2->rChild->row = (loc2->row) + 1;
(loc2->rChild->digit) = (loc2->digit) * 2 + 1;
OrderQueue2.EnQueue(loc2->rChild);
cout << "\"node" << loc2->ID << "\":f2->\"node" << loc2->rChild->ID << "\":f1;" << endl;
cout << loc2->rChild->element << endl;
fout << "\"node" << loc2->ID << "\":f2->\"node" << loc2->rChild->ID << "\":f1;" << endl;
}
}
fout << "}" << endl;
}
And the final output:

ArrayList Method Returns a null ArrayList, main program cannot access

I'm trying to create a basic function that calls on a method that creates the 2D ArrayList that will be used further in the main program to do things like calculate the row and column sums as well as print out the triangle.
However, after it runs the ArrayList returns null. What's going on?
Thanks,
public class Trib
{
private ArrayList<ArrayList<Integer>> triangle;
private int Asize;
public Trib (int size)
{
// convert the argument to type 'int' to be used in the program
Asize = size;
// create an ArrayList of ArrayLists, it will have 'size' number ArrayLists contained within
ArrayList<ArrayList<Integer>> triangle = new ArrayList<ArrayList<Integer>>(size);
// create the inner ArrayLists
for (int i = 0; i < size; i++)
{
// add to index 'i' of our ArrayList a new ArrayList of size (i+1)
triangle.add(new ArrayList<Integer>(i+1));
for (int j = 0; j <= i; j++)
{
if (j==0 || j == i)
{
triangle.get(i).add(1);
}
else
triangle.get(i).add(triangle.get(i-1).get(j-1)+triangle.get(i-1).get(j));
System.out.print(triangle.get(i).get(j) + " ");
}
System.out.println();
}
triangle.clone();
}
public void printTriangle()
{
System.out.print(triangle.get(1).get(1));
/*for (int i = 0; i < Asize; i++)
{
for (int j = 0; j <= i; j++)
{
System.out.print(triangle.get(1).get(1) + " ");
}
System.out.println();
}*/
}
/*public Trib()
{
this(5);
}*/
/*public int Psize()
{
return triangle.size();
}
public ArrayList<Integer> sumRows()
{
ArrayList<Integer> row_sum = new ArrayList<Integer>(Asize);
for (int i = 0; i < Asize; i++)
{
for (int j = 0; j < i; j++)
{
row_sum.add(triangle.get(i).get(j));
}
}
return row_sum;
}
public ArrayList<Integer> sumCols()
{
ArrayList<Integer> col_sum = new ArrayList<Integer>(Asize);
for (int i = 0; i < Asize; i++)
{
for (int j = 0; j < i; j++)
{
col_sum.add(triangle.get(i).get(i));
}
}
return col_sum;
}*/
public static void main(String[] args)
{
if(args.length < 1)
{
System.err.println("Sorry, this program needs an integer argument.");
System.exit(1);
}
Trib pt = new Trib(Integer.parseInt(args[0]));
pt.printTriangle();
//ArrayList<Object> sum_rows = new ArrayList<Object>(pt.Psize());
// sum_rows.add;
System.out.println("\nHere are the sum of rows:");
//for (int i = 0; i < pt.Psize(); i++)
//System.out.println(sum_rows.get(i));
//ArrayList<Integer> sum_cols = new ArrayList<Integer>(pt.Psize());
System.out.println("\nHere are the sum of columns:");
//for (int i = 0; i < pt.Psize(); i++)
//System.out.printf("%-5d", sum_cols.get(i));
}
}
Watch out what's what you are doing: Notice that you have TWO variables named "triangle": The first one is an instance variable and the second is a local variable, which is the only one you have initialized.
My suggestion to avoid this common mistake is to pre-pend "this." to any use of what you intend must be an instance variable. And, if in doubt, if you use a development environment as Eclipse, press CTRL and click on your variable to navigate to the point where it is declared.

Retrieving and manipulating data from file

The following code is supposed to retrieve the data related to the players info, sort it out and then rewrite the file now organized. Going to give an example of the files.
Original layout:
3
2 2
John 33 M 5
Anna 20 F 2
Rody 23 M 1
What it has to look like after the code:
3
2 2
Rody 23 M 1
Anna 20 F 2
John 33 M 5
I made the following code:
vector<string> playerScoresFromFile(const string filename) //Gets each one of those lines with the name, ..., and score of the person
{
int dim = filename[7] - '0'; // char to integer
vector<string> vec;
string line;
ifstream fin (filename.c_str());
for (int i = 0; i < dim + 1; i++)
{
getline(fin, line);
}
while(! fin.eof())
{
getline(fin, line);
vec.push_back(line);
}
return vec;
}
vector< vector<int> > readBoardFromFile(const string filename) //gets the board from the file (first 3 numbers)
{
int dim = filename[7] - '0'; // char to integer
string line;
vector< vector<int> >vec(dim, vector<int>(dim));
ifstream fin (filename.c_str());
int i = 0;
int j, k;
while(i < dim)
{
getline(fin, line);
int sizeOfLine = line.length();
if (line[0] == '\0')
{
break;
}
else
{
for (j = 0, k = 0; j < (sizeOfLine / 3); j++, k += 3)
{
string elementOfVectorStr = (line.substr(k,3));
int elementOfVectorInt = stringToInt(elementOfVectorStr);
if (abs(elementOfVectorInt) > 100) // when the element is a " ", the corresponding integer is always
{ // a very large number, positive or negative
elementOfVectorInt = 0;
}
vec[i][j] = elementOfVectorInt;
}
}
i++;
}
return vec;
}
vector<string> sortPlayersByTime (vector<string> &vec) // Creates a substring of the string extracted by "playerScoresFromFile" and analyses the times (Which are the last numbers to the right)
{
vector<int> timesInt(vec.size());
for (size_t i = 0; i < vec.size(); i++)
{
string str = vec[i];
timesInt[i] = stringToInt(str.substr(26));
}
for (size_t i = 0; i < vec.size() - 1; i++)
{
if(timesInt[i] > timesInt[i+1])
{
swap(vec[i], vec[i+1]);
}
}
return vec;
}
bool isOrdered (const vector<string> vec) //Checks if the vector is ordered
{
vector<int> timesInt(vec.size());
for (size_t i = 0; i < vec.size(); i++)
{
string str = vec[i];
timesInt[i] = stringToInt(str.substr(26));
}
for (size_t i = 0; i < vec.size() - 1; i++)
{
if(timesInt[i] > timesInt[i+1])
{
return false;
}
}
return true;
}
void writeBoardToFile(vector< vector<int> >&vec, string filename) //Rewrites the board to the file (Those first 3 numbers of the file)
{
ofstream fout(filename.c_str());
for (size_t i = 0; i < vec.size(); i++)
{
for (size_t j = 0; j < vec.size(); j++)
{
if(vec[i][j] != 0)
{
fout << setw(3) << vec[i][j];
}
else
{
fout << setw(3) << " ";
}
}
fout << endl;
}
fout << endl;
}
void vec_to_file(vector<string> vec, string filename) //Rewrites the vector to the file
{
ofstream fout(filename, ios::app);
for (int i = 0; i < vec.size(); i++)
{
fout << vec[i] <<endl;
}
}
void displayFile (string filename) //Displays the final board to check if it worked
{
vector<string> vec;
string line;
ifstream myfile (filename);
while ( ! myfile.eof() )
{
getline (myfile, line);
vec.push_back(line);
}
for (size_t i = 0; i < vec.size(); i++)
{
cout << vec[i] <<endl;
}
}
int main()
{
vector< vector<int> > vec = readBoardFromFile("puzzle_2x2_001.txt");
vector<string> vecxz = playerScoresFromFile("puzzle_2x2_001.txt");
writeBoardToFile(vec, "puzzle_2x2_001.txt"); //Writes the board to the file
while (! isOrdered(vecxz)) //This loop should run while they haven't been sorted out, but the program crashes here and I have no idea why.
{
sortPlayersByTime(vecxz);
}
//vec_to_file(vecxy, "puzzle_2x2_001.txt"); //Should write the vector to the file upon sorting them out successfully.
cin.get();
}
My problem is the program crashes everytime it gets to the while(! isOrdered(vecxz)) loop but I have no idea why. Can anyone give me a hand? I'd be thankful :)

c++ print out arrays incrementally

I am trying to print out arrays incrementally like this;
TractMultBox->Text = rows[0] + newline;
TractMultBox->Text += rows[1] + rows[0] + newline;
TractMultBox->Text += rows[2] + rows[1] + rows[0] + newline;
which would give an output like this
3
43
543
I can do fine with this code, however. It would like to use a for loop, that would make it easier, since I would like it to output all arrays until max is reached automatically.
I'm assuming you want to concatenate and not sum.
string text;
for (int i = 0; i < rows.count; ++i)
{
text = rows[i] + text;
TractMultBox->Text = text + newline;
}
for less lines of code.
string text = newline;
for (int i = 0; i < rows.count; ++i)
{
TractMultBox->Text = (text = rows[i] + text);
}
but that's a little hard to read.
Sounds like a job for a for loop indeed perhaps something like this:
#include <iostream>
int main()
{
int rows[3] = {3, 4, 5};
for (int i(0); i < 3; ++i)
{
for (int j(i); j >= 0; --j)
std::cout << rows[j];
std::cout << "\n";
}
std::cin.get();
return 0;
}
If rows contained 345 this would give you the following output:
3
43
543
Not sure if that's what you wanted but you can adjust the loops accordingly. The key is to have 2 for loops.
Edit: Changed to self contained example you can play with
What about a double loop like:
for (int i = 0; i < maxNRows; ++i)
{
for (int j = 0; j < i; ++j)
{
TractMultBox->Text += rows[j];
}
TractMultBox->Text += newline;
}